Motion of Body Connected Together
LAWS OF MOTION (ADDITIONAL)

372244 A person of \(70 \mathrm{~kg}\) mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration 4 \(\mathrm{ms}^{-2}\) the tension in the rope is (taking \(\mathrm{g}=10 \mathrm{~ms}^{-}\) )

1 \(250 \mathrm{~N}\)
2 \(490 \mathrm{~N}\)
3 \(980 \mathrm{~N}\)
4 \(1960 \mathrm{~N}\)
LAWS OF MOTION (ADDITIONAL)

372245 The weight of a man in a lift, moving upwards is \(608 \mathrm{~N}\) while the weight of the same man in the lift moving downwards, with the same acceleration, is \(368 \mathrm{~N}\). His normal weight in newton is:

1 488
2 588
3 480
4 240
LAWS OF MOTION (ADDITIONAL)

372246 In the system shown in the adjoining figure, the tension \(T_{2}\) is

1 \(g\)
2 \(2 \mathrm{~g}\)
3 \(5 \mathrm{~g}\)
4 \(6 \mathrm{~g}\)
LAWS OF MOTION (ADDITIONAL)

372247 Four blocks of same mass connected by cords are pulled by a force \(F\) on a smooth horizontal surface, as shown in figure. The tensions \(T_{1}, T_{2}\) and \(T_{3}\) will be
\(\mathrm{F} \longleftarrow \mathrm{M} \stackrel{\mathrm{T}_{1}}{\longleftarrow} \mathrm{M} \stackrel{\mathrm{T}_{2}}{\longleftarrow} \mathrm{M} \stackrel{\mathrm{T}_{3}}{\longleftarrow} \mathrm{M}\)

1 \(\mathrm{T}_{1}=\frac{1}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{3}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{4} \mathrm{~F}\)
2 \(\mathrm{T}_{1}=\frac{1}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{2} \mathrm{~F}\)
3 \(\mathrm{T}_{1}=\frac{3}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{4} \mathrm{~F}\)
4 \(\mathrm{T}_{1}=\frac{3}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{2} \mathrm{~F}\)
LAWS OF MOTION (ADDITIONAL)

372244 A person of \(70 \mathrm{~kg}\) mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration 4 \(\mathrm{ms}^{-2}\) the tension in the rope is (taking \(\mathrm{g}=10 \mathrm{~ms}^{-}\) )

1 \(250 \mathrm{~N}\)
2 \(490 \mathrm{~N}\)
3 \(980 \mathrm{~N}\)
4 \(1960 \mathrm{~N}\)
LAWS OF MOTION (ADDITIONAL)

372245 The weight of a man in a lift, moving upwards is \(608 \mathrm{~N}\) while the weight of the same man in the lift moving downwards, with the same acceleration, is \(368 \mathrm{~N}\). His normal weight in newton is:

1 488
2 588
3 480
4 240
LAWS OF MOTION (ADDITIONAL)

372246 In the system shown in the adjoining figure, the tension \(T_{2}\) is

1 \(g\)
2 \(2 \mathrm{~g}\)
3 \(5 \mathrm{~g}\)
4 \(6 \mathrm{~g}\)
LAWS OF MOTION (ADDITIONAL)

372247 Four blocks of same mass connected by cords are pulled by a force \(F\) on a smooth horizontal surface, as shown in figure. The tensions \(T_{1}, T_{2}\) and \(T_{3}\) will be
\(\mathrm{F} \longleftarrow \mathrm{M} \stackrel{\mathrm{T}_{1}}{\longleftarrow} \mathrm{M} \stackrel{\mathrm{T}_{2}}{\longleftarrow} \mathrm{M} \stackrel{\mathrm{T}_{3}}{\longleftarrow} \mathrm{M}\)

1 \(\mathrm{T}_{1}=\frac{1}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{3}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{4} \mathrm{~F}\)
2 \(\mathrm{T}_{1}=\frac{1}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{2} \mathrm{~F}\)
3 \(\mathrm{T}_{1}=\frac{3}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{4} \mathrm{~F}\)
4 \(\mathrm{T}_{1}=\frac{3}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{2} \mathrm{~F}\)
LAWS OF MOTION (ADDITIONAL)

