148101 $1 \mathrm{~cm}^{3}$ of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of $1671 \mathrm{~cm}^{3}$. If the atmospheric pressure $=$ $1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$ and the mechanical equivalent of heat $=4.19 \mathrm{~J} / \mathrm{cal}$, the energy spent in this process in overcoming intermolecular process in overcoming intermolecular forces is
148101 $1 \mathrm{~cm}^{3}$ of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of $1671 \mathrm{~cm}^{3}$. If the atmospheric pressure $=$ $1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$ and the mechanical equivalent of heat $=4.19 \mathrm{~J} / \mathrm{cal}$, the energy spent in this process in overcoming intermolecular process in overcoming intermolecular forces is
148101 $1 \mathrm{~cm}^{3}$ of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of $1671 \mathrm{~cm}^{3}$. If the atmospheric pressure $=$ $1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$ and the mechanical equivalent of heat $=4.19 \mathrm{~J} / \mathrm{cal}$, the energy spent in this process in overcoming intermolecular process in overcoming intermolecular forces is
148101 $1 \mathrm{~cm}^{3}$ of water at its boiling point absorbs 540 cal of heat to becomes steam with a volume of $1671 \mathrm{~cm}^{3}$. If the atmospheric pressure $=$ $1.013 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}$ and the mechanical equivalent of heat $=4.19 \mathrm{~J} / \mathrm{cal}$, the energy spent in this process in overcoming intermolecular process in overcoming intermolecular forces is