03. Buffer Solution
Ionic Equilibrium

229744 Consider the following solutions of equal concentrations
$\begin{array}{ll}
\mathrm{A}=\mathrm{NH}_4 \mathrm{Cl} ; & \mathrm{B}=\mathrm{CH}_3 \mathrm{COONa} \\
\mathrm{C}=\mathrm{NH}_4 \mathrm{OH} ; & \mathrm{D}=\mathrm{CH}_3 \mathrm{COOH}
\end{array}$
A buffer solution can be obtained by mixing equal volumes of

1 $\mathrm{C}$ and $\mathrm{D}$
2 $A$ and $B$
3 $\mathrm{A}$ and $\mathrm{C}$
4 $C$ and $D$
Ionic Equilibrium

229746 Which of the following 1 : 1 mixture will act as buffer solution?

1 $\mathrm{HCl}$ and $\mathrm{NaOH}$
2 $\mathrm{KOH}$ and $\mathrm{CH}_3 \mathrm{COOH}$
3 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{NaCl}$
4 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{CH}_3 \mathrm{COONa}$
Ionic Equilibrium

229747 A buffer solution is prepared in which the concentration of $\mathrm{NH}_3$ is $0.30 \mathrm{M}$ and the concentration of $\mathrm{NH}_4^{+}$is 0.20 M. If the equilibrium constant, $\mathrm{K}_{\mathrm{b}}$ for $\mathrm{NH}_3$ equals $1.8 \times 10^{-5}$, What is this $\mathrm{pH}$ of the solution? (log $2.7=0.43$ )

1 9.43
2 11.72
3 8.73
4 9.08
Ionic Equilibrium

229750 Which will make basic buffer ?

1 $100 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{HCl}+100 \mathrm{~mL}$ of $0.1 \mathrm{~m}$ $\mathrm{NaOH}$
2 $50 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}+25 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{CH}_3 \mathrm{COOH}$
3 $100 \mathrm{~mL}$ of $0.1 \mathrm{CH}_3 \mathrm{COOH}+100 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{NaOH}$
4 $100 \mathrm{~mL}$ of $0.1 \mathrm{HCl}+200 \mathrm{~mL}$ of 0.1 of $\mathrm{NH}_4 \mathrm{OH}$
Ionic Equilibrium

229752 The dissociation of a weak acid is $1 \times 10^{-4}$. In order to prepare a buffer solution with a $\mathrm{pH}=$ 5 , the [Salt]/[Acid] ration should be

1 $4: 5$
2 $10: 1$
3 $5: 4$
4 $1: 10$
Ionic Equilibrium

229744 Consider the following solutions of equal concentrations
$\begin{array}{ll}
\mathrm{A}=\mathrm{NH}_4 \mathrm{Cl} ; & \mathrm{B}=\mathrm{CH}_3 \mathrm{COONa} \\
\mathrm{C}=\mathrm{NH}_4 \mathrm{OH} ; & \mathrm{D}=\mathrm{CH}_3 \mathrm{COOH}
\end{array}$
A buffer solution can be obtained by mixing equal volumes of

1 $\mathrm{C}$ and $\mathrm{D}$
2 $A$ and $B$
3 $\mathrm{A}$ and $\mathrm{C}$
4 $C$ and $D$
Ionic Equilibrium

229746 Which of the following 1 : 1 mixture will act as buffer solution?

1 $\mathrm{HCl}$ and $\mathrm{NaOH}$
2 $\mathrm{KOH}$ and $\mathrm{CH}_3 \mathrm{COOH}$
3 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{NaCl}$
4 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{CH}_3 \mathrm{COONa}$
Ionic Equilibrium

229747 A buffer solution is prepared in which the concentration of $\mathrm{NH}_3$ is $0.30 \mathrm{M}$ and the concentration of $\mathrm{NH}_4^{+}$is 0.20 M. If the equilibrium constant, $\mathrm{K}_{\mathrm{b}}$ for $\mathrm{NH}_3$ equals $1.8 \times 10^{-5}$, What is this $\mathrm{pH}$ of the solution? (log $2.7=0.43$ )

