184450
When a tall and red flowered individual is crossed with a dwarf and white flowered individual, phenotype of the progeny will be
1 homozygous tall and red
2 heterozygous tall and red
3 homozygous tall and white
4 homozygous dwarf and white
Explanation:
When a tall and red flowered individuals is crossed with dwarf and white flowered individuals phenotype of the progeny will be hetrozygous tall and red. Parents (Tall red flowers) TtRr (Dwarf and white flower) generation (Tall and Red progeny) So, progeny will be heterozygous tall and red because recessive phenotype appears only when both of its parents having this allele.
BHU PMT-2001
Principle of Inheritance and Variation
184451
In a dihybrid cross between RRYY and rryyparents, the number of genotypes in generation will be
1 4
2 3
3 2
4 1
Explanation:
According to question, the cross made between RRYY and rryy generation- generation- self cross is done between RrYy. The gametes formed are RY, Ry, rY, ry. {|c|c|c|c|c|} | | RY | Ry | rY | ry | |---|---|---|---|---| |RY | RRYY | RRYy | RrYY | RrYy | |Ry | RRYy | RRyy | RrYy | Rryy | |rY | RrYY | RrYy | rrYY | rrYy | |ry | RrYy | Rryy | rrYy | rryy | | The number of RrYy heterozygous hybrid obtained are 4.
J and K CET-2008
Principle of Inheritance and Variation
184453
Out of a population of 800 individuals in generation of cross between yellow round and green wrinkled pea plants, what would be number of yellow and wrinkled seed?
1 400
2 800
3 200
4 150
Explanation:
Exp: Homozygous Homozygous yellow Green Wrinkle round seed (YYRR) Seeds (yyrr) (Yy Rr) (Heterozygous Yellow Round) When this plant is subjected to self pollination in the generation. - 9 Plant are yellow round - 3 Plant are yellow wrinkled - 3 Plant are green round - 1 Plant is green wrinkled Phenotypic ratio is 9:3:3:1. So, in the dihybrid cross, 800 individuals are formed in this 450 are yellow round, 150 are yellow wrinkled, 150 are green round, 50 are green wrinkled.
AP EAMCET-25.09.2020 Shift-II
Principle of Inheritance and Variation
184455
A cross between pure tall pea plant with green pods and dwarf pea with yellow pods will produce tall plants, out of 16
1 15
2 13
3 12
4 7
Explanation:
According to question, - A cross between pure tall pea plant with green pods and dwarf pea plant with yellow pods will produce tall plant out of 16 . (Tall plant with green pod dwarf yellow pod Tt Yy Gametes: Ty Ty tY ty Selfing | | TY | Ty | tY | ty | | :---: | :---: | :---: | :---: | :---: | | TY | TTYY | TTYy | TtYY | TtYy | | Ty | TTYy | TTyy | TtYy | Ttyy | | tY | TtYY | TtYy | ttYY | ttYy | | ty | TtyY | Ttyy | ttyY | ttyy | Out of 16,12 plants will be tall.
Rajasthan PMT-2011
Principle of Inheritance and Variation
184456
A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of hybrid of his cross, 64 progenies were obtained in generation. Find out the number of progenies showing non-parental characters.
1 36
2 4
3 12
4 24
Explanation:
The phenotopic ratio in a dihybrid cross is 9:3:3:1. Second and third term i.e. 3 and 3 represent recombinant genotype. So, 24 of progenies out of 64 progenies showing non-parental character.
184450
When a tall and red flowered individual is crossed with a dwarf and white flowered individual, phenotype of the progeny will be
1 homozygous tall and red
2 heterozygous tall and red
3 homozygous tall and white
4 homozygous dwarf and white
Explanation:
When a tall and red flowered individuals is crossed with dwarf and white flowered individuals phenotype of the progeny will be hetrozygous tall and red. Parents (Tall red flowers) TtRr (Dwarf and white flower) generation (Tall and Red progeny) So, progeny will be heterozygous tall and red because recessive phenotype appears only when both of its parents having this allele.
