05. Measuring Instruments
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Units and Measurements

139968 A screw gauge has least count of \(0.01 \mathrm{~mm}\) and there are 50 divisions in its circular scale.
The pitch of the screw gauge is

1 \(0.25 \mathrm{~mm}\)
2 \(0.5 \mathrm{~mm}\)
3 \(1.0 \mathrm{~mm}\)
4 \(0.01 \mathrm{~mm}\)
NEET (Sep.) 2020
Units and Measurements

139969 The least count of the main scale of a screw gauge is \(1 \mathrm{~mm}\). The minimum number of divisions on its circular scale required to measure \(5 \mu \mathrm{m}\) diameter of a wire is

1 50
2 200
3 500
4 100
JEE Main-12.01.2019
Units and Measurements

139970 The pitch and the number of divisions, on the circular scale for a given screw gauge are 0.5 \(\mathrm{mm}\) and 100, respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet are 5.5 \(\mathrm{mm}\) and 48 respectively, the thickness of this sheet is

1 \(5.950 \mathrm{~mm}\)
2 \(5.725 \mathrm{~mm}\)
3 \(5.755 \mathrm{~mm}\)
4 \(5.740 \mathrm{~mm}\)
JEE Main-09.01.2019
Units and Measurements

139971 \(N\) divisions on the main scale of a vernier calipers coincide with \((N+1)\) division of the vernier scale. If each division of main scale is a units, then the least count of the calipers is :

1 \(\frac{a}{N}\)
2 a
3 \(\frac{\mathrm{a}}{\mathrm{N}+1}\)
4 \(\frac{\mathrm{Na}}{\mathrm{N}+1}\)
AP EAMCET (21.04.2019) Shift-II
Units and Measurements

139972 The main scale of a vernier calliper has \(n\) divisions/cm. \(n\) divisions of the Vernier scale coincide with \((n-1)\) divisions of main scale. The least count of the vernier callipers is

1 \(\frac{1}{(\mathrm{n}+1)(\mathrm{n}-1)} \mathrm{cm}\)
2 \(\frac{1}{\mathrm{n}} \mathrm{cm}\)
3 \(\frac{1}{\mathrm{n}^{2}} \mathrm{~cm}\)
4 \(\frac{1}{\mathrm{n}(\mathrm{n}+1)} \mathrm{cm}\)
NEET (Odisha) 2019
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Units and Measurements

139968 A screw gauge has least count of \(0.01 \mathrm{~mm}\) and there are 50 divisions in its circular scale.
The pitch of the screw gauge is

1 \(0.25 \mathrm{~mm}\)
2 \(0.5 \mathrm{~mm}\)
3 \(1.0 \mathrm{~mm}\)
4 \(0.01 \mathrm{~mm}\)
NEET (Sep.) 2020
Units and Measurements

139969 The least count of the main scale of a screw gauge is \(1 \mathrm{~mm}\). The minimum number of divisions on its circular scale required to measure \(5 \mu \mathrm{m}\) diameter of a wire is

1 50
2 200
3 500
4 100
JEE Main-12.01.2019
Units and Measurements

139970 The pitch and the number of divisions, on the circular scale for a given screw gauge are 0.5 \(\mathrm{mm}\) and 100, respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet are 5.5 \(\mathrm{mm}\) and 48 respectively, the thickness of this sheet is

1 \(5.950 \mathrm{~mm}\)
2 \(5.725 \mathrm{~mm}\)
3 \(5.755 \mathrm{~mm}\)
4 \(5.740 \mathrm{~mm}\)
JEE Main-09.01.2019
Units and Measurements

139971 \(N\) divisions on the main scale of a vernier calipers coincide with \((N+1)\) division of the vernier scale. If each division of main scale is a units, then the least count of the calipers is :

