232297
Which of the following do not obey Huckel's rule for aromaticity?
1 I, IV
2 I, II
3 III, IV
4 All of these
Explanation:
(C): According to the Huckel's rule for aromaticity, a compound follow the following rule- (I) It must be cyclic (II) It must be planar with conjugation (III) It must having the $(4 n+2) \pi \mathrm{e}^{\ominus}$ Thus, compound (III) and (IV) do not follow the Huckel's rule.
A.P. EAMCET(MEDICAL) - 2009
GENERAL ORGANIC CHEMISTRY
232298
Which of the following is aromatic compound?
1
2 It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
3
4 All of these
Explanation:
(D): According to Huckel's rule compound become aromatic compound if it must be cyclic and have conjugated system. It must be planer i.e. it should be $\mathrm{sp}^{2}$ hybridised. It must have $(4 n+2) \pi \mathrm{e}^{-}$system where $\mathrm{n}$ is $0,1,2,3$. It is an aromatic compound because it has $6 \pi \mathrm{e}^{-}$system. (b.) It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
AMU-2016
GENERAL ORGANIC CHEMISTRY
232299
Which one of the following is an aromatic compound?
1
2
3
4
Explanation:
The compound which has conjugated system and planar structure and follow $(4 \mathrm{n}+2), \pi \mathrm{e}^{-}$system rule where $\mathrm{n}=0,1,2,3$. It is not aromatic compound because it does not have conjugated system. It also not have $\mathrm{sp}^{2}$ hybridisation. It is aromatic compound because it has conjugated system and all carbon atom has $\mathrm{sp}^{2}$ hybridisation. It is not an aromatic because it does have planer structure due to presence of $\mathrm{sp}^{3}$ hybridisation. It also does not have conjugated system and planer structure so it is not aromatic compound.
AMU-2015
GENERAL ORGANIC CHEMISTRY
232302
$\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}+3 \mathrm{NaOH} \rightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ In the above reaction, the product ' $\mathrm{A}$ ' is
1 chlorobenzene
2 phenyl isocyanide
3 phenyl cyanide
4 phenyl chloride
Explanation:
(B): $\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5}+3 \mathrm{NaOH} \longrightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ The given above reaction is known as carbyl amine reaction. **Carbylalamine reaction-** Alcoholic solution of primary amine are react with chloroform and potossium hydroxide solution to yield isocynide called carbylamine reaction, Mechanism- In the above Reaction product $\mathrm{A}$ is $\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{NC}$ (phenyl isocynide).
BCECE-2007
GENERAL ORGANIC CHEMISTRY
232305
Which of the following compound in its anionic form is aromatic?
1
2
3
4
Explanation:
(A): All structure given are cyclic, only those structure are aromatic in which after removal of Hydrogen it follow $(4 n+2) \pi$ electron system. It is aromatic \& it has $6 \pi \mathrm{e}^{-}$so it follow Huckle rule. After removal of Hydrogen it become $4 \pi \mathrm{e}^{-}$so it is antiaromatic After removal Hydrogen it does become aromatic because it does not have conjugated system. It does not show aromatic because it has one carbon is $\mathrm{sp}^{3}$ hybridisation.
232297
Which of the following do not obey Huckel's rule for aromaticity?
1 I, IV
2 I, II
3 III, IV
4 All of these
Explanation:
(C): According to the Huckel's rule for aromaticity, a compound follow the following rule- (I) It must be cyclic (II) It must be planar with conjugation (III) It must having the $(4 n+2) \pi \mathrm{e}^{\ominus}$ Thus, compound (III) and (IV) do not follow the Huckel's rule.
A.P. EAMCET(MEDICAL) - 2009
GENERAL ORGANIC CHEMISTRY
232298
Which of the following is aromatic compound?
1
2 It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
3
4 All of these
Explanation:
(D): According to Huckel's rule compound become aromatic compound if it must be cyclic and have conjugated system. It must be planer i.e. it should be $\mathrm{sp}^{2}$ hybridised. It must have $(4 n+2) \pi \mathrm{e}^{-}$system where $\mathrm{n}$ is $0,1,2,3$. It is an aromatic compound because it has $6 \pi \mathrm{e}^{-}$system. (b.) It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
AMU-2016
GENERAL ORGANIC CHEMISTRY
232299
Which one of the following is an aromatic compound?