BHU PMT-2001
Principle of Inheritance and Variation
184451
In a dihybrid cross between RRYY and rryyparents, the number of genotypes in generation will be
1 4
2 3
3 2
4 1
Explanation:
According to question, the cross made between RRYY and rryy generation- generation- self cross is done between RrYy. The gametes formed are RY, Ry, rY, ry. {|c|c|c|c|c|} | | RY | Ry | rY | ry | |---|---|---|---|---| |RY | RRYY | RRYy | RrYY | RrYy | |Ry | RRYy | RRyy | RrYy | Rryy | |rY | RrYY | RrYy | rrYY | rrYy | |ry | RrYy | Rryy | rrYy | rryy | | The number of RrYy heterozygous hybrid obtained are 4.
J and K CET-2008
Principle of Inheritance and Variation
184453
Out of a population of 800 individuals in generation of cross between yellow round and green wrinkled pea plants, what would be number of yellow and wrinkled seed?
1 400
2 800
3 200
4 150
Explanation:
Exp: Homozygous Homozygous yellow Green Wrinkle round seed (YYRR) Seeds (yyrr) (Yy Rr) (Heterozygous Yellow Round) When this plant is subjected to self pollination in the generation. - 9 Plant are yellow round - 3 Plant are yellow wrinkled - 3 Plant are green round - 1 Plant is green wrinkled Phenotypic ratio is 9:3:3:1. So, in the dihybrid cross, 800 individuals are formed in this 450 are yellow round, 150 are yellow wrinkled, 150 are green round, 50 are green wrinkled.
AP EAMCET-25.09.2020 Shift-II
Principle of Inheritance and Variation
184455
A cross between pure tall pea plant with green pods and dwarf pea with yellow pods will produce tall plants, out of 16
1 15
2 13
3 12
4 7
Explanation:
According to question, - A cross between pure tall pea plant with green pods and dwarf pea plant with yellow pods will produce tall plant out of 16 . (Tall plant with green pod dwarf yellow pod Tt Yy Gametes: Ty Ty tY ty Selfing | | TY | Ty | tY | ty | | :---: | :---: | :---: | :---: | :---: | | TY | TTYY | TTYy | TtYY | TtYy | | Ty | TTYy | TTyy | TtYy | Ttyy | | tY | TtYY | TtYy | ttYY | ttYy | | ty | TtyY | Ttyy | ttyY | ttyy | Out of 16,12 plants will be tall.
Rajasthan PMT-2011
Principle of Inheritance and Variation
184456
A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of hybrid of his cross, 64 progenies were obtained in generation. Find out the number of progenies showing non-parental characters.
1 36
2 4
3 12
4 24
Explanation:
The phenotopic ratio in a dihybrid cross is 9:3:3:1. Second and third term i.e. 3 and 3 represent recombinant genotype. So, 24 of progenies out of 64 progenies showing non-parental character.
184450
When a tall and red flowered individual is crossed with a dwarf and white flowered individual, phenotype of the progeny will be
1 homozygous tall and red
2 heterozygous tall and red
3 homozygous tall and white
4 homozygous dwarf and white
Explanation:
When a tall and red flowered individuals is crossed with dwarf and white flowered individuals phenotype of the progeny will be hetrozygous tall and red. Parents (Tall red flowers) TtRr (Dwarf and white flower) generation (Tall and Red progeny) So, progeny will be heterozygous tall and red because recessive phenotype appears only when both of its parents having this allele.
BHU PMT-2001
Principle of Inheritance and Variation
184451
In a dihybrid cross between RRYY and rryyparents, the number of genotypes in generation will be
1 4
2 3
3 2
4 1
Explanation:
According to question, the cross made between RRYY and rryy generation- generation- self cross is done between RrYy. The gametes formed are RY, Ry, rY, ry. {|c|c|c|c|c|} | | RY | Ry | rY | ry | |---|---|---|---|---| |RY | RRYY | RRYy | RrYY | RrYy | |Ry | RRYy | RRyy | RrYy | Rryy | |rY | RrYY | RrYy | rrYY | rrYy | |ry | RrYy | Rryy | rrYy | rryy | | The number of RrYy heterozygous hybrid obtained are 4.
J and K CET-2008
Principle of Inheritance and Variation
184453
Out of a population of 800 individuals in generation of cross between yellow round and green wrinkled pea plants, what would be number of yellow and wrinkled seed?
