277353 A solution of 1.25 of ' $P$ ' in $50 \mathrm{~g}$ of water lowers freezing point by $0.3^{\circ} \mathrm{C}$. Molar mass of ' $P$ ' is 94 . $K_{f \text { (water) }}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$. The degree of association of ' $P$ ' in water is

277354 An aqueous solution containing $3 \mathrm{~g}$ of a solute of molar mass $111.6 \mathrm{~g} \mathrm{~mol}^{-1}$ in a certain mass of water freezes at $-\mathbf{0 . 1 2 5}{ }^{\circ} \mathrm{C}$. The mass of water in grams present in the solution is $\left(K_{f}=1.86 \mathrm{~K} \mathrm{~kg}\right.$ mol $^{-1}$ )

277356 A 0.001 molal solution of $\left[\operatorname{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{4}\right]$ in water had a freezing point depression of $0.0054^{0} \mathrm{C}$. If $K_{f}$ for water is 1.80 the correct formulation of the above molecule is

277358 Vapour pressure in $\mathrm{mm} \mathrm{Hg}$ of 0.1 mole of urea in $180 \mathrm{~g}$ of water at $25^{\circ} \mathrm{C}$ is (The vapour pressure of water at $25^{\circ} \mathrm{C}$ is $24 \mathbf{~ m m ~ H g ) ~}$

277353 A solution of 1.25 of ' $P$ ' in $50 \mathrm{~g}$ of water lowers freezing point by $0.3^{\circ} \mathrm{C}$. Molar mass of ' $P$ ' is 94 . $K_{f \text { (water) }}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$. The degree of association of ' $P$ ' in water is

277354 An aqueous solution containing $3 \mathrm{~g}$ of a solute of molar mass $111.6 \mathrm{~g} \mathrm{~mol}^{-1}$ in a certain mass of water freezes at $-\mathbf{0 . 1 2 5}{ }^{\circ} \mathrm{C}$. The mass of water in grams present in the solution is $\left(K_{f}=1.86 \mathrm{~K} \mathrm{~kg}\right.$ mol $^{-1}$ )

277356 A 0.001 molal solution of $\left[\operatorname{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{4}\right]$ in water had a freezing point depression of $0.0054^{0} \mathrm{C}$. If $K_{f}$ for water is 1.80 the correct formulation of the above molecule is

277358 Vapour pressure in $\mathrm{mm} \mathrm{Hg}$ of 0.1 mole of urea in $180 \mathrm{~g}$ of water at $25^{\circ} \mathrm{C}$ is (The vapour pressure of water at $25^{\circ} \mathrm{C}$ is $24 \mathbf{~ m m ~ H g ) ~}$

277353 A solution of 1.25 of ' $P$ ' in $50 \mathrm{~g}$ of water lowers freezing point by $0.3^{\circ} \mathrm{C}$. Molar mass of ' $P$ ' is 94 . $K_{f \text { (water) }}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$. The degree of association of ' $P$ ' in water is

277354 An aqueous solution containing $3 \mathrm{~g}$ of a solute of molar mass $111.6 \mathrm{~g} \mathrm{~mol}^{-1}$ in a certain mass of water freezes at $-\mathbf{0 . 1 2 5}{ }^{\circ} \mathrm{C}$. The mass of water in grams present in the solution is $\left(K_{f}=1.86 \mathrm{~K} \mathrm{~kg}\right.$ mol $^{-1}$ )

277356 A 0.001 molal solution of $\left[\operatorname{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{4}\right]$ in water had a freezing point depression of $0.0054^{0} \mathrm{C}$. If $K_{f}$ for water is 1.80 the correct formulation of the above molecule is

277358 Vapour pressure in $\mathrm{mm} \mathrm{Hg}$ of 0.1 mole of urea in $180 \mathrm{~g}$ of water at $25^{\circ} \mathrm{C}$ is (The vapour pressure of water at $25^{\circ} \mathrm{C}$ is $24 \mathbf{~ m m ~ H g ) ~}$

277353 A solution of 1.25 of ' $P$ ' in $50 \mathrm{~g}$ of water lowers freezing point by $0.3^{\circ} \mathrm{C}$. Molar mass of ' $P$ ' is 94 . $K_{f \text { (water) }}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$. The degree of association of ' $P$ ' in water is

277354 An aqueous solution containing $3 \mathrm{~g}$ of a solute of molar mass $111.6 \mathrm{~g} \mathrm{~mol}^{-1}$ in a certain mass of water freezes at $-\mathbf{0 . 1 2 5}{ }^{\circ} \mathrm{C}$. The mass of water in grams present in the solution is $\left(K_{f}=1.86 \mathrm{~K} \mathrm{~kg}\right.$ mol $^{-1}$ )

277356 A 0.001 molal solution of $\left[\operatorname{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{4}\right]$ in water had a freezing point depression of $0.0054^{0} \mathrm{C}$. If $K_{f}$ for water is 1.80 the correct formulation of the above molecule is

277358 Vapour pressure in $\mathrm{mm} \mathrm{Hg}$ of 0.1 mole of urea in $180 \mathrm{~g}$ of water at $25^{\circ} \mathrm{C}$ is (The vapour pressure of water at $25^{\circ} \mathrm{C}$ is $24 \mathbf{~ m m ~ H g ) ~}$