274310
$\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ is a $3 d^{2}$ system, the value of crystal field stabilization energy decreases by
1 $4 \times 10^{-1} \Delta_{0}$
2 $4.0 \Delta_{0}$
3 $8.0 \Delta_{0}$
4 $8 \times 10^{-1} \Delta_{0}$
Explanation:
(D) : The given compound is $\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$. The oxidation number of metal is +2 . The electronic configuration of $\mathrm{Ti}^{2+}$ is $[\mathrm{Ar}] 3 \mathrm{~d}^{2}$. Hence the splitting of d-orbital can be written as- CFSE $=-0.4 \mathrm{~N}_{+2 \mathrm{~g}}+0.6 \mathrm{Neg}$ $\mathrm{CFSE}=-0.4 \times 2+0.6 \times 0$ $\mathrm{CFSE}=-0.8$ or $\mathrm{CFSE}=8 \times 10^{-1} \Delta$ 。
COMEDK 2015]**
COORDINATION COMPOUNDS
274313
In which of the following octahedral complexes of Co (At. No. 27), will the magnitude of $\Delta_{0}$ be the highest?
(A) : The given compounds are : (i) $\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}$ (ii) $\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ (iii) $\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ (iv) $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ The crystal field stabilisation is also depends upon the spectrochemical series i.e. which type of ligand attached to the central metal atom. As we know that $\mathrm{CN}$ is the strong field ligand and extra pairing occurred in the $t_{2 g}$ orbital. So, the CFSE will be more.
VITEEE- 2011
COORDINATION COMPOUNDS
274315
Crystal field splitting energy for high spin $d^{4}$ octahedral complex is
1 $-1.2 \Delta_{\mathrm{o}}$
2 $-0.6 \Delta_{\mathrm{o}}$
3 $-0.8 \Delta_{\mathrm{o}}$
4 $-1.6 \Delta_{\mathrm{o}}$
Explanation:
(B) : The given $\mathrm{d}=$ orbital is $\mathrm{d}^{4}$ for high spin. CFSE $=-0.4 \Delta_{\circ} \mathrm{N}_{\mathrm{t}_{2 \mathrm{~g}}}+0.6 \Delta_{\mathrm{o}} \mathrm{N}_{\mathrm{e}_{\mathrm{g}}}$ CFSE $=-0.4 \Delta_{\circ} \times 3+0.6 \Delta_{\circ} \times 1$ $\mathrm{CFSE}=-1.2 \Delta_{\circ}+0.6 \Delta$ 。 $\mathrm{CFSE}=-0.6 \Delta$ 。
Karnataka NEET 2013
COORDINATION COMPOUNDS
274316
Assertion : Copper sulphate solution is not stored in zinc vessel. Reason: Zinc forms complex with $\mathrm{CuSO}_{4}$.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 I the Assertion is correct but Reason is incorrect.
4 I both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
(A) : Copper sulphate solution is not stored in zinc vessel because zinc is more reactive than copper, therefore reaction will be take place and forms the zinc sulphate. The reaction is illustrated below - $\mathrm{Zn}+\mathrm{CuSO}_{4} \longrightarrow \mathrm{ZnSO}_{4}+\mathrm{Cu}$
274310
$\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ is a $3 d^{2}$ system, the value of crystal field stabilization energy decreases by
1 $4 \times 10^{-1} \Delta_{0}$
2 $4.0 \Delta_{0}$
3 $8.0 \Delta_{0}$
4 $8 \times 10^{-1} \Delta_{0}$
Explanation:
(D) : The given compound is $\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$. The oxidation number of metal is +2 . The electronic configuration of $\mathrm{Ti}^{2+}$ is $[\mathrm{Ar}] 3 \mathrm{~d}^{2}$. Hence the splitting of d-orbital can be written as- CFSE $=-0.4 \mathrm{~N}_{+2 \mathrm{~g}}+0.6 \mathrm{Neg}$ $\mathrm{CFSE}=-0.4 \times 2+0.6 \times 0$ $\mathrm{CFSE}=-0.8$ or $\mathrm{CFSE}=8 \times 10^{-1} \Delta$ 。
COMEDK 2015]**
COORDINATION COMPOUNDS
274313
In which of the following octahedral complexes of Co (At. No. 27), will the magnitude of $\Delta_{0}$ be the highest?
