03. Electro negativity
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Classification of Elements and Periodicity in Properties

89538 Which of the following is second most electronegative element?

1 Chlorine
2 Oxygen
3 Sulphur
4 Fluorine
UP CPMT-2007
Classification of Elements and Periodicity in Properties

89515 Correct order of electronegativeity is:

1 $\mathrm{F}>\mathrm{O}>\mathrm{Cl}=\mathrm{N}$
2 $\mathrm{F}>\mathrm{Cl}>\mathrm{O}>\mathrm{N}$
3 $\mathrm{Cl}>\mathrm{F}>\mathrm{O}<\mathrm{N}$
4 None of these
CG PET-22.05.2022
Classification of Elements and Periodicity in Properties

89520 Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Dipole - dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.
Reason (R) : Fluorine is the most electronegative element and hydrogen bonds in HF are symmetrical.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 $A$ is false but $R$ is true.
2 Both $\mathrm{A}$ and $\mathrm{R}$ are true and $\mathrm{R}$ is the correct explanation of $A$.
3 $A$ is true $\mathrm{R}$ is false.
4 Both $\mathrm{A}$ and $\mathrm{R}$ are true but $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$.
(JEE Main 2021
Classification of Elements and Periodicity in Properties

89525 Given that ionization potential and electron gain enthalpy of chlorine are $13 \mathrm{eV}$ and $4 \mathrm{eV}$ respectively. The electronegativity of chlorine on Mulliken scale approximately equals to

1 $8.5 \mathrm{eV}$
2 $6.0 \mathrm{eV}$
3 $3.0 \mathrm{eV}$
4 $1.5 \mathrm{eV}$
AP EAPCET 19-08-2021 Shift-I
Classification of Elements and Periodicity in Properties

89529 The correct option with respect to the Pauling electronegativity values of the elements is

1 $\mathrm{P}>\mathrm{S}$
2 Si $<\mathrm{Al}$
3 $\mathrm{Te}>\mathrm{Se}$
4 $\mathrm{Ga}<\mathrm{Ge}$
(JEE Main 2019
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Classification of Elements and Periodicity in Properties

89538 Which of the following is second most electronegative element?

1 Chlorine
2 Oxygen
3 Sulphur
4 Fluorine
UP CPMT-2007
Classification of Elements and Periodicity in Properties

89515 Correct order of electronegativeity is:

1 $\mathrm{F}>\mathrm{O}>\mathrm{Cl}=\mathrm{N}$
2 $\mathrm{F}>\mathrm{Cl}>\mathrm{O}>\mathrm{N}$
3 $\mathrm{Cl}>\mathrm{F}>\mathrm{O}<\mathrm{N}$
4 None of these
CG PET-22.05.2022
Classification of Elements and Periodicity in Properties

89520 Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Dipole - dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.
Reason (R) : Fluorine is the most electronegative element and hydrogen bonds in HF are symmetrical.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 $A$ is false but $R$ is true.
2 Both $\mathrm{A}$ and $\mathrm{R}$ are true and $\mathrm{R}$ is the correct explanation of $A$.
3 $A$ is true $\mathrm{R}$ is false.
4 Both $\mathrm{A}$ and $\mathrm{R}$ are true but $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$.
(JEE Main 2021
Classification of Elements and Periodicity in Properties

89525 Given that ionization potential and electron gain enthalpy of chlorine are $13 \mathrm{eV}$ and $4 \mathrm{eV}$ respectively. The electronegativity of chlorine on Mulliken scale approximately equals to

1 $8.5 \mathrm{eV}$
2 $6.0 \mathrm{eV}$
3 $3.0 \mathrm{eV}$
4 $1.5 \mathrm{eV}$
AP EAPCET 19-08-2021 Shift-I
Classification of Elements and Periodicity in Properties

89529 The correct option with respect to the Pauling electronegativity values of the elements is

1 $\mathrm{P}>\mathrm{S}$
2 Si $<\mathrm{Al}$
3 $\mathrm{Te}>\mathrm{Se}$
4 $\mathrm{Ga}<\mathrm{Ge}$
(JEE Main 2019
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NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Classification of Elements and Periodicity in Properties

89538 Which of the following is second most electronegative element?

1 Chlorine
2 Oxygen
3 Sulphur
4 Fluorine
UP CPMT-2007
Classification of Elements and Periodicity in Properties

89515 Correct order of electronegativeity is:

1 $\mathrm{F}>\mathrm{O}>\mathrm{Cl}=\mathrm{N}$
2 $\mathrm{F}>\mathrm{Cl}>\mathrm{O}>\mathrm{N}$
3 $\mathrm{Cl}>\mathrm{F}>\mathrm{O}<\mathrm{N}$
4 None of these
CG PET-22.05.2022
Classification of Elements and Periodicity in Properties

89520 Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Dipole - dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.
Reason (R) : Fluorine is the most electronegative element and hydrogen bonds in HF are symmetrical.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 $A$ is false but $R$ is true.
2 Both $\mathrm{A}$ and $\mathrm{R}$ are true and $\mathrm{R}$ is the correct explanation of $A$.
3 $A$ is true $\mathrm{R}$ is false.
4 Both $\mathrm{A}$ and $\mathrm{R}$ are true but $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$.
(JEE Main 2021
Classification of Elements and Periodicity in Properties

