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Mechanical Properties of Solids

140928 Stress v/s strain for the elastic tissue of the aorta, the large tube (vessel) carrying blood from the heart, will be: [Stress is proportional to square of the strain for the elastic tissue of the aorta].

1

2

3

4

Explanation:

A Given that,
Stress is proportional to the square of the strain for the elastic tissue of aorta.
$∴$ Stress $\propto (strain)^{2}$

TSEAMCET 28.09.2020

Mechanical Properties of Solids

140930 A square wire frame of size $L$ is dipped in a liquid. On taking out a membrane is formed. If the surface tension of liquid is $T$ , then force acting on a frame will be

1

2 T L

2

4 T L

3

8 T L

4

16 T L

Explanation:

C Since, the wire frame is dipped in liquid, therefore its membrane has two free surfaces.
Total length of square wire frame in contact of membrane $(l) = 2 \times$ perimeter of square
$l = 2 \times 4 L = 8 L .$
Hence, force acting on a frame.

JIPMER-2010

Mechanical Properties of Solids

140945 The area of cross-section of steel wire is $0.1 {cm}^{2}$ and Young's modulus of steel is $2 \times 10^{11} N m^{- 2}$ . The force required to stretched by $0.1 %$ of its length is

1

1000 N

2

2000 N

3

5000 N

4

4000 N

Explanation:

B Given, area of cross-section (A) $= 0.1 {cm}^{2} =$ $0.1 \times 10^{- 4} m^{2}$ , Young modulus $(Y) = 2 \times 10^{11} N / m^{2}$ and $\frac{Δ L}{L} = \frac{0.1}{100} = 0.001$
Therefore, $Δ L = \frac{FL}{AY}$
$F = \frac{Δ L}{L} \times A \times Y$
$F = 0.001 \times 0.1 \times 10^{- 4} \times 2 \times 10^{11}$
$F = 2000 N$

AP EAMCET (22.04.2019) Shift-II

Mechanical Properties of Solids

140888 Which of the following is true for elastic potential energy density?

1 Energy density

= 1 / 2 \times

strain

\times

stress

2 Energy density

= (strain)^{2} \times

volume

3 Energy density

= (

strain

) \times

volume

4 Energy density

= (

stress

) \times

volume

Explanation:

A Elastic potential energy is energy stored as result of applying a force to deform on elastic object.
Potential energy density $= \frac{1}{2} \times$ Stress $\times$ Strain

UPSEE - 2010

Mechanical Properties of Solids

140838 Given below are two statement : one is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion (A): Steel used in the construction of buildings and bridges.
Reason (R): Steel is more elastic and its elastic limit is high.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both A and R are correct but R is the correct explanation of

A

2 Both

A

and

R

are correct and

R

is the correct explanation of

A

3 A is not correct but

R

is correct

4 A is correct but

R

is not correct

JEE Main-24.01.2023

Mechanical Properties of Solids

140928 Stress v/s strain for the elastic tissue of the aorta, the large tube (vessel) carrying blood from the heart, will be: [Stress is proportional to square of the strain for the elastic tissue of the aorta].

1

2

3

4

Explanation:

A Given that,
Stress is proportional to the square of the strain for the elastic tissue of aorta.
$∴$ Stress $\propto (strain)^{2}$

TSEAMCET 28.09.2020

Mechanical Properties of Solids

140930 A square wire frame of size $L$ is dipped in a liquid. On taking out a membrane is formed. If the surface tension of liquid is $T$ , then force acting on a frame will be

1

2 T L

2

4 T L

3

8 T L

4

16 T L

Explanation:

C Since, the wire frame is dipped in liquid, therefore its membrane has two free surfaces.
Total length of square wire frame in contact of membrane $(l) = 2 \times$ perimeter of square
$l = 2 \times 4 L = 8 L .$
Hence, force acting on a frame.

JIPMER-2010

Mechanical Properties of Solids

140945 The area of cross-section of steel wire is $0.1 {cm}^{2}$ and Young's modulus of steel is $2 \times 10^{11} N m^{- 2}$ . The force required to stretched by $0.1 %$ of its length is

1

1000 N

2

2000 N

3

5000 N

4

4000 N

Explanation:

B Given, area of cross-section (A) $= 0.1 {cm}^{2} =$ $0.1 \times 10^{- 4} m^{2}$ , Young modulus $(Y) = 2 \times 10^{11} N / m^{2}$ and $\frac{Δ L}{L} = \frac{0.1}{100} = 0.001$
Therefore, $Δ L = \frac{FL}{AY}$
$F = \frac{Δ L}{L} \times A \times Y$
$F = 0.001 \times 0.1 \times 10^{- 4} \times 2 \times 10^{11}$
$F = 2000 N$

