03. Hybridisation
Hydrocarbons

230697 The number of $\mathrm{sp}^2$-hybrid orbitals in a molecule of benzene is:

1 24
2 12
3 18
4 6
Hydrocarbons

230700 Underlined carbon is $\mathrm{sp}^3$ hybridised in

1 $\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2$
2 $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$
3 $\mathrm{CH}_3 \mathrm{CONH}_2$
4 $\mathrm{CH}_3 \mathrm{CH}_2 \underline{\mathrm{C}} \mathrm{N}$
Hydrocarbons

230708 In which of the following species, all the three types of hybrid carbons are present?

1 $\mathrm{CH}_2=\mathrm{C}=\mathrm{CH}_2$
2 $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2^{+}$
3 $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_2^{+}$
4 $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2$
5 $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2$
Hydrocarbons

230709 Consider the following compounds:
(i) chloroethene (ii) benzene
(iii) 1, 3-butadiene (iv) 1, 3, 5 -hexatriene
All the carbon atoms are $\mathrm{sp}^2$ hybridised in:

1 (i), (iii), (iv) only
2 (i), (ii) only
3 (ii), (iii), (iv) only
4 (iii), (iv) only
5 (i), (ii), (iii) and (iv)
Hydrocarbons

230697 The number of $\mathrm{sp}^2$-hybrid orbitals in a molecule of benzene is:

1 24
2 12
3 18
4 6
Hydrocarbons

230700 Underlined carbon is $\mathrm{sp}^3$ hybridised in

1 $\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2$
2 $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$
3 $\mathrm{CH}_3 \mathrm{CONH}_2$
4 $\mathrm{CH}_3 \mathrm{CH}_2 \underline{\mathrm{C}} \mathrm{N}$
Hydrocarbons

230708 In which of the following species, all the three types of hybrid carbons are present?

1 $\mathrm{CH}_2=\mathrm{C}=\mathrm{CH}_2$
2 $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2^{+}$
3 $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_2^{+}$
4 $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2$
5 $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2$
Hydrocarbons

230709 Consider the following compounds:
(i) chloroethene (ii) benzene
(iii) 1, 3-butadiene (iv) 1, 3, 5 -hexatriene
All the carbon atoms are $\mathrm{sp}^2$ hybridised in:

1 (i), (iii), (iv) only
2 (i), (ii) only
3 (ii), (iii), (iv) only
4 (iii), (iv) only
5 (i), (ii), (iii) and (iv)
Hydrocarbons

230697 The number of $\mathrm{sp}^2$-hybrid orbitals in a molecule of benzene is:

1 24
2 12
3 18
4 6
Hydrocarbons

230700 Underlined carbon is $\mathrm{sp}^3$ hybridised in

1 $\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2$
2 $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$
3 $\mathrm{CH}_3 \mathrm{CONH}_2$
4 $\mathrm{CH}_3 \mathrm{CH}_2 \underline{\mathrm{C}} \mathrm{N}$
Hydrocarbons

230708 In which of the following species, all the three types of hybrid carbons are present?

1 $\mathrm{CH}_2=\mathrm{C}=\mathrm{CH}_2$
2 $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2^{+}$
3 $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_2^{+}$
4 $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2$
5 $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2$
Hydrocarbons

230709 Consider the following compounds:
(i) chloroethene (ii) benzene
(iii) 1, 3-butadiene (iv) 1, 3, 5 -hexatriene
All the carbon atoms are $\mathrm{sp}^2$ hybridised in:

1 (i), (iii), (iv) only
2 (i), (ii) only
3 (ii), (iii), (iv) only
4 (iii), (iv) only
5 (i), (ii), (iii) and (iv)
Hydrocarbons

230697 The number of $\mathrm{sp}^2$-hybrid orbitals in a molecule of benzene is:

1 24
2 12
3 18
4 6
Hydrocarbons

230700 Underlined carbon is $\mathrm{sp}^3$ hybridised in

1 $\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2$
2 $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$
3 $\mathrm{CH}_3 \mathrm{CONH}_2$
4 $\mathrm{CH}_3 \mathrm{CH}_2 \underline{\mathrm{C}} \mathrm{N}$
Hydrocarbons

230708 In which of the following species, all the three types of hybrid carbons are present?

1 $\mathrm{CH}_2=\mathrm{C}=\mathrm{CH}_2$
2 $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2^{+}$
3 $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_2^{+}$
4 $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2$
5 $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2$
Hydrocarbons

230709 Consider the following compounds:
(i) chloroethene (ii) benzene
(iii) 1, 3-butadiene (iv) 1, 3, 5 -hexatriene
All the carbon atoms are $\mathrm{sp}^2$ hybridised in:

1 (i), (iii), (iv) only
2 (i), (ii) only
3 (ii), (iii), (iv) only
4 (iii), (iv) only
5 (i), (ii), (iii) and (iv)
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