NEET Test Series from KOTA - 10 Papers In MS WORD
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Gravitation
138720
Assertion: The escape speed does not depend on the direction in which the projectile is fired. Reason: Attaining the escape speed is easier if a projectile is fired in the direction the launch site is moving as the earth rotates about its axis.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
B Escape velocity is common. It is more accurately described as a speed than a velocity because it is independent of direction; escape velocity increase with the mass of primary body and decreases with the distance from the primary body. Attaining the escape speed is easier if a projectile is fired in the direction the launch site is moving as the earth rotates about its axis.
Gravitation
138721
The period of moon's rotation around the earth is nearly 29 days. If moon's mass were 2 fold its present value and all other things remain unchanged, the period of moon's rotation would be nearly
1 $29 \sqrt{2}$ days
2 $29 / \sqrt{2}$ days
3 $29 \times 2$ days
4 29 days
Explanation:
D As we know, time period of a satellite orbiting around a planet of mass $\mathrm{M}$ is - $\mathrm{T}=\frac{2 \pi \mathrm{R}}{\mathrm{v}_{\text {orbital }}} \quad\left(\mathrm{v}_{\mathrm{o}}=\sqrt{\frac{\mathrm{GM}}{\mathrm{R}}}\right)$ $\mathrm{T}=2 \pi \mathrm{R} \sqrt{\frac{\mathrm{R}}{\mathrm{GM}}}=2 \pi \sqrt{\frac{\mathrm{R}^{3}}{\mathrm{GM}}}$ Hence, it is clear that there is no dependency of the satellite's mass for orbital time period. Now we can say that mass of the satellite does not affect the time period of the orbit. Hence, the time period of the moon's rotation around the earth will remain the same, i.e. 29 days.
AIIMS-27.05.2018(M)
Gravitation
138722
The angular speed of earth in $\mathrm{rad} / \mathrm{s}$, so that bodies on equator may appear weightless is: [Use $g=10 \mathrm{~m} / \mathrm{s}^{2}$ and the radius of earth $=6.4 \times$ $\left.10^{3} \mathrm{~km}\right]$
1 $1.25 \times 10^{-3}$
2 $1.56 \times 10^{-3}$
3 $1.25 \times 10^{-1}$
4 1.56
Explanation:
A As we know, $\text { At equator } \mathrm{g}^{\prime}=\mathrm{g}-\mathrm{R} \omega^{2}$ $\quad 0 \quad \mathrm{~g}-\mathrm{R} \omega^{2} \quad\left(\because \mathrm{g}^{\prime}=0\right)$ $\therefore \quad \omega=\sqrt{\frac{\mathrm{g}}{\mathrm{R}_{\mathrm{e}}}}$ $\omega=\sqrt{\frac{10}{6400 \times 10^{3}}}$ $\omega=1.25 \times 10^{-3} \mathrm{rad} / \mathrm{s}$
AIIMS-2011
Gravitation
138718
Assertion: Water kept in an open vessel will quickly evaporate on the surface of the moon. Reason: The temperature at the surface of the moon is much higher than boiling point of the water.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
C Water kept in an open vessel will quickly evaporate on the surface of the moon because on the surface of moon the atmospheric presser is low this leads to a lower boiling point.
138720
Assertion: The escape speed does not depend on the direction in which the projectile is fired. Reason: Attaining the escape speed is easier if a projectile is fired in the direction the launch site is moving as the earth rotates about its axis.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
B Escape velocity is common. It is more accurately described as a speed than a velocity because it is independent of direction; escape velocity increase with the mass of primary body and decreases with the distance from the primary body. Attaining the escape speed is easier if a projectile is fired in the direction the launch site is moving as the earth rotates about its axis.