1
2
3
4
Explanation:
The compound which has conjugated system and planar structure and follow $(4 \mathrm{n}+2), \pi \mathrm{e}^{-}$system rule where $\mathrm{n}=0,1,2,3$. It is not aromatic compound because it does not have conjugated system. It also not have $\mathrm{sp}^{2}$ hybridisation. It is aromatic compound because it has conjugated system and all carbon atom has $\mathrm{sp}^{2}$ hybridisation. It is not an aromatic because it does have planer structure due to presence of $\mathrm{sp}^{3}$ hybridisation. It also does not have conjugated system and planer structure so it is not aromatic compound.
AMU-2015
GENERAL ORGANIC CHEMISTRY
232302
$\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}+3 \mathrm{NaOH} \rightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ In the above reaction, the product ' $\mathrm{A}$ ' is
1 chlorobenzene
2 phenyl isocyanide
3 phenyl cyanide
4 phenyl chloride
Explanation:
(B): $\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5}+3 \mathrm{NaOH} \longrightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ The given above reaction is known as carbyl amine reaction. **Carbylalamine reaction-** Alcoholic solution of primary amine are react with chloroform and potossium hydroxide solution to yield isocynide called carbylamine reaction, Mechanism- In the above Reaction product $\mathrm{A}$ is $\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{NC}$ (phenyl isocynide).
BCECE-2007
GENERAL ORGANIC CHEMISTRY
232305
Which of the following compound in its anionic form is aromatic?
1
2
3
4
Explanation:
(A): All structure given are cyclic, only those structure are aromatic in which after removal of Hydrogen it follow $(4 n+2) \pi$ electron system. It is aromatic \& it has $6 \pi \mathrm{e}^{-}$so it follow Huckle rule. After removal of Hydrogen it become $4 \pi \mathrm{e}^{-}$so it is antiaromatic After removal Hydrogen it does become aromatic because it does not have conjugated system. It does not show aromatic because it has one carbon is $\mathrm{sp}^{3}$ hybridisation.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
GENERAL ORGANIC CHEMISTRY
232297
Which of the following do not obey Huckel's rule for aromaticity?
1 I, IV
2 I, II
3 III, IV
4 All of these
Explanation:
(C): According to the Huckel's rule for aromaticity, a compound follow the following rule- (I) It must be cyclic (II) It must be planar with conjugation (III) It must having the $(4 n+2) \pi \mathrm{e}^{\ominus}$ Thus, compound (III) and (IV) do not follow the Huckel's rule.
A.P. EAMCET(MEDICAL) - 2009
GENERAL ORGANIC CHEMISTRY
232298
Which of the following is aromatic compound?
1
2 It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
3
4 All of these
Explanation:
(D): According to Huckel's rule compound become aromatic compound if it must be cyclic and have conjugated system. It must be planer i.e. it should be $\mathrm{sp}^{2}$ hybridised. It must have $(4 n+2) \pi \mathrm{e}^{-}$system where $\mathrm{n}$ is $0,1,2,3$. It is an aromatic compound because it has $6 \pi \mathrm{e}^{-}$system. (b.) It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
AMU-2016
GENERAL ORGANIC CHEMISTRY
232299
Which one of the following is an aromatic compound?
1
2
3
4
Explanation:
The compound which has conjugated system and planar structure and follow $(4 \mathrm{n}+2), \pi \mathrm{e}^{-}$system rule where $\mathrm{n}=0,1,2,3$. It is not aromatic compound because it does not have conjugated system. It also not have $\mathrm{sp}^{2}$ hybridisation. It is aromatic compound because it has conjugated system and all carbon atom has $\mathrm{sp}^{2}$ hybridisation. It is not an aromatic because it does have planer structure due to presence of $\mathrm{sp}^{3}$ hybridisation. It also does not have conjugated system and planer structure so it is not aromatic compound.
