140864
Under elastic limit, the stress is .......... .
1 Inversely proportional to strain
2 Directly proportional to strain
3 Square root of strain
4 Independent of strain
Explanation:
B From Hook's Law, Hook's Law states that within the elastic limit, the stress is directly proportional to strain. Stress $\propto$ Strain
Shift-II]
Mechanical Properties of Solids
140886
Which one of the following statement is correct? In the case of
1 shearing stress there is change in volume
2 tensile stress there is no change in volume
3 shearing stress there is no change in shape
4 hydraulic stress there is no change in volume
5 tensile stress there is no change in shape
Explanation:
B - Tensile stress is responsible to change in length not volume. In Tension stress there is no change in volume. - Shear stress is change shape without any change in volume. - Hydraulic stress is change in volume without any change in shape.
Kerala CEE - 2010
Mechanical Properties of Solids
140890
A metallic rod breaks when strain produced is $0.2 \%$. The Young's modulus of the material of the rod is $7 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$. What should be its area of cross-section to support a load of $10^{4} \mathrm{~N}$ ?
1 $7.1 \times 10^{-8} \mathrm{~m}^{2}$
2 $7.1 \times 10^{-6} \mathrm{~m}^{2}$
3 $7.1 \times 10^{-4} \mathrm{~m}^{2}$
4 $7.1 \times 10^{-2} \mathrm{~m}^{2}$
Explanation:
C Given, Strain produced $=0.2 \%=\frac{0.2}{100}=\frac{2}{1000}$ Young modulus $(\mathrm{Y})=7 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}, \operatorname{Load}(\mathrm{F})=10^{4} \mathrm{~N}$ We know, $\text { Stress }=Y \times \text { strain }$ $\frac{\text { Force }}{\text { Area }}=7 \times 10^{9} \times \frac{2}{1000} .$
BITSAT-2009
Mechanical Properties of Solids
140893
Write copper, steel, glass and rubber in order of increasing coefficient of elasticity.
1 Steel, rubber, copper, glass
2 Rubber, glass copper, steel
3 Rubber, glass, steel, copper
4 Rubber, glass, copper, steel
Explanation:
B We know, $\text { Stress }=\frac{\mathrm{F}}{\mathrm{A}}$ Force $\propto$ Area of cross-section From the above expression, It is clear that load does not depends upon the length of the wire. It depends upon the cross-section of the wire.
140864
Under elastic limit, the stress is .......... .
1 Inversely proportional to strain
2 Directly proportional to strain
3 Square root of strain
4 Independent of strain
Explanation:
B From Hook's Law, Hook's Law states that within the elastic limit, the stress is directly proportional to strain. Stress $\propto$ Strain
Shift-II]
Mechanical Properties of Solids
140886
Which one of the following statement is correct? In the case of
1 shearing stress there is change in volume
2 tensile stress there is no change in volume
3 shearing stress there is no change in shape
4 hydraulic stress there is no change in volume
5 tensile stress there is no change in shape
Explanation:
B - Tensile stress is responsible to change in length not volume. In Tension stress there is no change in volume. - Shear stress is change shape without any change in volume. - Hydraulic stress is change in volume without any change in shape.
Kerala CEE - 2010
Mechanical Properties of Solids
140890
A metallic rod breaks when strain produced is $0.2 \%$. The Young's modulus of the material of the rod is $7 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$. What should be its area of cross-section to support a load of $10^{4} \mathrm{~N}$ ?
1 $7.1 \times 10^{-8} \mathrm{~m}^{2}$
2 $7.1 \times 10^{-6} \mathrm{~m}^{2}$
3 $7.1 \times 10^{-4} \mathrm{~m}^{2}$
4 $7.1 \times 10^{-2} \mathrm{~m}^{2}$
Explanation:
C Given, Strain produced $=0.2 \%=\frac{0.2}{100}=\frac{2}{1000}$ Young modulus $(\mathrm{Y})=7 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}, \operatorname{Load}(\mathrm{F})=10^{4} \mathrm{~N}$ We know, $\text { Stress }=Y \times \text { strain }$ $\frac{\text { Force }}{\text { Area }}=7 \times 10^{9} \times \frac{2}{1000} .$
BITSAT-2009
Mechanical Properties of Solids
140893
Write copper, steel, glass and rubber in order of increasing coefficient of elasticity.
1 Steel, rubber, copper, glass
2 Rubber, glass copper, steel
3 Rubber, glass, steel, copper
4 Rubber, glass, copper, steel
Explanation:
B We know, $\text { Stress }=\frac{\mathrm{F}}{\mathrm{A}}$ Force $\propto$ Area of cross-section From the above expression, It is clear that load does not depends upon the length of the wire. It depends upon the cross-section of the wire.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Mechanical Properties of Solids
140864
Under elastic limit, the stress is .......... .
