232314
Among the following, the aromatic compounds are: Choose the correct answer from the following options.
1 Only (A) and (B)
2 Only (B) and (C)
3 (B), (C) and (D)
4 (A), (B) and (C)
Explanation:
Compound to become aromatic It must have cyclic structure. It must have planar compound is all carbon atom is $\mathrm{sp}^{2}$ hybridized. It must follow Huckel's rule i.e. $(4 n+2) \pi$ electron where, $\mathrm{n}=0,1,2,3 \ldots \ldots$. If compound has $4 \pi \mathrm{e}^{-}$then it is anti aromatic compound. Out of four only (B) and (C) is aromatic compound
JEE Main-2021
GENERAL ORGANIC CHEMISTRY
232306
Which one of the following will be aromatic?
1
2
3
4
Explanation:
Compound to become aromatic it must have cyclic system conjugated system and have planar structure and compound also have $(4 n+2) \pi$ electron system It's not aromatic because it has one carbon atom and $\mathrm{Sp}^{3}$ hybridisation It also not an aromatic compound although it conjugated system because it have $4 \pi \mathrm{e}^{-}$ $\&$ it is anti aromatic. It does not aromatic because have $8 \pi \mathrm{e}^{-}$which does not follow $(4 \mathrm{n}+2) \pi$ electron hence it is not aromatic it is anti aromatic. (d) It is aromatic because it has $6 \pi \mathrm{e}^{-}$ system and it follow Huckle's rule
BCECE-2018
GENERAL ORGANIC CHEMISTRY
232308
Which compound (s) out of the following is/are not aromatic?
1 (B), (C) and (D)
2 (C) and (D)
3 (B)
4 (A) and (C)
Explanation:
: To show compound is aromatic \(\rightarrow\) It should be cyclic compound \(\rightarrow\) It have planar structure i.e. all carbon is \(\mathrm{sp}^2\) hybridised. \(\rightarrow\) It must follow \((4 n+2) \pi\)-electron system where \(\mathrm{n}=0,1,2,3 \ldots \ldots\). It compound follow these condition then it will be aromatic other wise Anti-aromatic or Non-aromatic. For Anti-aromatic it must have \(4 \pi \mathrm{e}^{-}\)system. In all compound \(b c d\) is not aromatic compound and a is aromatic compound.
JEE Main-2019
GENERAL ORGANIC CHEMISTRY
232310
The increasing order of the reactivity of the following compounds towards electrophilic aromatic substitution reaction is:
1 III $<$ I $<$ II
2 I $<$ I $<$ II
3 III $<$ II $<$ I
4 I $<$ III $<$ II
Explanation:
(A): Reactivity of the compound due to electrophilic electron density of aromatic substitution reaction in the aromatic ring is given on the basis of hyperconjugation Inductive effect and mesomeric effect.
232314
Among the following, the aromatic compounds are: Choose the correct answer from the following options.
1 Only (A) and (B)
2 Only (B) and (C)
3 (B), (C) and (D)
4 (A), (B) and (C)
Explanation:
Compound to become aromatic It must have cyclic structure. It must have planar compound is all carbon atom is $\mathrm{sp}^{2}$ hybridized. It must follow Huckel's rule i.e. $(4 n+2) \pi$ electron where, $\mathrm{n}=0,1,2,3 \ldots \ldots$. If compound has $4 \pi \mathrm{e}^{-}$then it is anti aromatic compound. Out of four only (B) and (C) is aromatic compound
JEE Main-2021
GENERAL ORGANIC CHEMISTRY
232306
Which one of the following will be aromatic?
1
2
3
4
Explanation:
Compound to become aromatic it must have cyclic system conjugated system and have planar structure and compound also have $(4 n+2) \pi$ electron system It's not aromatic because it has one carbon atom and $\mathrm{Sp}^{3}$ hybridisation It also not an aromatic compound although it conjugated system because it have $4 \pi \mathrm{e}^{-}$ $\&$ it is anti aromatic. It does not aromatic because have $8 \pi \mathrm{e}^{-}$which does not follow $(4 \mathrm{n}+2) \pi$ electron hence it is not aromatic it is anti aromatic. (d) It is aromatic because it has $6 \pi \mathrm{e}^{-}$ system and it follow Huckle's rule
BCECE-2018
GENERAL ORGANIC CHEMISTRY
232308
Which compound (s) out of the following is/are not aromatic?
1 (B), (C) and (D)
2 (C) and (D)
3 (B)
4 (A) and (C)
Explanation:
: To show compound is aromatic \(\rightarrow\) It should be cyclic compound \(\rightarrow\) It have planar structure i.e. all carbon is \(\mathrm{sp}^2\) hybridised. \(\rightarrow\) It must follow \((4 n+2) \pi\)-electron system where \(\mathrm{n}=0,1,2,3 \ldots \ldots\). It compound follow these condition then it will be aromatic other wise Anti-aromatic or Non-aromatic. For Anti-aromatic it must have \(4 \pi \mathrm{e}^{-}\)system. In all compound \(b c d\) is not aromatic compound and a is aromatic compound.
JEE Main-2019
GENERAL ORGANIC CHEMISTRY
232310
The increasing order of the reactivity of the following compounds towards electrophilic aromatic substitution reaction is:
1 III $<$ I $<$ II
2 I $<$ I $<$ II
3 III $<$ II $<$ I
4 I $<$ III $<$ II
Explanation:
(A): Reactivity of the compound due to electrophilic electron density of aromatic substitution reaction in the aromatic ring is given on the basis of hyperconjugation Inductive effect and mesomeric effect.
