274301
Which combines with $\mathrm{Fe}^{2+}$ to form brown complex?
1 $\mathrm{NO}$
2 $\mathrm{N}_{2} \mathrm{O}$
3 $\mathrm{N}_{2} \mathrm{O}_{3}$
4 $\mathrm{N}_{2} \mathrm{O}_{5}$
Explanation:
(A) : A common nitrate test is also known as the brown ring test. $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}+\mathrm{NO} \longrightarrow\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right]^{2+}+\mathrm{H}_{2} \mathrm{O}$ Thus, $\mathrm{NO}$ combines with $\mathrm{Fe}^{2+}$ to form the brown complex.
CG PET -2019
COORDINATION COMPOUNDS
274306
Which one of the following statement is correct for $\mathrm{d}^{\mathbf{4}}$ ions [ $\mathrm{P}=$ pairing energy]
1 When $\Delta_{\mathrm{o}}>\mathrm{P}$, low-spin complex form
2 When $\Delta_{\mathrm{o}}<\mathrm{P}$, low-spin complex form
3 When $\Delta_{0}>$ P, high-spin complex form
4 When $\Delta_{\mathrm{o}}<\mathrm{P}$, both high-spin and low-spin complexes form
Explanation:
(A) : For When value of $\Delta_{o}$ is greater than pairing energy pairing of electron takes place hence low-spin complexes are formed.
TS EAMCET-2017
COORDINATION COMPOUNDS
274307
The correct electronic configuration of $d^{4}$ in low spin state according to Crystal Field Splitting theory is
(C) : According to the spectrochemical series, the ascending order of ligand field strength of the ligands are- $$ \mathrm{I}^{-}<\mathrm{F}^{-}<\mathrm{H}_{2} \mathrm{O}^{-}<\mathrm{CN}^{-}<\mathrm{CO} $$
NEET Test Series from KOTA - 10 Papers In MS WORD
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COORDINATION COMPOUNDS
274301
Which combines with $\mathrm{Fe}^{2+}$ to form brown complex?
1 $\mathrm{NO}$
2 $\mathrm{N}_{2} \mathrm{O}$
3 $\mathrm{N}_{2} \mathrm{O}_{3}$
4 $\mathrm{N}_{2} \mathrm{O}_{5}$
Explanation:
(A) : A common nitrate test is also known as the brown ring test. $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}+\mathrm{NO} \longrightarrow\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right]^{2+}+\mathrm{H}_{2} \mathrm{O}$ Thus, $\mathrm{NO}$ combines with $\mathrm{Fe}^{2+}$ to form the brown complex.
CG PET -2019
COORDINATION COMPOUNDS
274306
Which one of the following statement is correct for $\mathrm{d}^{\mathbf{4}}$ ions [ $\mathrm{P}=$ pairing energy]
1 When $\Delta_{\mathrm{o}}>\mathrm{P}$, low-spin complex form
2 When $\Delta_{\mathrm{o}}<\mathrm{P}$, low-spin complex form
3 When $\Delta_{0}>$ P, high-spin complex form
4 When $\Delta_{\mathrm{o}}<\mathrm{P}$, both high-spin and low-spin complexes form
Explanation:
(A) : For When value of $\Delta_{o}$ is greater than pairing energy pairing of electron takes place hence low-spin complexes are formed.
TS EAMCET-2017
COORDINATION COMPOUNDS
274307
The correct electronic configuration of $d^{4}$ in low spin state according to Crystal Field Splitting theory is
(C) : According to the spectrochemical series, the ascending order of ligand field strength of the ligands are- $$ \mathrm{I}^{-}<\mathrm{F}^{-}<\mathrm{H}_{2} \mathrm{O}^{-}<\mathrm{CN}^{-}<\mathrm{CO} $$
274301
Which combines with $\mathrm{Fe}^{2+}$ to form brown complex?
1 $\mathrm{NO}$
2 $\mathrm{N}_{2} \mathrm{O}$
3 $\mathrm{N}_{2} \mathrm{O}_{3}$
4 $\mathrm{N}_{2} \mathrm{O}_{5}$
Explanation:
(A) : A common nitrate test is also known as the brown ring test. $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}+\mathrm{NO} \longrightarrow\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right]^{2+}+\mathrm{H}_{2} \mathrm{O}$ Thus, $\mathrm{NO}$ combines with $\mathrm{Fe}^{2+}$ to form the brown complex.
CG PET -2019
COORDINATION COMPOUNDS
274306
Which one of the following statement is correct for $\mathrm{d}^{\mathbf{4}}$ ions [ $\mathrm{P}=$ pairing energy]
1 When $\Delta_{\mathrm{o}}>\mathrm{P}$, low-spin complex form
2 When $\Delta_{\mathrm{o}}<\mathrm{P}$, low-spin complex form
3 When $\Delta_{0}>$ P, high-spin complex form
4 When $\Delta_{\mathrm{o}}<\mathrm{P}$, both high-spin and low-spin complexes form
Explanation:
(A) : For When value of $\Delta_{o}$ is greater than pairing energy pairing of electron takes place hence low-spin complexes are formed.
TS EAMCET-2017
COORDINATION COMPOUNDS
274307
The correct electronic configuration of $d^{4}$ in low spin state according to Crystal Field Splitting theory is
(C) : According to the spectrochemical series, the ascending order of ligand field strength of the ligands are- $$ \mathrm{I}^{-}<\mathrm{F}^{-}<\mathrm{H}_{2} \mathrm{O}^{-}<\mathrm{CN}^{-}<\mathrm{CO} $$
274301
Which combines with $\mathrm{Fe}^{2+}$ to form brown complex?
1 $\mathrm{NO}$
2 $\mathrm{N}_{2} \mathrm{O}$
3 $\mathrm{N}_{2} \mathrm{O}_{3}$
4 $\mathrm{N}_{2} \mathrm{O}_{5}$
Explanation:
(A) : A common nitrate test is also known as the brown ring test. $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}+\mathrm{NO} \longrightarrow\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right]^{2+}+\mathrm{H}_{2} \mathrm{O}$ Thus, $\mathrm{NO}$ combines with $\mathrm{Fe}^{2+}$ to form the brown complex.
CG PET -2019
COORDINATION COMPOUNDS
274306
Which one of the following statement is correct for $\mathrm{d}^{\mathbf{4}}$ ions [ $\mathrm{P}=$ pairing energy]
1 When $\Delta_{\mathrm{o}}>\mathrm{P}$, low-spin complex form
2 When $\Delta_{\mathrm{o}}<\mathrm{P}$, low-spin complex form
3 When $\Delta_{0}>$ P, high-spin complex form
4 When $\Delta_{\mathrm{o}}<\mathrm{P}$, both high-spin and low-spin complexes form
Explanation:
(A) : For When value of $\Delta_{o}$ is greater than pairing energy pairing of electron takes place hence low-spin complexes are formed.
TS EAMCET-2017
COORDINATION COMPOUNDS
274307
The correct electronic configuration of $d^{4}$ in low spin state according to Crystal Field Splitting theory is
(C) : According to the spectrochemical series, the ascending order of ligand field strength of the ligands are- $$ \mathrm{I}^{-}<\mathrm{F}^{-}<\mathrm{H}_{2} \mathrm{O}^{-}<\mathrm{CN}^{-}<\mathrm{CO} $$