1 Inversely proportional to strain
2 Directly proportional to strain
3 Square root of strain
4 Independent of strain
Explanation:
B From Hook's Law, Hook's Law states that within the elastic limit, the stress is directly proportional to strain. Stress $\propto$ Strain
Shift-II]
Mechanical Properties of Solids
140886
Which one of the following statement is correct? In the case of
1 shearing stress there is change in volume
2 tensile stress there is no change in volume
3 shearing stress there is no change in shape
4 hydraulic stress there is no change in volume
5 tensile stress there is no change in shape
Explanation:
B - Tensile stress is responsible to change in length not volume. In Tension stress there is no change in volume. - Shear stress is change shape without any change in volume. - Hydraulic stress is change in volume without any change in shape.
Kerala CEE - 2010
Mechanical Properties of Solids
140890
A metallic rod breaks when strain produced is $0.2 \%$. The Young's modulus of the material of the rod is $7 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$. What should be its area of cross-section to support a load of $10^{4} \mathrm{~N}$ ?
1 $7.1 \times 10^{-8} \mathrm{~m}^{2}$
2 $7.1 \times 10^{-6} \mathrm{~m}^{2}$
3 $7.1 \times 10^{-4} \mathrm{~m}^{2}$
4 $7.1 \times 10^{-2} \mathrm{~m}^{2}$
Explanation:
C Given, Strain produced $=0.2 \%=\frac{0.2}{100}=\frac{2}{1000}$ Young modulus $(\mathrm{Y})=7 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}, \operatorname{Load}(\mathrm{F})=10^{4} \mathrm{~N}$ We know, $\text { Stress }=Y \times \text { strain }$ $\frac{\text { Force }}{\text { Area }}=7 \times 10^{9} \times \frac{2}{1000} .$
BITSAT-2009
Mechanical Properties of Solids
140893
Write copper, steel, glass and rubber in order of increasing coefficient of elasticity.
1 Steel, rubber, copper, glass
2 Rubber, glass copper, steel
3 Rubber, glass, steel, copper
4 Rubber, glass, copper, steel
Explanation:
B We know, $\text { Stress }=\frac{\mathrm{F}}{\mathrm{A}}$ Force $\propto$ Area of cross-section From the above expression, It is clear that load does not depends upon the length of the wire. It depends upon the cross-section of the wire.
140864
Under elastic limit, the stress is .......... .
1 Inversely proportional to strain
2 Directly proportional to strain
3 Square root of strain
4 Independent of strain
Explanation:
B From Hook's Law, Hook's Law states that within the elastic limit, the stress is directly proportional to strain. Stress $\propto$ Strain
Shift-II]
Mechanical Properties of Solids
140886
Which one of the following statement is correct? In the case of
1 shearing stress there is change in volume
2 tensile stress there is no change in volume
3 shearing stress there is no change in shape
4 hydraulic stress there is no change in volume
5 tensile stress there is no change in shape
Explanation:
B - Tensile stress is responsible to change in length not volume. In Tension stress there is no change in volume. - Shear stress is change shape without any change in volume. - Hydraulic stress is change in volume without any change in shape.
Kerala CEE - 2010
Mechanical Properties of Solids
140890
A metallic rod breaks when strain produced is $0.2 \%$. The Young's modulus of the material of the rod is $7 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$. What should be its area of cross-section to support a load of $10^{4} \mathrm{~N}$ ?
1 $7.1 \times 10^{-8} \mathrm{~m}^{2}$
2 $7.1 \times 10^{-6} \mathrm{~m}^{2}$
3 $7.1 \times 10^{-4} \mathrm{~m}^{2}$
4 $7.1 \times 10^{-2} \mathrm{~m}^{2}$
Explanation:
C Given, Strain produced $=0.2 \%=\frac{0.2}{100}=\frac{2}{1000}$ Young modulus $(\mathrm{Y})=7 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}, \operatorname{Load}(\mathrm{F})=10^{4} \mathrm{~N}$ We know, $\text { Stress }=Y \times \text { strain }$ $\frac{\text { Force }}{\text { Area }}=7 \times 10^{9} \times \frac{2}{1000} .$
BITSAT-2009
Mechanical Properties of Solids
140893
Write copper, steel, glass and rubber in order of increasing coefficient of elasticity.
1 Steel, rubber, copper, glass
2 Rubber, glass copper, steel
3 Rubber, glass, steel, copper
4 Rubber, glass, copper, steel
Explanation:
B We know, $\text { Stress }=\frac{\mathrm{F}}{\mathrm{A}}$ Force $\propto$ Area of cross-section From the above expression, It is clear that load does not depends upon the length of the wire. It depends upon the cross-section of the wire.
