274360
The oxidation state of chromium in chromium trioxide is
1 +3
2 +4
3 +5
4 +6
Explanation:
(D) : The chemical formula of chromium oxide is $\mathrm{CrO}_{3}$. The oxidation state of $\mathrm{Cr}$ is - $\therefore \mathrm{x}+3(-2)=0$ $\mathrm{x}=+6$ Hence, the oxidation state of $\mathrm{Cr}$ is +6 .
J and K CET-(2007)
COORDINATION COMPOUNDS
274335
Which of the following complex ion is the most stable?
(A) : The complex compound which has the strong field ligand, are more stable in nature. Here, $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ has the $\mathrm{NH}_{3}$ ligand which is act as SFL in $\mathrm{Co}^{3+}$.
GUJCET-2019
COORDINATION COMPOUNDS
274339
In case of ring rest of $\mathrm{NO}_{3}^{-}$ion, the complex formed has formula $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}_{3} \mathrm{SO}_{4}\right.$. The oxidation state of iron in the complex is
1 +1
2 +2
3 +3
4 +6
Explanation:
(A) : The oxidation state of $\mathrm{Fe}$ in Brown ring is +1 . The complex formed is $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right] \mathrm{SO}_{4}$. The charge on anion is-2 Hence, charge on cation complex has to be +2 as ring is electrically neutral. The charge on $\mathrm{Fe}$ on calculation comes as +2 . But as the electron transfer takes place from $\mathrm{NO}$ to $\mathrm{Fe}$. Hence, $\mathrm{NO}$ and $\mathrm{Fe}$ acquire a charge of +1 each.
CG PET -2017
COORDINATION COMPOUNDS
274351
Aluminium reacts with $\mathrm{NaOH}$ and forms compound ' $X$ '. If the coordination number of aluminium is 6 , the correct formula of $\mathrm{X}$ is
(C) : Aluminum reacts with $\mathrm{NaOH}$ and forms the sodium meta aluminates $\left(\mathrm{NaAlO}_{3}\right)$. The complex is soluble in water and forms the $\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}(\mathrm{OH})_{4}\right]$ Number of Al in complex is 6 .
274360
The oxidation state of chromium in chromium trioxide is
1 +3
2 +4
3 +5
4 +6
Explanation:
(D) : The chemical formula of chromium oxide is $\mathrm{CrO}_{3}$. The oxidation state of $\mathrm{Cr}$ is - $\therefore \mathrm{x}+3(-2)=0$ $\mathrm{x}=+6$ Hence, the oxidation state of $\mathrm{Cr}$ is +6 .
J and K CET-(2007)
COORDINATION COMPOUNDS
274335
Which of the following complex ion is the most stable?
(A) : The complex compound which has the strong field ligand, are more stable in nature. Here, $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ has the $\mathrm{NH}_{3}$ ligand which is act as SFL in $\mathrm{Co}^{3+}$.
GUJCET-2019
COORDINATION COMPOUNDS
274339
In case of ring rest of $\mathrm{NO}_{3}^{-}$ion, the complex formed has formula $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}_{3} \mathrm{SO}_{4}\right.$. The oxidation state of iron in the complex is
1 +1
2 +2
3 +3
4 +6
Explanation:
(A) : The oxidation state of $\mathrm{Fe}$ in Brown ring is +1 . The complex formed is $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right] \mathrm{SO}_{4}$. The charge on anion is-2 Hence, charge on cation complex has to be +2 as ring is electrically neutral. The charge on $\mathrm{Fe}$ on calculation comes as +2 . But as the electron transfer takes place from $\mathrm{NO}$ to $\mathrm{Fe}$. Hence, $\mathrm{NO}$ and $\mathrm{Fe}$ acquire a charge of +1 each.
CG PET -2017
COORDINATION COMPOUNDS
274351
Aluminium reacts with $\mathrm{NaOH}$ and forms compound ' $X$ '. If the coordination number of aluminium is 6 , the correct formula of $\mathrm{X}$ is
(C) : Aluminum reacts with $\mathrm{NaOH}$ and forms the sodium meta aluminates $\left(\mathrm{NaAlO}_{3}\right)$. The complex is soluble in water and forms the $\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}(\mathrm{OH})_{4}\right]$ Number of Al in complex is 6 .
