371585
Assertion : The internal energy of an isothermal process does not change Reason : The internal energy of a system depends only on pressure of the system.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
For an ideal gas undergoing an isothermal process, \(\Rightarrow T=\mathrm{constant}\) \(\Rightarrow \Delta T=0\) Assertion is correct. The internal energy of a system depends on temperature only Reason is false. So correct option is (3).
PHXI12:THERMODYNAMICS
371586
During an isothermal expansion, a confined ideal gas does \( - 150\;J\) of work against its surroundings. This implies that
1 \(300\;J\) of heat has been added to the gas
2 No heat is transferred because the process is isothermal
3 \(150\;J\) of heat has been added to the gas
4 \(150\;J\) heat has been removed from the gas
Explanation:
From the first law of the thermodynamics \(\Delta U=Q-W\) For isothermaal processes, \(\Delta U=0\) \(\therefore Q=W\) Given, \(W = 150\;J\) (Work done by the gas) Where \(Q\) is positive, the heat is added to the gas.
PHXI12:THERMODYNAMICS
371587
When an ideal gas in a cylinder was compressed isothermally by a piston, the work done on the gas was found to be \(1.5 \times 10^{4}\) joules. During this process
1 \(3.6 \times {10^3}cal\) of heat flowed into the gas
2 \(3.6 \times {10^3}cal\) of heat flowed goes out from the gas
3 \(1.5 \times {10^4}cal\) of heat flowed goes out from the gas
4 \(1.5 \times {10^4}cal\) of heat flowed into the gas
Explanation:
In isothermal compression, there is always an increase of heat which must flow out of the gas. \(\Delta Q = \Delta U + \Delta W \Rightarrow \Delta Q = \Delta W\quad [\because \Delta U = 0]\) \( \Rightarrow \Delta Q = - 1.5 \times {10^4}\;J = \frac{{1.5 \times {{10}^4}}}{{4.18}}cal = - 3.6 \times {10^3}cal.\)
PHXI12:THERMODYNAMICS
371588
One mole of an ideal gas undergoes an isothermal change at temperature \(T\) so that its volume 7 times its initial value. \(R\) is the molar gas constant. Work done by the gas during this change is
1 \(RT\ln 4\)
2 \(RT\ln 7\)
3 \(RT\ln 1\)
4 \(RT\ln 3\)
Explanation:
Work done by the gas during the isothermal process. \(W=n R T \ln \dfrac{V_{2}}{V_{1}}\) \(=(1) R T \ln \left(\dfrac{7 V}{V}\right)=R T \ln 7\)
PHXI12:THERMODYNAMICS
371589
In which of the processes, does the internal energy of the system remain constant?
1 Isobaric
2 Isothermal
3 Adiabatic
4 Isochoric
Explanation:
The internal energy of a system remains a constant when the temperature does not change.
371585
Assertion : The internal energy of an isothermal process does not change Reason : The internal energy of a system depends only on pressure of the system.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
For an ideal gas undergoing an isothermal process, \(\Rightarrow T=\mathrm{constant}\) \(\Rightarrow \Delta T=0\) Assertion is correct. The internal energy of a system depends on temperature only Reason is false. So correct option is (3).
PHXI12:THERMODYNAMICS
371586
During an isothermal expansion, a confined ideal gas does \( - 150\;J\) of work against its surroundings. This implies that
1 \(300\;J\) of heat has been added to the gas
2 No heat is transferred because the process is isothermal
3 \(150\;J\) of heat has been added to the gas
4 \(150\;J\) heat has been removed from the gas
Explanation:
From the first law of the thermodynamics \(\Delta U=Q-W\) For isothermaal processes, \(\Delta U=0\) \(\therefore Q=W\) Given, \(W = 150\;J\) (Work done by the gas) Where \(Q\) is positive, the heat is added to the gas.
PHXI12:THERMODYNAMICS
371587
When an ideal gas in a cylinder was compressed isothermally by a piston, the work done on the gas was found to be \(1.5 \times 10^{4}\) joules. During this process
1 \(3.6 \times {10^3}cal\) of heat flowed into the gas
2 \(3.6 \times {10^3}cal\) of heat flowed goes out from the gas
3 \(1.5 \times {10^4}cal\) of heat flowed goes out from the gas
4 \(1.5 \times {10^4}cal\) of heat flowed into the gas
Explanation:
In isothermal compression, there is always an increase of heat which must flow out of the gas. \(\Delta Q = \Delta U + \Delta W \Rightarrow \Delta Q = \Delta W\quad [\because \Delta U = 0]\) \( \Rightarrow \Delta Q = - 1.5 \times {10^4}\;J = \frac{{1.5 \times {{10}^4}}}{{4.18}}cal = - 3.6 \times {10^3}cal.\)
PHXI12:THERMODYNAMICS
371588
One mole of an ideal gas undergoes an isothermal change at temperature \(T\) so that its volume 7 times its initial value. \(R\) is the molar gas constant. Work done by the gas during this change is
1 \(RT\ln 4\)
2 \(RT\ln 7\)
3 \(RT\ln 1\)
4 \(RT\ln 3\)
Explanation:
Work done by the gas during the isothermal process. \(W=n R T \ln \dfrac{V_{2}}{V_{1}}\) \(=(1) R T \ln \left(\dfrac{7 V}{V}\right)=R T \ln 7\)
PHXI12:THERMODYNAMICS
371589
In which of the processes, does the internal energy of the system remain constant?
