Nucleosome are the basic packing unit of genomic DNA built from histone proteins around which DNA is coiled. - Chromosome :- A chromosome is a long DNA molecule with part or all of the genetic material of an organisms.
Karnataka CET-2022
Molecular Basis of Inheritance and
166098
The length of DNA having 23 base pair is
1 \(78 \AA\)
2 \(78.4 \AA\)
3 \(74.8 \AA\)
4 \(78.2 \AA\)
Explanation:
The lenght of DNA having 23 base pair is 78.2 \(\AA\). The distance between first and second base pair will be \(3.4 \AA\) similarly, The distance between 23 base pairs will be \(3.4 \times 23=78.2 \AA\). - DNA is the genetic material. The nucleotides are the major structural unit of the DNA. \(\begin{aligned} & \text { - The backbone is connected by covalent bonds. } \\ & \text { - The bases are connected by hydrogen bonds. } \end{aligned}\)
WB JEE-2009
Molecular Basis of Inheritance and
166100
Which of the following is structural subunit of DNA?
1 Protein
2 Carbohydrate
3 RNA
4 Nucleotide
Explanation:
A nucleotide is the basic building block of nucleic acid (DNA \& RNA). Nucleotide has 3 smallest molecules. (i) Nitrogenous bases (ii) A molecule of a pentose sugar (iii) A phosphate group All linked by dehydration condensation.
WB JEE-2010
Molecular Basis of Inheritance and
166122
In a DNA molecule, the adenine is \(15 \%\) what will be the percentage of guanine in this DNA?
1 \(15 \%\)
2 \(35 \%\)
3 \(70 \%\)
4 \(30 \%\)
Explanation:
If adenine (A) is present in a DNA molecule at \(15 \%\), it means that thymine (T), which pairs with adenine, would also be present at \(15 \%\) because they always occur in equal proportions due to this pairing rule. So, in this DNA molecule; \(\mathrm{A}=15 \%\) \(\mathrm{T}\), which pairs with A, would also be \(15 \%\) Since guanine (G) pairs with cytosine (C), the remaining \(70 \%\) of the DNA bases would be made up of guanine \((\mathrm{G})\) and cytosine \((\mathrm{C})\) in equal proportions: \(\mathrm{G}=70 \% / 2=35 \%\) \(\mathrm{C}=70 \% / 2=35 \%\)
DUMET-2008
Molecular Basis of Inheritance and
166131
What is the length of human DNA containing \(6.6 \times 10^{9} \mathrm{bp}\) ?
1 \(22 \mathrm{~nm}\)
2 \(0.22 \mathrm{~mm}\)
3 \(2.2 \mathrm{~m}\)
4 \(22 \mathrm{~m}\)
Explanation:
The length of human DNA containing \(6.6 \times\) \(10^{9}\) base pair can be calculated as follows: \(1 \mathrm{bp}=0.34\) nanometers. So, the length would be \(6.6 \times 10^{9} \mathrm{bp} \times 0.34 \mathrm{~nm} / \mathrm{bp}\) \(=2.244 \times 10^{9} \mathrm{~nm}\) To convert \(\mathrm{nm}\) to meters: \(\begin{aligned} 2.244 \times 10^{9} \mathrm{~nm}= & \frac{2.244 \times 10^{9} \mathrm{~nm} \times 1 \mathrm{n}}{1,000,000,000 \mathrm{~nm}} \\ & =2.244 \text { meter. } \\ & =2.2 \mathrm{~m} . \end{aligned}\)
Nucleosome are the basic packing unit of genomic DNA built from histone proteins around which DNA is coiled. - Chromosome :- A chromosome is a long DNA molecule with part or all of the genetic material of an organisms.
Karnataka CET-2022
Molecular Basis of Inheritance and
166098
The length of DNA having 23 base pair is
1 \(78 \AA\)
2 \(78.4 \AA\)
3 \(74.8 \AA\)
4 \(78.2 \AA\)
Explanation:
The lenght of DNA having 23 base pair is 78.2 \(\AA\). The distance between first and second base pair will be \(3.4 \AA\) similarly, The distance between 23 base pairs will be \(3.4 \times 23=78.2 \AA\). - DNA is the genetic material. The nucleotides are the major structural unit of the DNA. \(\begin{aligned} & \text { - The backbone is connected by covalent bonds. } \\ & \text { - The bases are connected by hydrogen bonds. } \end{aligned}\)
WB JEE-2009
Molecular Basis of Inheritance and
166100
Which of the following is structural subunit of DNA?
