140895
A copper wire and a steel wire of the same diameter and length are joined end to end and a force is applied which stretches their combined length by $1 \mathrm{~cm}$. Then, the two wires will have
1 the same stress and strain
2 the same stress but different strains
3 the same strain but different stresses
4 different stresses and strains
Explanation:
B As, same force is applied to each wire having equal area of cross - section. So, stress is same but extensions will be different for wires as they are of different materials. So, Same stress but different strain are there.
Manipal UGET-2012
Mechanical Properties of Solids
140897
The pressure applied from all directions on a cube is p. How much its temperature should be raised to maintain the original volume? The volume elasticity of the cube is $\beta$ and the coefficient of volume expansion is $\alpha$.
1 $\frac{p}{\alpha \beta}$
2 $\frac{\mathrm{p} \alpha}{\beta}$
3 $\frac{\mathrm{p} \beta}{\alpha}$
4 $\frac{\alpha \beta}{\mathrm{p}}$
Explanation:
A If coefficient of volume expansion is $\alpha$ and rise in temperature is $\Delta \theta$, then $\Delta \mathrm{V}=\mathrm{V} \alpha \Delta \theta$ $\frac{\Delta \mathrm{V}}{\mathrm{V}}=\alpha \Delta \theta$ $\therefore$ Volume elasticity $(\beta)=\frac{\text { Stress }}{\text { Strain }}$ $=\frac{\mathrm{P}}{\alpha \Delta \theta}$ $\Delta \theta =\frac{\mathrm{p}}{\alpha \beta}$
Mechanical Properties of Solids
140912
The elastic energy stored per unit volume in a stretched wire is
A Energy stored per unit volume. $\mathrm{E}=\frac{1}{2} \times \text { stress } \times \text { strain }$ We know that, $\text { Strain }=\frac{\text { stress }}{\text { Young's modulus }(\mathrm{Y})}$ $\mathrm{E}=\frac{1}{2} \times \mathrm{Y} \times(\text { strain })^{2}$
J and K CET- 2010
Mechanical Properties of Solids
140915
If longitudinal strain for a wire is 0.03 and its Poisson's ratio is 0.5 , then its lateral strain is
1 0.003
2 0.0075
3 0.015
4 0.4
Explanation:
C Poisson 's ratio $=-\frac{\text { lateral strain }}{\text { longitudinal strain }}$ Longitudinal strain for wire in 0.03 and poisson ratio is 0.5 . $0.5=-\frac{\text { lateral strain }}{0.03}$ Lateral strain $=-0.015$ [Negative sign shows decrease in dimension in lateral direction.]
140895
A copper wire and a steel wire of the same diameter and length are joined end to end and a force is applied which stretches their combined length by $1 \mathrm{~cm}$. Then, the two wires will have
1 the same stress and strain
2 the same stress but different strains
3 the same strain but different stresses
4 different stresses and strains
Explanation:
B As, same force is applied to each wire having equal area of cross - section. So, stress is same but extensions will be different for wires as they are of different materials. So, Same stress but different strain are there.
Manipal UGET-2012
Mechanical Properties of Solids
140897
The pressure applied from all directions on a cube is p. How much its temperature should be raised to maintain the original volume? The volume elasticity of the cube is $\beta$ and the coefficient of volume expansion is $\alpha$.
1 $\frac{p}{\alpha \beta}$
2 $\frac{\mathrm{p} \alpha}{\beta}$
3 $\frac{\mathrm{p} \beta}{\alpha}$
4 $\frac{\alpha \beta}{\mathrm{p}}$
Explanation:
A If coefficient of volume expansion is $\alpha$ and rise in temperature is $\Delta \theta$, then $\Delta \mathrm{V}=\mathrm{V} \alpha \Delta \theta$ $\frac{\Delta \mathrm{V}}{\mathrm{V}}=\alpha \Delta \theta$ $\therefore$ Volume elasticity $(\beta)=\frac{\text { Stress }}{\text { Strain }}$ $=\frac{\mathrm{P}}{\alpha \Delta \theta}$ $\Delta \theta =\frac{\mathrm{p}}{\alpha \beta}$
Mechanical Properties of Solids
140912
The elastic energy stored per unit volume in a stretched wire is
A Energy stored per unit volume. $\mathrm{E}=\frac{1}{2} \times \text { stress } \times \text { strain }$ We know that, $\text { Strain }=\frac{\text { stress }}{\text { Young's modulus }(\mathrm{Y})}$ $\mathrm{E}=\frac{1}{2} \times \mathrm{Y} \times(\text { strain })^{2}$
J and K CET- 2010
Mechanical Properties of Solids
140915
If longitudinal strain for a wire is 0.03 and its Poisson's ratio is 0.5 , then its lateral strain is
1 0.003
2 0.0075
3 0.015
4 0.4
Explanation:
C Poisson 's ratio $=-\frac{\text { lateral strain }}{\text { longitudinal strain }}$ Longitudinal strain for wire in 0.03 and poisson ratio is 0.5 . $0.5=-\frac{\text { lateral strain }}{0.03}$ Lateral strain $=-0.015$ [Negative sign shows decrease in dimension in lateral direction.]
