06. Application of Kp and Kc
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Chemical Equilibrium

229284 Calculate $K_{c}$ for the reversible process given below if $K_{p}=167$ and $T=800^{\circ} \mathrm{C}$.
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$

1 1.95
2 1.85
3 1.89
4 1.60
WB-JEE-2010
Chemical Equilibrium

229287 If the equilibrium constant of the reaction $2 \mathrm{HI} \rightleftharpoons \mathrm{H}_{2}+\mathrm{I}_{2}$ is 0.25 , then the equilibrium constant for the reaction $\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons \quad 2 \mathrm{HI}$ would be

1 1
2 2
3 3
4 4
BITSAT 2009
Chemical Equilibrium

229288 For the reaction, $2 B+A \rightleftharpoons \quad C$, the equilibrium constant is-

1 $\frac{[\mathrm{A}][\mathrm{B}]^{3}}{[\mathrm{C}]}$
2 $\frac{[\mathrm{C}]}{[\mathrm{A}][2 \mathrm{~B}]}$
3 $\frac{[\mathrm{C}]}{[\mathrm{A}][\mathrm{B}]^{2}}$
4 $\frac{[\mathrm{A}][\mathrm{B}]}{[\mathrm{C}]}$
BCECE-2009
Chemical Equilibrium

229289 One mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ is heated in a flask with a volume of $0.1 \mathrm{dm}^{3}$. At equilibrium 1.708 mole of $\mathrm{NO}_{2}$ and 0.146 mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ were found at $134^{0} \mathrm{C}$. The equilibrium constant will be

1 $250 \mathrm{~mol} \mathrm{dm}^{-3}$
2 $300 \mathrm{~mol} \mathrm{dm}^{-3}$
3 $200 \mathrm{~mol} \mathrm{dm}^{-3}$
4 $230 \mathrm{~mol} \mathrm{dm}^{-3}$
MPPET-2009
Chemical Equilibrium

229290 Assertion : For reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Unit of $\mathrm{K}_{\mathrm{c}}=\mathrm{L}^{2} \mathrm{~mol}^{-2}$
Reason : For the reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Equilibrium constant, $K_{c}=\frac{\left[\mathrm{NH}_{3}\right]^{2}}{\left[\mathrm{~N}_{2}\right]\left[\mathrm{H}_{2}\right]^{3}}$

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 In the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the assertion is incorrect but the Reason is correct.
AIIMS-(2008)
NEET DIGITAL LIBRARY
Chemical Equilibrium

229284 Calculate $K_{c}$ for the reversible process given below if $K_{p}=167$ and $T=800^{\circ} \mathrm{C}$.
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$

1 1.95
2 1.85
3 1.89
4 1.60
WB-JEE-2010
Chemical Equilibrium

229287 If the equilibrium constant of the reaction $2 \mathrm{HI} \rightleftharpoons \mathrm{H}_{2}+\mathrm{I}_{2}$ is 0.25 , then the equilibrium constant for the reaction $\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons \quad 2 \mathrm{HI}$ would be

1 1
2 2
3 3
4 4
BITSAT 2009
Chemical Equilibrium

229288 For the reaction, $2 B+A \rightleftharpoons \quad C$, the equilibrium constant is-

1 $\frac{[\mathrm{A}][\mathrm{B}]^{3}}{[\mathrm{C}]}$
2 $\frac{[\mathrm{C}]}{[\mathrm{A}][2 \mathrm{~B}]}$
3 $\frac{[\mathrm{C}]}{[\mathrm{A}][\mathrm{B}]^{2}}$
4 $\frac{[\mathrm{A}][\mathrm{B}]}{[\mathrm{C}]}$
BCECE-2009
Chemical Equilibrium

229289 One mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ is heated in a flask with a volume of $0.1 \mathrm{dm}^{3}$. At equilibrium 1.708 mole of $\mathrm{NO}_{2}$ and 0.146 mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ were found at $134^{0} \mathrm{C}$. The equilibrium constant will be