(A) : The given compounds are : (i) $\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}$ (ii) $\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ (iii) $\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ (iv) $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ The crystal field stabilisation is also depends upon the spectrochemical series i.e. which type of ligand attached to the central metal atom. As we know that $\mathrm{CN}$ is the strong field ligand and extra pairing occurred in the $t_{2 g}$ orbital. So, the CFSE will be more.
VITEEE- 2011
COORDINATION COMPOUNDS
274315
Crystal field splitting energy for high spin $d^{4}$ octahedral complex is
1 $-1.2 \Delta_{\mathrm{o}}$
2 $-0.6 \Delta_{\mathrm{o}}$
3 $-0.8 \Delta_{\mathrm{o}}$
4 $-1.6 \Delta_{\mathrm{o}}$
Explanation:
(B) : The given $\mathrm{d}=$ orbital is $\mathrm{d}^{4}$ for high spin. CFSE $=-0.4 \Delta_{\circ} \mathrm{N}_{\mathrm{t}_{2 \mathrm{~g}}}+0.6 \Delta_{\mathrm{o}} \mathrm{N}_{\mathrm{e}_{\mathrm{g}}}$ CFSE $=-0.4 \Delta_{\circ} \times 3+0.6 \Delta_{\circ} \times 1$ $\mathrm{CFSE}=-1.2 \Delta_{\circ}+0.6 \Delta$ 。 $\mathrm{CFSE}=-0.6 \Delta$ 。
Karnataka NEET 2013
COORDINATION COMPOUNDS
274316
Assertion : Copper sulphate solution is not stored in zinc vessel. Reason: Zinc forms complex with $\mathrm{CuSO}_{4}$.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 I the Assertion is correct but Reason is incorrect.
4 I both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
(A) : Copper sulphate solution is not stored in zinc vessel because zinc is more reactive than copper, therefore reaction will be take place and forms the zinc sulphate. The reaction is illustrated below - $\mathrm{Zn}+\mathrm{CuSO}_{4} \longrightarrow \mathrm{ZnSO}_{4}+\mathrm{Cu}$
NEET Test Series from KOTA - 10 Papers In MS WORD
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COORDINATION COMPOUNDS
274310
$\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ is a $3 d^{2}$ system, the value of crystal field stabilization energy decreases by
1 $4 \times 10^{-1} \Delta_{0}$
2 $4.0 \Delta_{0}$
3 $8.0 \Delta_{0}$
4 $8 \times 10^{-1} \Delta_{0}$
Explanation:
(D) : The given compound is $\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$. The oxidation number of metal is +2 . The electronic configuration of $\mathrm{Ti}^{2+}$ is $[\mathrm{Ar}] 3 \mathrm{~d}^{2}$. Hence the splitting of d-orbital can be written as- CFSE $=-0.4 \mathrm{~N}_{+2 \mathrm{~g}}+0.6 \mathrm{Neg}$ $\mathrm{CFSE}=-0.4 \times 2+0.6 \times 0$ $\mathrm{CFSE}=-0.8$ or $\mathrm{CFSE}=8 \times 10^{-1} \Delta$ 。
COMEDK 2015]**
COORDINATION COMPOUNDS
274313
In which of the following octahedral complexes of Co (At. No. 27), will the magnitude of $\Delta_{0}$ be the highest?
(A) : The given compounds are : (i) $\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}$ (ii) $\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ (iii) $\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ (iv) $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ The crystal field stabilisation is also depends upon the spectrochemical series i.e. which type of ligand attached to the central metal atom. As we know that $\mathrm{CN}$ is the strong field ligand and extra pairing occurred in the $t_{2 g}$ orbital. So, the CFSE will be more.
