274367
Which of the following ions in aqueous solution in colourless?
1 $\mathrm{Ti}^{3+}$
2 $\mathrm{Ti}^{4+}$
3 $\mathrm{Co}^{2+}$
4 $\mathrm{Cu}^{2+}$
Explanation:
(B) : Electronic configuration of $\mathrm{Ti}^{4+}$ is $[\mathrm{Ar}] 3 \mathrm{~d}^{0}$ $4 s^{0}$. $\therefore \mathrm{Ti}^{4+}$ ions is ions in aqeous solution in colourless.
Assam-CEE-31.07.2022
COORDINATION COMPOUNDS
274370
The potassium ferrocyanide solution gives a prussian blue colour, when added to
1 $\mathrm{CoCl}_{3}$
2 $\mathrm{FeCl}_{2}$
3 $\mathrm{CoCl}_{2}$
4 $\mathrm{FeCl}_{3}$
Explanation:
(D) : $\mathrm{FeCl}_{3}+\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow \mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$ Prussian blue
JEE Main 2021
COORDINATION COMPOUNDS
274373
Correct increasing order for the wavelength of absorption in the visible region for the complexes of $\mathrm{Co}^{3+}$ is:
(A) : Strength of ligands attached with $\mathrm{Co}^{3+}$ ion is in the order of $\mathrm{CN}^{-}>\mathrm{NH}_{3}>\mathrm{H}_{2} \mathrm{O}>\mathrm{Cl}^{-}$. So, order of crystal field splitting energy (values of $\Delta_{0}$ ) will be in the same order. $\therefore$ Wavelength of absorbing light $\propto \frac{1}{\Delta_{\mathrm{o}}}$
AIIMS 26 May 2019 (Morning)
COORDINATION COMPOUNDS
274375
Homoleptic octahedral complexes of a metal ion $\mathrm{M}^{3+}$, with three monodentate ligands $\mathrm{L}_{1}, \mathrm{~L}_{2}$ and $L_{3}$ absorb wavelengths in the region of green, blue and red respectively. The increasing order of the ligand strength is
1 $\mathrm{L}_{1}<\mathrm{L}_{2}<\mathrm{L}_{3}$
2 $\mathrm{L}_{2}<\mathrm{L}_{1}<\mathrm{L}_{3}$
3 $\mathrm{L}_{3}<\mathrm{L}_{1}<\mathrm{L}_{2}$
4 $\mathrm{L}_{3}<\mathrm{L}_{2}<\mathrm{L}_{1}$
Explanation:
(C) : Stronger the ligand absorption of light having lower wavelength As $\lambda_{\mathrm{L}_{3}}>\lambda_{\mathrm{L}_{1}}>\lambda_{\mathrm{L}_{2}}$ Hence, ligand strength is $\mathrm{L}_{3}<\mathrm{L}_{1}<\mathrm{L}_{2}$
274367
Which of the following ions in aqueous solution in colourless?
1 $\mathrm{Ti}^{3+}$
2 $\mathrm{Ti}^{4+}$
3 $\mathrm{Co}^{2+}$
4 $\mathrm{Cu}^{2+}$
Explanation:
(B) : Electronic configuration of $\mathrm{Ti}^{4+}$ is $[\mathrm{Ar}] 3 \mathrm{~d}^{0}$ $4 s^{0}$. $\therefore \mathrm{Ti}^{4+}$ ions is ions in aqeous solution in colourless.
Assam-CEE-31.07.2022
COORDINATION COMPOUNDS
274370
The potassium ferrocyanide solution gives a prussian blue colour, when added to
1 $\mathrm{CoCl}_{3}$
2 $\mathrm{FeCl}_{2}$
3 $\mathrm{CoCl}_{2}$
4 $\mathrm{FeCl}_{3}$
Explanation:
(D) : $\mathrm{FeCl}_{3}+\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow \mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$ Prussian blue
JEE Main 2021
COORDINATION COMPOUNDS
274373
Correct increasing order for the wavelength of absorption in the visible region for the complexes of $\mathrm{Co}^{3+}$ is:
(A) : Strength of ligands attached with $\mathrm{Co}^{3+}$ ion is in the order of $\mathrm{CN}^{-}>\mathrm{NH}_{3}>\mathrm{H}_{2} \mathrm{O}>\mathrm{Cl}^{-}$. So, order of crystal field splitting energy (values of $\Delta_{0}$ ) will be in the same order. $\therefore$ Wavelength of absorbing light $\propto \frac{1}{\Delta_{\mathrm{o}}}$
AIIMS 26 May 2019 (Morning)
COORDINATION COMPOUNDS
274375
Homoleptic octahedral complexes of a metal ion $\mathrm{M}^{3+}$, with three monodentate ligands $\mathrm{L}_{1}, \mathrm{~L}_{2}$ and $L_{3}$ absorb wavelengths in the region of green, blue and red respectively. The increasing order of the ligand strength is
1 $\mathrm{L}_{1}<\mathrm{L}_{2}<\mathrm{L}_{3}$
2 $\mathrm{L}_{2}<\mathrm{L}_{1}<\mathrm{L}_{3}$
3 $\mathrm{L}_{3}<\mathrm{L}_{1}<\mathrm{L}_{2}$
4 $\mathrm{L}_{3}<\mathrm{L}_{2}<\mathrm{L}_{1}$
Explanation:
(C) : Stronger the ligand absorption of light having lower wavelength As $\lambda_{\mathrm{L}_{3}}>\lambda_{\mathrm{L}_{1}}>\lambda_{\mathrm{L}_{2}}$ Hence, ligand strength is $\mathrm{L}_{3}<\mathrm{L}_{1}<\mathrm{L}_{2}$
274367
Which of the following ions in aqueous solution in colourless?
