Friction, and Inclined Plane Friction Motion
LAWS OF MOTION (ADDITIONAL)

372094 An object is placed on the surface of a smooth inclined plane of inclination \(\theta\). It takes time \(t\) to reach the bottom. If the same object is allowed to slide down a rough inclined plane of inclination \(\theta\), it takes time nt to reach the bottom, where \(n\) is a number greater than 1 . The coefficient of friction \(\mu\) is given by-

1 \(\mu=\tan \theta\left(1-\frac{1}{\mathrm{n}^{2}}\right)\)
2 \(\mu=\cos \theta\left(1-\frac{1}{\mathrm{n}^{2}}\right)\)
3 \(\mu=\tan \theta \sqrt{1-\frac{1}{\sqrt{\mathrm{n}^{2}}}}\)
4 \(\mu=\cot \theta \sqrt{1-\frac{1}{\mathrm{n}^{2}}}\)
LAWS OF MOTION (ADDITIONAL)

372095 A marble block of mass \(2 \mathrm{~kg}\) lying on ice when given a velocity of \(6 \mathrm{~m} / \mathrm{s}\) is stopped by friction in \(10 \mathrm{~s}\). Then the coefficient of friction is (Take \(\mathbf{g}=\mathbf{1 0} \mathbf{m s}^{-2}\) )

1 0.06
2 0.03
3 0.04
4 0.01
LAWS OF MOTION (ADDITIONAL)

372096 A bullet of mass \(0.02 \mathrm{~kg}\) travelling horizontally with velocity \(250 \mathrm{~ms}^{-1}\) strikes a block of wood of mass \(0.23 \mathrm{~kg}\) which rests on a rough horizontal surface. After the impact, the block and bullet move together and come to rest after travelling a distance of \(40 \mathrm{~m}\). The coefficient of sliding friction of the rough surface is \(\left(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\right)\)

1 0.75
2 0.61
3 0.51
4 0.30
LAWS OF MOTION (ADDITIONAL)

372097 A small bar starts sliding down on inclined plane making an angle \(\alpha\) with the horizontal. The coefficient of friction \(k\) depends on the distance \(x\) as \(\mathrm{k}=a x\) where \(a\) is a constant. The distance covered by the bar till it stops is

1 \(\frac{(\tan \alpha)}{a}\)
2 \(\frac{2(\tan \alpha)}{a}\)
3 \(2 \mathrm{a} \tan \alpha\)
4 \(\frac{\tan \alpha}{(2 \mathrm{a})}\)
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LAWS OF MOTION (ADDITIONAL)

372094 An object is placed on the surface of a smooth inclined plane of inclination \(\theta\). It takes time \(t\) to reach the bottom. If the same object is allowed to slide down a rough inclined plane of inclination \(\theta\), it takes time nt to reach the bottom, where \(n\) is a number greater than 1 . The coefficient of friction \(\mu\) is given by-

1 \(\mu=\tan \theta\left(1-\frac{1}{\mathrm{n}^{2}}\right)\)
2 \(\mu=\cos \theta\left(1-\frac{1}{\mathrm{n}^{2}}\right)\)
3 \(\mu=\tan \theta \sqrt{1-\frac{1}{\sqrt{\mathrm{n}^{2}}}}\)
4 \(\mu=\cot \theta \sqrt{1-\frac{1}{\mathrm{n}^{2}}}\)
LAWS OF MOTION (ADDITIONAL)

372095 A marble block of mass \(2 \mathrm{~kg}\) lying on ice when given a velocity of \(6 \mathrm{~m} / \mathrm{s}\) is stopped by friction in \(10 \mathrm{~s}\). Then the coefficient of friction is (Take \(\mathbf{g}=\mathbf{1 0} \mathbf{m s}^{-2}\) )

1 0.06
2 0.03
3 0.04
4 0.01
LAWS OF MOTION (ADDITIONAL)

372096 A bullet of mass \(0.02 \mathrm{~kg}\) travelling horizontally with velocity \(250 \mathrm{~ms}^{-1}\) strikes a block of wood of mass \(0.23 \mathrm{~kg}\) which rests on a rough horizontal surface. After the impact, the block and bullet move together and come to rest after travelling a distance of \(40 \mathrm{~m}\). The coefficient of sliding friction of the rough surface is \(\left(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\right)\)

1 0.75
2 0.61
3 0.51
4 0.30
LAWS OF MOTION (ADDITIONAL)

372097 A small bar starts sliding down on inclined plane making an angle \(\alpha\) with the horizontal. The coefficient of friction \(k\) depends on the distance \(x\) as \(\mathrm{k}=a x\) where \(a\) is a constant. The distance covered by the bar till it stops is

1 \(\frac{(\tan \alpha)}{a}\)
2 \(\frac{2(\tan \alpha)}{a}\)
3 \(2 \mathrm{a} \tan \alpha\)
4 \(\frac{\tan \alpha}{(2 \mathrm{a})}\)
LAWS OF MOTION (ADDITIONAL)

