00. First and Zeroth Law of Thermodynamics
Thermodynamics

148097 An ideal gas is taken through the cycle $A \rightarrow B \rightarrow C \rightarrow A$, as shown in the figure below. If the net heat supplied to the gas is $5 \mathrm{~J}$, then the work done by the gas in the process $C \rightarrow A$ is

1 $-5 \mathrm{~J}$
2 $-10 \mathrm{~J}$
3 $-15 \mathrm{~J}$
4 $-20 \mathrm{~J}$
Thermodynamics

148098 Calculate the heat required to increases the temperature of 1 mole of one atomic gas from $0^{\circ} \mathrm{C}$ to $150^{\circ} \mathrm{C}$, when no work is done. $\left[C_{p}=2.5 \mathrm{R}\right.$ and $R=83 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ ]

1 $867.5 \mathrm{~J}$
2 $186.5 \mathrm{~J}$
3 $1867.5 \mathrm{~J}$
4 $86.7 \mathrm{~J}$
Thermodynamics

148100 Ideal gas is contained in a thermally insulated and rigid container and it is heated through a resistance $100 \Omega$ by passing a current of $1 \mathrm{~A}$ for five minutes, then change in internal energy of the gas is

1 $0 \mathrm{~kJ}$
2 $30 \mathrm{~kJ}$
3 $10 \mathrm{~kJ}$
4 $20 \mathrm{~kJ}$
Thermodynamics

148101 $1 \mathrm{~cm}^{3}$ of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of $1671 \mathrm{~cm}^{3}$. If the atmospheric pressure $=$ $1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$ and the mechanical equivalent of heat $=4.19 \mathrm{~J} / \mathrm{cal}$, the energy spent in this process in overcoming intermolecular process in overcoming intermolecular forces is

1 $540 \mathrm{cal}$
2 $40 \mathrm{cal}$
3 $500 \mathrm{cal}$
4 zero
Thermodynamics

148097 An ideal gas is taken through the cycle $A \rightarrow B \rightarrow C \rightarrow A$, as shown in the figure below. If the net heat supplied to the gas is $5 \mathrm{~J}$, then the work done by the gas in the process $C \rightarrow A$ is

1 $-5 \mathrm{~J}$
2 $-10 \mathrm{~J}$
3 $-15 \mathrm{~J}$
4 $-20 \mathrm{~J}$
Thermodynamics

148098 Calculate the heat required to increases the temperature of 1 mole of one atomic gas from $0^{\circ} \mathrm{C}$ to $150^{\circ} \mathrm{C}$, when no work is done. $\left[C_{p}=2.5 \mathrm{R}\right.$ and $R=83 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ ]

1 $867.5 \mathrm{~J}$
2 $186.5 \mathrm{~J}$
3 $1867.5 \mathrm{~J}$
4 $86.7 \mathrm{~J}$
Thermodynamics

148100 Ideal gas is contained in a thermally insulated and rigid container and it is heated through a resistance $100 \Omega$ by passing a current of $1 \mathrm{~A}$ for five minutes, then change in internal energy of the gas is

1 $0 \mathrm{~kJ}$
2 $30 \mathrm{~kJ}$
3 $10 \mathrm{~kJ}$
4 $20 \mathrm{~kJ}$
Thermodynamics

148101 $1 \mathrm{~cm}^{3}$ of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of $1671 \mathrm{~cm}^{3}$. If the atmospheric pressure $=$ $1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$ and the mechanical equivalent of heat $=4.19 \mathrm{~J} / \mathrm{cal}$, the energy spent in this process in overcoming intermolecular process in overcoming intermolecular forces is

1 $540 \mathrm{cal}$
2 $40 \mathrm{cal}$
3 $500 \mathrm{cal}$
4 zero
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Thermodynamics

148097 An ideal gas is taken through the cycle $A \rightarrow B \rightarrow C \rightarrow A$, as shown in the figure below. If the net heat supplied to the gas is $5 \mathrm{~J}$, then the work done by the gas in the process $C \rightarrow A$ is

1 $-5 \mathrm{~J}$
2 $-10 \mathrm{~J}$
3 $-15 \mathrm{~J}$
4 $-20 \mathrm{~J}$
Thermodynamics

148098 Calculate the heat required to increases the temperature of 1 mole of one atomic gas from $0^{\circ} \mathrm{C}$ to $150^{\circ} \mathrm{C}$, when no work is done. $\left[C_{p}=2.5 \mathrm{R}\right.$ and $R=83 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ ]

1 $867.5 \mathrm{~J}$
2 $186.5 \mathrm{~J}$
3 $1867.5 \mathrm{~J}$
4 $86.7 \mathrm{~J}$
Thermodynamics

148100 Ideal gas is contained in a thermally insulated and rigid container and it is heated through a resistance $100 \Omega$ by passing a current of $1 \mathrm{~A}$ for five minutes, then change in internal energy of the gas is

1 $0 \mathrm{~kJ}$
2 $30 \mathrm{~kJ}$
3 $10 \mathrm{~kJ}$
4 $20 \mathrm{~kJ}$
Thermodynamics

148101 $1 \mathrm{~cm}^{3}$ of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of $1671 \mathrm{~cm}^{3}$. If the atmospheric pressure $=$ $1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$ and the mechanical equivalent of heat $=4.19 \mathrm{~J} / \mathrm{cal}$, the energy spent in this process in overcoming intermolecular process in overcoming intermolecular forces is

1 $540 \mathrm{cal}$
2 $40 \mathrm{cal}$
3 $500 \mathrm{cal}$
4 zero
Thermodynamics

148097 An ideal gas is taken through the cycle $A \rightarrow B \rightarrow C \rightarrow A$, as shown in the figure below. If the net heat supplied to the gas is $5 \mathrm{~J}$, then the work done by the gas in the process $C \rightarrow A$ is

1 $-5 \mathrm{~J}$
2 $-10 \mathrm{~J}$
3 $-15 \mathrm{~J}$
4 $-20 \mathrm{~J}$
Thermodynamics

148098 Calculate the heat required to increases the temperature of 1 mole of one atomic gas from $0^{\circ} \mathrm{C}$ to $150^{\circ} \mathrm{C}$, when no work is done. $\left[C_{p}=2.5 \mathrm{R}\right.$ and $R=83 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ ]

1 $867.5 \mathrm{~J}$
2 $186.5 \mathrm{~J}$
3 $1867.5 \mathrm{~J}$
4 $86.7 \mathrm{~J}$
Thermodynamics

148100 Ideal gas is contained in a thermally insulated and rigid container and it is heated through a resistance $100 \Omega$ by passing a current of $1 \mathrm{~A}$ for five minutes, then change in internal energy of the gas is

1 $0 \mathrm{~kJ}$
2 $30 \mathrm{~kJ}$
3 $10 \mathrm{~kJ}$
4 $20 \mathrm{~kJ}$
Thermodynamics

148101 $1 \mathrm{~cm}^{3}$ of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of $1671 \mathrm{~cm}^{3}$. If the atmospheric pressure $=$ $1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$ and the mechanical equivalent of heat $=4.19 \mathrm{~J} / \mathrm{cal}$, the energy spent in this process in overcoming intermolecular process in overcoming intermolecular forces is

1 $540 \mathrm{cal}$
2 $40 \mathrm{cal}$
3 $500 \mathrm{cal}$
4 zero