QBManager

COORDINATION COMPOUNDS

274250 Number of ions for the complex
$[Co {({CH}_{3})}_{4} Cl] {Cl}_{2}$ shown by the conductivity measurement, is

1 2

2 4

3 3

4 1

Explanation:

(C) : $[Co {({CH}_{3})}_{4} Cl] {Cl}_{2}$ will give 3 ions on ionization.
$[Co {({CH}_{3})}_{4} Cl] {Cl}_{2} ⟶ {[Co {({CH}_{3})}_{4} {Cl}^{-}]}^{2 +} + 2 {Cl}^{-}$
No. of ions $= 3$

CG PET -2006

COORDINATION COMPOUNDS

274252 The equation which is balanced and represents the correct product(s) is

1

{Li}_{2} O + 2 KCl \to 2 LiCl + K_{2} O

2

{[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} ⟶ {CO}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}

3

{[Mg (H_{2} O_{6})]}^{2 +} (EDTA)^{4 -}

\overset{excess NaOH}{\to} [Mg (EDTA)]^{2 +} + 6 H_{2} O

4

{CuSO}_{4} + 4 KCN \to K_{2} [Cu (CN)_{4}] + K_{2} {SO}_{4}

Explanation:

(B) : The balanced and correct representation of product is
${[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} ⟶ {CO}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}$

JEE Main 2013

COORDINATION COMPOUNDS

274254 EDTA can form complex with how many number of donor atoms?

1 One

2 Two

3 Six

4 Three

J and K CET-(2014)

COORDINATION COMPOUNDS

274256 Among the following the ambidentate ligand is

1

H_{2} {NCH}_{2} {CH}_{2} {NH}_{2}

2

{CO}^{2 -}

3

{NO}_{2}^{-}

4

C_{2} O_{4}^{2 -}

Explanation:

(C) : Those ligands which has two different donor atom but at a time only one donor atom is attached with metal.
original image
Nitrito - $N$ Nitrito - $O$
${NO}_{2}^{-}$ has two donor sites $N$ and $O$ .

J and K CET-(2011)

COORDINATION COMPOUNDS

274250 Number of ions for the complex
$[Co {({CH}_{3})}_{4} Cl] {Cl}_{2}$ shown by the conductivity measurement, is

1 2

2 4

3 3

4 1

Explanation:

(C) : $[Co {({CH}_{3})}_{4} Cl] {Cl}_{2}$ will give 3 ions on ionization.
$[Co {({CH}_{3})}_{4} Cl] {Cl}_{2} ⟶ {[Co {({CH}_{3})}_{4} {Cl}^{-}]}^{2 +} + 2 {Cl}^{-}$
No. of ions $= 3$

CG PET -2006

COORDINATION COMPOUNDS

274252 The equation which is balanced and represents the correct product(s) is

1

{Li}_{2} O + 2 KCl \to 2 LiCl + K_{2} O

2

{[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} ⟶ {CO}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}

3

{[Mg (H_{2} O_{6})]}^{2 +} (EDTA)^{4 -}

\overset{excess NaOH}{\to} [Mg (EDTA)]^{2 +} + 6 H_{2} O

4

{CuSO}_{4} + 4 KCN \to K_{2} [Cu (CN)_{4}] + K_{2} {SO}_{4}

Explanation:

(B) : The balanced and correct representation of product is
${[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} ⟶ {CO}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}$

JEE Main 2013

COORDINATION COMPOUNDS

274254 EDTA can form complex with how many number of donor atoms?

1 One

2 Two

3 Six

4 Three

J and K CET-(2014)

COORDINATION COMPOUNDS

274256 Among the following the ambidentate ligand is

1

H_{2} {NCH}_{2} {CH}_{2} {NH}_{2}

2

{CO}^{2 -}

3

{NO}_{2}^{-}

4

C_{2} O_{4}^{2 -}

Explanation:

(C) : Those ligands which has two different donor atom but at a time only one donor atom is attached with metal.
original image
Nitrito - $N$ Nitrito - $O$
${NO}_{2}^{-}$ has two donor sites $N$ and $O$ .