1 9.43
2 11.72
3 8.73
4 9.08
Ionic Equilibrium

229750 Which will make basic buffer ?

1 $100 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{HCl}+100 \mathrm{~mL}$ of $0.1 \mathrm{~m}$ $\mathrm{NaOH}$
2 $50 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}+25 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{CH}_3 \mathrm{COOH}$
3 $100 \mathrm{~mL}$ of $0.1 \mathrm{CH}_3 \mathrm{COOH}+100 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{NaOH}$
4 $100 \mathrm{~mL}$ of $0.1 \mathrm{HCl}+200 \mathrm{~mL}$ of 0.1 of $\mathrm{NH}_4 \mathrm{OH}$
Ionic Equilibrium

229752 The dissociation of a weak acid is $1 \times 10^{-4}$. In order to prepare a buffer solution with a $\mathrm{pH}=$ 5 , the [Salt]/[Acid] ration should be

1 $4: 5$
2 $10: 1$
3 $5: 4$
4 $1: 10$
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Ionic Equilibrium

229744 Consider the following solutions of equal concentrations
$\begin{array}{ll}
\mathrm{A}=\mathrm{NH}_4 \mathrm{Cl} ; & \mathrm{B}=\mathrm{CH}_3 \mathrm{COONa} \\
\mathrm{C}=\mathrm{NH}_4 \mathrm{OH} ; & \mathrm{D}=\mathrm{CH}_3 \mathrm{COOH}
\end{array}$
A buffer solution can be obtained by mixing equal volumes of

1 $\mathrm{C}$ and $\mathrm{D}$
2 $A$ and $B$
3 $\mathrm{A}$ and $\mathrm{C}$
4 $C$ and $D$
Ionic Equilibrium

229746 Which of the following 1 : 1 mixture will act as buffer solution?

1 $\mathrm{HCl}$ and $\mathrm{NaOH}$
2 $\mathrm{KOH}$ and $\mathrm{CH}_3 \mathrm{COOH}$
3 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{NaCl}$
4 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{CH}_3 \mathrm{COONa}$
Ionic Equilibrium

229747 A buffer solution is prepared in which the concentration of $\mathrm{NH}_3$ is $0.30 \mathrm{M}$ and the concentration of $\mathrm{NH}_4^{+}$is 0.20 M. If the equilibrium constant, $\mathrm{K}_{\mathrm{b}}$ for $\mathrm{NH}_3$ equals $1.8 \times 10^{-5}$, What is this $\mathrm{pH}$ of the solution? (log $2.7=0.43$ )

1 9.43
2 11.72
3 8.73
4 9.08
Ionic Equilibrium

229750 Which will make basic buffer ?

1 $100 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{HCl}+100 \mathrm{~mL}$ of $0.1 \mathrm{~m}$ $\mathrm{NaOH}$
2 $50 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}+25 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{CH}_3 \mathrm{COOH}$
3 $100 \mathrm{~mL}$ of $0.1 \mathrm{CH}_3 \mathrm{COOH}+100 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{NaOH}$
4 $100 \mathrm{~mL}$ of $0.1 \mathrm{HCl}+200 \mathrm{~mL}$ of 0.1 of $\mathrm{NH}_4 \mathrm{OH}$
Ionic Equilibrium

229752 The dissociation of a weak acid is $1 \times 10^{-4}$. In order to prepare a buffer solution with a $\mathrm{pH}=$ 5 , the [Salt]/[Acid] ration should be

1 $4: 5$
2 $10: 1$
3 $5: 4$
4 $1: 10$
Ionic Equilibrium

229744 Consider the following solutions of equal concentrations
$\begin{array}{ll}
\mathrm{A}=\mathrm{NH}_4 \mathrm{Cl} ; & \mathrm{B}=\mathrm{CH}_3 \mathrm{COONa} \\
\mathrm{C}=\mathrm{NH}_4 \mathrm{OH} ; & \mathrm{D}=\mathrm{CH}_3 \mathrm{COOH}
\end{array}$
A buffer solution can be obtained by mixing equal volumes of

1 $\mathrm{C}$ and $\mathrm{D}$
2 $A$ and $B$
3 $\mathrm{A}$ and $\mathrm{C}$
4 $C$ and $D$
Ionic Equilibrium

229746 Which of the following 1 : 1 mixture will act as buffer solution?

1 $\mathrm{HCl}$ and $\mathrm{NaOH}$
2 $\mathrm{KOH}$ and $\mathrm{CH}_3 \mathrm{COOH}$
3 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{NaCl}$
4 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{CH}_3 \mathrm{COONa}$
Ionic Equilibrium

