231726
The most reactive towards electrophilic reagent is :
1
2
3
4
Explanation:
The most reactive towards electrophilic reagent is O-ceresol. The phenolic group increases the electron density on benzene ring through resonance with increases in electro density electrophilic reagent increases. The decreasing order of activating influence of substituent toward electrophilic agent. $\mathrm{NP}_{2}>-\mathrm{NHR}>-\mathrm{NH}_{2}>-\mathrm{OH}>-\mathrm{OR}>-\mathrm{NHCOR}>-\mathrm{Ph}>-\mathrm{R}$ Option $\mathrm{C}$ is correct because it has $+\mathrm{I}$ as well as $+\mathrm{R}$ group
Manipal 2016
GENERAL ORGANIC CHEMISTRY
231730
In pyrrole the electron density is maximum
1 2 and 4
2 3 and 4
3 2 and 4
4 2 and 5
Explanation:
To check maximum electron density of one pyrrole we have to make resonating structure. From the above we can see that electron density is maximum at 2 and 5 position.
NEET-II 2016
GENERAL ORGANIC CHEMISTRY
231731
The most stable carbocation, among the following is
Carbocation are those species which have positive charge on carbon atom. Stability of carbocation is directly proportional to the magnitude of charge $3^{\circ}>2^{\circ}>1^{\circ}$ In this case we determine with the help of $\alpha$-Hydrogen. More $\alpha$-Hydrogen has more stability. Hence, option (c) is more stable due to more $\alpha$ Hydrogen.
Odisa NEET-2020
GENERAL ORGANIC CHEMISTRY
231732
Which among the given molecules can exhibit tautomerism?
1 III only
2 Both I and III
3 Both I and II
4 Both II and III
Explanation:
(A) : Only III will show tautomerism because in I \& II $\alpha$ Hydrogen at bridge carbon can participate in tautomerism. Only III can show tautomerism.
231726
The most reactive towards electrophilic reagent is :
1
2
3
4
Explanation:
The most reactive towards electrophilic reagent is O-ceresol. The phenolic group increases the electron density on benzene ring through resonance with increases in electro density electrophilic reagent increases. The decreasing order of activating influence of substituent toward electrophilic agent. $\mathrm{NP}_{2}>-\mathrm{NHR}>-\mathrm{NH}_{2}>-\mathrm{OH}>-\mathrm{OR}>-\mathrm{NHCOR}>-\mathrm{Ph}>-\mathrm{R}$ Option $\mathrm{C}$ is correct because it has $+\mathrm{I}$ as well as $+\mathrm{R}$ group
Manipal 2016
GENERAL ORGANIC CHEMISTRY
231730
In pyrrole the electron density is maximum
1 2 and 4
2 3 and 4
3 2 and 4
4 2 and 5
Explanation:
To check maximum electron density of one pyrrole we have to make resonating structure. From the above we can see that electron density is maximum at 2 and 5 position.
NEET-II 2016
GENERAL ORGANIC CHEMISTRY
231731
The most stable carbocation, among the following is
Carbocation are those species which have positive charge on carbon atom. Stability of carbocation is directly proportional to the magnitude of charge $3^{\circ}>2^{\circ}>1^{\circ}$ In this case we determine with the help of $\alpha$-Hydrogen. More $\alpha$-Hydrogen has more stability. Hence, option (c) is more stable due to more $\alpha$ Hydrogen.
Odisa NEET-2020
GENERAL ORGANIC CHEMISTRY
231732
Which among the given molecules can exhibit tautomerism?
1 III only
2 Both I and III
3 Both I and II
4 Both II and III
Explanation:
(A) : Only III will show tautomerism because in I \& II $\alpha$ Hydrogen at bridge carbon can participate in tautomerism. Only III can show tautomerism.
231726
The most reactive towards electrophilic reagent is :
1
2
3
4
Explanation:
The most reactive towards electrophilic reagent is O-ceresol. The phenolic group increases the electron density on benzene ring through resonance with increases in electro density electrophilic reagent increases. The decreasing order of activating influence of substituent toward electrophilic agent. $\mathrm{NP}_{2}>-\mathrm{NHR}>-\mathrm{NH}_{2}>-\mathrm{OH}>-\mathrm{OR}>-\mathrm{NHCOR}>-\mathrm{Ph}>-\mathrm{R}$ Option $\mathrm{C}$ is correct because it has $+\mathrm{I}$ as well as $+\mathrm{R}$ group
Manipal 2016
GENERAL ORGANIC CHEMISTRY
231730
In pyrrole the electron density is maximum
1 2 and 4
2 3 and 4
3 2 and 4
4 2 and 5
Explanation:
To check maximum electron density of one pyrrole we have to make resonating structure. From the above we can see that electron density is maximum at 2 and 5 position.
NEET-II 2016
GENERAL ORGANIC CHEMISTRY
231731
The most stable carbocation, among the following is
Carbocation are those species which have positive charge on carbon atom. Stability of carbocation is directly proportional to the magnitude of charge $3^{\circ}>2^{\circ}>1^{\circ}$ In this case we determine with the help of $\alpha$-Hydrogen. More $\alpha$-Hydrogen has more stability. Hence, option (c) is more stable due to more $\alpha$ Hydrogen.
Odisa NEET-2020
GENERAL ORGANIC CHEMISTRY
231732
Which among the given molecules can exhibit tautomerism?
1 III only
2 Both I and III
3 Both I and II
4 Both II and III
Explanation:
(A) : Only III will show tautomerism because in I \& II $\alpha$ Hydrogen at bridge carbon can participate in tautomerism. Only III can show tautomerism.
231726
The most reactive towards electrophilic reagent is :
1
2
3
4
Explanation:
The most reactive towards electrophilic reagent is O-ceresol. The phenolic group increases the electron density on benzene ring through resonance with increases in electro density electrophilic reagent increases. The decreasing order of activating influence of substituent toward electrophilic agent. $\mathrm{NP}_{2}>-\mathrm{NHR}>-\mathrm{NH}_{2}>-\mathrm{OH}>-\mathrm{OR}>-\mathrm{NHCOR}>-\mathrm{Ph}>-\mathrm{R}$ Option $\mathrm{C}$ is correct because it has $+\mathrm{I}$ as well as $+\mathrm{R}$ group
Manipal 2016
GENERAL ORGANIC CHEMISTRY
231730
In pyrrole the electron density is maximum
1 2 and 4
2 3 and 4
3 2 and 4
4 2 and 5
Explanation:
To check maximum electron density of one pyrrole we have to make resonating structure. From the above we can see that electron density is maximum at 2 and 5 position.
NEET-II 2016
GENERAL ORGANIC CHEMISTRY
231731
The most stable carbocation, among the following is
Carbocation are those species which have positive charge on carbon atom. Stability of carbocation is directly proportional to the magnitude of charge $3^{\circ}>2^{\circ}>1^{\circ}$ In this case we determine with the help of $\alpha$-Hydrogen. More $\alpha$-Hydrogen has more stability. Hence, option (c) is more stable due to more $\alpha$ Hydrogen.
Odisa NEET-2020
GENERAL ORGANIC CHEMISTRY
231732
Which among the given molecules can exhibit tautomerism?
1 III only
2 Both I and III
3 Both I and II
4 Both II and III
Explanation:
(A) : Only III will show tautomerism because in I \& II $\alpha$ Hydrogen at bridge carbon can participate in tautomerism. Only III can show tautomerism.
