274349
The ratio of anion radius to cation radius of a crystal is $10: 9.3$. Then, the coordination number of the cation in the crystal is
1 6
2 8
3 2
4 4
Explanation:
(D) : Given that, the ratio of anion to cation radius $=10: 9.3$ $\therefore$ The ratio of cation to anion radius is $=\frac{9.3}{10}=0.93$ Since, the ratio of cation to anion radius lie between 0.732 to 1.00 , thus the co-ordination number of cation is 8.
AP EAMCET- (Engg.) - 2010
COORDINATION COMPOUNDS
274353
The effective atomic number (EAN) of central metal atom in $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$ is [at. No. of $\mathbf{C o}=27]$
1 34
2 35
3 36
4 32
Explanation:
(C) :The given complex is $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$. Effective atomic number $(\mathrm{EAN})=\mathrm{Z}$-oxidation number $+2 \times$ co-ordinationa number $\mathrm{EAN}=27-3+2 \times 6$ $=27-3+12$ $=36$
COMEDK 2012
COORDINATION COMPOUNDS
274358
The tetrahedral complexes have coordination number
1 3
2 6
3 4
4 8
Explanation:
(C) : The tetrahedral complexs have co-ordination number 4 because the central metal attacted with the four donor atom or ligands.
J and K CET-(2007)
COORDINATION COMPOUNDS
274359
The oxidation number of cobalt in $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_{4}\right]$ is
1 +1
2 +3
3 -1
4 -3
Explanation:
(C) : $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_{4}\right]$ Let, $\mathrm{x}$ be the oxidation state of $\mathrm{Co}$. $\therefore+1+\mathrm{x}+4 \times 0=0$ $\mathrm{x}=-1$ Thus, the oxidation state of the $\mathrm{Co}$ is -1
274349
The ratio of anion radius to cation radius of a crystal is $10: 9.3$. Then, the coordination number of the cation in the crystal is
1 6
2 8
3 2
4 4
Explanation:
(D) : Given that, the ratio of anion to cation radius $=10: 9.3$ $\therefore$ The ratio of cation to anion radius is $=\frac{9.3}{10}=0.93$ Since, the ratio of cation to anion radius lie between 0.732 to 1.00 , thus the co-ordination number of cation is 8.
AP EAMCET- (Engg.) - 2010
COORDINATION COMPOUNDS
274353
The effective atomic number (EAN) of central metal atom in $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$ is [at. No. of $\mathbf{C o}=27]$
1 34
2 35
3 36
4 32
Explanation:
(C) :The given complex is $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$. Effective atomic number $(\mathrm{EAN})=\mathrm{Z}$-oxidation number $+2 \times$ co-ordinationa number $\mathrm{EAN}=27-3+2 \times 6$ $=27-3+12$ $=36$
COMEDK 2012
COORDINATION COMPOUNDS
274358
The tetrahedral complexes have coordination number
1 3
2 6
3 4
4 8
Explanation:
(C) : The tetrahedral complexs have co-ordination number 4 because the central metal attacted with the four donor atom or ligands.
J and K CET-(2007)
COORDINATION COMPOUNDS
274359
The oxidation number of cobalt in $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_{4}\right]$ is
1 +1
2 +3
3 -1
4 -3
Explanation:
(C) : $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_{4}\right]$ Let, $\mathrm{x}$ be the oxidation state of $\mathrm{Co}$. $\therefore+1+\mathrm{x}+4 \times 0=0$ $\mathrm{x}=-1$ Thus, the oxidation state of the $\mathrm{Co}$ is -1
274349
The ratio of anion radius to cation radius of a crystal is $10: 9.3$. Then, the coordination number of the cation in the crystal is
1 6
2 8
3 2
4 4
Explanation:
(D) : Given that, the ratio of anion to cation radius $=10: 9.3$ $\therefore$ The ratio of cation to anion radius is $=\frac{9.3}{10}=0.93$ Since, the ratio of cation to anion radius lie between 0.732 to 1.00 , thus the co-ordination number of cation is 8.
AP EAMCET- (Engg.) - 2010
COORDINATION COMPOUNDS
274353
The effective atomic number (EAN) of central metal atom in $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$ is [at. No. of $\mathbf{C o}=27]$
1 34
2 35
3 36
4 32
Explanation:
(C) :The given complex is $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$. Effective atomic number $(\mathrm{EAN})=\mathrm{Z}$-oxidation number $+2 \times$ co-ordinationa number $\mathrm{EAN}=27-3+2 \times 6$ $=27-3+12$ $=36$
COMEDK 2012
COORDINATION COMPOUNDS
274358
The tetrahedral complexes have coordination number
1 3
2 6
3 4
4 8
Explanation:
(C) : The tetrahedral complexs have co-ordination number 4 because the central metal attacted with the four donor atom or ligands.
J and K CET-(2007)
COORDINATION COMPOUNDS
274359
The oxidation number of cobalt in $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_{4}\right]$ is
1 +1
2 +3
3 -1
4 -3
Explanation:
(C) : $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_{4}\right]$ Let, $\mathrm{x}$ be the oxidation state of $\mathrm{Co}$. $\therefore+1+\mathrm{x}+4 \times 0=0$ $\mathrm{x}=-1$ Thus, the oxidation state of the $\mathrm{Co}$ is -1
274349
The ratio of anion radius to cation radius of a crystal is $10: 9.3$. Then, the coordination number of the cation in the crystal is
1 6
2 8
3 2
4 4
Explanation:
(D) : Given that, the ratio of anion to cation radius $=10: 9.3$ $\therefore$ The ratio of cation to anion radius is $=\frac{9.3}{10}=0.93$ Since, the ratio of cation to anion radius lie between 0.732 to 1.00 , thus the co-ordination number of cation is 8.
AP EAMCET- (Engg.) - 2010
COORDINATION COMPOUNDS
274353
The effective atomic number (EAN) of central metal atom in $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$ is [at. No. of $\mathbf{C o}=27]$
1 34
2 35
3 36
4 32
Explanation:
(C) :The given complex is $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$. Effective atomic number $(\mathrm{EAN})=\mathrm{Z}$-oxidation number $+2 \times$ co-ordinationa number $\mathrm{EAN}=27-3+2 \times 6$ $=27-3+12$ $=36$
COMEDK 2012
COORDINATION COMPOUNDS
274358
The tetrahedral complexes have coordination number
1 3
2 6
3 4
4 8
Explanation:
(C) : The tetrahedral complexs have co-ordination number 4 because the central metal attacted with the four donor atom or ligands.
J and K CET-(2007)
COORDINATION COMPOUNDS
274359
The oxidation number of cobalt in $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_{4}\right]$ is
1 +1
2 +3
3 -1
4 -3
Explanation:
(C) : $\mathrm{K}\left[\mathrm{Co}(\mathrm{CO})_{4}\right]$ Let, $\mathrm{x}$ be the oxidation state of $\mathrm{Co}$. $\therefore+1+\mathrm{x}+4 \times 0=0$ $\mathrm{x}=-1$ Thus, the oxidation state of the $\mathrm{Co}$ is -1