372094 An object is placed on the surface of a smooth inclined plane of inclination \(\theta\). It takes time \(t\) to reach the bottom. If the same object is allowed to slide down a rough inclined plane of inclination \(\theta\), it takes time nt to reach the bottom, where \(n\) is a number greater than 1 . The coefficient of friction \(\mu\) is given by-

1 \(\mu=\tan \theta\left(1-\frac{1}{\mathrm{n}^{2}}\right)\)
2 \(\mu=\cos \theta\left(1-\frac{1}{\mathrm{n}^{2}}\right)\)
3 \(\mu=\tan \theta \sqrt{1-\frac{1}{\sqrt{\mathrm{n}^{2}}}}\)
4 \(\mu=\cot \theta \sqrt{1-\frac{1}{\mathrm{n}^{2}}}\)
LAWS OF MOTION (ADDITIONAL)

372095 A marble block of mass \(2 \mathrm{~kg}\) lying on ice when given a velocity of \(6 \mathrm{~m} / \mathrm{s}\) is stopped by friction in \(10 \mathrm{~s}\). Then the coefficient of friction is (Take \(\mathbf{g}=\mathbf{1 0} \mathbf{m s}^{-2}\) )

1 0.06
2 0.03
3 0.04
4 0.01
LAWS OF MOTION (ADDITIONAL)

372096 A bullet of mass \(0.02 \mathrm{~kg}\) travelling horizontally with velocity \(250 \mathrm{~ms}^{-1}\) strikes a block of wood of mass \(0.23 \mathrm{~kg}\) which rests on a rough horizontal surface. After the impact, the block and bullet move together and come to rest after travelling a distance of \(40 \mathrm{~m}\). The coefficient of sliding friction of the rough surface is \(\left(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\right)\)

1 0.75
2 0.61
3 0.51
4 0.30
LAWS OF MOTION (ADDITIONAL)

372097 A small bar starts sliding down on inclined plane making an angle \(\alpha\) with the horizontal. The coefficient of friction \(k\) depends on the distance \(x\) as \(\mathrm{k}=a x\) where \(a\) is a constant. The distance covered by the bar till it stops is

1 \(\frac{(\tan \alpha)}{a}\)
2 \(\frac{2(\tan \alpha)}{a}\)
3 \(2 \mathrm{a} \tan \alpha\)
4 \(\frac{\tan \alpha}{(2 \mathrm{a})}\)
LAWS OF MOTION (ADDITIONAL)

372094 An object is placed on the surface of a smooth inclined plane of inclination \(\theta\). It takes time \(t\) to reach the bottom. If the same object is allowed to slide down a rough inclined plane of inclination \(\theta\), it takes time nt to reach the bottom, where \(n\) is a number greater than 1 . The coefficient of friction \(\mu\) is given by-

1 \(\mu=\tan \theta\left(1-\frac{1}{\mathrm{n}^{2}}\right)\)
2 \(\mu=\cos \theta\left(1-\frac{1}{\mathrm{n}^{2}}\right)\)
3 \(\mu=\tan \theta \sqrt{1-\frac{1}{\sqrt{\mathrm{n}^{2}}}}\)
4 \(\mu=\cot \theta \sqrt{1-\frac{1}{\mathrm{n}^{2}}}\)
LAWS OF MOTION (ADDITIONAL)

372095 A marble block of mass \(2 \mathrm{~kg}\) lying on ice when given a velocity of \(6 \mathrm{~m} / \mathrm{s}\) is stopped by friction in \(10 \mathrm{~s}\). Then the coefficient of friction is (Take \(\mathbf{g}=\mathbf{1 0} \mathbf{m s}^{-2}\) )

1 0.06
2 0.03
3 0.04
4 0.01
LAWS OF MOTION (ADDITIONAL)

372096 A bullet of mass \(0.02 \mathrm{~kg}\) travelling horizontally with velocity \(250 \mathrm{~ms}^{-1}\) strikes a block of wood of mass \(0.23 \mathrm{~kg}\) which rests on a rough horizontal surface. After the impact, the block and bullet move together and come to rest after travelling a distance of \(40 \mathrm{~m}\). The coefficient of sliding friction of the rough surface is \(\left(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\right)\)

1 0.75
2 0.61
3 0.51
4 0.30
LAWS OF MOTION (ADDITIONAL)

372097 A small bar starts sliding down on inclined plane making an angle \(\alpha\) with the horizontal. The coefficient of friction \(k\) depends on the distance \(x\) as \(\mathrm{k}=a x\) where \(a\) is a constant. The distance covered by the bar till it stops is

1 \(\frac{(\tan \alpha)}{a}\)
2 \(\frac{2(\tan \alpha)}{a}\)
3 \(2 \mathrm{a} \tan \alpha\)
4 \(\frac{\tan \alpha}{(2 \mathrm{a})}\)