140895
A copper wire and a steel wire of the same diameter and length are joined end to end and a force is applied which stretches their combined length by $1 \mathrm{~cm}$. Then, the two wires will have
1 the same stress and strain
2 the same stress but different strains
3 the same strain but different stresses
4 different stresses and strains
Explanation:
B As, same force is applied to each wire having equal area of cross - section. So, stress is same but extensions will be different for wires as they are of different materials. So, Same stress but different strain are there.
Manipal UGET-2012
Mechanical Properties of Solids
140897
The pressure applied from all directions on a cube is p. How much its temperature should be raised to maintain the original volume? The volume elasticity of the cube is $\beta$ and the coefficient of volume expansion is $\alpha$.
1 $\frac{p}{\alpha \beta}$
2 $\frac{\mathrm{p} \alpha}{\beta}$
3 $\frac{\mathrm{p} \beta}{\alpha}$
4 $\frac{\alpha \beta}{\mathrm{p}}$
Explanation:
A If coefficient of volume expansion is $\alpha$ and rise in temperature is $\Delta \theta$, then $\Delta \mathrm{V}=\mathrm{V} \alpha \Delta \theta$ $\frac{\Delta \mathrm{V}}{\mathrm{V}}=\alpha \Delta \theta$ $\therefore$ Volume elasticity $(\beta)=\frac{\text { Stress }}{\text { Strain }}$ $=\frac{\mathrm{P}}{\alpha \Delta \theta}$ $\Delta \theta =\frac{\mathrm{p}}{\alpha \beta}$
Mechanical Properties of Solids
140912
The elastic energy stored per unit volume in a stretched wire is
A Energy stored per unit volume. $\mathrm{E}=\frac{1}{2} \times \text { stress } \times \text { strain }$ We know that, $\text { Strain }=\frac{\text { stress }}{\text { Young's modulus }(\mathrm{Y})}$ $\mathrm{E}=\frac{1}{2} \times \mathrm{Y} \times(\text { strain })^{2}$
J and K CET- 2010
Mechanical Properties of Solids
140915
If longitudinal strain for a wire is 0.03 and its Poisson's ratio is 0.5 , then its lateral strain is
1 0.003
2 0.0075
3 0.015
4 0.4
Explanation:
C Poisson 's ratio $=-\frac{\text { lateral strain }}{\text { longitudinal strain }}$ Longitudinal strain for wire in 0.03 and poisson ratio is 0.5 . $0.5=-\frac{\text { lateral strain }}{0.03}$ Lateral strain $=-0.015$ [Negative sign shows decrease in dimension in lateral direction.]
140895
A copper wire and a steel wire of the same diameter and length are joined end to end and a force is applied which stretches their combined length by $1 \mathrm{~cm}$. Then, the two wires will have
1 the same stress and strain
2 the same stress but different strains
3 the same strain but different stresses
4 different stresses and strains
Explanation:
B As, same force is applied to each wire having equal area of cross - section. So, stress is same but extensions will be different for wires as they are of different materials. So, Same stress but different strain are there.
Manipal UGET-2012
Mechanical Properties of Solids
140897
The pressure applied from all directions on a cube is p. How much its temperature should be raised to maintain the original volume? The volume elasticity of the cube is $\beta$ and the coefficient of volume expansion is $\alpha$.
1 $\frac{p}{\alpha \beta}$
2 $\frac{\mathrm{p} \alpha}{\beta}$
3 $\frac{\mathrm{p} \beta}{\alpha}$
4 $\frac{\alpha \beta}{\mathrm{p}}$
Explanation:
A If coefficient of volume expansion is $\alpha$ and rise in temperature is $\Delta \theta$, then $\Delta \mathrm{V}=\mathrm{V} \alpha \Delta \theta$ $\frac{\Delta \mathrm{V}}{\mathrm{V}}=\alpha \Delta \theta$ $\therefore$ Volume elasticity $(\beta)=\frac{\text { Stress }}{\text { Strain }}$ $=\frac{\mathrm{P}}{\alpha \Delta \theta}$ $\Delta \theta =\frac{\mathrm{p}}{\alpha \beta}$
Mechanical Properties of Solids
140912
The elastic energy stored per unit volume in a stretched wire is
A Energy stored per unit volume. $\mathrm{E}=\frac{1}{2} \times \text { stress } \times \text { strain }$ We know that, $\text { Strain }=\frac{\text { stress }}{\text { Young's modulus }(\mathrm{Y})}$ $\mathrm{E}=\frac{1}{2} \times \mathrm{Y} \times(\text { strain })^{2}$
J and K CET- 2010
Mechanical Properties of Solids
140915
If longitudinal strain for a wire is 0.03 and its Poisson's ratio is 0.5 , then its lateral strain is
1 0.003
2 0.0075
3 0.015
4 0.4
Explanation:
C Poisson 's ratio $=-\frac{\text { lateral strain }}{\text { longitudinal strain }}$ Longitudinal strain for wire in 0.03 and poisson ratio is 0.5 . $0.5=-\frac{\text { lateral strain }}{0.03}$ Lateral strain $=-0.015$ [Negative sign shows decrease in dimension in lateral direction.]