AMU-2015
GENERAL ORGANIC CHEMISTRY
232302
$\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}+3 \mathrm{NaOH} \rightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ In the above reaction, the product ' $\mathrm{A}$ ' is
1 chlorobenzene
2 phenyl isocyanide
3 phenyl cyanide
4 phenyl chloride
Explanation:
(B): $\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5}+3 \mathrm{NaOH} \longrightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ The given above reaction is known as carbyl amine reaction. **Carbylalamine reaction-** Alcoholic solution of primary amine are react with chloroform and potossium hydroxide solution to yield isocynide called carbylamine reaction, Mechanism- In the above Reaction product $\mathrm{A}$ is $\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{NC}$ (phenyl isocynide).
BCECE-2007
GENERAL ORGANIC CHEMISTRY
232305
Which of the following compound in its anionic form is aromatic?
1
2
3
4
Explanation:
(A): All structure given are cyclic, only those structure are aromatic in which after removal of Hydrogen it follow $(4 n+2) \pi$ electron system. It is aromatic \& it has $6 \pi \mathrm{e}^{-}$so it follow Huckle rule. After removal of Hydrogen it become $4 \pi \mathrm{e}^{-}$so it is antiaromatic After removal Hydrogen it does become aromatic because it does not have conjugated system. It does not show aromatic because it has one carbon is $\mathrm{sp}^{3}$ hybridisation.
232297
Which of the following do not obey Huckel's rule for aromaticity?
1 I, IV
2 I, II
3 III, IV
4 All of these
Explanation:
(C): According to the Huckel's rule for aromaticity, a compound follow the following rule- (I) It must be cyclic (II) It must be planar with conjugation (III) It must having the $(4 n+2) \pi \mathrm{e}^{\ominus}$ Thus, compound (III) and (IV) do not follow the Huckel's rule.
A.P. EAMCET(MEDICAL) - 2009
GENERAL ORGANIC CHEMISTRY
232298
Which of the following is aromatic compound?
1
2 It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
3
4 All of these
Explanation:
(D): According to Huckel's rule compound become aromatic compound if it must be cyclic and have conjugated system. It must be planer i.e. it should be $\mathrm{sp}^{2}$ hybridised. It must have $(4 n+2) \pi \mathrm{e}^{-}$system where $\mathrm{n}$ is $0,1,2,3$. It is an aromatic compound because it has $6 \pi \mathrm{e}^{-}$system. (b.) It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
AMU-2016
GENERAL ORGANIC CHEMISTRY
232299
Which one of the following is an aromatic compound?
1
2
3
4
Explanation:
The compound which has conjugated system and planar structure and follow $(4 \mathrm{n}+2), \pi \mathrm{e}^{-}$system rule where $\mathrm{n}=0,1,2,3$. It is not aromatic compound because it does not have conjugated system. It also not have $\mathrm{sp}^{2}$ hybridisation. It is aromatic compound because it has conjugated system and all carbon atom has $\mathrm{sp}^{2}$ hybridisation. It is not an aromatic because it does have planer structure due to presence of $\mathrm{sp}^{3}$ hybridisation. It also does not have conjugated system and planer structure so it is not aromatic compound.
AMU-2015
GENERAL ORGANIC CHEMISTRY
232302
$\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}+3 \mathrm{NaOH} \rightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ In the above reaction, the product ' $\mathrm{A}$ ' is
1 chlorobenzene
2 phenyl isocyanide
3 phenyl cyanide
4 phenyl chloride
Explanation:
(B): $\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5}+3 \mathrm{NaOH} \longrightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ The given above reaction is known as carbyl amine reaction. **Carbylalamine reaction-** Alcoholic solution of primary amine are react with chloroform and potossium hydroxide solution to yield isocynide called carbylamine reaction, Mechanism- In the above Reaction product $\mathrm{A}$ is $\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{NC}$ (phenyl isocynide).
BCECE-2007
GENERAL ORGANIC CHEMISTRY
232305
Which of the following compound in its anionic form is aromatic?