232314
Among the following, the aromatic compounds are: Choose the correct answer from the following options.
1 Only (A) and (B)
2 Only (B) and (C)
3 (B), (C) and (D)
4 (A), (B) and (C)
Explanation:
Compound to become aromatic It must have cyclic structure. It must have planar compound is all carbon atom is $\mathrm{sp}^{2}$ hybridized. It must follow Huckel's rule i.e. $(4 n+2) \pi$ electron where, $\mathrm{n}=0,1,2,3 \ldots \ldots$. If compound has $4 \pi \mathrm{e}^{-}$then it is anti aromatic compound. Out of four only (B) and (C) is aromatic compound
JEE Main-2021
GENERAL ORGANIC CHEMISTRY
232306
Which one of the following will be aromatic?
1
2
3
4
Explanation:
Compound to become aromatic it must have cyclic system conjugated system and have planar structure and compound also have $(4 n+2) \pi$ electron system It's not aromatic because it has one carbon atom and $\mathrm{Sp}^{3}$ hybridisation It also not an aromatic compound although it conjugated system because it have $4 \pi \mathrm{e}^{-}$ $\&$ it is anti aromatic. It does not aromatic because have $8 \pi \mathrm{e}^{-}$which does not follow $(4 \mathrm{n}+2) \pi$ electron hence it is not aromatic it is anti aromatic. (d) It is aromatic because it has $6 \pi \mathrm{e}^{-}$ system and it follow Huckle's rule
BCECE-2018
GENERAL ORGANIC CHEMISTRY
232308
Which compound (s) out of the following is/are not aromatic?
1 (B), (C) and (D)
2 (C) and (D)
3 (B)
4 (A) and (C)
Explanation:
: To show compound is aromatic \(\rightarrow\) It should be cyclic compound \(\rightarrow\) It have planar structure i.e. all carbon is \(\mathrm{sp}^2\) hybridised. \(\rightarrow\) It must follow \((4 n+2) \pi\)-electron system where \(\mathrm{n}=0,1,2,3 \ldots \ldots\). It compound follow these condition then it will be aromatic other wise Anti-aromatic or Non-aromatic. For Anti-aromatic it must have \(4 \pi \mathrm{e}^{-}\)system. In all compound \(b c d\) is not aromatic compound and a is aromatic compound.
JEE Main-2019
GENERAL ORGANIC CHEMISTRY
232310
The increasing order of the reactivity of the following compounds towards electrophilic aromatic substitution reaction is:
1 III $<$ I $<$ II
2 I $<$ I $<$ II
3 III $<$ II $<$ I
4 I $<$ III $<$ II
Explanation:
(A): Reactivity of the compound due to electrophilic electron density of aromatic substitution reaction in the aromatic ring is given on the basis of hyperconjugation Inductive effect and mesomeric effect.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
GENERAL ORGANIC CHEMISTRY
232314
Among the following, the aromatic compounds are: Choose the correct answer from the following options.
1 Only (A) and (B)
2 Only (B) and (C)
3 (B), (C) and (D)
4 (A), (B) and (C)
Explanation:
Compound to become aromatic It must have cyclic structure. It must have planar compound is all carbon atom is $\mathrm{sp}^{2}$ hybridized. It must follow Huckel's rule i.e. $(4 n+2) \pi$ electron where, $\mathrm{n}=0,1,2,3 \ldots \ldots$. If compound has $4 \pi \mathrm{e}^{-}$then it is anti aromatic compound. Out of four only (B) and (C) is aromatic compound
JEE Main-2021
GENERAL ORGANIC CHEMISTRY
232306
Which one of the following will be aromatic?
1
2
3
4
Explanation:
Compound to become aromatic it must have cyclic system conjugated system and have planar structure and compound also have $(4 n+2) \pi$ electron system It's not aromatic because it has one carbon atom and $\mathrm{Sp}^{3}$ hybridisation It also not an aromatic compound although it conjugated system because it have $4 \pi \mathrm{e}^{-}$ $\&$ it is anti aromatic. It does not aromatic because have $8 \pi \mathrm{e}^{-}$which does not follow $(4 \mathrm{n}+2) \pi$ electron hence it is not aromatic it is anti aromatic. (d) It is aromatic because it has $6 \pi \mathrm{e}^{-}$ system and it follow Huckle's rule
BCECE-2018
GENERAL ORGANIC CHEMISTRY
232308
Which compound (s) out of the following is/are not aromatic?
1 (B), (C) and (D)
2 (C) and (D)
3 (B)
4 (A) and (C)
Explanation:
: To show compound is aromatic \(\rightarrow\) It should be cyclic compound \(\rightarrow\) It have planar structure i.e. all carbon is \(\mathrm{sp}^2\) hybridised. \(\rightarrow\) It must follow \((4 n+2) \pi\)-electron system where \(\mathrm{n}=0,1,2,3 \ldots \ldots\). It compound follow these condition then it will be aromatic other wise Anti-aromatic or Non-aromatic. For Anti-aromatic it must have \(4 \pi \mathrm{e}^{-}\)system. In all compound \(b c d\) is not aromatic compound and a is aromatic compound.
JEE Main-2019
GENERAL ORGANIC CHEMISTRY
232310
The increasing order of the reactivity of the following compounds towards electrophilic aromatic substitution reaction is:
1 III $<$ I $<$ II
2 I $<$ I $<$ II
3 III $<$ II $<$ I
4 I $<$ III $<$ II
Explanation:
(A): Reactivity of the compound due to electrophilic electron density of aromatic substitution reaction in the aromatic ring is given on the basis of hyperconjugation Inductive effect and mesomeric effect.