Gravitation
138721
The period of moon's rotation around the earth is nearly 29 days. If moon's mass were 2 fold its present value and all other things remain unchanged, the period of moon's rotation would be nearly
1 $29 \sqrt{2}$ days
2 $29 / \sqrt{2}$ days
3 $29 \times 2$ days
4 29 days
Explanation:
D As we know, time period of a satellite orbiting around a planet of mass $\mathrm{M}$ is - $\mathrm{T}=\frac{2 \pi \mathrm{R}}{\mathrm{v}_{\text {orbital }}} \quad\left(\mathrm{v}_{\mathrm{o}}=\sqrt{\frac{\mathrm{GM}}{\mathrm{R}}}\right)$ $\mathrm{T}=2 \pi \mathrm{R} \sqrt{\frac{\mathrm{R}}{\mathrm{GM}}}=2 \pi \sqrt{\frac{\mathrm{R}^{3}}{\mathrm{GM}}}$ Hence, it is clear that there is no dependency of the satellite's mass for orbital time period. Now we can say that mass of the satellite does not affect the time period of the orbit. Hence, the time period of the moon's rotation around the earth will remain the same, i.e. 29 days.
AIIMS-27.05.2018(M)
Gravitation
138722
The angular speed of earth in $\mathrm{rad} / \mathrm{s}$, so that bodies on equator may appear weightless is: [Use $g=10 \mathrm{~m} / \mathrm{s}^{2}$ and the radius of earth $=6.4 \times$ $\left.10^{3} \mathrm{~km}\right]$
1 $1.25 \times 10^{-3}$
2 $1.56 \times 10^{-3}$
3 $1.25 \times 10^{-1}$
4 1.56
Explanation:
A As we know, $\text { At equator } \mathrm{g}^{\prime}=\mathrm{g}-\mathrm{R} \omega^{2}$ $\quad 0 \quad \mathrm{~g}-\mathrm{R} \omega^{2} \quad\left(\because \mathrm{g}^{\prime}=0\right)$ $\therefore \quad \omega=\sqrt{\frac{\mathrm{g}}{\mathrm{R}_{\mathrm{e}}}}$ $\omega=\sqrt{\frac{10}{6400 \times 10^{3}}}$ $\omega=1.25 \times 10^{-3} \mathrm{rad} / \mathrm{s}$
AIIMS-2011
Gravitation
138718
Assertion: Water kept in an open vessel will quickly evaporate on the surface of the moon. Reason: The temperature at the surface of the moon is much higher than boiling point of the water.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
C Water kept in an open vessel will quickly evaporate on the surface of the moon because on the surface of moon the atmospheric presser is low this leads to a lower boiling point.
138720
Assertion: The escape speed does not depend on the direction in which the projectile is fired. Reason: Attaining the escape speed is easier if a projectile is fired in the direction the launch site is moving as the earth rotates about its axis.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
B Escape velocity is common. It is more accurately described as a speed than a velocity because it is independent of direction; escape velocity increase with the mass of primary body and decreases with the distance from the primary body. Attaining the escape speed is easier if a projectile is fired in the direction the launch site is moving as the earth rotates about its axis.
Gravitation
138721
The period of moon's rotation around the earth is nearly 29 days. If moon's mass were 2 fold its present value and all other things remain unchanged, the period of moon's rotation would be nearly
1 $29 \sqrt{2}$ days
2 $29 / \sqrt{2}$ days
3 $29 \times 2$ days
4 29 days
Explanation:
D As we know, time period of a satellite orbiting around a planet of mass $\mathrm{M}$ is - $\mathrm{T}=\frac{2 \pi \mathrm{R}}{\mathrm{v}_{\text {orbital }}} \quad\left(\mathrm{v}_{\mathrm{o}}=\sqrt{\frac{\mathrm{GM}}{\mathrm{R}}}\right)$ $\mathrm{T}=2 \pi \mathrm{R} \sqrt{\frac{\mathrm{R}}{\mathrm{GM}}}=2 \pi \sqrt{\frac{\mathrm{R}^{3}}{\mathrm{GM}}}$ Hence, it is clear that there is no dependency of the satellite's mass for orbital time period. Now we can say that mass of the satellite does not affect the time period of the orbit. Hence, the time period of the moon's rotation around the earth will remain the same, i.e. 29 days.
