There are 3 different DNA type - A-DNA:- It is right handed double helix similar to the B-DNA. - B-DNA:- This is the most common DNA conformation and is a right handed helix. - Z-DNA:- Z-DNA is a left handed DNA where the double helix wride to the left in a zig-zag pattern. Directions. In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
BHU PMT (Mains)-2008
Molecular Basis of Inheritance and
166175
Match the column- I with column-II and select the correct option
Column-I
Column-II
----------
---------
(A) Female banded Krait
(i) Humulin
(B) Pancreas from dog
(ii) DNA sample
(C) Hair root of human
(iii) Insulin
(D) E. coli
(iv) DNA Probe
1 A-i, B-ii, C-iv, D-iii
2 A-ii, B-i, C-iii, D-iv
3 A-iii, B-iv C-ii, D-i
4 A-iv, B-iii C-ii, D-i
Explanation:
Exp:
Column-I
Column-II
----------------------------
----------------------
(iv) DNA Probe
(A) Female banded Krait
(iii) Insulin extracted and purified
(B) Pancreas from dog
(ii) DNA sample
(C) Hair root of human
(i) Humulin
(D) E. coli
MHT CET-04.10.2020 Shift-I
Molecular Basis of Inheritance and
166180
If the length of a DNA molecule is 1.1 metres, what will be the approximate number of base pairs?
1 \(6.6 \times 10^{6} \mathrm{bp}\)
2 \(3.3 \times 10^{9} \mathrm{bp}\)
3 \(6.6 \times 10^{9} \mathrm{bp}\)
4 \(3.3 \times 10^{6} \mathrm{bp}\)
Explanation:
Length between the two base pairs \(=0.34 \mathrm{~nm}\) Total length of the double helix of DNA = Total number of base pairs \(\mathrm{X}\) distance between the two base pairs. Let us consider the total number of base pairs as \(\mathrm{x}\). \(1.1 \mathrm{~m}=\mathrm{x} \times 304 \times 10^{-10} \mathrm{~m}\) \(\mathrm{x}=3.3 \times 10^{9} \mathrm{bp}\) So, in a \(1.1 \mathrm{~m}\) length of DNA, there unit be about \(3.3 \times\) \(10^{9} \mathrm{bp}\).
NEET-2022
Molecular Basis of Inheritance and
166186
The diagram shows an important concept in the genetic implication of DNA. Fill in the blanks \(A\) to \(C\) :
1 A-translation B-extension C-Roslalind Franklin
2 A-Transcription B-replication C-James Watson
3 A-translation B-transcription C-Erevin Chargaff
4 A-transcription B-translation C-Francis
Explanation:
Cell carry out many vital function. The DNA codes for the production of messenger RNA (mRNA). During transcription messenger RNA carries coded information to ribosome read this information and use it DNA \(\xrightarrow{\text { Transcription }}\) mRNA \(\xrightarrow{\text { Translation }}\) Protein (Francis Crick.)
There are 3 different DNA type - A-DNA:- It is right handed double helix similar to the B-DNA. - B-DNA:- This is the most common DNA conformation and is a right handed helix. - Z-DNA:- Z-DNA is a left handed DNA where the double helix wride to the left in a zig-zag pattern. Directions. In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
BHU PMT (Mains)-2008
Molecular Basis of Inheritance and
166175
Match the column- I with column-II and select the correct option
Column-I
Column-II
----------
---------
(A) Female banded Krait
(i) Humulin
(B) Pancreas from dog
(ii) DNA sample
(C) Hair root of human
(iii) Insulin
(D) E. coli
(iv) DNA Probe
1 A-i, B-ii, C-iv, D-iii
2 A-ii, B-i, C-iii, D-iv
3 A-iii, B-iv C-ii, D-i
4 A-iv, B-iii C-ii, D-i
Explanation:
Exp:
Column-I
Column-II
----------------------------
----------------------
(iv) DNA Probe
(A) Female banded Krait
(iii) Insulin extracted and purified
(B) Pancreas from dog
(ii) DNA sample
(C) Hair root of human
(i) Humulin
(D) E. coli
MHT CET-04.10.2020 Shift-I
Molecular Basis of Inheritance and
166180
If the length of a DNA molecule is 1.1 metres, what will be the approximate number of base pairs?