1 $250 \mathrm{~mol} \mathrm{dm}^{-3}$
2 $300 \mathrm{~mol} \mathrm{dm}^{-3}$
3 $200 \mathrm{~mol} \mathrm{dm}^{-3}$
4 $230 \mathrm{~mol} \mathrm{dm}^{-3}$
MPPET-2009
Chemical Equilibrium

229290 Assertion : For reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Unit of $\mathrm{K}_{\mathrm{c}}=\mathrm{L}^{2} \mathrm{~mol}^{-2}$
Reason : For the reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Equilibrium constant, $K_{c}=\frac{\left[\mathrm{NH}_{3}\right]^{2}}{\left[\mathrm{~N}_{2}\right]\left[\mathrm{H}_{2}\right]^{3}}$

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 In the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the assertion is incorrect but the Reason is correct.
AIIMS-(2008)
Join With Us for More Updates
Chemical Equilibrium

229284 Calculate $K_{c}$ for the reversible process given below if $K_{p}=167$ and $T=800^{\circ} \mathrm{C}$.
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$

1 1.95
2 1.85
3 1.89
4 1.60
WB-JEE-2010
Chemical Equilibrium

229287 If the equilibrium constant of the reaction $2 \mathrm{HI} \rightleftharpoons \mathrm{H}_{2}+\mathrm{I}_{2}$ is 0.25 , then the equilibrium constant for the reaction $\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons \quad 2 \mathrm{HI}$ would be

1 1
2 2
3 3
4 4
BITSAT 2009
Chemical Equilibrium

229288 For the reaction, $2 B+A \rightleftharpoons \quad C$, the equilibrium constant is-

1 $\frac{[\mathrm{A}][\mathrm{B}]^{3}}{[\mathrm{C}]}$
2 $\frac{[\mathrm{C}]}{[\mathrm{A}][2 \mathrm{~B}]}$
3 $\frac{[\mathrm{C}]}{[\mathrm{A}][\mathrm{B}]^{2}}$
4 $\frac{[\mathrm{A}][\mathrm{B}]}{[\mathrm{C}]}$
BCECE-2009
Chemical Equilibrium

229289 One mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ is heated in a flask with a volume of $0.1 \mathrm{dm}^{3}$. At equilibrium 1.708 mole of $\mathrm{NO}_{2}$ and 0.146 mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ were found at $134^{0} \mathrm{C}$. The equilibrium constant will be

1 $250 \mathrm{~mol} \mathrm{dm}^{-3}$
2 $300 \mathrm{~mol} \mathrm{dm}^{-3}$
3 $200 \mathrm{~mol} \mathrm{dm}^{-3}$
4 $230 \mathrm{~mol} \mathrm{dm}^{-3}$
MPPET-2009
Chemical Equilibrium

229290 Assertion : For reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Unit of $\mathrm{K}_{\mathrm{c}}=\mathrm{L}^{2} \mathrm{~mol}^{-2}$
Reason : For the reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Equilibrium constant, $K_{c}=\frac{\left[\mathrm{NH}_{3}\right]^{2}}{\left[\mathrm{~N}_{2}\right]\left[\mathrm{H}_{2}\right]^{3}}$

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 In the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the assertion is incorrect but the Reason is correct.
AIIMS-(2008)
For More Updates join with Us
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Chemical Equilibrium

229284 Calculate $K_{c}$ for the reversible process given below if $K_{p}=167$ and $T=800^{\circ} \mathrm{C}$.
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$

1 1.95
2 1.85
3 1.89
4 1.60
WB-JEE-2010
Chemical Equilibrium

229287 If the equilibrium constant of the reaction $2 \mathrm{HI} \rightleftharpoons \mathrm{H}_{2}+\mathrm{I}_{2}$ is 0.25 , then the equilibrium constant for the reaction $\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons \quad 2 \mathrm{HI}$ would be