J and K CET-(2011)

COORDINATION COMPOUNDS

274250 Number of ions for the complex
$[Co {({CH}_{3})}_{4} Cl] {Cl}_{2}$ shown by the conductivity measurement, is

1 2

2 4

3 3

4 1

Explanation:

(C) : $[Co {({CH}_{3})}_{4} Cl] {Cl}_{2}$ will give 3 ions on ionization.
$[Co {({CH}_{3})}_{4} Cl] {Cl}_{2} ⟶ {[Co {({CH}_{3})}_{4} {Cl}^{-}]}^{2 +} + 2 {Cl}^{-}$
No. of ions $= 3$

CG PET -2006

COORDINATION COMPOUNDS

274252 The equation which is balanced and represents the correct product(s) is

1

{Li}_{2} O + 2 KCl \to 2 LiCl + K_{2} O

2

{[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} ⟶ {CO}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}

3

{[Mg (H_{2} O_{6})]}^{2 +} (EDTA)^{4 -}

\overset{excess NaOH}{\to} [Mg (EDTA)]^{2 +} + 6 H_{2} O

4

{CuSO}_{4} + 4 KCN \to K_{2} [Cu (CN)_{4}] + K_{2} {SO}_{4}

Explanation:

(B) : The balanced and correct representation of product is
${[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} ⟶ {CO}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}$

JEE Main 2013

COORDINATION COMPOUNDS

274254 EDTA can form complex with how many number of donor atoms?

1 One

2 Two

3 Six

4 Three

J and K CET-(2014)

COORDINATION COMPOUNDS

274256 Among the following the ambidentate ligand is

1

H_{2} {NCH}_{2} {CH}_{2} {NH}_{2}

2

{CO}^{2 -}

3

{NO}_{2}^{-}

4

C_{2} O_{4}^{2 -}

Explanation:

(C) : Those ligands which has two different donor atom but at a time only one donor atom is attached with metal.
original image
Nitrito - $N$ Nitrito - $O$
${NO}_{2}^{-}$ has two donor sites $N$ and $O$ .

J and K CET-(2011)

COORDINATION COMPOUNDS

274250 Number of ions for the complex
$[Co {({CH}_{3})}_{4} Cl] {Cl}_{2}$ shown by the conductivity measurement, is

1 2

2 4

3 3

4 1

Explanation:

(C) : $[Co {({CH}_{3})}_{4} Cl] {Cl}_{2}$ will give 3 ions on ionization.
$[Co {({CH}_{3})}_{4} Cl] {Cl}_{2} ⟶ {[Co {({CH}_{3})}_{4} {Cl}^{-}]}^{2 +} + 2 {Cl}^{-}$
No. of ions $= 3$

CG PET -2006

COORDINATION COMPOUNDS

274252 The equation which is balanced and represents the correct product(s) is

1

{Li}_{2} O + 2 KCl \to 2 LiCl + K_{2} O

2

{[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} ⟶ {CO}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}

3

{[Mg (H_{2} O_{6})]}^{2 +} (EDTA)^{4 -}

\overset{excess NaOH}{\to} [Mg (EDTA)]^{2 +} + 6 H_{2} O

4

{CuSO}_{4} + 4 KCN \to K_{2} [Cu (CN)_{4}] + K_{2} {SO}_{4}

Explanation:

(B) : The balanced and correct representation of product is
${[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} ⟶ {CO}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}$

JEE Main 2013

COORDINATION COMPOUNDS

274254 EDTA can form complex with how many number of donor atoms?

1 One

2 Two

3 Six

4 Three

J and K CET-(2014)

COORDINATION COMPOUNDS

274256 Among the following the ambidentate ligand is

1

H_{2} {NCH}_{2} {CH}_{2} {NH}_{2}

2

{CO}^{2 -}

3

{NO}_{2}^{-}

4

C_{2} O_{4}^{2 -}

Explanation:

(C) : Those ligands which has two different donor atom but at a time only one donor atom is attached with metal.
original image
Nitrito - $N$ Nitrito - $O$
${NO}_{2}^{-}$ has two donor sites $N$ and $O$ .

J and K CET-(2011)