1 \(6.6 \times 10^{6} \mathrm{bp}\)
2 \(3.3 \times 10^{9} \mathrm{bp}\)
3 \(6.6 \times 10^{9} \mathrm{bp}\)
4 \(3.3 \times 10^{6} \mathrm{bp}\)
Explanation:
Length between the two base pairs \(=0.34 \mathrm{~nm}\) Total length of the double helix of DNA = Total number of base pairs \(\mathrm{X}\) distance between the two base pairs. Let us consider the total number of base pairs as \(\mathrm{x}\). \(1.1 \mathrm{~m}=\mathrm{x} \times 304 \times 10^{-10} \mathrm{~m}\) \(\mathrm{x}=3.3 \times 10^{9} \mathrm{bp}\) So, in a \(1.1 \mathrm{~m}\) length of DNA, there unit be about \(3.3 \times\) \(10^{9} \mathrm{bp}\).
NEET-2022
Molecular Basis of Inheritance and
166186
The diagram shows an important concept in the genetic implication of DNA. Fill in the blanks \(A\) to \(C\) :
1 A-translation B-extension C-Roslalind Franklin
2 A-Transcription B-replication C-James Watson
3 A-translation B-transcription C-Erevin Chargaff
4 A-transcription B-translation C-Francis
Explanation:
Cell carry out many vital function. The DNA codes for the production of messenger RNA (mRNA). During transcription messenger RNA carries coded information to ribosome read this information and use it DNA \(\xrightarrow{\text { Transcription }}\) mRNA \(\xrightarrow{\text { Translation }}\) Protein (Francis Crick.)
There are 3 different DNA type - A-DNA:- It is right handed double helix similar to the B-DNA. - B-DNA:- This is the most common DNA conformation and is a right handed helix. - Z-DNA:- Z-DNA is a left handed DNA where the double helix wride to the left in a zig-zag pattern. Directions. In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
BHU PMT (Mains)-2008
Molecular Basis of Inheritance and
166175
Match the column- I with column-II and select the correct option
Column-I
Column-II
----------
---------
(A) Female banded Krait
(i) Humulin
(B) Pancreas from dog
(ii) DNA sample
(C) Hair root of human
(iii) Insulin
(D) E. coli
(iv) DNA Probe
1 A-i, B-ii, C-iv, D-iii
2 A-ii, B-i, C-iii, D-iv
3 A-iii, B-iv C-ii, D-i
4 A-iv, B-iii C-ii, D-i
Explanation:
Exp:
Column-I
Column-II
----------------------------
----------------------
(iv) DNA Probe
(A) Female banded Krait
(iii) Insulin extracted and purified
(B) Pancreas from dog
(ii) DNA sample
(C) Hair root of human
(i) Humulin
(D) E. coli
MHT CET-04.10.2020 Shift-I
Molecular Basis of Inheritance and
166180
If the length of a DNA molecule is 1.1 metres, what will be the approximate number of base pairs?
1 \(6.6 \times 10^{6} \mathrm{bp}\)
2 \(3.3 \times 10^{9} \mathrm{bp}\)
3 \(6.6 \times 10^{9} \mathrm{bp}\)
4 \(3.3 \times 10^{6} \mathrm{bp}\)
Explanation:
Length between the two base pairs \(=0.34 \mathrm{~nm}\) Total length of the double helix of DNA = Total number of base pairs \(\mathrm{X}\) distance between the two base pairs. Let us consider the total number of base pairs as \(\mathrm{x}\). \(1.1 \mathrm{~m}=\mathrm{x} \times 304 \times 10^{-10} \mathrm{~m}\) \(\mathrm{x}=3.3 \times 10^{9} \mathrm{bp}\) So, in a \(1.1 \mathrm{~m}\) length of DNA, there unit be about \(3.3 \times\) \(10^{9} \mathrm{bp}\).