VITEEE- 2011
COORDINATION COMPOUNDS
274315
Crystal field splitting energy for high spin $d^{4}$ octahedral complex is
1 $-1.2 \Delta_{\mathrm{o}}$
2 $-0.6 \Delta_{\mathrm{o}}$
3 $-0.8 \Delta_{\mathrm{o}}$
4 $-1.6 \Delta_{\mathrm{o}}$
Explanation:
(B) : The given $\mathrm{d}=$ orbital is $\mathrm{d}^{4}$ for high spin. CFSE $=-0.4 \Delta_{\circ} \mathrm{N}_{\mathrm{t}_{2 \mathrm{~g}}}+0.6 \Delta_{\mathrm{o}} \mathrm{N}_{\mathrm{e}_{\mathrm{g}}}$ CFSE $=-0.4 \Delta_{\circ} \times 3+0.6 \Delta_{\circ} \times 1$ $\mathrm{CFSE}=-1.2 \Delta_{\circ}+0.6 \Delta$ 。 $\mathrm{CFSE}=-0.6 \Delta$ 。
Karnataka NEET 2013
COORDINATION COMPOUNDS
274316
Assertion : Copper sulphate solution is not stored in zinc vessel. Reason: Zinc forms complex with $\mathrm{CuSO}_{4}$.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 I the Assertion is correct but Reason is incorrect.
4 I both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
(A) : Copper sulphate solution is not stored in zinc vessel because zinc is more reactive than copper, therefore reaction will be take place and forms the zinc sulphate. The reaction is illustrated below - $\mathrm{Zn}+\mathrm{CuSO}_{4} \longrightarrow \mathrm{ZnSO}_{4}+\mathrm{Cu}$
274310
$\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ is a $3 d^{2}$ system, the value of crystal field stabilization energy decreases by
1 $4 \times 10^{-1} \Delta_{0}$
2 $4.0 \Delta_{0}$
3 $8.0 \Delta_{0}$
4 $8 \times 10^{-1} \Delta_{0}$
Explanation:
(D) : The given compound is $\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$. The oxidation number of metal is +2 . The electronic configuration of $\mathrm{Ti}^{2+}$ is $[\mathrm{Ar}] 3 \mathrm{~d}^{2}$. Hence the splitting of d-orbital can be written as- CFSE $=-0.4 \mathrm{~N}_{+2 \mathrm{~g}}+0.6 \mathrm{Neg}$ $\mathrm{CFSE}=-0.4 \times 2+0.6 \times 0$ $\mathrm{CFSE}=-0.8$ or $\mathrm{CFSE}=8 \times 10^{-1} \Delta$ 。
COMEDK 2015]**
COORDINATION COMPOUNDS
274313
In which of the following octahedral complexes of Co (At. No. 27), will the magnitude of $\Delta_{0}$ be the highest?
(A) : The given compounds are : (i) $\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}$ (ii) $\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}$ (iii) $\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ (iv) $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ The crystal field stabilisation is also depends upon the spectrochemical series i.e. which type of ligand attached to the central metal atom. As we know that $\mathrm{CN}$ is the strong field ligand and extra pairing occurred in the $t_{2 g}$ orbital. So, the CFSE will be more.
VITEEE- 2011
COORDINATION COMPOUNDS
274315
Crystal field splitting energy for high spin $d^{4}$ octahedral complex is
1 $-1.2 \Delta_{\mathrm{o}}$
2 $-0.6 \Delta_{\mathrm{o}}$
3 $-0.8 \Delta_{\mathrm{o}}$
4 $-1.6 \Delta_{\mathrm{o}}$
Explanation:
(B) : The given $\mathrm{d}=$ orbital is $\mathrm{d}^{4}$ for high spin. CFSE $=-0.4 \Delta_{\circ} \mathrm{N}_{\mathrm{t}_{2 \mathrm{~g}}}+0.6 \Delta_{\mathrm{o}} \mathrm{N}_{\mathrm{e}_{\mathrm{g}}}$ CFSE $=-0.4 \Delta_{\circ} \times 3+0.6 \Delta_{\circ} \times 1$ $\mathrm{CFSE}=-1.2 \Delta_{\circ}+0.6 \Delta$ 。 $\mathrm{CFSE}=-0.6 \Delta$ 。
Karnataka NEET 2013
COORDINATION COMPOUNDS
274316
Assertion : Copper sulphate solution is not stored in zinc vessel. Reason: Zinc forms complex with $\mathrm{CuSO}_{4}$.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 I the Assertion is correct but Reason is incorrect.
4 I both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
(A) : Copper sulphate solution is not stored in zinc vessel because zinc is more reactive than copper, therefore reaction will be take place and forms the zinc sulphate. The reaction is illustrated below - $\mathrm{Zn}+\mathrm{CuSO}_{4} \longrightarrow \mathrm{ZnSO}_{4}+\mathrm{Cu}$
