05. Measuring Instruments
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Units and Measurements

139973 The length is measured using a vernier system whose main scale is \(30 \mathrm{~cm}\) long with 600 divisions. If 19 divisions of the main scale coincide with 20 divisions of the vernier scale, then its least count is

1 \(0.25 \mathrm{~cm}\)
2 \(0.025 \mathrm{~cm}\)
3 \(0.25 \mathrm{~mm}\)
4 \(0.025 \mathrm{~mm}\)
5 \(0.0025 \mathrm{~mm}\)
Units and Measurements

139975 A screw gauge with a pitch of \(0.5 \mathrm{~mm}\) and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminum. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the \(\mathbf{4 5}^{\text {th }}\) division
coincides with the main scale line and that the zero of the main scale is barely visible.
What is the thickness of the sheet, if the main scale reading is \(0.5 \mathrm{~mm}\) and the \(25^{\text {th }}\) division coincides with the main scale line?

1 \(0.75 \mathrm{~mm}\)
2 \(0.80 \mathrm{~mm}\)
3 \(0.70 \mathrm{~mm}\)
4 \(0.50 \mathrm{~mm}\)
Units and Measurements

139976 A student measured the length of a rod and wrote it as \(3.50 \mathrm{~cm}\). Which instrument did he use to measure it?

1 A meter scale
2 A vernier caliper where the 10 divisions in vernier scale matches with 9 divisions in main scale and main scale has 10 divisions in \(1 \mathrm{~cm}\)
3 A screw gauge having 100 divisions in the circular scale and pitch as \(1 \mathrm{~mm}\)
4 A screw gauge having 50 divisions in the circular scale and pitch as \(1 \mathrm{~mm}\)
Units and Measurements

139977 A screw gauge gives the following reading when used to measure the diameter of a wire. Main scale reading \(0 \mathrm{~mm}\) circular scale reading 52 divisions Given that \(1 \mathrm{~mm}\) on main scale corresponds to 100 divisions of the circular scale. The diameter of wire from the above data is

1 \(0.052 \mathrm{~cm}\)
2 \(0.026 \mathrm{~cm}\)
3 \(0.005 \mathrm{~cm}\)
4 \(0.52 \mathrm{~cm}\)
Units and Measurements

139973 The length is measured using a vernier system whose main scale is \(30 \mathrm{~cm}\) long with 600 divisions. If 19 divisions of the main scale coincide with 20 divisions of the vernier scale, then its least count is

1 \(0.25 \mathrm{~cm}\)
2 \(0.025 \mathrm{~cm}\)
3 \(0.25 \mathrm{~mm}\)
4 \(0.025 \mathrm{~mm}\)
5 \(0.0025 \mathrm{~mm}\)
Units and Measurements

139975 A screw gauge with a pitch of \(0.5 \mathrm{~mm}\) and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminum. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the \(\mathbf{4 5}^{\text {th }}\) division
coincides with the main scale line and that the zero of the main scale is barely visible.
What is the thickness of the sheet, if the main scale reading is \(0.5 \mathrm{~mm}\) and the \(25^{\text {th }}\) division coincides with the main scale line?

1 \(0.75 \mathrm{~mm}\)
2 \(0.80 \mathrm{~mm}\)
3 \(0.70 \mathrm{~mm}\)
4 \(0.50 \mathrm{~mm}\)
Units and Measurements

139976 A student measured the length of a rod and wrote it as \(3.50 \mathrm{~cm}\). Which instrument did he use to measure it?

1 A meter scale
2 A vernier caliper where the 10 divisions in vernier scale matches with 9 divisions in main scale and main scale has 10 divisions in \(1 \mathrm{~cm}\)
3 A screw gauge having 100 divisions in the circular scale and pitch as \(1 \mathrm{~mm}\)
4 A screw gauge having 50 divisions in the circular scale and pitch as \(1 \mathrm{~mm}\)
Units and Measurements

139977 A screw gauge gives the following reading when used to measure the diameter of a wire. Main scale reading \(0 \mathrm{~mm}\) circular scale reading 52 divisions Given that \(1 \mathrm{~mm}\) on main scale corresponds to 100 divisions of the circular scale. The diameter of wire from the above data is

1 \(0.052 \mathrm{~cm}\)
2 \(0.026 \mathrm{~cm}\)
3 \(0.005 \mathrm{~cm}\)
4 \(0.52 \mathrm{~cm}\)
Units and Measurements

