Friction, and Inclined Plane Friction Motion
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
LAWS OF MOTION (ADDITIONAL)

371966 A block of mass \(10 \mathrm{~kg}\) starts sliding on a surface with an initial velocity of \(9.8 \mathrm{~ms}^{-1}\). The coefficient of friction between the surface and block is 0.5 . The distance covered by the block before coming to rest is:
[use \(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\) ]

1 \(4.9 \mathrm{~m}\)
2 \(9.8 \mathrm{~m}\)
3 \(12.5 \mathrm{~m}\)
4 \(19.6 \mathrm{~m}\)
LAWS OF MOTION (ADDITIONAL)

371967 A \(30 \mathrm{~kg}\) slab \(B\) rests on a frictionless floor as shown in the figure. A \(10 \mathrm{~kg}\) block \(A\) rests on top of the slab-B The coefficients of static and kinetic friction between the block \(A\) and the slab \(B\) are 0.60 and 0.40 respectively. When block - \(A\) is acted upon by a horizontal force of \(100 \mathrm{~N}\), as shown, find the resulting acceleration of the slab- \(B\left(g=9.8 \mathrm{~m} . \mathrm{s}^{-2}\right)\)

1 \(0.98 \mathrm{~m} \cdot \mathrm{s}^{-2}\)
2 \(1.47 \mathrm{~m} . \mathrm{s}^{-2}\)
3 \(1.52 \mathrm{~m} . \mathrm{s}^{-2}\)
4 \(1.31 \mathrm{~m} \cdot \mathrm{s}^{-2}\)
LAWS OF MOTION (ADDITIONAL)

371968 A coefficient of static friction for steel on ice is 0.1. The coefficient of the sliding friction therefore can be

1 0.1
2 0.11
3 0.01
4 1.1
LAWS OF MOTION (ADDITIONAL)

371969 A uniform chain has a mass ' \(m\) ' and length ' \(l\) '. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is:

1 \(\frac{\mathrm{mg} l}{72}\)
2 \(\frac{\mathrm{mg} l}{36}\)
3 \(\frac{\mathrm{mg} l}{12}\)
4 \(\frac{\mathrm{mg} l}{6}\)
LAWS OF MOTION (ADDITIONAL)

371966 A block of mass \(10 \mathrm{~kg}\) starts sliding on a surface with an initial velocity of \(9.8 \mathrm{~ms}^{-1}\). The coefficient of friction between the surface and block is 0.5 . The distance covered by the block before coming to rest is:
[use \(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\) ]

1 \(4.9 \mathrm{~m}\)
2 \(9.8 \mathrm{~m}\)
3 \(12.5 \mathrm{~m}\)
4 \(19.6 \mathrm{~m}\)
LAWS OF MOTION (ADDITIONAL)

371967 A \(30 \mathrm{~kg}\) slab \(B\) rests on a frictionless floor as shown in the figure. A \(10 \mathrm{~kg}\) block \(A\) rests on top of the slab-B The coefficients of static and kinetic friction between the block \(A\) and the slab \(B\) are 0.60 and 0.40 respectively. When block - \(A\) is acted upon by a horizontal force of \(100 \mathrm{~N}\), as shown, find the resulting acceleration of the slab- \(B\left(g=9.8 \mathrm{~m} . \mathrm{s}^{-2}\right)\)

1 \(0.98 \mathrm{~m} \cdot \mathrm{s}^{-2}\)
2 \(1.47 \mathrm{~m} . \mathrm{s}^{-2}\)
3 \(1.52 \mathrm{~m} . \mathrm{s}^{-2}\)
4 \(1.31 \mathrm{~m} \cdot \mathrm{s}^{-2}\)
LAWS OF MOTION (ADDITIONAL)

371968 A coefficient of static friction for steel on ice is 0.1. The coefficient of the sliding friction therefore can be

1 0.1
2 0.11
3 0.01
4 1.1
LAWS OF MOTION (ADDITIONAL)

371969 A uniform chain has a mass ' \(m\) ' and length ' \(l\) '. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is:

1 \(\frac{\mathrm{mg} l}{72}\)
2 \(\frac{\mathrm{mg} l}{36}\)
3 \(\frac{\mathrm{mg} l}{12}\)
4 \(\frac{\mathrm{mg} l}{6}\)
LAWS OF MOTION (ADDITIONAL)