1 Protein
2 Carbohydrate
3 RNA
4 Nucleotide
Explanation:
A nucleotide is the basic building block of nucleic acid (DNA \& RNA). Nucleotide has 3 smallest molecules. (i) Nitrogenous bases (ii) A molecule of a pentose sugar (iii) A phosphate group All linked by dehydration condensation.
WB JEE-2010
Molecular Basis of Inheritance and
166122
In a DNA molecule, the adenine is \(15 \%\) what will be the percentage of guanine in this DNA?
1 \(15 \%\)
2 \(35 \%\)
3 \(70 \%\)
4 \(30 \%\)
Explanation:
If adenine (A) is present in a DNA molecule at \(15 \%\), it means that thymine (T), which pairs with adenine, would also be present at \(15 \%\) because they always occur in equal proportions due to this pairing rule. So, in this DNA molecule; \(\mathrm{A}=15 \%\) \(\mathrm{T}\), which pairs with A, would also be \(15 \%\) Since guanine (G) pairs with cytosine (C), the remaining \(70 \%\) of the DNA bases would be made up of guanine \((\mathrm{G})\) and cytosine \((\mathrm{C})\) in equal proportions: \(\mathrm{G}=70 \% / 2=35 \%\) \(\mathrm{C}=70 \% / 2=35 \%\)
DUMET-2008
Molecular Basis of Inheritance and
166131
What is the length of human DNA containing \(6.6 \times 10^{9} \mathrm{bp}\) ?
1 \(22 \mathrm{~nm}\)
2 \(0.22 \mathrm{~mm}\)
3 \(2.2 \mathrm{~m}\)
4 \(22 \mathrm{~m}\)
Explanation:
The length of human DNA containing \(6.6 \times\) \(10^{9}\) base pair can be calculated as follows: \(1 \mathrm{bp}=0.34\) nanometers. So, the length would be \(6.6 \times 10^{9} \mathrm{bp} \times 0.34 \mathrm{~nm} / \mathrm{bp}\) \(=2.244 \times 10^{9} \mathrm{~nm}\) To convert \(\mathrm{nm}\) to meters: \(\begin{aligned} 2.244 \times 10^{9} \mathrm{~nm}= & \frac{2.244 \times 10^{9} \mathrm{~nm} \times 1 \mathrm{n}}{1,000,000,000 \mathrm{~nm}} \\ & =2.244 \text { meter. } \\ & =2.2 \mathrm{~m} . \end{aligned}\)
Nucleosome are the basic packing unit of genomic DNA built from histone proteins around which DNA is coiled. - Chromosome :- A chromosome is a long DNA molecule with part or all of the genetic material of an organisms.
Karnataka CET-2022
Molecular Basis of Inheritance and
166098
The length of DNA having 23 base pair is
1 \(78 \AA\)
2 \(78.4 \AA\)
3 \(74.8 \AA\)
4 \(78.2 \AA\)
Explanation:
The lenght of DNA having 23 base pair is 78.2 \(\AA\). The distance between first and second base pair will be \(3.4 \AA\) similarly, The distance between 23 base pairs will be \(3.4 \times 23=78.2 \AA\). - DNA is the genetic material. The nucleotides are the major structural unit of the DNA. \(\begin{aligned} & \text { - The backbone is connected by covalent bonds. } \\ & \text { - The bases are connected by hydrogen bonds. } \end{aligned}\)
WB JEE-2009
Molecular Basis of Inheritance and
166100
Which of the following is structural subunit of DNA?
1 Protein
2 Carbohydrate
3 RNA
4 Nucleotide
Explanation:
A nucleotide is the basic building block of nucleic acid (DNA \& RNA). Nucleotide has 3 smallest molecules. (i) Nitrogenous bases (ii) A molecule of a pentose sugar (iii) A phosphate group All linked by dehydration condensation.
WB JEE-2010
Molecular Basis of Inheritance and
166122
In a DNA molecule, the adenine is \(15 \%\) what will be the percentage of guanine in this DNA?
