273075
In an irreverible process taking place at constant $T$ and $p$ and in which only pressure- volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria
An irreversible process (i.e. spontaneous process ) $(\mathrm{ds})_{\mathrm{V}, \mathrm{E}}$ (change in entropy) $=+\mathrm{ve}>0$ $(\mathrm{dG})_{\mathrm{T}, \mathrm{p}}$ (change in Gibbs free energy) $=-\mathrm{ve}<0$
AIEEE-2003
Thermodynamics
273078
The incorrect expression among the following is
273084
When compared to $\Delta G^{\circ}$ for the formation of $\mathrm{Al}_2 \mathrm{O}_3$, the $\Delta \mathrm{G}^0$ for the formation of $\mathrm{Cr}_2 \mathrm{O}_3$ is
1 Higher
2 Lower
3 Unpredicted
4 Same
Explanation:
Between $\mathrm{Al}_2 \mathrm{O}_3$ and $\mathrm{Cr}_2 \mathrm{O}_3, \mathrm{Al}_2 \mathrm{O}_3$ is more stable, so its ease of formation is high i.e., $\Delta \mathrm{G}^{\circ}$ is negative or less than that of $\mathrm{Cr}_2 \mathrm{O}_3$.
Hence, $\Delta \mathrm{G}^{\circ}$ of $\mathrm{Cr}_2 \mathrm{O}_3>\Delta \mathrm{G}^{\circ}$ of $\mathrm{Al}_2 \mathrm{O}_3$.
273075
In an irreverible process taking place at constant $T$ and $p$ and in which only pressure- volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria
An irreversible process (i.e. spontaneous process ) $(\mathrm{ds})_{\mathrm{V}, \mathrm{E}}$ (change in entropy) $=+\mathrm{ve}>0$ $(\mathrm{dG})_{\mathrm{T}, \mathrm{p}}$ (change in Gibbs free energy) $=-\mathrm{ve}<0$
AIEEE-2003
Thermodynamics
273078
The incorrect expression among the following is
273084
When compared to $\Delta G^{\circ}$ for the formation of $\mathrm{Al}_2 \mathrm{O}_3$, the $\Delta \mathrm{G}^0$ for the formation of $\mathrm{Cr}_2 \mathrm{O}_3$ is
1 Higher
2 Lower
3 Unpredicted
4 Same
Explanation:
Between $\mathrm{Al}_2 \mathrm{O}_3$ and $\mathrm{Cr}_2 \mathrm{O}_3, \mathrm{Al}_2 \mathrm{O}_3$ is more stable, so its ease of formation is high i.e., $\Delta \mathrm{G}^{\circ}$ is negative or less than that of $\mathrm{Cr}_2 \mathrm{O}_3$.
Hence, $\Delta \mathrm{G}^{\circ}$ of $\mathrm{Cr}_2 \mathrm{O}_3>\Delta \mathrm{G}^{\circ}$ of $\mathrm{Al}_2 \mathrm{O}_3$.
273075
In an irreverible process taking place at constant $T$ and $p$ and in which only pressure- volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria
An irreversible process (i.e. spontaneous process ) $(\mathrm{ds})_{\mathrm{V}, \mathrm{E}}$ (change in entropy) $=+\mathrm{ve}>0$ $(\mathrm{dG})_{\mathrm{T}, \mathrm{p}}$ (change in Gibbs free energy) $=-\mathrm{ve}<0$
AIEEE-2003
Thermodynamics
273078
The incorrect expression among the following is
273084
When compared to $\Delta G^{\circ}$ for the formation of $\mathrm{Al}_2 \mathrm{O}_3$, the $\Delta \mathrm{G}^0$ for the formation of $\mathrm{Cr}_2 \mathrm{O}_3$ is
1 Higher
2 Lower
3 Unpredicted
4 Same
Explanation:
Between $\mathrm{Al}_2 \mathrm{O}_3$ and $\mathrm{Cr}_2 \mathrm{O}_3, \mathrm{Al}_2 \mathrm{O}_3$ is more stable, so its ease of formation is high i.e., $\Delta \mathrm{G}^{\circ}$ is negative or less than that of $\mathrm{Cr}_2 \mathrm{O}_3$.
Hence, $\Delta \mathrm{G}^{\circ}$ of $\mathrm{Cr}_2 \mathrm{O}_3>\Delta \mathrm{G}^{\circ}$ of $\mathrm{Al}_2 \mathrm{O}_3$.
273075
In an irreverible process taking place at constant $T$ and $p$ and in which only pressure- volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS), satisfy the criteria
An irreversible process (i.e. spontaneous process ) $(\mathrm{ds})_{\mathrm{V}, \mathrm{E}}$ (change in entropy) $=+\mathrm{ve}>0$ $(\mathrm{dG})_{\mathrm{T}, \mathrm{p}}$ (change in Gibbs free energy) $=-\mathrm{ve}<0$
AIEEE-2003
Thermodynamics
273078
The incorrect expression among the following is
273084
When compared to $\Delta G^{\circ}$ for the formation of $\mathrm{Al}_2 \mathrm{O}_3$, the $\Delta \mathrm{G}^0$ for the formation of $\mathrm{Cr}_2 \mathrm{O}_3$ is
1 Higher
2 Lower
3 Unpredicted
4 Same
Explanation:
Between $\mathrm{Al}_2 \mathrm{O}_3$ and $\mathrm{Cr}_2 \mathrm{O}_3, \mathrm{Al}_2 \mathrm{O}_3$ is more stable, so its ease of formation is high i.e., $\Delta \mathrm{G}^{\circ}$ is negative or less than that of $\mathrm{Cr}_2 \mathrm{O}_3$.
Hence, $\Delta \mathrm{G}^{\circ}$ of $\mathrm{Cr}_2 \mathrm{O}_3>\Delta \mathrm{G}^{\circ}$ of $\mathrm{Al}_2 \mathrm{O}_3$.