1 \(\frac{a}{N}\)
2 a
3 \(\frac{\mathrm{a}}{\mathrm{N}+1}\)
4 \(\frac{\mathrm{Na}}{\mathrm{N}+1}\)
AP EAMCET (21.04.2019) Shift-II
Units and Measurements

139972 The main scale of a vernier calliper has \(n\) divisions/cm. \(n\) divisions of the Vernier scale coincide with \((n-1)\) divisions of main scale. The least count of the vernier callipers is

1 \(\frac{1}{(\mathrm{n}+1)(\mathrm{n}-1)} \mathrm{cm}\)
2 \(\frac{1}{\mathrm{n}} \mathrm{cm}\)
3 \(\frac{1}{\mathrm{n}^{2}} \mathrm{~cm}\)
4 \(\frac{1}{\mathrm{n}(\mathrm{n}+1)} \mathrm{cm}\)
NEET (Odisha) 2019
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Units and Measurements

139968 A screw gauge has least count of \(0.01 \mathrm{~mm}\) and there are 50 divisions in its circular scale.
The pitch of the screw gauge is

1 \(0.25 \mathrm{~mm}\)
2 \(0.5 \mathrm{~mm}\)
3 \(1.0 \mathrm{~mm}\)
4 \(0.01 \mathrm{~mm}\)
NEET (Sep.) 2020
Units and Measurements

139969 The least count of the main scale of a screw gauge is \(1 \mathrm{~mm}\). The minimum number of divisions on its circular scale required to measure \(5 \mu \mathrm{m}\) diameter of a wire is

1 50
2 200
3 500
4 100
JEE Main-12.01.2019
Units and Measurements

139970 The pitch and the number of divisions, on the circular scale for a given screw gauge are 0.5 \(\mathrm{mm}\) and 100, respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet are 5.5 \(\mathrm{mm}\) and 48 respectively, the thickness of this sheet is

1 \(5.950 \mathrm{~mm}\)
2 \(5.725 \mathrm{~mm}\)
3 \(5.755 \mathrm{~mm}\)
4 \(5.740 \mathrm{~mm}\)
JEE Main-09.01.2019
Units and Measurements

139971 \(N\) divisions on the main scale of a vernier calipers coincide with \((N+1)\) division of the vernier scale. If each division of main scale is a units, then the least count of the calipers is :

1 \(\frac{a}{N}\)
2 a
3 \(\frac{\mathrm{a}}{\mathrm{N}+1}\)
4 \(\frac{\mathrm{Na}}{\mathrm{N}+1}\)
AP EAMCET (21.04.2019) Shift-II
Units and Measurements

139972 The main scale of a vernier calliper has \(n\) divisions/cm. \(n\) divisions of the Vernier scale coincide with \((n-1)\) divisions of main scale. The least count of the vernier callipers is

1 \(\frac{1}{(\mathrm{n}+1)(\mathrm{n}-1)} \mathrm{cm}\)
2 \(\frac{1}{\mathrm{n}} \mathrm{cm}\)
3 \(\frac{1}{\mathrm{n}^{2}} \mathrm{~cm}\)
4 \(\frac{1}{\mathrm{n}(\mathrm{n}+1)} \mathrm{cm}\)
NEET (Odisha) 2019
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Units and Measurements

139968 A screw gauge has least count of \(0.01 \mathrm{~mm}\) and there are 50 divisions in its circular scale.
The pitch of the screw gauge is

1 \(0.25 \mathrm{~mm}\)
2 \(0.5 \mathrm{~mm}\)
3 \(1.0 \mathrm{~mm}\)
4 \(0.01 \mathrm{~mm}\)
NEET (Sep.) 2020
Units and Measurements

139969 The least count of the main scale of a screw gauge is \(1 \mathrm{~mm}\). The minimum number of divisions on its circular scale required to measure \(5 \mu \mathrm{m}\) diameter of a wire is

