06. Application of Kp and Kc
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NEET DIGITAL LIBRARY
Chemical Equilibrium

229312 For the reaction
$\mathrm{C}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) \mathrm{\theta} \mathrm{2} \mathrm{CO}(\mathrm{g})$, the partial pressures of $\mathrm{CO}_{2}$ and $\mathrm{CO}$ are 2.0 and $4.0 \mathrm{~atm}$ respectively at equilibrium. What is the value of $K_{p}$ for the reaction?

1 0.5
2 4.0
3 8.0
4 32
AP EAMCET (Medical) -1998
Chemical Equilibrium

229313 The value of $K_{p}$ for the reaction $2 \mathrm{H}_{2} \mathrm{~S}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{S}_{2}(\mathrm{~g})$ is $\mathbf{1 . 2} \times \mathbf{1 0}^{-2}$ at $1065^{\circ} \mathrm{C}$. The value of $K_{c}$ for this reaction is

1 $1.2 \times 10^{-2}$
2 $<1.2 \times 10^{-2}$
3 83
4 $>1.2 \times 10^{-2}$
AP - EAMCET - (Medical)-1997
Chemical Equilibrium

229314 At $80^{\circ} \mathrm{C}$ distilled water has $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]$concentration equal to $1 \times 10^{-6}$ mole/litre. The value of $K_{p}$ at this temperature will be

1 $1 \times 10^{-12}$
2 $1 \times 10^{-15}$
3 $1 \times 10^{-6}$
4 $1 \times 10-9$
NEET-1994
Chemical Equilibrium

229316 For the reaction,
$\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{COCl}_{2}(\mathrm{~g})$, the $\mathrm{K}_{\mathrm{p}} / \mathrm{K}_{\mathrm{c}}$ is equal to

1 $1 / \mathrm{RT}$
2 $\mathrm{RT}$
3 $\sqrt{ } \mathrm{RT}$
4 1.0
AIEEE-2004
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Chemical Equilibrium

229312 For the reaction
$\mathrm{C}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) \mathrm{\theta} \mathrm{2} \mathrm{CO}(\mathrm{g})$, the partial pressures of $\mathrm{CO}_{2}$ and $\mathrm{CO}$ are 2.0 and $4.0 \mathrm{~atm}$ respectively at equilibrium. What is the value of $K_{p}$ for the reaction?

1 0.5
2 4.0
3 8.0
4 32
AP EAMCET (Medical) -1998
Chemical Equilibrium

229313 The value of $K_{p}$ for the reaction $2 \mathrm{H}_{2} \mathrm{~S}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{S}_{2}(\mathrm{~g})$ is $\mathbf{1 . 2} \times \mathbf{1 0}^{-2}$ at $1065^{\circ} \mathrm{C}$. The value of $K_{c}$ for this reaction is

1 $1.2 \times 10^{-2}$
2 $<1.2 \times 10^{-2}$
3 83
4 $>1.2 \times 10^{-2}$
AP - EAMCET - (Medical)-1997
Chemical Equilibrium

229314 At $80^{\circ} \mathrm{C}$ distilled water has $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]$concentration equal to $1 \times 10^{-6}$ mole/litre. The value of $K_{p}$ at this temperature will be

1 $1 \times 10^{-12}$
2 $1 \times 10^{-15}$
3 $1 \times 10^{-6}$
4 $1 \times 10-9$
NEET-1994
Chemical Equilibrium

229316 For the reaction,
$\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{COCl}_{2}(\mathrm{~g})$, the $\mathrm{K}_{\mathrm{p}} / \mathrm{K}_{\mathrm{c}}$ is equal to

1 $1 / \mathrm{RT}$
2 $\mathrm{RT}$
3 $\sqrt{ } \mathrm{RT}$
4 1.0
AIEEE-2004
For More Updates join with Us
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Chemical Equilibrium

229312 For the reaction
$\mathrm{C}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) \mathrm{\theta} \mathrm{2} \mathrm{CO}(\mathrm{g})$, the partial pressures of $\mathrm{CO}_{2}$ and $\mathrm{CO}$ are 2.0 and $4.0 \mathrm{~atm}$ respectively at equilibrium. What is the value of $K_{p}$ for the reaction?

1 0.5
2 4.0
3 8.0
4 32
AP EAMCET (Medical) -1998
Chemical Equilibrium

229313 The value of $K_{p}$ for the reaction $2 \mathrm{H}_{2} \mathrm{~S}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{S}_{2}(\mathrm{~g})$ is $\mathbf{1 . 2} \times \mathbf{1 0}^{-2}$ at $1065^{\circ} \mathrm{C}$. The value of $K_{c}$ for this reaction is

1 $1.2 \times 10^{-2}$
2 $<1.2 \times 10^{-2}$
3 83
4 $>1.2 \times 10^{-2}$
AP - EAMCET - (Medical)-1997
Chemical Equilibrium

229314 At $80^{\circ} \mathrm{C}$ distilled water has $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]$concentration equal to $1 \times 10^{-6}$ mole/litre. The value of $K_{p}$ at this temperature will be

1 $1 \times 10^{-12}$
2 $1 \times 10^{-15}$
3 $1 \times 10^{-6}$
4 $1 \times 10-9$
NEET-1994
Chemical Equilibrium

229316 For the reaction,
$\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{COCl}_{2}(\mathrm{~g})$, the $\mathrm{K}_{\mathrm{p}} / \mathrm{K}_{\mathrm{c}}$ is equal to

1 $1 / \mathrm{RT}$
2 $\mathrm{RT}$
3 $\sqrt{ } \mathrm{RT}$
4 1.0
AIEEE-2004
NEET DIGITAL LIBRARY
Chemical Equilibrium

229312 For the reaction
$\mathrm{C}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) \mathrm{\theta} \mathrm{2} \mathrm{CO}(\mathrm{g})$, the partial pressures of $\mathrm{CO}_{2}$ and $\mathrm{CO}$ are 2.0 and $4.0 \mathrm{~atm}$ respectively at equilibrium. What is the value of $K_{p}$ for the reaction?

1 0.5
2 4.0
3 8.0
4 32
AP EAMCET (Medical) -1998
Chemical Equilibrium

229313 The value of $K_{p}$ for the reaction $2 \mathrm{H}_{2} \mathrm{~S}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{S}_{2}(\mathrm{~g})$ is $\mathbf{1 . 2} \times \mathbf{1 0}^{-2}$ at $1065^{\circ} \mathrm{C}$. The value of $K_{c}$ for this reaction is

1 $1.2 \times 10^{-2}$
2 $<1.2 \times 10^{-2}$
3 83
4 $>1.2 \times 10^{-2}$
AP - EAMCET - (Medical)-1997
Chemical Equilibrium

229314 At $80^{\circ} \mathrm{C}$ distilled water has $\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]$concentration equal to $1 \times 10^{-6}$ mole/litre. The value of $K_{p}$ at this temperature will be

1 $1 \times 10^{-12}$
2 $1 \times 10^{-15}$
3 $1 \times 10^{-6}$
4 $1 \times 10-9$
NEET-1994
Chemical Equilibrium

229316 For the reaction,
$\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{COCl}_{2}(\mathrm{~g})$, the $\mathrm{K}_{\mathrm{p}} / \mathrm{K}_{\mathrm{c}}$ is equal to

1 $1 / \mathrm{RT}$
2 $\mathrm{RT}$
3 $\sqrt{ } \mathrm{RT}$
4 1.0
AIEEE-2004
Join With Us for More Updates