NEET-2022
Molecular Basis of Inheritance and
166186
The diagram shows an important concept in the genetic implication of DNA. Fill in the blanks \(A\) to \(C\) :
1 A-translation B-extension C-Roslalind Franklin
2 A-Transcription B-replication C-James Watson
3 A-translation B-transcription C-Erevin Chargaff
4 A-transcription B-translation C-Francis
Explanation:
Cell carry out many vital function. The DNA codes for the production of messenger RNA (mRNA). During transcription messenger RNA carries coded information to ribosome read this information and use it DNA \(\xrightarrow{\text { Transcription }}\) mRNA \(\xrightarrow{\text { Translation }}\) Protein (Francis Crick.)
There are 3 different DNA type - A-DNA:- It is right handed double helix similar to the B-DNA. - B-DNA:- This is the most common DNA conformation and is a right handed helix. - Z-DNA:- Z-DNA is a left handed DNA where the double helix wride to the left in a zig-zag pattern. Directions. In the following question more than one of the answers given may be correct. Select the correct answer and mark it according to the code:
BHU PMT (Mains)-2008
Molecular Basis of Inheritance and
166175
Match the column- I with column-II and select the correct option
Column-I
Column-II
----------
---------
(A) Female banded Krait
(i) Humulin
(B) Pancreas from dog
(ii) DNA sample
(C) Hair root of human
(iii) Insulin
(D) E. coli
(iv) DNA Probe
1 A-i, B-ii, C-iv, D-iii
2 A-ii, B-i, C-iii, D-iv
3 A-iii, B-iv C-ii, D-i
4 A-iv, B-iii C-ii, D-i
Explanation:
Exp:
Column-I
Column-II
----------------------------
----------------------
(iv) DNA Probe
(A) Female banded Krait
(iii) Insulin extracted and purified
(B) Pancreas from dog
(ii) DNA sample
(C) Hair root of human
(i) Humulin
(D) E. coli
MHT CET-04.10.2020 Shift-I
Molecular Basis of Inheritance and
166180
If the length of a DNA molecule is 1.1 metres, what will be the approximate number of base pairs?
1 \(6.6 \times 10^{6} \mathrm{bp}\)
2 \(3.3 \times 10^{9} \mathrm{bp}\)
3 \(6.6 \times 10^{9} \mathrm{bp}\)
4 \(3.3 \times 10^{6} \mathrm{bp}\)
Explanation:
Length between the two base pairs \(=0.34 \mathrm{~nm}\) Total length of the double helix of DNA = Total number of base pairs \(\mathrm{X}\) distance between the two base pairs. Let us consider the total number of base pairs as \(\mathrm{x}\). \(1.1 \mathrm{~m}=\mathrm{x} \times 304 \times 10^{-10} \mathrm{~m}\) \(\mathrm{x}=3.3 \times 10^{9} \mathrm{bp}\) So, in a \(1.1 \mathrm{~m}\) length of DNA, there unit be about \(3.3 \times\) \(10^{9} \mathrm{bp}\).
NEET-2022
Molecular Basis of Inheritance and
166186
The diagram shows an important concept in the genetic implication of DNA. Fill in the blanks \(A\) to \(C\) :
1 A-translation B-extension C-Roslalind Franklin
2 A-Transcription B-replication C-James Watson
3 A-translation B-transcription C-Erevin Chargaff
4 A-transcription B-translation C-Francis
Explanation:
Cell carry out many vital function. The DNA codes for the production of messenger RNA (mRNA). During transcription messenger RNA carries coded information to ribosome read this information and use it DNA \(\xrightarrow{\text { Transcription }}\) mRNA \(\xrightarrow{\text { Translation }}\) Protein (Francis Crick.)