1
2
3
4
Explanation:
(A): All structure given are cyclic, only those structure are aromatic in which after removal of Hydrogen it follow $(4 n+2) \pi$ electron system. It is aromatic \& it has $6 \pi \mathrm{e}^{-}$so it follow Huckle rule. After removal of Hydrogen it become $4 \pi \mathrm{e}^{-}$so it is antiaromatic After removal Hydrogen it does become aromatic because it does not have conjugated system. It does not show aromatic because it has one carbon is $\mathrm{sp}^{3}$ hybridisation.
232297
Which of the following do not obey Huckel's rule for aromaticity?
1 I, IV
2 I, II
3 III, IV
4 All of these
Explanation:
(C): According to the Huckel's rule for aromaticity, a compound follow the following rule- (I) It must be cyclic (II) It must be planar with conjugation (III) It must having the $(4 n+2) \pi \mathrm{e}^{\ominus}$ Thus, compound (III) and (IV) do not follow the Huckel's rule.
A.P. EAMCET(MEDICAL) - 2009
GENERAL ORGANIC CHEMISTRY
232298
Which of the following is aromatic compound?
1
2 It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
3
4 All of these
Explanation:
(D): According to Huckel's rule compound become aromatic compound if it must be cyclic and have conjugated system. It must be planer i.e. it should be $\mathrm{sp}^{2}$ hybridised. It must have $(4 n+2) \pi \mathrm{e}^{-}$system where $\mathrm{n}$ is $0,1,2,3$. It is an aromatic compound because it has $6 \pi \mathrm{e}^{-}$system. (b.) It is also an aromatic because it also have $6 \pi \mathrm{e}^{-}$system and follow huckle rule. In this case only one lone pair of sulphur is taken in conjugation. It also an aromatic compound because it also have $(4 n+2) \pi e^{-}$ie. $6 \pi$ e system. So from the above explanation all the three structure are aromatic in nature. **Conjugated System:-** It have alternate $\pi$-bond/+ve/-ve/ lone pair then such compound is conjugated system.
AMU-2016
GENERAL ORGANIC CHEMISTRY
232299
Which one of the following is an aromatic compound?
1
2
3
4
Explanation:
The compound which has conjugated system and planar structure and follow $(4 \mathrm{n}+2), \pi \mathrm{e}^{-}$system rule where $\mathrm{n}=0,1,2,3$. It is not aromatic compound because it does not have conjugated system. It also not have $\mathrm{sp}^{2}$ hybridisation. It is aromatic compound because it has conjugated system and all carbon atom has $\mathrm{sp}^{2}$ hybridisation. It is not an aromatic because it does have planer structure due to presence of $\mathrm{sp}^{3}$ hybridisation. It also does not have conjugated system and planer structure so it is not aromatic compound.
AMU-2015
GENERAL ORGANIC CHEMISTRY
232302
$\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}+3 \mathrm{NaOH} \rightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ In the above reaction, the product ' $\mathrm{A}$ ' is
1 chlorobenzene
2 phenyl isocyanide
3 phenyl cyanide
4 phenyl chloride
Explanation:
(B): $\mathrm{CHCl}_{3}+\mathrm{C}_{6} \mathrm{H}_{5}+3 \mathrm{NaOH} \longrightarrow \mathrm{A}+3 \mathrm{~B}+3 \mathrm{C}$ The given above reaction is known as carbyl amine reaction. **Carbylalamine reaction-** Alcoholic solution of primary amine are react with chloroform and potossium hydroxide solution to yield isocynide called carbylamine reaction, Mechanism- In the above Reaction product $\mathrm{A}$ is $\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{NC}$ (phenyl isocynide).
BCECE-2007
GENERAL ORGANIC CHEMISTRY
232305
Which of the following compound in its anionic form is aromatic?
1
2
3
4
Explanation:
(A): All structure given are cyclic, only those structure are aromatic in which after removal of Hydrogen it follow $(4 n+2) \pi$ electron system. It is aromatic \& it has $6 \pi \mathrm{e}^{-}$so it follow Huckle rule. After removal of Hydrogen it become $4 \pi \mathrm{e}^{-}$so it is antiaromatic After removal Hydrogen it does become aromatic because it does not have conjugated system. It does not show aromatic because it has one carbon is $\mathrm{sp}^{3}$ hybridisation.