1 400
2 800
3 200
4 150
Explanation:
Exp: Homozygous Homozygous yellow Green Wrinkle round seed (YYRR) Seeds (yyrr) (Yy Rr) (Heterozygous Yellow Round) When this plant is subjected to self pollination in the generation. - 9 Plant are yellow round - 3 Plant are yellow wrinkled - 3 Plant are green round - 1 Plant is green wrinkled Phenotypic ratio is 9:3:3:1. So, in the dihybrid cross, 800 individuals are formed in this 450 are yellow round, 150 are yellow wrinkled, 150 are green round, 50 are green wrinkled.
AP EAMCET-25.09.2020 Shift-II
Principle of Inheritance and Variation
184455
A cross between pure tall pea plant with green pods and dwarf pea with yellow pods will produce tall plants, out of 16
1 15
2 13
3 12
4 7
Explanation:
According to question, - A cross between pure tall pea plant with green pods and dwarf pea plant with yellow pods will produce tall plant out of 16 . (Tall plant with green pod dwarf yellow pod Tt Yy Gametes: Ty Ty tY ty Selfing | | TY | Ty | tY | ty | | :---: | :---: | :---: | :---: | :---: | | TY | TTYY | TTYy | TtYY | TtYy | | Ty | TTYy | TTyy | TtYy | Ttyy | | tY | TtYY | TtYy | ttYY | ttYy | | ty | TtyY | Ttyy | ttyY | ttyy | Out of 16,12 plants will be tall.
Rajasthan PMT-2011
Principle of Inheritance and Variation
184456
A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of hybrid of his cross, 64 progenies were obtained in generation. Find out the number of progenies showing non-parental characters.
1 36
2 4
3 12
4 24
Explanation:
The phenotopic ratio in a dihybrid cross is 9:3:3:1. Second and third term i.e. 3 and 3 represent recombinant genotype. So, 24 of progenies out of 64 progenies showing non-parental character.
184450
When a tall and red flowered individual is crossed with a dwarf and white flowered individual, phenotype of the progeny will be
1 homozygous tall and red
2 heterozygous tall and red
3 homozygous tall and white
4 homozygous dwarf and white
Explanation:
When a tall and red flowered individuals is crossed with dwarf and white flowered individuals phenotype of the progeny will be hetrozygous tall and red. Parents (Tall red flowers) TtRr (Dwarf and white flower) generation (Tall and Red progeny) So, progeny will be heterozygous tall and red because recessive phenotype appears only when both of its parents having this allele.
BHU PMT-2001
Principle of Inheritance and Variation
184451
In a dihybrid cross between RRYY and rryyparents, the number of genotypes in generation will be
1 4
2 3
3 2
4 1
Explanation:
According to question, the cross made between RRYY and rryy generation- generation- self cross is done between RrYy. The gametes formed are RY, Ry, rY, ry. {|c|c|c|c|c|} | | RY | Ry | rY | ry | |---|---|---|---|---| |RY | RRYY | RRYy | RrYY | RrYy | |Ry | RRYy | RRyy | RrYy | Rryy | |rY | RrYY | RrYy | rrYY | rrYy | |ry | RrYy | Rryy | rrYy | rryy | | The number of RrYy heterozygous hybrid obtained are 4.
J and K CET-2008
Principle of Inheritance and Variation
184453
Out of a population of 800 individuals in generation of cross between yellow round and green wrinkled pea plants, what would be number of yellow and wrinkled seed?
1 400
2 800
3 200
4 150
Explanation:
Exp: Homozygous Homozygous yellow Green Wrinkle round seed (YYRR) Seeds (yyrr) (Yy Rr) (Heterozygous Yellow Round) When this plant is subjected to self pollination in the generation. - 9 Plant are yellow round - 3 Plant are yellow wrinkled - 3 Plant are green round - 1 Plant is green wrinkled Phenotypic ratio is 9:3:3:1. So, in the dihybrid cross, 800 individuals are formed in this 450 are yellow round, 150 are yellow wrinkled, 150 are green round, 50 are green wrinkled.
AP EAMCET-25.09.2020 Shift-II
Principle of Inheritance and Variation
184455
A cross between pure tall pea plant with green pods and dwarf pea with yellow pods will produce tall plants, out of 16
1 15
2 13
3 12
4 7
Explanation:
According to question, - A cross between pure tall pea plant with green pods and dwarf pea plant with yellow pods will produce tall plant out of 16 . (Tall plant with green pod dwarf yellow pod Tt Yy Gametes: Ty Ty tY ty Selfing | | TY | Ty | tY | ty | | :---: | :---: | :---: | :---: | :---: | | TY | TTYY | TTYy | TtYY | TtYy | | Ty | TTYy | TTyy | TtYy | Ttyy | | tY | TtYY | TtYy | ttYY | ttYy | | ty | TtyY | Ttyy | ttyY | ttyy | Out of 16,12 plants will be tall.