1 Isobaric
2 Isothermal
3 Adiabatic
4 Isochoric
Explanation:
The internal energy of a system remains a constant when the temperature does not change.
371585
Assertion : The internal energy of an isothermal process does not change Reason : The internal energy of a system depends only on pressure of the system.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
For an ideal gas undergoing an isothermal process, \(\Rightarrow T=\mathrm{constant}\) \(\Rightarrow \Delta T=0\) Assertion is correct. The internal energy of a system depends on temperature only Reason is false. So correct option is (3).
PHXI12:THERMODYNAMICS
371586
During an isothermal expansion, a confined ideal gas does \( - 150\;J\) of work against its surroundings. This implies that
1 \(300\;J\) of heat has been added to the gas
2 No heat is transferred because the process is isothermal
3 \(150\;J\) of heat has been added to the gas
4 \(150\;J\) heat has been removed from the gas
Explanation:
From the first law of the thermodynamics \(\Delta U=Q-W\) For isothermaal processes, \(\Delta U=0\) \(\therefore Q=W\) Given, \(W = 150\;J\) (Work done by the gas) Where \(Q\) is positive, the heat is added to the gas.
PHXI12:THERMODYNAMICS
371587
When an ideal gas in a cylinder was compressed isothermally by a piston, the work done on the gas was found to be \(1.5 \times 10^{4}\) joules. During this process
1 \(3.6 \times {10^3}cal\) of heat flowed into the gas
2 \(3.6 \times {10^3}cal\) of heat flowed goes out from the gas
3 \(1.5 \times {10^4}cal\) of heat flowed goes out from the gas
4 \(1.5 \times {10^4}cal\) of heat flowed into the gas
Explanation:
In isothermal compression, there is always an increase of heat which must flow out of the gas. \(\Delta Q = \Delta U + \Delta W \Rightarrow \Delta Q = \Delta W\quad [\because \Delta U = 0]\) \( \Rightarrow \Delta Q = - 1.5 \times {10^4}\;J = \frac{{1.5 \times {{10}^4}}}{{4.18}}cal = - 3.6 \times {10^3}cal.\)
PHXI12:THERMODYNAMICS
371588
One mole of an ideal gas undergoes an isothermal change at temperature \(T\) so that its volume 7 times its initial value. \(R\) is the molar gas constant. Work done by the gas during this change is
1 \(RT\ln 4\)
2 \(RT\ln 7\)
3 \(RT\ln 1\)
4 \(RT\ln 3\)
Explanation:
Work done by the gas during the isothermal process. \(W=n R T \ln \dfrac{V_{2}}{V_{1}}\) \(=(1) R T \ln \left(\dfrac{7 V}{V}\right)=R T \ln 7\)
PHXI12:THERMODYNAMICS
371589
In which of the processes, does the internal energy of the system remain constant?
1 Isobaric
2 Isothermal
3 Adiabatic
4 Isochoric
Explanation:
The internal energy of a system remains a constant when the temperature does not change.
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PHXI12:THERMODYNAMICS
371585
Assertion : The internal energy of an isothermal process does not change Reason : The internal energy of a system depends only on pressure of the system.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
For an ideal gas undergoing an isothermal process, \(\Rightarrow T=\mathrm{constant}\) \(\Rightarrow \Delta T=0\) Assertion is correct. The internal energy of a system depends on temperature only Reason is false. So correct option is (3).
PHXI12:THERMODYNAMICS
371586
During an isothermal expansion, a confined ideal gas does \( - 150\;J\) of work against its surroundings. This implies that
1 \(300\;J\) of heat has been added to the gas
2 No heat is transferred because the process is isothermal
3 \(150\;J\) of heat has been added to the gas
4 \(150\;J\) heat has been removed from the gas
Explanation:
From the first law of the thermodynamics \(\Delta U=Q-W\) For isothermaal processes, \(\Delta U=0\) \(\therefore Q=W\) Given, \(W = 150\;J\) (Work done by the gas) Where \(Q\) is positive, the heat is added to the gas.