89525 Given that ionization potential and electron gain enthalpy of chlorine are $13 \mathrm{eV}$ and $4 \mathrm{eV}$ respectively. The electronegativity of chlorine on Mulliken scale approximately equals to

1 $8.5 \mathrm{eV}$
2 $6.0 \mathrm{eV}$
3 $3.0 \mathrm{eV}$
4 $1.5 \mathrm{eV}$
AP EAPCET 19-08-2021 Shift-I
Classification of Elements and Periodicity in Properties

89529 The correct option with respect to the Pauling electronegativity values of the elements is

1 $\mathrm{P}>\mathrm{S}$
2 Si $<\mathrm{Al}$
3 $\mathrm{Te}>\mathrm{Se}$
4 $\mathrm{Ga}<\mathrm{Ge}$
(JEE Main 2019
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Classification of Elements and Periodicity in Properties

89538 Which of the following is second most electronegative element?

1 Chlorine
2 Oxygen
3 Sulphur
4 Fluorine
UP CPMT-2007
Classification of Elements and Periodicity in Properties

89515 Correct order of electronegativeity is:

1 $\mathrm{F}>\mathrm{O}>\mathrm{Cl}=\mathrm{N}$
2 $\mathrm{F}>\mathrm{Cl}>\mathrm{O}>\mathrm{N}$
3 $\mathrm{Cl}>\mathrm{F}>\mathrm{O}<\mathrm{N}$
4 None of these
CG PET-22.05.2022
Classification of Elements and Periodicity in Properties

89520 Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Dipole - dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.
Reason (R) : Fluorine is the most electronegative element and hydrogen bonds in HF are symmetrical.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 $A$ is false but $R$ is true.
2 Both $\mathrm{A}$ and $\mathrm{R}$ are true and $\mathrm{R}$ is the correct explanation of $A$.
3 $A$ is true $\mathrm{R}$ is false.
4 Both $\mathrm{A}$ and $\mathrm{R}$ are true but $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$.
(JEE Main 2021
Classification of Elements and Periodicity in Properties

89525 Given that ionization potential and electron gain enthalpy of chlorine are $13 \mathrm{eV}$ and $4 \mathrm{eV}$ respectively. The electronegativity of chlorine on Mulliken scale approximately equals to

1 $8.5 \mathrm{eV}$
2 $6.0 \mathrm{eV}$
3 $3.0 \mathrm{eV}$
4 $1.5 \mathrm{eV}$
AP EAPCET 19-08-2021 Shift-I
Classification of Elements and Periodicity in Properties

89529 The correct option with respect to the Pauling electronegativity values of the elements is

1 $\mathrm{P}>\mathrm{S}$
2 Si $<\mathrm{Al}$
3 $\mathrm{Te}>\mathrm{Se}$
4 $\mathrm{Ga}<\mathrm{Ge}$
(JEE Main 2019
Join With Us for More Updates
Classification of Elements and Periodicity in Properties

89538 Which of the following is second most electronegative element?

1 Chlorine
2 Oxygen
3 Sulphur
4 Fluorine
UP CPMT-2007
Classification of Elements and Periodicity in Properties

89515 Correct order of electronegativeity is:

1 $\mathrm{F}>\mathrm{O}>\mathrm{Cl}=\mathrm{N}$
2 $\mathrm{F}>\mathrm{Cl}>\mathrm{O}>\mathrm{N}$
3 $\mathrm{Cl}>\mathrm{F}>\mathrm{O}<\mathrm{N}$
4 None of these
CG PET-22.05.2022
Classification of Elements and Periodicity in Properties

89520 Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Dipole - dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.
Reason (R) : Fluorine is the most electronegative element and hydrogen bonds in HF are symmetrical.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 $A$ is false but $R$ is true.
2 Both $\mathrm{A}$ and $\mathrm{R}$ are true and $\mathrm{R}$ is the correct explanation of $A$.
3 $A$ is true $\mathrm{R}$ is false.
4 Both $\mathrm{A}$ and $\mathrm{R}$ are true but $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$.
(JEE Main 2021
Classification of Elements and Periodicity in Properties

89525 Given that ionization potential and electron gain enthalpy of chlorine are $13 \mathrm{eV}$ and $4 \mathrm{eV}$ respectively. The electronegativity of chlorine on Mulliken scale approximately equals to

1 $8.5 \mathrm{eV}$
2 $6.0 \mathrm{eV}$
3 $3.0 \mathrm{eV}$
4 $1.5 \mathrm{eV}$
AP EAPCET 19-08-2021 Shift-I
Classification of Elements and Periodicity in Properties

89529 The correct option with respect to the Pauling electronegativity values of the elements is

1 $\mathrm{P}>\mathrm{S}$
2 Si $<\mathrm{Al}$
3 $\mathrm{Te}>\mathrm{Se}$
4 $\mathrm{Ga}<\mathrm{Ge}$
(JEE Main 2019