AP EAMCET (22.04.2019) Shift-II

Mechanical Properties of Solids

140888 Which of the following is true for elastic potential energy density?

1 Energy density

= 1 / 2 \times

strain

\times

stress

2 Energy density

= (strain)^{2} \times

volume

3 Energy density

= (

strain

) \times

volume

4 Energy density

= (

stress

) \times

volume

Explanation:

A Elastic potential energy is energy stored as result of applying a force to deform on elastic object.
Potential energy density $= \frac{1}{2} \times$ Stress $\times$ Strain

UPSEE - 2010

Mechanical Properties of Solids

140838 Given below are two statement : one is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion (A): Steel used in the construction of buildings and bridges.
Reason (R): Steel is more elastic and its elastic limit is high.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both A and R are correct but R is the correct explanation of

A

2 Both

A

and

R

are correct and

R

is the correct explanation of

A

3 A is not correct but

R

is correct

4 A is correct but

R

is not correct

JEE Main-24.01.2023

Mechanical Properties of Solids

140928 Stress v/s strain for the elastic tissue of the aorta, the large tube (vessel) carrying blood from the heart, will be: [Stress is proportional to square of the strain for the elastic tissue of the aorta].

1

2

3

4

Explanation:

A Given that,
Stress is proportional to the square of the strain for the elastic tissue of aorta.
$∴$ Stress $\propto (strain)^{2}$

TSEAMCET 28.09.2020

Mechanical Properties of Solids

140930 A square wire frame of size $L$ is dipped in a liquid. On taking out a membrane is formed. If the surface tension of liquid is $T$ , then force acting on a frame will be

1

2 T L

2

4 T L

3

8 T L

4

16 T L

Explanation:

C Since, the wire frame is dipped in liquid, therefore its membrane has two free surfaces.
Total length of square wire frame in contact of membrane $(l) = 2 \times$ perimeter of square
$l = 2 \times 4 L = 8 L .$
Hence, force acting on a frame.

JIPMER-2010

Mechanical Properties of Solids

140945 The area of cross-section of steel wire is $0.1 {cm}^{2}$ and Young's modulus of steel is $2 \times 10^{11} N m^{- 2}$ . The force required to stretched by $0.1 %$ of its length is

1

1000 N

2

2000 N

3

5000 N

4

4000 N

Explanation:

B Given, area of cross-section (A) $= 0.1 {cm}^{2} =$ $0.1 \times 10^{- 4} m^{2}$ , Young modulus $(Y) = 2 \times 10^{11} N / m^{2}$ and $\frac{Δ L}{L} = \frac{0.1}{100} = 0.001$
Therefore, $Δ L = \frac{FL}{AY}$
$F = \frac{Δ L}{L} \times A \times Y$
$F = 0.001 \times 0.1 \times 10^{- 4} \times 2 \times 10^{11}$
$F = 2000 N$

AP EAMCET (22.04.2019) Shift-II

Mechanical Properties of Solids

140888 Which of the following is true for elastic potential energy density?

1 Energy density

= 1 / 2 \times

strain

\times

stress

2 Energy density

= (strain)^{2} \times

volume

3 Energy density

= (

strain

) \times

volume

4 Energy density

= (

stress

) \times

volume

Explanation:

A Elastic potential energy is energy stored as result of applying a force to deform on elastic object.
Potential energy density $= \frac{1}{2} \times$ Stress $\times$ Strain

UPSEE - 2010

Mechanical Properties of Solids

140838 Given below are two statement : one is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion (A): Steel used in the construction of buildings and bridges.
Reason (R): Steel is more elastic and its elastic limit is high.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both A and R are correct but R is the correct explanation of

A

2 Both

A

and

R

are correct and

R

is the correct explanation of

A

3 A is not correct but

R

is correct

4 A is correct but

R

is not correct

JEE Main-24.01.2023

Mechanical Properties of Solids

140928 Stress v/s strain for the elastic tissue of the aorta, the large tube (vessel) carrying blood from the heart, will be: [Stress is proportional to square of the strain for the elastic tissue of the aorta].

1

2

3

4

Explanation:

A Given that,
Stress is proportional to the square of the strain for the elastic tissue of aorta.
$∴$ Stress $\propto (strain)^{2}$

TSEAMCET 28.09.2020

Mechanical Properties of Solids

140930 A square wire frame of size $L$ is dipped in a liquid. On taking out a membrane is formed. If the surface tension of liquid is $T$ , then force acting on a frame will be

1

2 T L

2

4 T L

3

8 T L

4

16 T L

Explanation:

C Since, the wire frame is dipped in liquid, therefore its membrane has two free surfaces.
Total length of square wire frame in contact of membrane $(l) = 2 \times$ perimeter of square
$l = 2 \times 4 L = 8 L .$
Hence, force acting on a frame.

