274022
The magnetic moment of $\mathrm{Fe}^{2+}$ is B.M.
1 3.87
2 0
3 4.9
4 1.73
Explanation:
(C) : Electronic configuration of $\mathrm{Fe}^{2+}=$ $={ }_{18}[\mathrm{Ar}], 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{\mathrm{o}}$ no. of unpaired electron $(\mathrm{n})=4$ $\therefore$ Formula of magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ $=\sqrt{4(4+2)}$ $=\sqrt{24}$ $=4.9$
AP EAPCET 19-08-2021
COORDINATION COMPOUNDS
274024
Identify the set of paramagnetic ions among the following.
(C) : Paramagnetic ions having unpaired electrons. No. of unpaired electron $=1$ No. of unpaired electron $=1$ No. of unpaired electron $=4$ Hence, $\mathrm{Ti}^{2+}, \mathrm{Cu}^{2+}$ and $\mathrm{Mn}^{3+}$ act paramagnetic ions.
274022
The magnetic moment of $\mathrm{Fe}^{2+}$ is B.M.
1 3.87
2 0
3 4.9
4 1.73
Explanation:
(C) : Electronic configuration of $\mathrm{Fe}^{2+}=$ $={ }_{18}[\mathrm{Ar}], 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{\mathrm{o}}$ no. of unpaired electron $(\mathrm{n})=4$ $\therefore$ Formula of magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ $=\sqrt{4(4+2)}$ $=\sqrt{24}$ $=4.9$
AP EAPCET 19-08-2021
COORDINATION COMPOUNDS
274024
Identify the set of paramagnetic ions among the following.
(C) : Paramagnetic ions having unpaired electrons. No. of unpaired electron $=1$ No. of unpaired electron $=1$ No. of unpaired electron $=4$ Hence, $\mathrm{Ti}^{2+}, \mathrm{Cu}^{2+}$ and $\mathrm{Mn}^{3+}$ act paramagnetic ions.
274022
The magnetic moment of $\mathrm{Fe}^{2+}$ is B.M.
1 3.87
2 0
3 4.9
4 1.73
Explanation:
(C) : Electronic configuration of $\mathrm{Fe}^{2+}=$ $={ }_{18}[\mathrm{Ar}], 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{\mathrm{o}}$ no. of unpaired electron $(\mathrm{n})=4$ $\therefore$ Formula of magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ $=\sqrt{4(4+2)}$ $=\sqrt{24}$ $=4.9$
AP EAPCET 19-08-2021
COORDINATION COMPOUNDS
274024
Identify the set of paramagnetic ions among the following.
(C) : Paramagnetic ions having unpaired electrons. No. of unpaired electron $=1$ No. of unpaired electron $=1$ No. of unpaired electron $=4$ Hence, $\mathrm{Ti}^{2+}, \mathrm{Cu}^{2+}$ and $\mathrm{Mn}^{3+}$ act paramagnetic ions.
274022
The magnetic moment of $\mathrm{Fe}^{2+}$ is B.M.
1 3.87
2 0
3 4.9
4 1.73
Explanation:
(C) : Electronic configuration of $\mathrm{Fe}^{2+}=$ $={ }_{18}[\mathrm{Ar}], 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{\mathrm{o}}$ no. of unpaired electron $(\mathrm{n})=4$ $\therefore$ Formula of magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ $=\sqrt{4(4+2)}$ $=\sqrt{24}$ $=4.9$
AP EAPCET 19-08-2021
COORDINATION COMPOUNDS
274024
Identify the set of paramagnetic ions among the following.
(C) : Paramagnetic ions having unpaired electrons. No. of unpaired electron $=1$ No. of unpaired electron $=1$ No. of unpaired electron $=4$ Hence, $\mathrm{Ti}^{2+}, \mathrm{Cu}^{2+}$ and $\mathrm{Mn}^{3+}$ act paramagnetic ions.
274022
The magnetic moment of $\mathrm{Fe}^{2+}$ is B.M.
1 3.87
2 0
3 4.9
4 1.73
Explanation:
(C) : Electronic configuration of $\mathrm{Fe}^{2+}=$ $={ }_{18}[\mathrm{Ar}], 3 \mathrm{~d}^{6}, 4 \mathrm{~s}^{\mathrm{o}}$ no. of unpaired electron $(\mathrm{n})=4$ $\therefore$ Formula of magnetic moment $=\sqrt{\mathrm{n}(\mathrm{n}+2)}$ $=\sqrt{4(4+2)}$ $=\sqrt{24}$ $=4.9$
AP EAPCET 19-08-2021
COORDINATION COMPOUNDS
274024
Identify the set of paramagnetic ions among the following.
(C) : Paramagnetic ions having unpaired electrons. No. of unpaired electron $=1$ No. of unpaired electron $=1$ No. of unpaired electron $=4$ Hence, $\mathrm{Ti}^{2+}, \mathrm{Cu}^{2+}$ and $\mathrm{Mn}^{3+}$ act paramagnetic ions.