1 $\mathrm{Ti}^{3+}$
2 $\mathrm{Ti}^{4+}$
3 $\mathrm{Co}^{2+}$
4 $\mathrm{Cu}^{2+}$
Explanation:
(B) : Electronic configuration of $\mathrm{Ti}^{4+}$ is $[\mathrm{Ar}] 3 \mathrm{~d}^{0}$ $4 s^{0}$. $\therefore \mathrm{Ti}^{4+}$ ions is ions in aqeous solution in colourless.
Assam-CEE-31.07.2022
COORDINATION COMPOUNDS
274370
The potassium ferrocyanide solution gives a prussian blue colour, when added to
1 $\mathrm{CoCl}_{3}$
2 $\mathrm{FeCl}_{2}$
3 $\mathrm{CoCl}_{2}$
4 $\mathrm{FeCl}_{3}$
Explanation:
(D) : $\mathrm{FeCl}_{3}+\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow \mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$ Prussian blue
JEE Main 2021
COORDINATION COMPOUNDS
274373
Correct increasing order for the wavelength of absorption in the visible region for the complexes of $\mathrm{Co}^{3+}$ is:
(A) : Strength of ligands attached with $\mathrm{Co}^{3+}$ ion is in the order of $\mathrm{CN}^{-}>\mathrm{NH}_{3}>\mathrm{H}_{2} \mathrm{O}>\mathrm{Cl}^{-}$. So, order of crystal field splitting energy (values of $\Delta_{0}$ ) will be in the same order. $\therefore$ Wavelength of absorbing light $\propto \frac{1}{\Delta_{\mathrm{o}}}$
AIIMS 26 May 2019 (Morning)
COORDINATION COMPOUNDS
274375
Homoleptic octahedral complexes of a metal ion $\mathrm{M}^{3+}$, with three monodentate ligands $\mathrm{L}_{1}, \mathrm{~L}_{2}$ and $L_{3}$ absorb wavelengths in the region of green, blue and red respectively. The increasing order of the ligand strength is
1 $\mathrm{L}_{1}<\mathrm{L}_{2}<\mathrm{L}_{3}$
2 $\mathrm{L}_{2}<\mathrm{L}_{1}<\mathrm{L}_{3}$
3 $\mathrm{L}_{3}<\mathrm{L}_{1}<\mathrm{L}_{2}$
4 $\mathrm{L}_{3}<\mathrm{L}_{2}<\mathrm{L}_{1}$
Explanation:
(C) : Stronger the ligand absorption of light having lower wavelength As $\lambda_{\mathrm{L}_{3}}>\lambda_{\mathrm{L}_{1}}>\lambda_{\mathrm{L}_{2}}$ Hence, ligand strength is $\mathrm{L}_{3}<\mathrm{L}_{1}<\mathrm{L}_{2}$
274367
Which of the following ions in aqueous solution in colourless?
1 $\mathrm{Ti}^{3+}$
2 $\mathrm{Ti}^{4+}$
3 $\mathrm{Co}^{2+}$
4 $\mathrm{Cu}^{2+}$
Explanation:
(B) : Electronic configuration of $\mathrm{Ti}^{4+}$ is $[\mathrm{Ar}] 3 \mathrm{~d}^{0}$ $4 s^{0}$. $\therefore \mathrm{Ti}^{4+}$ ions is ions in aqeous solution in colourless.
Assam-CEE-31.07.2022
COORDINATION COMPOUNDS
274370
The potassium ferrocyanide solution gives a prussian blue colour, when added to
1 $\mathrm{CoCl}_{3}$
2 $\mathrm{FeCl}_{2}$
3 $\mathrm{CoCl}_{2}$
4 $\mathrm{FeCl}_{3}$
Explanation:
(D) : $\mathrm{FeCl}_{3}+\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \rightarrow \mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$ Prussian blue
JEE Main 2021
COORDINATION COMPOUNDS
274373
Correct increasing order for the wavelength of absorption in the visible region for the complexes of $\mathrm{Co}^{3+}$ is:
(A) : Strength of ligands attached with $\mathrm{Co}^{3+}$ ion is in the order of $\mathrm{CN}^{-}>\mathrm{NH}_{3}>\mathrm{H}_{2} \mathrm{O}>\mathrm{Cl}^{-}$. So, order of crystal field splitting energy (values of $\Delta_{0}$ ) will be in the same order. $\therefore$ Wavelength of absorbing light $\propto \frac{1}{\Delta_{\mathrm{o}}}$
AIIMS 26 May 2019 (Morning)
COORDINATION COMPOUNDS
274375
Homoleptic octahedral complexes of a metal ion $\mathrm{M}^{3+}$, with three monodentate ligands $\mathrm{L}_{1}, \mathrm{~L}_{2}$ and $L_{3}$ absorb wavelengths in the region of green, blue and red respectively. The increasing order of the ligand strength is
1 $\mathrm{L}_{1}<\mathrm{L}_{2}<\mathrm{L}_{3}$
2 $\mathrm{L}_{2}<\mathrm{L}_{1}<\mathrm{L}_{3}$
3 $\mathrm{L}_{3}<\mathrm{L}_{1}<\mathrm{L}_{2}$
4 $\mathrm{L}_{3}<\mathrm{L}_{2}<\mathrm{L}_{1}$
Explanation:
(C) : Stronger the ligand absorption of light having lower wavelength As $\lambda_{\mathrm{L}_{3}}>\lambda_{\mathrm{L}_{1}}>\lambda_{\mathrm{L}_{2}}$ Hence, ligand strength is $\mathrm{L}_{3}<\mathrm{L}_{1}<\mathrm{L}_{2}$