229747 A buffer solution is prepared in which the concentration of $\mathrm{NH}_3$ is $0.30 \mathrm{M}$ and the concentration of $\mathrm{NH}_4^{+}$is 0.20 M. If the equilibrium constant, $\mathrm{K}_{\mathrm{b}}$ for $\mathrm{NH}_3$ equals $1.8 \times 10^{-5}$, What is this $\mathrm{pH}$ of the solution? (log $2.7=0.43$ )

1 9.43
2 11.72
3 8.73
4 9.08
Ionic Equilibrium

229750 Which will make basic buffer ?

1 $100 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{HCl}+100 \mathrm{~mL}$ of $0.1 \mathrm{~m}$ $\mathrm{NaOH}$
2 $50 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}+25 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{CH}_3 \mathrm{COOH}$
3 $100 \mathrm{~mL}$ of $0.1 \mathrm{CH}_3 \mathrm{COOH}+100 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{NaOH}$
4 $100 \mathrm{~mL}$ of $0.1 \mathrm{HCl}+200 \mathrm{~mL}$ of 0.1 of $\mathrm{NH}_4 \mathrm{OH}$
Ionic Equilibrium

229752 The dissociation of a weak acid is $1 \times 10^{-4}$. In order to prepare a buffer solution with a $\mathrm{pH}=$ 5 , the [Salt]/[Acid] ration should be

1 $4: 5$
2 $10: 1$
3 $5: 4$
4 $1: 10$
Ionic Equilibrium

229744 Consider the following solutions of equal concentrations
$\begin{array}{ll}
\mathrm{A}=\mathrm{NH}_4 \mathrm{Cl} ; & \mathrm{B}=\mathrm{CH}_3 \mathrm{COONa} \\
\mathrm{C}=\mathrm{NH}_4 \mathrm{OH} ; & \mathrm{D}=\mathrm{CH}_3 \mathrm{COOH}
\end{array}$
A buffer solution can be obtained by mixing equal volumes of

1 $\mathrm{C}$ and $\mathrm{D}$
2 $A$ and $B$
3 $\mathrm{A}$ and $\mathrm{C}$
4 $C$ and $D$
Ionic Equilibrium

229746 Which of the following 1 : 1 mixture will act as buffer solution?

1 $\mathrm{HCl}$ and $\mathrm{NaOH}$
2 $\mathrm{KOH}$ and $\mathrm{CH}_3 \mathrm{COOH}$
3 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{NaCl}$
4 $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{CH}_3 \mathrm{COONa}$
Ionic Equilibrium

229747 A buffer solution is prepared in which the concentration of $\mathrm{NH}_3$ is $0.30 \mathrm{M}$ and the concentration of $\mathrm{NH}_4^{+}$is 0.20 M. If the equilibrium constant, $\mathrm{K}_{\mathrm{b}}$ for $\mathrm{NH}_3$ equals $1.8 \times 10^{-5}$, What is this $\mathrm{pH}$ of the solution? (log $2.7=0.43$ )

1 9.43
2 11.72
3 8.73
4 9.08
Ionic Equilibrium

229750 Which will make basic buffer ?

1 $100 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{HCl}+100 \mathrm{~mL}$ of $0.1 \mathrm{~m}$ $\mathrm{NaOH}$
2 $50 \mathrm{~mL}$ of $0.1 \mathrm{M} \mathrm{NaOH}+25 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{CH}_3 \mathrm{COOH}$
3 $100 \mathrm{~mL}$ of $0.1 \mathrm{CH}_3 \mathrm{COOH}+100 \mathrm{~mL}$ of $0.1 \mathrm{M}$ $\mathrm{NaOH}$
4 $100 \mathrm{~mL}$ of $0.1 \mathrm{HCl}+200 \mathrm{~mL}$ of 0.1 of $\mathrm{NH}_4 \mathrm{OH}$
Ionic Equilibrium

229752 The dissociation of a weak acid is $1 \times 10^{-4}$. In order to prepare a buffer solution with a $\mathrm{pH}=$ 5 , the [Salt]/[Acid] ration should be

1 $4: 5$
2 $10: 1$
3 $5: 4$
4 $1: 10$