372244 A person of \(70 \mathrm{~kg}\) mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration 4 \(\mathrm{ms}^{-2}\) the tension in the rope is (taking \(\mathrm{g}=10 \mathrm{~ms}^{-}\) )

1 \(250 \mathrm{~N}\)
2 \(490 \mathrm{~N}\)
3 \(980 \mathrm{~N}\)
4 \(1960 \mathrm{~N}\)
LAWS OF MOTION (ADDITIONAL)

372245 The weight of a man in a lift, moving upwards is \(608 \mathrm{~N}\) while the weight of the same man in the lift moving downwards, with the same acceleration, is \(368 \mathrm{~N}\). His normal weight in newton is:

1 488
2 588
3 480
4 240
LAWS OF MOTION (ADDITIONAL)

372246 In the system shown in the adjoining figure, the tension \(T_{2}\) is

1 \(g\)
2 \(2 \mathrm{~g}\)
3 \(5 \mathrm{~g}\)
4 \(6 \mathrm{~g}\)
LAWS OF MOTION (ADDITIONAL)

372247 Four blocks of same mass connected by cords are pulled by a force \(F\) on a smooth horizontal surface, as shown in figure. The tensions \(T_{1}, T_{2}\) and \(T_{3}\) will be
\(\mathrm{F} \longleftarrow \mathrm{M} \stackrel{\mathrm{T}_{1}}{\longleftarrow} \mathrm{M} \stackrel{\mathrm{T}_{2}}{\longleftarrow} \mathrm{M} \stackrel{\mathrm{T}_{3}}{\longleftarrow} \mathrm{M}\)

1 \(\mathrm{T}_{1}=\frac{1}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{3}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{4} \mathrm{~F}\)
2 \(\mathrm{T}_{1}=\frac{1}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{2} \mathrm{~F}\)
3 \(\mathrm{T}_{1}=\frac{3}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{4} \mathrm{~F}\)
4 \(\mathrm{T}_{1}=\frac{3}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{2} \mathrm{~F}\)
LAWS OF MOTION (ADDITIONAL)

372244 A person of \(70 \mathrm{~kg}\) mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration 4 \(\mathrm{ms}^{-2}\) the tension in the rope is (taking \(\mathrm{g}=10 \mathrm{~ms}^{-}\) )

1 \(250 \mathrm{~N}\)
2 \(490 \mathrm{~N}\)
3 \(980 \mathrm{~N}\)
4 \(1960 \mathrm{~N}\)
LAWS OF MOTION (ADDITIONAL)

372245 The weight of a man in a lift, moving upwards is \(608 \mathrm{~N}\) while the weight of the same man in the lift moving downwards, with the same acceleration, is \(368 \mathrm{~N}\). His normal weight in newton is:

1 488
2 588
3 480
4 240
LAWS OF MOTION (ADDITIONAL)

372246 In the system shown in the adjoining figure, the tension \(T_{2}\) is

1 \(g\)
2 \(2 \mathrm{~g}\)
3 \(5 \mathrm{~g}\)
4 \(6 \mathrm{~g}\)
LAWS OF MOTION (ADDITIONAL)

372247 Four blocks of same mass connected by cords are pulled by a force \(F\) on a smooth horizontal surface, as shown in figure. The tensions \(T_{1}, T_{2}\) and \(T_{3}\) will be
\(\mathrm{F} \longleftarrow \mathrm{M} \stackrel{\mathrm{T}_{1}}{\longleftarrow} \mathrm{M} \stackrel{\mathrm{T}_{2}}{\longleftarrow} \mathrm{M} \stackrel{\mathrm{T}_{3}}{\longleftarrow} \mathrm{M}\)

1 \(\mathrm{T}_{1}=\frac{1}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{3}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{4} \mathrm{~F}\)
2 \(\mathrm{T}_{1}=\frac{1}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{2} \mathrm{~F}\)
3 \(\mathrm{T}_{1}=\frac{3}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{4} \mathrm{~F}\)
4 \(\mathrm{T}_{1}=\frac{3}{4} \mathrm{~F}, \mathrm{~T}_{2}=\frac{1}{2} \mathrm{~F}, \mathrm{~T}_{3}=\frac{1}{2} \mathrm{~F}\)