JIPMER-2010

Mechanical Properties of Solids

140945 The area of cross-section of steel wire is $0.1 {cm}^{2}$ and Young's modulus of steel is $2 \times 10^{11} N m^{- 2}$ . The force required to stretched by $0.1 %$ of its length is

1

1000 N

2

2000 N

3

5000 N

4

4000 N

Explanation:

B Given, area of cross-section (A) $= 0.1 {cm}^{2} =$ $0.1 \times 10^{- 4} m^{2}$ , Young modulus $(Y) = 2 \times 10^{11} N / m^{2}$ and $\frac{Δ L}{L} = \frac{0.1}{100} = 0.001$
Therefore, $Δ L = \frac{FL}{AY}$
$F = \frac{Δ L}{L} \times A \times Y$
$F = 0.001 \times 0.1 \times 10^{- 4} \times 2 \times 10^{11}$
$F = 2000 N$

AP EAMCET (22.04.2019) Shift-II

Mechanical Properties of Solids

140888 Which of the following is true for elastic potential energy density?

1 Energy density

= 1 / 2 \times

strain

\times

stress

2 Energy density

= (strain)^{2} \times

volume

3 Energy density

= (

strain

) \times

volume

4 Energy density

= (

stress

) \times

volume

Explanation:

A Elastic potential energy is energy stored as result of applying a force to deform on elastic object.
Potential energy density $= \frac{1}{2} \times$ Stress $\times$ Strain

UPSEE - 2010

Mechanical Properties of Solids

140838 Given below are two statement : one is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion (A): Steel used in the construction of buildings and bridges.
Reason (R): Steel is more elastic and its elastic limit is high.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both A and R are correct but R is the correct explanation of

A

2 Both

A

and

R

are correct and

R

is the correct explanation of

A

3 A is not correct but

R

is correct

4 A is correct but

R

is not correct

JEE Main-24.01.2023

Mechanical Properties of Solids

140928 Stress v/s strain for the elastic tissue of the aorta, the large tube (vessel) carrying blood from the heart, will be: [Stress is proportional to square of the strain for the elastic tissue of the aorta].

1

2

3

4

Explanation:

A Given that,
Stress is proportional to the square of the strain for the elastic tissue of aorta.
$∴$ Stress $\propto (strain)^{2}$

TSEAMCET 28.09.2020

Mechanical Properties of Solids

140930 A square wire frame of size $L$ is dipped in a liquid. On taking out a membrane is formed. If the surface tension of liquid is $T$ , then force acting on a frame will be

1

2 T L

2

4 T L

3

8 T L

4

16 T L

Explanation:

C Since, the wire frame is dipped in liquid, therefore its membrane has two free surfaces.
Total length of square wire frame in contact of membrane $(l) = 2 \times$ perimeter of square
$l = 2 \times 4 L = 8 L .$
Hence, force acting on a frame.

JIPMER-2010

Mechanical Properties of Solids

140945 The area of cross-section of steel wire is $0.1 {cm}^{2}$ and Young's modulus of steel is $2 \times 10^{11} N m^{- 2}$ . The force required to stretched by $0.1 %$ of its length is

1

1000 N

2

2000 N

3

5000 N

4

4000 N

Explanation:

B Given, area of cross-section (A) $= 0.1 {cm}^{2} =$ $0.1 \times 10^{- 4} m^{2}$ , Young modulus $(Y) = 2 \times 10^{11} N / m^{2}$ and $\frac{Δ L}{L} = \frac{0.1}{100} = 0.001$
Therefore, $Δ L = \frac{FL}{AY}$
$F = \frac{Δ L}{L} \times A \times Y$
$F = 0.001 \times 0.1 \times 10^{- 4} \times 2 \times 10^{11}$
$F = 2000 N$

AP EAMCET (22.04.2019) Shift-II

Mechanical Properties of Solids

140888 Which of the following is true for elastic potential energy density?

1 Energy density

= 1 / 2 \times

strain

\times

stress

2 Energy density

= (strain)^{2} \times

volume

3 Energy density

= (

strain

) \times

volume

4 Energy density

= (

stress

) \times

volume

Explanation:

A Elastic potential energy is energy stored as result of applying a force to deform on elastic object.
Potential energy density $= \frac{1}{2} \times$ Stress $\times$ Strain

UPSEE - 2010

Mechanical Properties of Solids

140838 Given below are two statement : one is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion (A): Steel used in the construction of buildings and bridges.
Reason (R): Steel is more elastic and its elastic limit is high.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both A and R are correct but R is the correct explanation of

A

2 Both

A

and

R

are correct and

R

is the correct explanation of

A

3 A is not correct but

R

is correct

4 A is correct but

R

is not correct

JEE Main-24.01.2023

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