277379 Freezing point of an aqueous solution is $-0.186^{\circ} \mathrm{C}$. If the values of $K_{b}$ and $K_{f}$ of water are respectively $0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ and $1.86 \mathrm{~K} \mathrm{~kg}^{-1}$ $\mathrm{mol}^{-1}$ then the elevation of boiling point of the solution in $K$ is
277379 Freezing point of an aqueous solution is $-0.186^{\circ} \mathrm{C}$. If the values of $K_{b}$ and $K_{f}$ of water are respectively $0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ and $1.86 \mathrm{~K} \mathrm{~kg}^{-1}$ $\mathrm{mol}^{-1}$ then the elevation of boiling point of the solution in $K$ is
277379 Freezing point of an aqueous solution is $-0.186^{\circ} \mathrm{C}$. If the values of $K_{b}$ and $K_{f}$ of water are respectively $0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ and $1.86 \mathrm{~K} \mathrm{~kg}^{-1}$ $\mathrm{mol}^{-1}$ then the elevation of boiling point of the solution in $K$ is
277379 Freezing point of an aqueous solution is $-0.186^{\circ} \mathrm{C}$. If the values of $K_{b}$ and $K_{f}$ of water are respectively $0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ and $1.86 \mathrm{~K} \mathrm{~kg}^{-1}$ $\mathrm{mol}^{-1}$ then the elevation of boiling point of the solution in $K$ is