NEET Test Series from KOTA - 10 Papers In MS WORD
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Classification of Elements and Periodicity in Properties
89550
If the ionization energy and electron affinity of an element are 275 and 86 kcal $\mathrm{mol}^{-}$ respectively, then electronegativity of the element on the Mulliken scale is 5. Ionization Energy
1 2.8
2 0.0
3 4.0
4 2.6
Explanation:
Given that Ionisation energy (I.E) $=275 \mathrm{Kcal} / \mathrm{mol}$ Electron affinity (E.A) $=86 \mathrm{Kcal} / \mathrm{mol}$ According to Mulliken, electronegativity of an atom is average of IE and E.A. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{2}$ If IE and E.A are in K.cal.mol ${ }^{-1}$. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{125}=\frac{275+86}{125}=2.88 \text {. }$
A.P.EAMCET 1992
Classification of Elements and Periodicity in Properties
89551
If the ionization energy and electron affinity of an element are 275 and 86 kcal $\mathrm{mol}^{-}$ respectively, then electronegativity of the element on the Mulliken scale is 5. Ionization Energy
1 2.8
2 0.0
3 4.0
4 2.6
Explanation:
Given that Ionisation energy (I.E) $=275 \mathrm{Kcal} / \mathrm{mol}$ Electron affinity (E.A) $=86 \mathrm{Kcal} / \mathrm{mol}$ According to Mulliken, electronegativity of an atom is average of IE and E.A. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{2}$ If IE and E.A are in K.cal.mol ${ }^{-1}$. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{125}=\frac{275+86}{125}=2.88 \text {. }$
A.P.EAMCET 1992
Classification of Elements and Periodicity in Properties
89522
The correct increasing order of the electronegativity is
1 B $<$ C $<$ S $<$ Cl
2 B $<$ S $<$ C $<$ Cl
3 B $<\mathrm{C}<\mathrm{Cl}<\mathrm{S}$
4 C $<$ B $<$ S $<$ Cl
Explanation:
When we move left to right in the period then electronegative increases whereas electronegativity decreases down the group. Hence, the correct order will be- $$ \mathrm{B}<\mathrm{C}<\mathrm{S}<\mathrm{Cl} $$
TS-EAMCET (Engg.)
Classification of Elements and Periodicity in Properties
89523
The electronegativity order of the following elements is
Classification of Elements and Periodicity in Properties
89550
If the ionization energy and electron affinity of an element are 275 and 86 kcal $\mathrm{mol}^{-}$ respectively, then electronegativity of the element on the Mulliken scale is 5. Ionization Energy
1 2.8
2 0.0
3 4.0
4 2.6
Explanation:
Given that Ionisation energy (I.E) $=275 \mathrm{Kcal} / \mathrm{mol}$ Electron affinity (E.A) $=86 \mathrm{Kcal} / \mathrm{mol}$ According to Mulliken, electronegativity of an atom is average of IE and E.A. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{2}$ If IE and E.A are in K.cal.mol ${ }^{-1}$. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{125}=\frac{275+86}{125}=2.88 \text {. }$
A.P.EAMCET 1992
Classification of Elements and Periodicity in Properties
89551
If the ionization energy and electron affinity of an element are 275 and 86 kcal $\mathrm{mol}^{-}$ respectively, then electronegativity of the element on the Mulliken scale is 5. Ionization Energy
1 2.8
2 0.0
3 4.0
4 2.6
Explanation:
Given that Ionisation energy (I.E) $=275 \mathrm{Kcal} / \mathrm{mol}$ Electron affinity (E.A) $=86 \mathrm{Kcal} / \mathrm{mol}$ According to Mulliken, electronegativity of an atom is average of IE and E.A. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{2}$ If IE and E.A are in K.cal.mol ${ }^{-1}$. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{125}=\frac{275+86}{125}=2.88 \text {. }$
A.P.EAMCET 1992
Classification of Elements and Periodicity in Properties
89522
The correct increasing order of the electronegativity is
1 B $<$ C $<$ S $<$ Cl
2 B $<$ S $<$ C $<$ Cl
3 B $<\mathrm{C}<\mathrm{Cl}<\mathrm{S}$
4 C $<$ B $<$ S $<$ Cl
Explanation:
When we move left to right in the period then electronegative increases whereas electronegativity decreases down the group. Hence, the correct order will be- $$ \mathrm{B}<\mathrm{C}<\mathrm{S}<\mathrm{Cl} $$
TS-EAMCET (Engg.)
