230690
One mole of alkene $X$ on ozonolysis gave one mole of acetaldehyde and one mole of acetone. The IUPAC name of $X$ is
1 2-methyl-2-butene
2 2-methyl-1-butene
3 2-butene
4 1-butene
Explanation:
: To determine the structure of alkene that undergoes ozonolysis, add the products and replace $\mathrm{O}$ by double $(=)$ bond. Thus,
VITEEE- 2009
Hydrocarbons
230691
What is the hybridization of oxygen atom in an alcohol molecule?
1 $\mathrm{sp}^3$
2 $\mathrm{sp}$
3 $\mathrm{sp}^2$
4 $\mathrm{sp}^2 \mathrm{~d}$
Explanation:
: Oxygen atom in alcohol molecule is $\mathrm{sp}^3$ hybridised.
VITEEE- 2006
Hydrocarbons
230693
Which of the d-orbital is used in $s p^3 d$ hybridization?
1 $\mathrm{d}_{x y}$
2 $\mathrm{d}_{\mathrm{x}^2-y^2}$
3 $\mathrm{d}_{z^2}$
4 $\mathrm{d}_{y z}$
Explanation:
: Hybridisation is defined as concept of mixing two atomic orbital's having the same energy levels to give a new degenerate orbital's. In $\mathrm{sp}^3 \mathrm{~d}$ hybridisation five orbitals are degenerate that is their energies are the same but configurations are different. In this $\mathrm{sp}^3 \mathrm{~d}$ hybridisation there are a total 5 orbital's which are $\mathrm{s}, \mathrm{px}$, py, pz and $\mathrm{dz}^2$ orbital take part in hybridisation.
AMU-2011
Hydrocarbons
230694
In the compound $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$, the pair of hybridized which involved in the formation of $\mathrm{C}_2-\mathrm{C}_3$ bond is
1 $\mathrm{sp}-\mathrm{sp}^2$
2 $s \mathrm{p}-\mathrm{sp} \mathrm{p}^3$
3 $s \mathrm{p}^2-s p^3$
4 $\mathrm{sp}^3-\mathrm{sp}^3$
Explanation:
: $\mathrm{CH}_3=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$ Hybridisation at $\mathrm{C}_2=\mathrm{sp}^2$ and $\mathrm{C}_3=\mathrm{sp}^3$
230690
One mole of alkene $X$ on ozonolysis gave one mole of acetaldehyde and one mole of acetone. The IUPAC name of $X$ is
1 2-methyl-2-butene
2 2-methyl-1-butene
3 2-butene
4 1-butene
Explanation:
: To determine the structure of alkene that undergoes ozonolysis, add the products and replace $\mathrm{O}$ by double $(=)$ bond. Thus,
VITEEE- 2009
Hydrocarbons
230691
What is the hybridization of oxygen atom in an alcohol molecule?
1 $\mathrm{sp}^3$
2 $\mathrm{sp}$
3 $\mathrm{sp}^2$
4 $\mathrm{sp}^2 \mathrm{~d}$
Explanation:
: Oxygen atom in alcohol molecule is $\mathrm{sp}^3$ hybridised.
VITEEE- 2006
Hydrocarbons
230693
Which of the d-orbital is used in $s p^3 d$ hybridization?
1 $\mathrm{d}_{x y}$
2 $\mathrm{d}_{\mathrm{x}^2-y^2}$
3 $\mathrm{d}_{z^2}$
4 $\mathrm{d}_{y z}$
Explanation:
: Hybridisation is defined as concept of mixing two atomic orbital's having the same energy levels to give a new degenerate orbital's. In $\mathrm{sp}^3 \mathrm{~d}$ hybridisation five orbitals are degenerate that is their energies are the same but configurations are different. In this $\mathrm{sp}^3 \mathrm{~d}$ hybridisation there are a total 5 orbital's which are $\mathrm{s}, \mathrm{px}$, py, pz and $\mathrm{dz}^2$ orbital take part in hybridisation.
AMU-2011
Hydrocarbons
230694
In the compound $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$, the pair of hybridized which involved in the formation of $\mathrm{C}_2-\mathrm{C}_3$ bond is
1 $\mathrm{sp}-\mathrm{sp}^2$
2 $s \mathrm{p}-\mathrm{sp} \mathrm{p}^3$
3 $s \mathrm{p}^2-s p^3$
4 $\mathrm{sp}^3-\mathrm{sp}^3$
Explanation:
: $\mathrm{CH}_3=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$ Hybridisation at $\mathrm{C}_2=\mathrm{sp}^2$ and $\mathrm{C}_3=\mathrm{sp}^3$
230690
One mole of alkene $X$ on ozonolysis gave one mole of acetaldehyde and one mole of acetone. The IUPAC name of $X$ is
1 2-methyl-2-butene
2 2-methyl-1-butene
3 2-butene
4 1-butene
Explanation:
: To determine the structure of alkene that undergoes ozonolysis, add the products and replace $\mathrm{O}$ by double $(=)$ bond. Thus,
VITEEE- 2009
Hydrocarbons
230691
What is the hybridization of oxygen atom in an alcohol molecule?
