371444
Assertion : In adiabatic expansion process, the product of \(p\) and \(V\) always decreases. Reason : In adiabatic expansion process, work is done by the gas at the cost of internal energy of gas.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Both Assertion and Reason are incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
In an adiabatic expansion temperature decreases, hence product \(P V\) decreases \((\therefore P V=\mu R T)\). So assertion is correct. Reason is also correct and supports assertion since work is done by the system at the cost of its internal energy. So, correct choice is (1).
AIIMS - 2017
PHXI12:THERMODYNAMICS
371445
A cycle tyre bursts suddenly. What is the type of this process?
1 Isochoric
2 Isothermal
3 Isobaric
4 Adiabatic
Explanation:
Sudden bursting of the cycle tyre is an adiabatic process.
KCET - 2014
PHXI12:THERMODYNAMICS
371446
A mass of diatomic gas \((\gamma=1.4)\) at a pressure of \(2\;atm\) is compressed adiabatically so that its temperature rise from \(27^\circ C\) to \(927^\circ C\). The pressure of the gas in final state is
1 \(28\;atm\)
2 \(68.7\,atm\)
3 \(256\,atm\)
4 \(8\,atm\)
Explanation:
\({T_1} = 273 + 27 = 300\;K\) \({T_2} = 273 + 927 = 1200\;K\) Gas equation for adiabatic process \(\begin{aligned}& P V^{\gamma}=\text { constant } \\& p\left(\dfrac{T}{p}\right)^{\gamma}=\text { constant } \quad(\because P V=R T) \\& \dfrac{p_{2}}{p_{1}}=\left(\dfrac{T_{2}}{T_{1}}\right)^{\frac{\gamma}{\gamma-1}} \text { or } p_{2}=p_{1}\left(\dfrac{T_{2}}{T_{1}}\right)^{\frac{\gamma}{\gamma-1}}\end{aligned}\) \({p_2} = 2{\left( {\frac{{1200}}{{300}}} \right)^{\frac{{1.4}}{{1.4 - 1}}}}\) \({p_2} = 256\;atm.\)
PHXI12:THERMODYNAMICS
371447
\(1\;g\) mole of an ideal gas at STP is subjected to a reversible adiabatic expansion to double its volume. Find the change in internal energy \((\gamma=1.4)\).
1 \(769.5\;J\)
2 \(1169.5\;J\)
3 \(969.5\;J\)
4 \(1369.5\;J\)
Explanation:
Use \(T_{1} V_{1}^{\gamma-1}=T_{2} V_{2}^{\gamma-1}\) \({T_2} = \frac{{{T_1}V_1^{\gamma - 1}}}{{V_2^{\gamma - 1}}} = \frac{{273}}{{{{(2)}^{0.4}}}} = 207\;K\) Change in internal energy \(\Delta u = \frac{R}{{(1 - \gamma )}}\left( {{T_1} - {T_2}} \right) = \frac{{8.31(273 - 207)}}{{1.4 - 1}} = 1369.5\;J\)
371444
Assertion : In adiabatic expansion process, the product of \(p\) and \(V\) always decreases. Reason : In adiabatic expansion process, work is done by the gas at the cost of internal energy of gas.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Both Assertion and Reason are incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
In an adiabatic expansion temperature decreases, hence product \(P V\) decreases \((\therefore P V=\mu R T)\). So assertion is correct. Reason is also correct and supports assertion since work is done by the system at the cost of its internal energy. So, correct choice is (1).
AIIMS - 2017
PHXI12:THERMODYNAMICS
371445
A cycle tyre bursts suddenly. What is the type of this process?
1 Isochoric
2 Isothermal
3 Isobaric
4 Adiabatic
Explanation:
Sudden bursting of the cycle tyre is an adiabatic process.