1 1
2 2
3 3
4 4
BITSAT 2009
Chemical Equilibrium

229288 For the reaction, $2 B+A \rightleftharpoons \quad C$, the equilibrium constant is-

1 $\frac{[\mathrm{A}][\mathrm{B}]^{3}}{[\mathrm{C}]}$
2 $\frac{[\mathrm{C}]}{[\mathrm{A}][2 \mathrm{~B}]}$
3 $\frac{[\mathrm{C}]}{[\mathrm{A}][\mathrm{B}]^{2}}$
4 $\frac{[\mathrm{A}][\mathrm{B}]}{[\mathrm{C}]}$
BCECE-2009
Chemical Equilibrium

229289 One mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ is heated in a flask with a volume of $0.1 \mathrm{dm}^{3}$. At equilibrium 1.708 mole of $\mathrm{NO}_{2}$ and 0.146 mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ were found at $134^{0} \mathrm{C}$. The equilibrium constant will be

1 $250 \mathrm{~mol} \mathrm{dm}^{-3}$
2 $300 \mathrm{~mol} \mathrm{dm}^{-3}$
3 $200 \mathrm{~mol} \mathrm{dm}^{-3}$
4 $230 \mathrm{~mol} \mathrm{dm}^{-3}$
MPPET-2009
Chemical Equilibrium

229290 Assertion : For reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Unit of $\mathrm{K}_{\mathrm{c}}=\mathrm{L}^{2} \mathrm{~mol}^{-2}$
Reason : For the reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Equilibrium constant, $K_{c}=\frac{\left[\mathrm{NH}_{3}\right]^{2}}{\left[\mathrm{~N}_{2}\right]\left[\mathrm{H}_{2}\right]^{3}}$

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 In the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the assertion is incorrect but the Reason is correct.
AIIMS-(2008)
NEET DIGITAL LIBRARY
Chemical Equilibrium

229284 Calculate $K_{c}$ for the reversible process given below if $K_{p}=167$ and $T=800^{\circ} \mathrm{C}$.
$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})$

1 1.95
2 1.85
3 1.89
4 1.60
WB-JEE-2010
Chemical Equilibrium

229287 If the equilibrium constant of the reaction $2 \mathrm{HI} \rightleftharpoons \mathrm{H}_{2}+\mathrm{I}_{2}$ is 0.25 , then the equilibrium constant for the reaction $\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons \quad 2 \mathrm{HI}$ would be

1 1
2 2
3 3
4 4
BITSAT 2009
Chemical Equilibrium

229288 For the reaction, $2 B+A \rightleftharpoons \quad C$, the equilibrium constant is-

1 $\frac{[\mathrm{A}][\mathrm{B}]^{3}}{[\mathrm{C}]}$
2 $\frac{[\mathrm{C}]}{[\mathrm{A}][2 \mathrm{~B}]}$
3 $\frac{[\mathrm{C}]}{[\mathrm{A}][\mathrm{B}]^{2}}$
4 $\frac{[\mathrm{A}][\mathrm{B}]}{[\mathrm{C}]}$
BCECE-2009
Chemical Equilibrium

229289 One mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ is heated in a flask with a volume of $0.1 \mathrm{dm}^{3}$. At equilibrium 1.708 mole of $\mathrm{NO}_{2}$ and 0.146 mole of $\mathrm{N}_{2} \mathrm{O}_{4}$ were found at $134^{0} \mathrm{C}$. The equilibrium constant will be

1 $250 \mathrm{~mol} \mathrm{dm}^{-3}$
2 $300 \mathrm{~mol} \mathrm{dm}^{-3}$
3 $200 \mathrm{~mol} \mathrm{dm}^{-3}$
4 $230 \mathrm{~mol} \mathrm{dm}^{-3}$
MPPET-2009
Chemical Equilibrium

229290 Assertion : For reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Unit of $\mathrm{K}_{\mathrm{c}}=\mathrm{L}^{2} \mathrm{~mol}^{-2}$
Reason : For the reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
Equilibrium constant, $K_{c}=\frac{\left[\mathrm{NH}_{3}\right]^{2}}{\left[\mathrm{~N}_{2}\right]\left[\mathrm{H}_{2}\right]^{3}}$

1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 In the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the assertion is incorrect but the Reason is correct.
AIIMS-(2008)