00. Electrode Potential
ELECTROCHEMISTRY

275860 For the cell $\operatorname{Ag}(\mathrm{s})\left \vert\operatorname{Ag}^{+}(\mathrm{aq}) \ \vert \mathrm{Cu}^{2+}(\mathrm{aq})\right \vert \mathrm{Cu}(\mathrm{s})$, the reduction potentials of the left and right hand electrodes are 0.337 and 0.799 volts, the cell e.m.f. is

1 -1.136 volt
2 1.136 volt
3 -0.462 volt
4 0.462 volt
ELECTROCHEMISTRY

275861 Given $\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{0}=-0.72 \mathrm{~V}, \mathrm{E}_{\mathrm{Fe}^{2+} / \mathrm{Fe}}^{0}=-0.42 \mathrm{~V}$.
The potential for the cell
$\mathrm{Cr}_{2}\left \vert\mathrm{Cr}^{3+}(0.1 \mathrm{M}) \ \vert \mathrm{Fe}^{2+}(0.01 \mathrm{M})\right \vert \mathrm{Fe}$ is

1 $0.26 \mathrm{~V}$
2 $0.399 \mathrm{~V}$
3 $-0.399 \mathrm{~V}$
4 $-0.26 \mathrm{~V}$
ELECTROCHEMISTRY

275862 The $\mathrm{E}_{\mathrm{M}^{3+} / \mathrm{M}^{2+}}^{0}$ values for $\mathrm{Cr}, \mathrm{Mn}, \mathrm{Fe}$ and $\mathrm{Co}$ are $-0.41,+1.57,+0.77$, and $+1.97 \mathrm{~V}$, respectively. For which one of these metals the change in oxidation state from +2 to +3 is easiest?

1 $\mathrm{Cr}$
2 $\mathrm{Mn}$
3 $\mathrm{Fe}$
4 $\mathrm{Co}$
ELECTROCHEMISTRY

275863 At temperature of $298 \mathrm{~K}$, the emf of the following electrochemical cell, $\operatorname{Ag}(\mathrm{s})\left \vert\operatorname{Ag}^{+}(0.1 \mathrm{M}) \ \vert \mathrm{Zn}^{2+}\right \vert \mathrm{Zn}(\mathrm{s})(0.1 \mathrm{M})$
Will be (Given, $\mathrm{E}_{\text {cell }}^{0}=-1.562 \mathrm{~V}$ )

1 $-1.532 \mathrm{~V}$
2 $-1.503 \mathrm{~V}$
3 $1.532 \mathrm{~V}$
4 $-3.06 \mathrm{~V}$
ELECTROCHEMISTRY

275860 For the cell $\operatorname{Ag}(\mathrm{s})\left \vert\operatorname{Ag}^{+}(\mathrm{aq}) \ \vert \mathrm{Cu}^{2+}(\mathrm{aq})\right \vert \mathrm{Cu}(\mathrm{s})$, the reduction potentials of the left and right hand electrodes are 0.337 and 0.799 volts, the cell e.m.f. is

1 -1.136 volt
2 1.136 volt
3 -0.462 volt
4 0.462 volt
ELECTROCHEMISTRY

275861 Given $\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{0}=-0.72 \mathrm{~V}, \mathrm{E}_{\mathrm{Fe}^{2+} / \mathrm{Fe}}^{0}=-0.42 \mathrm{~V}$.
The potential for the cell
$\mathrm{Cr}_{2}\left \vert\mathrm{Cr}^{3+}(0.1 \mathrm{M}) \ \vert \mathrm{Fe}^{2+}(0.01 \mathrm{M})\right \vert \mathrm{Fe}$ is

1 $0.26 \mathrm{~V}$
2 $0.399 \mathrm{~V}$
3 $-0.399 \mathrm{~V}$
4 $-0.26 \mathrm{~V}$
ELECTROCHEMISTRY

275862 The $\mathrm{E}_{\mathrm{M}^{3+} / \mathrm{M}^{2+}}^{0}$ values for $\mathrm{Cr}, \mathrm{Mn}, \mathrm{Fe}$ and $\mathrm{Co}$ are $-0.41,+1.57,+0.77$, and $+1.97 \mathrm{~V}$, respectively. For which one of these metals the change in oxidation state from +2 to +3 is easiest?

1 $\mathrm{Cr}$
2 $\mathrm{Mn}$
3 $\mathrm{Fe}$
4 $\mathrm{Co}$
ELECTROCHEMISTRY

275863 At temperature of $298 \mathrm{~K}$, the emf of the following electrochemical cell, $\operatorname{Ag}(\mathrm{s})\left \vert\operatorname{Ag}^{+}(0.1 \mathrm{M}) \ \vert \mathrm{Zn}^{2+}\right \vert \mathrm{Zn}(\mathrm{s})(0.1 \mathrm{M})$
Will be (Given, $\mathrm{E}_{\text {cell }}^{0}=-1.562 \mathrm{~V}$ )

1 $-1.532 \mathrm{~V}$
2 $-1.503 \mathrm{~V}$
3 $1.532 \mathrm{~V}$
4 $-3.06 \mathrm{~V}$
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
ELECTROCHEMISTRY