KCET - 2014
PHXI12:THERMODYNAMICS
371446
A mass of diatomic gas \((\gamma=1.4)\) at a pressure of \(2\;atm\) is compressed adiabatically so that its temperature rise from \(27^\circ C\) to \(927^\circ C\). The pressure of the gas in final state is
1 \(28\;atm\)
2 \(68.7\,atm\)
3 \(256\,atm\)
4 \(8\,atm\)
Explanation:
\({T_1} = 273 + 27 = 300\;K\) \({T_2} = 273 + 927 = 1200\;K\) Gas equation for adiabatic process \(\begin{aligned}& P V^{\gamma}=\text { constant } \\& p\left(\dfrac{T}{p}\right)^{\gamma}=\text { constant } \quad(\because P V=R T) \\& \dfrac{p_{2}}{p_{1}}=\left(\dfrac{T_{2}}{T_{1}}\right)^{\frac{\gamma}{\gamma-1}} \text { or } p_{2}=p_{1}\left(\dfrac{T_{2}}{T_{1}}\right)^{\frac{\gamma}{\gamma-1}}\end{aligned}\) \({p_2} = 2{\left( {\frac{{1200}}{{300}}} \right)^{\frac{{1.4}}{{1.4 - 1}}}}\) \({p_2} = 256\;atm.\)
PHXI12:THERMODYNAMICS
371447
\(1\;g\) mole of an ideal gas at STP is subjected to a reversible adiabatic expansion to double its volume. Find the change in internal energy \((\gamma=1.4)\).
1 \(769.5\;J\)
2 \(1169.5\;J\)
3 \(969.5\;J\)
4 \(1369.5\;J\)
Explanation:
Use \(T_{1} V_{1}^{\gamma-1}=T_{2} V_{2}^{\gamma-1}\) \({T_2} = \frac{{{T_1}V_1^{\gamma - 1}}}{{V_2^{\gamma - 1}}} = \frac{{273}}{{{{(2)}^{0.4}}}} = 207\;K\) Change in internal energy \(\Delta u = \frac{R}{{(1 - \gamma )}}\left( {{T_1} - {T_2}} \right) = \frac{{8.31(273 - 207)}}{{1.4 - 1}} = 1369.5\;J\)
371444
Assertion : In adiabatic expansion process, the product of \(p\) and \(V\) always decreases. Reason : In adiabatic expansion process, work is done by the gas at the cost of internal energy of gas.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Both Assertion and Reason are incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
In an adiabatic expansion temperature decreases, hence product \(P V\) decreases \((\therefore P V=\mu R T)\). So assertion is correct. Reason is also correct and supports assertion since work is done by the system at the cost of its internal energy. So, correct choice is (1).
AIIMS - 2017
PHXI12:THERMODYNAMICS
371445
A cycle tyre bursts suddenly. What is the type of this process?
1 Isochoric
2 Isothermal
3 Isobaric
4 Adiabatic
Explanation:
Sudden bursting of the cycle tyre is an adiabatic process.
KCET - 2014
PHXI12:THERMODYNAMICS
371446
A mass of diatomic gas \((\gamma=1.4)\) at a pressure of \(2\;atm\) is compressed adiabatically so that its temperature rise from \(27^\circ C\) to \(927^\circ C\). The pressure of the gas in final state is
1 \(28\;atm\)
2 \(68.7\,atm\)
3 \(256\,atm\)
4 \(8\,atm\)
Explanation:
\({T_1} = 273 + 27 = 300\;K\) \({T_2} = 273 + 927 = 1200\;K\) Gas equation for adiabatic process \(\begin{aligned}& P V^{\gamma}=\text { constant } \\& p\left(\dfrac{T}{p}\right)^{\gamma}=\text { constant } \quad(\because P V=R T) \\& \dfrac{p_{2}}{p_{1}}=\left(\dfrac{T_{2}}{T_{1}}\right)^{\frac{\gamma}{\gamma-1}} \text { or } p_{2}=p_{1}\left(\dfrac{T_{2}}{T_{1}}\right)^{\frac{\gamma}{\gamma-1}}\end{aligned}\) \({p_2} = 2{\left( {\frac{{1200}}{{300}}} \right)^{\frac{{1.4}}{{1.4 - 1}}}}\) \({p_2} = 256\;atm.\)
PHXI12:THERMODYNAMICS
371447
\(1\;g\) mole of an ideal gas at STP is subjected to a reversible adiabatic expansion to double its volume. Find the change in internal energy \((\gamma=1.4)\).