139973 The length is measured using a vernier system whose main scale is \(30 \mathrm{~cm}\) long with 600 divisions. If 19 divisions of the main scale coincide with 20 divisions of the vernier scale, then its least count is

1 \(0.25 \mathrm{~cm}\)
2 \(0.025 \mathrm{~cm}\)
3 \(0.25 \mathrm{~mm}\)
4 \(0.025 \mathrm{~mm}\)
5 \(0.0025 \mathrm{~mm}\)
Units and Measurements

139975 A screw gauge with a pitch of \(0.5 \mathrm{~mm}\) and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminum. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the \(\mathbf{4 5}^{\text {th }}\) division
coincides with the main scale line and that the zero of the main scale is barely visible.
What is the thickness of the sheet, if the main scale reading is \(0.5 \mathrm{~mm}\) and the \(25^{\text {th }}\) division coincides with the main scale line?

1 \(0.75 \mathrm{~mm}\)
2 \(0.80 \mathrm{~mm}\)
3 \(0.70 \mathrm{~mm}\)
4 \(0.50 \mathrm{~mm}\)
Units and Measurements

139976 A student measured the length of a rod and wrote it as \(3.50 \mathrm{~cm}\). Which instrument did he use to measure it?

1 A meter scale
2 A vernier caliper where the 10 divisions in vernier scale matches with 9 divisions in main scale and main scale has 10 divisions in \(1 \mathrm{~cm}\)
3 A screw gauge having 100 divisions in the circular scale and pitch as \(1 \mathrm{~mm}\)
4 A screw gauge having 50 divisions in the circular scale and pitch as \(1 \mathrm{~mm}\)
Units and Measurements

139977 A screw gauge gives the following reading when used to measure the diameter of a wire. Main scale reading \(0 \mathrm{~mm}\) circular scale reading 52 divisions Given that \(1 \mathrm{~mm}\) on main scale corresponds to 100 divisions of the circular scale. The diameter of wire from the above data is

1 \(0.052 \mathrm{~cm}\)
2 \(0.026 \mathrm{~cm}\)
3 \(0.005 \mathrm{~cm}\)
4 \(0.52 \mathrm{~cm}\)
Units and Measurements

139973 The length is measured using a vernier system whose main scale is \(30 \mathrm{~cm}\) long with 600 divisions. If 19 divisions of the main scale coincide with 20 divisions of the vernier scale, then its least count is

1 \(0.25 \mathrm{~cm}\)
2 \(0.025 \mathrm{~cm}\)
3 \(0.25 \mathrm{~mm}\)
4 \(0.025 \mathrm{~mm}\)
5 \(0.0025 \mathrm{~mm}\)
Units and Measurements

139975 A screw gauge with a pitch of \(0.5 \mathrm{~mm}\) and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminum. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the \(\mathbf{4 5}^{\text {th }}\) division
coincides with the main scale line and that the zero of the main scale is barely visible.
What is the thickness of the sheet, if the main scale reading is \(0.5 \mathrm{~mm}\) and the \(25^{\text {th }}\) division coincides with the main scale line?

1 \(0.75 \mathrm{~mm}\)
2 \(0.80 \mathrm{~mm}\)
3 \(0.70 \mathrm{~mm}\)
4 \(0.50 \mathrm{~mm}\)
Units and Measurements

139976 A student measured the length of a rod and wrote it as \(3.50 \mathrm{~cm}\). Which instrument did he use to measure it?

1 A meter scale
2 A vernier caliper where the 10 divisions in vernier scale matches with 9 divisions in main scale and main scale has 10 divisions in \(1 \mathrm{~cm}\)
3 A screw gauge having 100 divisions in the circular scale and pitch as \(1 \mathrm{~mm}\)
4 A screw gauge having 50 divisions in the circular scale and pitch as \(1 \mathrm{~mm}\)
Units and Measurements

139977 A screw gauge gives the following reading when used to measure the diameter of a wire. Main scale reading \(0 \mathrm{~mm}\) circular scale reading 52 divisions Given that \(1 \mathrm{~mm}\) on main scale corresponds to 100 divisions of the circular scale. The diameter of wire from the above data is

1 \(0.052 \mathrm{~cm}\)
2 \(0.026 \mathrm{~cm}\)
3 \(0.005 \mathrm{~cm}\)
4 \(0.52 \mathrm{~cm}\)