Classification of Elements and Periodicity in Properties
89523
The electronegativity order of the following elements is
Classification of Elements and Periodicity in Properties
89550
If the ionization energy and electron affinity of an element are 275 and 86 kcal $\mathrm{mol}^{-}$ respectively, then electronegativity of the element on the Mulliken scale is 5. Ionization Energy
1 2.8
2 0.0
3 4.0
4 2.6
Explanation:
Given that Ionisation energy (I.E) $=275 \mathrm{Kcal} / \mathrm{mol}$ Electron affinity (E.A) $=86 \mathrm{Kcal} / \mathrm{mol}$ According to Mulliken, electronegativity of an atom is average of IE and E.A. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{2}$ If IE and E.A are in K.cal.mol ${ }^{-1}$. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{125}=\frac{275+86}{125}=2.88 \text {. }$
A.P.EAMCET 1992
Classification of Elements and Periodicity in Properties
89551
If the ionization energy and electron affinity of an element are 275 and 86 kcal $\mathrm{mol}^{-}$ respectively, then electronegativity of the element on the Mulliken scale is 5. Ionization Energy
1 2.8
2 0.0
3 4.0
4 2.6
Explanation:
Given that Ionisation energy (I.E) $=275 \mathrm{Kcal} / \mathrm{mol}$ Electron affinity (E.A) $=86 \mathrm{Kcal} / \mathrm{mol}$ According to Mulliken, electronegativity of an atom is average of IE and E.A. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{2}$ If IE and E.A are in K.cal.mol ${ }^{-1}$. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{125}=\frac{275+86}{125}=2.88 \text {. }$
A.P.EAMCET 1992
Classification of Elements and Periodicity in Properties
89522
The correct increasing order of the electronegativity is
1 B $<$ C $<$ S $<$ Cl
2 B $<$ S $<$ C $<$ Cl
3 B $<\mathrm{C}<\mathrm{Cl}<\mathrm{S}$
4 C $<$ B $<$ S $<$ Cl
Explanation:
When we move left to right in the period then electronegative increases whereas electronegativity decreases down the group. Hence, the correct order will be- $$ \mathrm{B}<\mathrm{C}<\mathrm{S}<\mathrm{Cl} $$
TS-EAMCET (Engg.)
Classification of Elements and Periodicity in Properties
89523
The electronegativity order of the following elements is
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Classification of Elements and Periodicity in Properties
89550
If the ionization energy and electron affinity of an element are 275 and 86 kcal $\mathrm{mol}^{-}$ respectively, then electronegativity of the element on the Mulliken scale is 5. Ionization Energy
1 2.8
2 0.0
3 4.0
4 2.6
Explanation:
Given that Ionisation energy (I.E) $=275 \mathrm{Kcal} / \mathrm{mol}$ Electron affinity (E.A) $=86 \mathrm{Kcal} / \mathrm{mol}$ According to Mulliken, electronegativity of an atom is average of IE and E.A. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{2}$ If IE and E.A are in K.cal.mol ${ }^{-1}$. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{125}=\frac{275+86}{125}=2.88 \text {. }$
A.P.EAMCET 1992
Classification of Elements and Periodicity in Properties
89551
If the ionization energy and electron affinity of an element are 275 and 86 kcal $\mathrm{mol}^{-}$ respectively, then electronegativity of the element on the Mulliken scale is 5. Ionization Energy
1 2.8
2 0.0
3 4.0
4 2.6
Explanation:
Given that Ionisation energy (I.E) $=275 \mathrm{Kcal} / \mathrm{mol}$ Electron affinity (E.A) $=86 \mathrm{Kcal} / \mathrm{mol}$ According to Mulliken, electronegativity of an atom is average of IE and E.A. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{2}$ If IE and E.A are in K.cal.mol ${ }^{-1}$. $\mathrm{EN}=\frac{\mathrm{IE}+\mathrm{EA}}{125}=\frac{275+86}{125}=2.88 \text {. }$
A.P.EAMCET 1992
Classification of Elements and Periodicity in Properties
89522
The correct increasing order of the electronegativity is
1 B $<$ C $<$ S $<$ Cl
2 B $<$ S $<$ C $<$ Cl
3 B $<\mathrm{C}<\mathrm{Cl}<\mathrm{S}$
4 C $<$ B $<$ S $<$ Cl
Explanation:
When we move left to right in the period then electronegative increases whereas electronegativity decreases down the group. Hence, the correct order will be- $$ \mathrm{B}<\mathrm{C}<\mathrm{S}<\mathrm{Cl} $$
TS-EAMCET (Engg.)
Classification of Elements and Periodicity in Properties
89523
The electronegativity order of the following elements is