1 \(769.5\;J\)
2 \(1169.5\;J\)
3 \(969.5\;J\)
4 \(1369.5\;J\)
Explanation:
Use \(T_{1} V_{1}^{\gamma-1}=T_{2} V_{2}^{\gamma-1}\) \({T_2} = \frac{{{T_1}V_1^{\gamma - 1}}}{{V_2^{\gamma - 1}}} = \frac{{273}}{{{{(2)}^{0.4}}}} = 207\;K\) Change in internal energy \(\Delta u = \frac{R}{{(1 - \gamma )}}\left( {{T_1} - {T_2}} \right) = \frac{{8.31(273 - 207)}}{{1.4 - 1}} = 1369.5\;J\)
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PHXI12:THERMODYNAMICS
371444
Assertion : In adiabatic expansion process, the product of \(p\) and \(V\) always decreases. Reason : In adiabatic expansion process, work is done by the gas at the cost of internal energy of gas.
1 Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
3 Both Assertion and Reason are incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
In an adiabatic expansion temperature decreases, hence product \(P V\) decreases \((\therefore P V=\mu R T)\). So assertion is correct. Reason is also correct and supports assertion since work is done by the system at the cost of its internal energy. So, correct choice is (1).
AIIMS - 2017
PHXI12:THERMODYNAMICS
371445
A cycle tyre bursts suddenly. What is the type of this process?
1 Isochoric
2 Isothermal
3 Isobaric
4 Adiabatic
Explanation:
Sudden bursting of the cycle tyre is an adiabatic process.
KCET - 2014
PHXI12:THERMODYNAMICS
371446
A mass of diatomic gas \((\gamma=1.4)\) at a pressure of \(2\;atm\) is compressed adiabatically so that its temperature rise from \(27^\circ C\) to \(927^\circ C\). The pressure of the gas in final state is
1 \(28\;atm\)
2 \(68.7\,atm\)
3 \(256\,atm\)
4 \(8\,atm\)
Explanation:
\({T_1} = 273 + 27 = 300\;K\) \({T_2} = 273 + 927 = 1200\;K\) Gas equation for adiabatic process \(\begin{aligned}& P V^{\gamma}=\text { constant } \\& p\left(\dfrac{T}{p}\right)^{\gamma}=\text { constant } \quad(\because P V=R T) \\& \dfrac{p_{2}}{p_{1}}=\left(\dfrac{T_{2}}{T_{1}}\right)^{\frac{\gamma}{\gamma-1}} \text { or } p_{2}=p_{1}\left(\dfrac{T_{2}}{T_{1}}\right)^{\frac{\gamma}{\gamma-1}}\end{aligned}\) \({p_2} = 2{\left( {\frac{{1200}}{{300}}} \right)^{\frac{{1.4}}{{1.4 - 1}}}}\) \({p_2} = 256\;atm.\)
PHXI12:THERMODYNAMICS
371447
\(1\;g\) mole of an ideal gas at STP is subjected to a reversible adiabatic expansion to double its volume. Find the change in internal energy \((\gamma=1.4)\).
1 \(769.5\;J\)
2 \(1169.5\;J\)
3 \(969.5\;J\)
4 \(1369.5\;J\)
Explanation:
Use \(T_{1} V_{1}^{\gamma-1}=T_{2} V_{2}^{\gamma-1}\) \({T_2} = \frac{{{T_1}V_1^{\gamma - 1}}}{{V_2^{\gamma - 1}}} = \frac{{273}}{{{{(2)}^{0.4}}}} = 207\;K\) Change in internal energy \(\Delta u = \frac{R}{{(1 - \gamma )}}\left( {{T_1} - {T_2}} \right) = \frac{{8.31(273 - 207)}}{{1.4 - 1}} = 1369.5\;J\)