1 \(15 \%\)
2 \(35 \%\)
3 \(70 \%\)
4 \(30 \%\)
Explanation:
If adenine (A) is present in a DNA molecule at \(15 \%\), it means that thymine (T), which pairs with adenine, would also be present at \(15 \%\) because they always occur in equal proportions due to this pairing rule. So, in this DNA molecule; \(\mathrm{A}=15 \%\) \(\mathrm{T}\), which pairs with A, would also be \(15 \%\) Since guanine (G) pairs with cytosine (C), the remaining \(70 \%\) of the DNA bases would be made up of guanine \((\mathrm{G})\) and cytosine \((\mathrm{C})\) in equal proportions: \(\mathrm{G}=70 \% / 2=35 \%\) \(\mathrm{C}=70 \% / 2=35 \%\)
DUMET-2008
Molecular Basis of Inheritance and
166131
What is the length of human DNA containing \(6.6 \times 10^{9} \mathrm{bp}\) ?
1 \(22 \mathrm{~nm}\)
2 \(0.22 \mathrm{~mm}\)
3 \(2.2 \mathrm{~m}\)
4 \(22 \mathrm{~m}\)
Explanation:
The length of human DNA containing \(6.6 \times\) \(10^{9}\) base pair can be calculated as follows: \(1 \mathrm{bp}=0.34\) nanometers. So, the length would be \(6.6 \times 10^{9} \mathrm{bp} \times 0.34 \mathrm{~nm} / \mathrm{bp}\) \(=2.244 \times 10^{9} \mathrm{~nm}\) To convert \(\mathrm{nm}\) to meters: \(\begin{aligned} 2.244 \times 10^{9} \mathrm{~nm}= & \frac{2.244 \times 10^{9} \mathrm{~nm} \times 1 \mathrm{n}}{1,000,000,000 \mathrm{~nm}} \\ & =2.244 \text { meter. } \\ & =2.2 \mathrm{~m} . \end{aligned}\)
Nucleosome are the basic packing unit of genomic DNA built from histone proteins around which DNA is coiled. - Chromosome :- A chromosome is a long DNA molecule with part or all of the genetic material of an organisms.
Karnataka CET-2022
Molecular Basis of Inheritance and
166098
The length of DNA having 23 base pair is
1 \(78 \AA\)
2 \(78.4 \AA\)
3 \(74.8 \AA\)
4 \(78.2 \AA\)
Explanation:
The lenght of DNA having 23 base pair is 78.2 \(\AA\). The distance between first and second base pair will be \(3.4 \AA\) similarly, The distance between 23 base pairs will be \(3.4 \times 23=78.2 \AA\). - DNA is the genetic material. The nucleotides are the major structural unit of the DNA. \(\begin{aligned} & \text { - The backbone is connected by covalent bonds. } \\ & \text { - The bases are connected by hydrogen bonds. } \end{aligned}\)
WB JEE-2009
Molecular Basis of Inheritance and
166100
Which of the following is structural subunit of DNA?
1 Protein
2 Carbohydrate
3 RNA
4 Nucleotide
Explanation:
A nucleotide is the basic building block of nucleic acid (DNA \& RNA). Nucleotide has 3 smallest molecules. (i) Nitrogenous bases (ii) A molecule of a pentose sugar (iii) A phosphate group All linked by dehydration condensation.
WB JEE-2010
Molecular Basis of Inheritance and
166122
In a DNA molecule, the adenine is \(15 \%\) what will be the percentage of guanine in this DNA?
1 \(15 \%\)
2 \(35 \%\)
3 \(70 \%\)
4 \(30 \%\)
Explanation:
If adenine (A) is present in a DNA molecule at \(15 \%\), it means that thymine (T), which pairs with adenine, would also be present at \(15 \%\) because they always occur in equal proportions due to this pairing rule. So, in this DNA molecule; \(\mathrm{A}=15 \%\) \(\mathrm{T}\), which pairs with A, would also be \(15 \%\) Since guanine (G) pairs with cytosine (C), the remaining \(70 \%\) of the DNA bases would be made up of guanine \((\mathrm{G})\) and cytosine \((\mathrm{C})\) in equal proportions: \(\mathrm{G}=70 \% / 2=35 \%\) \(\mathrm{C}=70 \% / 2=35 \%\)
DUMET-2008
Molecular Basis of Inheritance and
166131
What is the length of human DNA containing \(6.6 \times 10^{9} \mathrm{bp}\) ?