371966 A block of mass \(10 \mathrm{~kg}\) starts sliding on a surface with an initial velocity of \(9.8 \mathrm{~ms}^{-1}\). The coefficient of friction between the surface and block is 0.5 . The distance covered by the block before coming to rest is:
[use \(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\) ]

1 \(4.9 \mathrm{~m}\)
2 \(9.8 \mathrm{~m}\)
3 \(12.5 \mathrm{~m}\)
4 \(19.6 \mathrm{~m}\)
LAWS OF MOTION (ADDITIONAL)

371967 A \(30 \mathrm{~kg}\) slab \(B\) rests on a frictionless floor as shown in the figure. A \(10 \mathrm{~kg}\) block \(A\) rests on top of the slab-B The coefficients of static and kinetic friction between the block \(A\) and the slab \(B\) are 0.60 and 0.40 respectively. When block - \(A\) is acted upon by a horizontal force of \(100 \mathrm{~N}\), as shown, find the resulting acceleration of the slab- \(B\left(g=9.8 \mathrm{~m} . \mathrm{s}^{-2}\right)\)

1 \(0.98 \mathrm{~m} \cdot \mathrm{s}^{-2}\)
2 \(1.47 \mathrm{~m} . \mathrm{s}^{-2}\)
3 \(1.52 \mathrm{~m} . \mathrm{s}^{-2}\)
4 \(1.31 \mathrm{~m} \cdot \mathrm{s}^{-2}\)
LAWS OF MOTION (ADDITIONAL)

371968 A coefficient of static friction for steel on ice is 0.1. The coefficient of the sliding friction therefore can be

1 0.1
2 0.11
3 0.01
4 1.1
LAWS OF MOTION (ADDITIONAL)

371969 A uniform chain has a mass ' \(m\) ' and length ' \(l\) '. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is:

1 \(\frac{\mathrm{mg} l}{72}\)
2 \(\frac{\mathrm{mg} l}{36}\)
3 \(\frac{\mathrm{mg} l}{12}\)
4 \(\frac{\mathrm{mg} l}{6}\)
LAWS OF MOTION (ADDITIONAL)

371966 A block of mass \(10 \mathrm{~kg}\) starts sliding on a surface with an initial velocity of \(9.8 \mathrm{~ms}^{-1}\). The coefficient of friction between the surface and block is 0.5 . The distance covered by the block before coming to rest is:
[use \(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\) ]

1 \(4.9 \mathrm{~m}\)
2 \(9.8 \mathrm{~m}\)
3 \(12.5 \mathrm{~m}\)
4 \(19.6 \mathrm{~m}\)
LAWS OF MOTION (ADDITIONAL)

371967 A \(30 \mathrm{~kg}\) slab \(B\) rests on a frictionless floor as shown in the figure. A \(10 \mathrm{~kg}\) block \(A\) rests on top of the slab-B The coefficients of static and kinetic friction between the block \(A\) and the slab \(B\) are 0.60 and 0.40 respectively. When block - \(A\) is acted upon by a horizontal force of \(100 \mathrm{~N}\), as shown, find the resulting acceleration of the slab- \(B\left(g=9.8 \mathrm{~m} . \mathrm{s}^{-2}\right)\)

1 \(0.98 \mathrm{~m} \cdot \mathrm{s}^{-2}\)
2 \(1.47 \mathrm{~m} . \mathrm{s}^{-2}\)
3 \(1.52 \mathrm{~m} . \mathrm{s}^{-2}\)
4 \(1.31 \mathrm{~m} \cdot \mathrm{s}^{-2}\)
LAWS OF MOTION (ADDITIONAL)

371968 A coefficient of static friction for steel on ice is 0.1. The coefficient of the sliding friction therefore can be

1 0.1
2 0.11
3 0.01
4 1.1
LAWS OF MOTION (ADDITIONAL)

371969 A uniform chain has a mass ' \(m\) ' and length ' \(l\) '. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is:

1 \(\frac{\mathrm{mg} l}{72}\)
2 \(\frac{\mathrm{mg} l}{36}\)
3 \(\frac{\mathrm{mg} l}{12}\)
4 \(\frac{\mathrm{mg} l}{6}\)