Rajasthan PMT-2011
Principle of Inheritance and Variation
184456
A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of hybrid of his cross, 64 progenies were obtained in generation. Find out the number of progenies showing non-parental characters.
1 36
2 4
3 12
4 24
Explanation:
The phenotopic ratio in a dihybrid cross is 9:3:3:1. Second and third term i.e. 3 and 3 represent recombinant genotype. So, 24 of progenies out of 64 progenies showing non-parental character.
184450
When a tall and red flowered individual is crossed with a dwarf and white flowered individual, phenotype of the progeny will be
1 homozygous tall and red
2 heterozygous tall and red
3 homozygous tall and white
4 homozygous dwarf and white
Explanation:
When a tall and red flowered individuals is crossed with dwarf and white flowered individuals phenotype of the progeny will be hetrozygous tall and red. Parents (Tall red flowers) TtRr (Dwarf and white flower) generation (Tall and Red progeny) So, progeny will be heterozygous tall and red because recessive phenotype appears only when both of its parents having this allele.
BHU PMT-2001
Principle of Inheritance and Variation
184451
In a dihybrid cross between RRYY and rryyparents, the number of genotypes in generation will be
1 4
2 3
3 2
4 1
Explanation:
According to question, the cross made between RRYY and rryy generation- generation- self cross is done between RrYy. The gametes formed are RY, Ry, rY, ry. {|c|c|c|c|c|} | | RY | Ry | rY | ry | |---|---|---|---|---| |RY | RRYY | RRYy | RrYY | RrYy | |Ry | RRYy | RRyy | RrYy | Rryy | |rY | RrYY | RrYy | rrYY | rrYy | |ry | RrYy | Rryy | rrYy | rryy | | The number of RrYy heterozygous hybrid obtained are 4.
J and K CET-2008
Principle of Inheritance and Variation
184453
Out of a population of 800 individuals in generation of cross between yellow round and green wrinkled pea plants, what would be number of yellow and wrinkled seed?
1 400
2 800
3 200
4 150
Explanation:
Exp: Homozygous Homozygous yellow Green Wrinkle round seed (YYRR) Seeds (yyrr) (Yy Rr) (Heterozygous Yellow Round) When this plant is subjected to self pollination in the generation. - 9 Plant are yellow round - 3 Plant are yellow wrinkled - 3 Plant are green round - 1 Plant is green wrinkled Phenotypic ratio is 9:3:3:1. So, in the dihybrid cross, 800 individuals are formed in this 450 are yellow round, 150 are yellow wrinkled, 150 are green round, 50 are green wrinkled.
AP EAMCET-25.09.2020 Shift-II
Principle of Inheritance and Variation
184455
A cross between pure tall pea plant with green pods and dwarf pea with yellow pods will produce tall plants, out of 16
1 15
2 13
3 12
4 7
Explanation:
According to question, - A cross between pure tall pea plant with green pods and dwarf pea plant with yellow pods will produce tall plant out of 16 . (Tall plant with green pod dwarf yellow pod Tt Yy Gametes: Ty Ty tY ty Selfing | | TY | Ty | tY | ty | | :---: | :---: | :---: | :---: | :---: | | TY | TTYY | TTYy | TtYY | TtYy | | Ty | TTYy | TTyy | TtYy | Ttyy | | tY | TtYY | TtYy | ttYY | ttYy | | ty | TtyY | Ttyy | ttyY | ttyy | Out of 16,12 plants will be tall.
Rajasthan PMT-2011
Principle of Inheritance and Variation
184456
A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of hybrid of his cross, 64 progenies were obtained in generation. Find out the number of progenies showing non-parental characters.
1 36
2 4
3 12
4 24
Explanation:
The phenotopic ratio in a dihybrid cross is 9:3:3:1. Second and third term i.e. 3 and 3 represent recombinant genotype. So, 24 of progenies out of 64 progenies showing non-parental character.