1 \(22 \mathrm{~nm}\)
2 \(0.22 \mathrm{~mm}\)
3 \(2.2 \mathrm{~m}\)
4 \(22 \mathrm{~m}\)
Explanation:
The length of human DNA containing \(6.6 \times\) \(10^{9}\) base pair can be calculated as follows: \(1 \mathrm{bp}=0.34\) nanometers. So, the length would be \(6.6 \times 10^{9} \mathrm{bp} \times 0.34 \mathrm{~nm} / \mathrm{bp}\) \(=2.244 \times 10^{9} \mathrm{~nm}\) To convert \(\mathrm{nm}\) to meters: \(\begin{aligned} 2.244 \times 10^{9} \mathrm{~nm}= & \frac{2.244 \times 10^{9} \mathrm{~nm} \times 1 \mathrm{n}}{1,000,000,000 \mathrm{~nm}} \\ & =2.244 \text { meter. } \\ & =2.2 \mathrm{~m} . \end{aligned}\)
Nucleosome are the basic packing unit of genomic DNA built from histone proteins around which DNA is coiled. - Chromosome :- A chromosome is a long DNA molecule with part or all of the genetic material of an organisms.
Karnataka CET-2022
Molecular Basis of Inheritance and
166098
The length of DNA having 23 base pair is
1 \(78 \AA\)
2 \(78.4 \AA\)
3 \(74.8 \AA\)
4 \(78.2 \AA\)
Explanation:
The lenght of DNA having 23 base pair is 78.2 \(\AA\). The distance between first and second base pair will be \(3.4 \AA\) similarly, The distance between 23 base pairs will be \(3.4 \times 23=78.2 \AA\). - DNA is the genetic material. The nucleotides are the major structural unit of the DNA. \(\begin{aligned} & \text { - The backbone is connected by covalent bonds. } \\ & \text { - The bases are connected by hydrogen bonds. } \end{aligned}\)
WB JEE-2009
Molecular Basis of Inheritance and
166100
Which of the following is structural subunit of DNA?
1 Protein
2 Carbohydrate
3 RNA
4 Nucleotide
Explanation:
A nucleotide is the basic building block of nucleic acid (DNA \& RNA). Nucleotide has 3 smallest molecules. (i) Nitrogenous bases (ii) A molecule of a pentose sugar (iii) A phosphate group All linked by dehydration condensation.
WB JEE-2010
Molecular Basis of Inheritance and
166122
In a DNA molecule, the adenine is \(15 \%\) what will be the percentage of guanine in this DNA?
1 \(15 \%\)
2 \(35 \%\)
3 \(70 \%\)
4 \(30 \%\)
Explanation:
If adenine (A) is present in a DNA molecule at \(15 \%\), it means that thymine (T), which pairs with adenine, would also be present at \(15 \%\) because they always occur in equal proportions due to this pairing rule. So, in this DNA molecule; \(\mathrm{A}=15 \%\) \(\mathrm{T}\), which pairs with A, would also be \(15 \%\) Since guanine (G) pairs with cytosine (C), the remaining \(70 \%\) of the DNA bases would be made up of guanine \((\mathrm{G})\) and cytosine \((\mathrm{C})\) in equal proportions: \(\mathrm{G}=70 \% / 2=35 \%\) \(\mathrm{C}=70 \% / 2=35 \%\)
DUMET-2008
Molecular Basis of Inheritance and
166131
What is the length of human DNA containing \(6.6 \times 10^{9} \mathrm{bp}\) ?
1 \(22 \mathrm{~nm}\)
2 \(0.22 \mathrm{~mm}\)
3 \(2.2 \mathrm{~m}\)
4 \(22 \mathrm{~m}\)
Explanation:
The length of human DNA containing \(6.6 \times\) \(10^{9}\) base pair can be calculated as follows: \(1 \mathrm{bp}=0.34\) nanometers. So, the length would be \(6.6 \times 10^{9} \mathrm{bp} \times 0.34 \mathrm{~nm} / \mathrm{bp}\) \(=2.244 \times 10^{9} \mathrm{~nm}\) To convert \(\mathrm{nm}\) to meters: \(\begin{aligned} 2.244 \times 10^{9} \mathrm{~nm}= & \frac{2.244 \times 10^{9} \mathrm{~nm} \times 1 \mathrm{n}}{1,000,000,000 \mathrm{~nm}} \\ & =2.244 \text { meter. } \\ & =2.2 \mathrm{~m} . \end{aligned}\)