1 50
2 200
3 500
4 100
JEE Main-12.01.2019
Units and Measurements

139970 The pitch and the number of divisions, on the circular scale for a given screw gauge are 0.5 \(\mathrm{mm}\) and 100, respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet are 5.5 \(\mathrm{mm}\) and 48 respectively, the thickness of this sheet is

1 \(5.950 \mathrm{~mm}\)
2 \(5.725 \mathrm{~mm}\)
3 \(5.755 \mathrm{~mm}\)
4 \(5.740 \mathrm{~mm}\)
JEE Main-09.01.2019
Units and Measurements

139971 \(N\) divisions on the main scale of a vernier calipers coincide with \((N+1)\) division of the vernier scale. If each division of main scale is a units, then the least count of the calipers is :

1 \(\frac{a}{N}\)
2 a
3 \(\frac{\mathrm{a}}{\mathrm{N}+1}\)
4 \(\frac{\mathrm{Na}}{\mathrm{N}+1}\)
AP EAMCET (21.04.2019) Shift-II
Units and Measurements

139972 The main scale of a vernier calliper has \(n\) divisions/cm. \(n\) divisions of the Vernier scale coincide with \((n-1)\) divisions of main scale. The least count of the vernier callipers is

1 \(\frac{1}{(\mathrm{n}+1)(\mathrm{n}-1)} \mathrm{cm}\)
2 \(\frac{1}{\mathrm{n}} \mathrm{cm}\)
3 \(\frac{1}{\mathrm{n}^{2}} \mathrm{~cm}\)
4 \(\frac{1}{\mathrm{n}(\mathrm{n}+1)} \mathrm{cm}\)
NEET (Odisha) 2019
Join With Us for More Updates
Units and Measurements

139968 A screw gauge has least count of \(0.01 \mathrm{~mm}\) and there are 50 divisions in its circular scale.
The pitch of the screw gauge is

1 \(0.25 \mathrm{~mm}\)
2 \(0.5 \mathrm{~mm}\)
3 \(1.0 \mathrm{~mm}\)
4 \(0.01 \mathrm{~mm}\)
NEET (Sep.) 2020
Units and Measurements

139969 The least count of the main scale of a screw gauge is \(1 \mathrm{~mm}\). The minimum number of divisions on its circular scale required to measure \(5 \mu \mathrm{m}\) diameter of a wire is

1 50
2 200
3 500
4 100
JEE Main-12.01.2019
Units and Measurements

139970 The pitch and the number of divisions, on the circular scale for a given screw gauge are 0.5 \(\mathrm{mm}\) and 100, respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet are 5.5 \(\mathrm{mm}\) and 48 respectively, the thickness of this sheet is

1 \(5.950 \mathrm{~mm}\)
2 \(5.725 \mathrm{~mm}\)
3 \(5.755 \mathrm{~mm}\)
4 \(5.740 \mathrm{~mm}\)
JEE Main-09.01.2019
Units and Measurements

139971 \(N\) divisions on the main scale of a vernier calipers coincide with \((N+1)\) division of the vernier scale. If each division of main scale is a units, then the least count of the calipers is :

1 \(\frac{a}{N}\)
2 a
3 \(\frac{\mathrm{a}}{\mathrm{N}+1}\)
4 \(\frac{\mathrm{Na}}{\mathrm{N}+1}\)
AP EAMCET (21.04.2019) Shift-II
Units and Measurements

139972 The main scale of a vernier calliper has \(n\) divisions/cm. \(n\) divisions of the Vernier scale coincide with \((n-1)\) divisions of main scale. The least count of the vernier callipers is

1 \(\frac{1}{(\mathrm{n}+1)(\mathrm{n}-1)} \mathrm{cm}\)
2 \(\frac{1}{\mathrm{n}} \mathrm{cm}\)
3 \(\frac{1}{\mathrm{n}^{2}} \mathrm{~cm}\)
4 \(\frac{1}{\mathrm{n}(\mathrm{n}+1)} \mathrm{cm}\)
NEET (Odisha) 2019