PHXI12:THERMODYNAMICS
371587
When an ideal gas in a cylinder was compressed isothermally by a piston, the work done on the gas was found to be \(1.5 \times 10^{4}\) joules. During this process
1 \(3.6 \times {10^3}cal\) of heat flowed into the gas
2 \(3.6 \times {10^3}cal\) of heat flowed goes out from the gas
3 \(1.5 \times {10^4}cal\) of heat flowed goes out from the gas
4 \(1.5 \times {10^4}cal\) of heat flowed into the gas
Explanation:
In isothermal compression, there is always an increase of heat which must flow out of the gas. \(\Delta Q = \Delta U + \Delta W \Rightarrow \Delta Q = \Delta W\quad [\because \Delta U = 0]\) \( \Rightarrow \Delta Q = - 1.5 \times {10^4}\;J = \frac{{1.5 \times {{10}^4}}}{{4.18}}cal = - 3.6 \times {10^3}cal.\)
PHXI12:THERMODYNAMICS
371588
One mole of an ideal gas undergoes an isothermal change at temperature \(T\) so that its volume 7 times its initial value. \(R\) is the molar gas constant. Work done by the gas during this change is
1 \(RT\ln 4\)
2 \(RT\ln 7\)
3 \(RT\ln 1\)
4 \(RT\ln 3\)
Explanation:
Work done by the gas during the isothermal process. \(W=n R T \ln \dfrac{V_{2}}{V_{1}}\) \(=(1) R T \ln \left(\dfrac{7 V}{V}\right)=R T \ln 7\)
PHXI12:THERMODYNAMICS
371589
In which of the processes, does the internal energy of the system remain constant?
1 Isobaric
2 Isothermal
3 Adiabatic
4 Isochoric
Explanation:
The internal energy of a system remains a constant when the temperature does not change.
371585
Assertion : The internal energy of an isothermal process does not change Reason : The internal energy of a system depends only on pressure of the system.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
For an ideal gas undergoing an isothermal process, \(\Rightarrow T=\mathrm{constant}\) \(\Rightarrow \Delta T=0\) Assertion is correct. The internal energy of a system depends on temperature only Reason is false. So correct option is (3).
PHXI12:THERMODYNAMICS
371586
During an isothermal expansion, a confined ideal gas does \( - 150\;J\) of work against its surroundings. This implies that
1 \(300\;J\) of heat has been added to the gas
2 No heat is transferred because the process is isothermal
3 \(150\;J\) of heat has been added to the gas
4 \(150\;J\) heat has been removed from the gas
Explanation:
From the first law of the thermodynamics \(\Delta U=Q-W\) For isothermaal processes, \(\Delta U=0\) \(\therefore Q=W\) Given, \(W = 150\;J\) (Work done by the gas) Where \(Q\) is positive, the heat is added to the gas.
PHXI12:THERMODYNAMICS
371587
When an ideal gas in a cylinder was compressed isothermally by a piston, the work done on the gas was found to be \(1.5 \times 10^{4}\) joules. During this process
1 \(3.6 \times {10^3}cal\) of heat flowed into the gas
2 \(3.6 \times {10^3}cal\) of heat flowed goes out from the gas
3 \(1.5 \times {10^4}cal\) of heat flowed goes out from the gas
4 \(1.5 \times {10^4}cal\) of heat flowed into the gas
Explanation:
In isothermal compression, there is always an increase of heat which must flow out of the gas. \(\Delta Q = \Delta U + \Delta W \Rightarrow \Delta Q = \Delta W\quad [\because \Delta U = 0]\) \( \Rightarrow \Delta Q = - 1.5 \times {10^4}\;J = \frac{{1.5 \times {{10}^4}}}{{4.18}}cal = - 3.6 \times {10^3}cal.\)
PHXI12:THERMODYNAMICS
371588
One mole of an ideal gas undergoes an isothermal change at temperature \(T\) so that its volume 7 times its initial value. \(R\) is the molar gas constant. Work done by the gas during this change is
1 \(RT\ln 4\)
2 \(RT\ln 7\)
3 \(RT\ln 1\)
4 \(RT\ln 3\)
Explanation:
Work done by the gas during the isothermal process. \(W=n R T \ln \dfrac{V_{2}}{V_{1}}\) \(=(1) R T \ln \left(\dfrac{7 V}{V}\right)=R T \ln 7\)
PHXI12:THERMODYNAMICS
371589
In which of the processes, does the internal energy of the system remain constant?
1 Isobaric
2 Isothermal
3 Adiabatic
4 Isochoric
Explanation:
The internal energy of a system remains a constant when the temperature does not change.