275860 For the cell $\operatorname{Ag}(\mathrm{s})\left \vert\operatorname{Ag}^{+}(\mathrm{aq}) \ \vert \mathrm{Cu}^{2+}(\mathrm{aq})\right \vert \mathrm{Cu}(\mathrm{s})$, the reduction potentials of the left and right hand electrodes are 0.337 and 0.799 volts, the cell e.m.f. is

1 -1.136 volt
2 1.136 volt
3 -0.462 volt
4 0.462 volt
ELECTROCHEMISTRY

275861 Given $\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{0}=-0.72 \mathrm{~V}, \mathrm{E}_{\mathrm{Fe}^{2+} / \mathrm{Fe}}^{0}=-0.42 \mathrm{~V}$.
The potential for the cell
$\mathrm{Cr}_{2}\left \vert\mathrm{Cr}^{3+}(0.1 \mathrm{M}) \ \vert \mathrm{Fe}^{2+}(0.01 \mathrm{M})\right \vert \mathrm{Fe}$ is

1 $0.26 \mathrm{~V}$
2 $0.399 \mathrm{~V}$
3 $-0.399 \mathrm{~V}$
4 $-0.26 \mathrm{~V}$
ELECTROCHEMISTRY

275862 The $\mathrm{E}_{\mathrm{M}^{3+} / \mathrm{M}^{2+}}^{0}$ values for $\mathrm{Cr}, \mathrm{Mn}, \mathrm{Fe}$ and $\mathrm{Co}$ are $-0.41,+1.57,+0.77$, and $+1.97 \mathrm{~V}$, respectively. For which one of these metals the change in oxidation state from +2 to +3 is easiest?

1 $\mathrm{Cr}$
2 $\mathrm{Mn}$
3 $\mathrm{Fe}$
4 $\mathrm{Co}$
ELECTROCHEMISTRY

275863 At temperature of $298 \mathrm{~K}$, the emf of the following electrochemical cell, $\operatorname{Ag}(\mathrm{s})\left \vert\operatorname{Ag}^{+}(0.1 \mathrm{M}) \ \vert \mathrm{Zn}^{2+}\right \vert \mathrm{Zn}(\mathrm{s})(0.1 \mathrm{M})$
Will be (Given, $\mathrm{E}_{\text {cell }}^{0}=-1.562 \mathrm{~V}$ )

1 $-1.532 \mathrm{~V}$
2 $-1.503 \mathrm{~V}$
3 $1.532 \mathrm{~V}$
4 $-3.06 \mathrm{~V}$
ELECTROCHEMISTRY

275860 For the cell $\operatorname{Ag}(\mathrm{s})\left \vert\operatorname{Ag}^{+}(\mathrm{aq}) \ \vert \mathrm{Cu}^{2+}(\mathrm{aq})\right \vert \mathrm{Cu}(\mathrm{s})$, the reduction potentials of the left and right hand electrodes are 0.337 and 0.799 volts, the cell e.m.f. is

1 -1.136 volt
2 1.136 volt
3 -0.462 volt
4 0.462 volt
ELECTROCHEMISTRY

275861 Given $\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{0}=-0.72 \mathrm{~V}, \mathrm{E}_{\mathrm{Fe}^{2+} / \mathrm{Fe}}^{0}=-0.42 \mathrm{~V}$.
The potential for the cell
$\mathrm{Cr}_{2}\left \vert\mathrm{Cr}^{3+}(0.1 \mathrm{M}) \ \vert \mathrm{Fe}^{2+}(0.01 \mathrm{M})\right \vert \mathrm{Fe}$ is

1 $0.26 \mathrm{~V}$
2 $0.399 \mathrm{~V}$
3 $-0.399 \mathrm{~V}$
4 $-0.26 \mathrm{~V}$
ELECTROCHEMISTRY

275862 The $\mathrm{E}_{\mathrm{M}^{3+} / \mathrm{M}^{2+}}^{0}$ values for $\mathrm{Cr}, \mathrm{Mn}, \mathrm{Fe}$ and $\mathrm{Co}$ are $-0.41,+1.57,+0.77$, and $+1.97 \mathrm{~V}$, respectively. For which one of these metals the change in oxidation state from +2 to +3 is easiest?

1 $\mathrm{Cr}$
2 $\mathrm{Mn}$
3 $\mathrm{Fe}$
4 $\mathrm{Co}$
ELECTROCHEMISTRY

275863 At temperature of $298 \mathrm{~K}$, the emf of the following electrochemical cell, $\operatorname{Ag}(\mathrm{s})\left \vert\operatorname{Ag}^{+}(0.1 \mathrm{M}) \ \vert \mathrm{Zn}^{2+}\right \vert \mathrm{Zn}(\mathrm{s})(0.1 \mathrm{M})$
Will be (Given, $\mathrm{E}_{\text {cell }}^{0}=-1.562 \mathrm{~V}$ )

1 $-1.532 \mathrm{~V}$
2 $-1.503 \mathrm{~V}$
3 $1.532 \mathrm{~V}$
4 $-3.06 \mathrm{~V}$