1 $\mathrm{sp}^3$
2 $\mathrm{sp}$
3 $\mathrm{sp}^2$
4 $\mathrm{sp}^2 \mathrm{~d}$
Explanation:
: Oxygen atom in alcohol molecule is $\mathrm{sp}^3$ hybridised.
VITEEE- 2006
Hydrocarbons
230693
Which of the d-orbital is used in $s p^3 d$ hybridization?
1 $\mathrm{d}_{x y}$
2 $\mathrm{d}_{\mathrm{x}^2-y^2}$
3 $\mathrm{d}_{z^2}$
4 $\mathrm{d}_{y z}$
Explanation:
: Hybridisation is defined as concept of mixing two atomic orbital's having the same energy levels to give a new degenerate orbital's. In $\mathrm{sp}^3 \mathrm{~d}$ hybridisation five orbitals are degenerate that is their energies are the same but configurations are different. In this $\mathrm{sp}^3 \mathrm{~d}$ hybridisation there are a total 5 orbital's which are $\mathrm{s}, \mathrm{px}$, py, pz and $\mathrm{dz}^2$ orbital take part in hybridisation.
AMU-2011
Hydrocarbons
230694
In the compound $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$, the pair of hybridized which involved in the formation of $\mathrm{C}_2-\mathrm{C}_3$ bond is
1 $\mathrm{sp}-\mathrm{sp}^2$
2 $s \mathrm{p}-\mathrm{sp} \mathrm{p}^3$
3 $s \mathrm{p}^2-s p^3$
4 $\mathrm{sp}^3-\mathrm{sp}^3$
Explanation:
: $\mathrm{CH}_3=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$ Hybridisation at $\mathrm{C}_2=\mathrm{sp}^2$ and $\mathrm{C}_3=\mathrm{sp}^3$
230690
One mole of alkene $X$ on ozonolysis gave one mole of acetaldehyde and one mole of acetone. The IUPAC name of $X$ is
1 2-methyl-2-butene
2 2-methyl-1-butene
3 2-butene
4 1-butene
Explanation:
: To determine the structure of alkene that undergoes ozonolysis, add the products and replace $\mathrm{O}$ by double $(=)$ bond. Thus,
VITEEE- 2009
Hydrocarbons
230691
What is the hybridization of oxygen atom in an alcohol molecule?
1 $\mathrm{sp}^3$
2 $\mathrm{sp}$
3 $\mathrm{sp}^2$
4 $\mathrm{sp}^2 \mathrm{~d}$
Explanation:
: Oxygen atom in alcohol molecule is $\mathrm{sp}^3$ hybridised.
VITEEE- 2006
Hydrocarbons
230693
Which of the d-orbital is used in $s p^3 d$ hybridization?
1 $\mathrm{d}_{x y}$
2 $\mathrm{d}_{\mathrm{x}^2-y^2}$
3 $\mathrm{d}_{z^2}$
4 $\mathrm{d}_{y z}$
Explanation:
: Hybridisation is defined as concept of mixing two atomic orbital's having the same energy levels to give a new degenerate orbital's. In $\mathrm{sp}^3 \mathrm{~d}$ hybridisation five orbitals are degenerate that is their energies are the same but configurations are different. In this $\mathrm{sp}^3 \mathrm{~d}$ hybridisation there are a total 5 orbital's which are $\mathrm{s}, \mathrm{px}$, py, pz and $\mathrm{dz}^2$ orbital take part in hybridisation.
AMU-2011
Hydrocarbons
230694
In the compound $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$, the pair of hybridized which involved in the formation of $\mathrm{C}_2-\mathrm{C}_3$ bond is
1 $\mathrm{sp}-\mathrm{sp}^2$
2 $s \mathrm{p}-\mathrm{sp} \mathrm{p}^3$
3 $s \mathrm{p}^2-s p^3$
4 $\mathrm{sp}^3-\mathrm{sp}^3$
Explanation:
: $\mathrm{CH}_3=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}$ Hybridisation at $\mathrm{C}_2=\mathrm{sp}^2$ and $\mathrm{C}_3=\mathrm{sp}^3$