274360
The oxidation state of chromium in chromium trioxide is
1 +3
2 +4
3 +5
4 +6
Explanation:
(D) : The chemical formula of chromium oxide is $\mathrm{CrO}_{3}$. The oxidation state of $\mathrm{Cr}$ is - $\therefore \mathrm{x}+3(-2)=0$ $\mathrm{x}=+6$ Hence, the oxidation state of $\mathrm{Cr}$ is +6 .
J and K CET-(2007)
COORDINATION COMPOUNDS
274335
Which of the following complex ion is the most stable?
(A) : The complex compound which has the strong field ligand, are more stable in nature. Here, $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ has the $\mathrm{NH}_{3}$ ligand which is act as SFL in $\mathrm{Co}^{3+}$.
GUJCET-2019
COORDINATION COMPOUNDS
274339
In case of ring rest of $\mathrm{NO}_{3}^{-}$ion, the complex formed has formula $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}_{3} \mathrm{SO}_{4}\right.$. The oxidation state of iron in the complex is
1 +1
2 +2
3 +3
4 +6
Explanation:
(A) : The oxidation state of $\mathrm{Fe}$ in Brown ring is +1 . The complex formed is $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right] \mathrm{SO}_{4}$. The charge on anion is-2 Hence, charge on cation complex has to be +2 as ring is electrically neutral. The charge on $\mathrm{Fe}$ on calculation comes as +2 . But as the electron transfer takes place from $\mathrm{NO}$ to $\mathrm{Fe}$. Hence, $\mathrm{NO}$ and $\mathrm{Fe}$ acquire a charge of +1 each.
CG PET -2017
COORDINATION COMPOUNDS
274351
Aluminium reacts with $\mathrm{NaOH}$ and forms compound ' $X$ '. If the coordination number of aluminium is 6 , the correct formula of $\mathrm{X}$ is
(C) : Aluminum reacts with $\mathrm{NaOH}$ and forms the sodium meta aluminates $\left(\mathrm{NaAlO}_{3}\right)$. The complex is soluble in water and forms the $\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}(\mathrm{OH})_{4}\right]$ Number of Al in complex is 6 .
274360
The oxidation state of chromium in chromium trioxide is
1 +3
2 +4
3 +5
4 +6
Explanation:
(D) : The chemical formula of chromium oxide is $\mathrm{CrO}_{3}$. The oxidation state of $\mathrm{Cr}$ is - $\therefore \mathrm{x}+3(-2)=0$ $\mathrm{x}=+6$ Hence, the oxidation state of $\mathrm{Cr}$ is +6 .
J and K CET-(2007)
COORDINATION COMPOUNDS
274335
Which of the following complex ion is the most stable?
(A) : The complex compound which has the strong field ligand, are more stable in nature. Here, $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ has the $\mathrm{NH}_{3}$ ligand which is act as SFL in $\mathrm{Co}^{3+}$.
GUJCET-2019
COORDINATION COMPOUNDS
274339
In case of ring rest of $\mathrm{NO}_{3}^{-}$ion, the complex formed has formula $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}_{3} \mathrm{SO}_{4}\right.$. The oxidation state of iron in the complex is
1 +1
2 +2
3 +3
4 +6
Explanation:
(A) : The oxidation state of $\mathrm{Fe}$ in Brown ring is +1 . The complex formed is $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right] \mathrm{SO}_{4}$. The charge on anion is-2 Hence, charge on cation complex has to be +2 as ring is electrically neutral. The charge on $\mathrm{Fe}$ on calculation comes as +2 . But as the electron transfer takes place from $\mathrm{NO}$ to $\mathrm{Fe}$. Hence, $\mathrm{NO}$ and $\mathrm{Fe}$ acquire a charge of +1 each.
CG PET -2017
COORDINATION COMPOUNDS
274351
Aluminium reacts with $\mathrm{NaOH}$ and forms compound ' $X$ '. If the coordination number of aluminium is 6 , the correct formula of $\mathrm{X}$ is
(C) : Aluminum reacts with $\mathrm{NaOH}$ and forms the sodium meta aluminates $\left(\mathrm{NaAlO}_{3}\right)$. The complex is soluble in water and forms the $\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}(\mathrm{OH})_{4}\right]$ Number of Al in complex is 6 .