AIIMS-27.05.2018(M)
Gravitation
138722
The angular speed of earth in $\mathrm{rad} / \mathrm{s}$, so that bodies on equator may appear weightless is: [Use $g=10 \mathrm{~m} / \mathrm{s}^{2}$ and the radius of earth $=6.4 \times$ $\left.10^{3} \mathrm{~km}\right]$
1 $1.25 \times 10^{-3}$
2 $1.56 \times 10^{-3}$
3 $1.25 \times 10^{-1}$
4 1.56
Explanation:
A As we know, $\text { At equator } \mathrm{g}^{\prime}=\mathrm{g}-\mathrm{R} \omega^{2}$ $\quad 0 \quad \mathrm{~g}-\mathrm{R} \omega^{2} \quad\left(\because \mathrm{g}^{\prime}=0\right)$ $\therefore \quad \omega=\sqrt{\frac{\mathrm{g}}{\mathrm{R}_{\mathrm{e}}}}$ $\omega=\sqrt{\frac{10}{6400 \times 10^{3}}}$ $\omega=1.25 \times 10^{-3} \mathrm{rad} / \mathrm{s}$
AIIMS-2011
Gravitation
138718
Assertion: Water kept in an open vessel will quickly evaporate on the surface of the moon. Reason: The temperature at the surface of the moon is much higher than boiling point of the water.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
C Water kept in an open vessel will quickly evaporate on the surface of the moon because on the surface of moon the atmospheric presser is low this leads to a lower boiling point.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Gravitation
138720
Assertion: The escape speed does not depend on the direction in which the projectile is fired. Reason: Attaining the escape speed is easier if a projectile is fired in the direction the launch site is moving as the earth rotates about its axis.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
B Escape velocity is common. It is more accurately described as a speed than a velocity because it is independent of direction; escape velocity increase with the mass of primary body and decreases with the distance from the primary body. Attaining the escape speed is easier if a projectile is fired in the direction the launch site is moving as the earth rotates about its axis.
Gravitation
138721
The period of moon's rotation around the earth is nearly 29 days. If moon's mass were 2 fold its present value and all other things remain unchanged, the period of moon's rotation would be nearly
1 $29 \sqrt{2}$ days
2 $29 / \sqrt{2}$ days
3 $29 \times 2$ days
4 29 days
Explanation:
D As we know, time period of a satellite orbiting around a planet of mass $\mathrm{M}$ is - $\mathrm{T}=\frac{2 \pi \mathrm{R}}{\mathrm{v}_{\text {orbital }}} \quad\left(\mathrm{v}_{\mathrm{o}}=\sqrt{\frac{\mathrm{GM}}{\mathrm{R}}}\right)$ $\mathrm{T}=2 \pi \mathrm{R} \sqrt{\frac{\mathrm{R}}{\mathrm{GM}}}=2 \pi \sqrt{\frac{\mathrm{R}^{3}}{\mathrm{GM}}}$ Hence, it is clear that there is no dependency of the satellite's mass for orbital time period. Now we can say that mass of the satellite does not affect the time period of the orbit. Hence, the time period of the moon's rotation around the earth will remain the same, i.e. 29 days.
AIIMS-27.05.2018(M)
Gravitation
138722
The angular speed of earth in $\mathrm{rad} / \mathrm{s}$, so that bodies on equator may appear weightless is: [Use $g=10 \mathrm{~m} / \mathrm{s}^{2}$ and the radius of earth $=6.4 \times$ $\left.10^{3} \mathrm{~km}\right]$
1 $1.25 \times 10^{-3}$
2 $1.56 \times 10^{-3}$
3 $1.25 \times 10^{-1}$
4 1.56
Explanation:
A As we know, $\text { At equator } \mathrm{g}^{\prime}=\mathrm{g}-\mathrm{R} \omega^{2}$ $\quad 0 \quad \mathrm{~g}-\mathrm{R} \omega^{2} \quad\left(\because \mathrm{g}^{\prime}=0\right)$ $\therefore \quad \omega=\sqrt{\frac{\mathrm{g}}{\mathrm{R}_{\mathrm{e}}}}$ $\omega=\sqrt{\frac{10}{6400 \times 10^{3}}}$ $\omega=1.25 \times 10^{-3} \mathrm{rad} / \mathrm{s}$
AIIMS-2011
Gravitation
138718
Assertion: Water kept in an open vessel will quickly evaporate on the surface of the moon. Reason: The temperature at the surface of the moon is much higher than boiling point of the water.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
C Water kept in an open vessel will quickly evaporate on the surface of the moon because on the surface of moon the atmospheric presser is low this leads to a lower boiling point.