NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXI12:THERMODYNAMICS
371297
One mole of a monoatomic ideal gas follows a process \({A B}\), as shown. The specific heat of the process is \({\dfrac{13 R}{6}}\). The value of \({n}\) on \({P}\)-axis is
371298
A gas at pressure \(6 \times {10^5}N{m^{ - 2}}\) and volume \(1\;{m^3}\) and its pressure falls to \(4 \times {10^5}N{m^{ - 2}}\) when its volume is \(3\;{m^3}\). Given that the indicator diagram is a straight line, work done by the system is
1 \(6 \times {10^5}\;J\)
2 \(3 \times {10^5}\;J\)
3 \(4 \times {10^5}\;J\)
4 \(10 \times {10^5}\;J\)
Explanation:
Work done by the system \(=\) area of rectangle \(BCDE + \) area of \(\Delta ABC\) \(=4 \times 10^{5} \times 2+\dfrac{2 \times 10^{5} \times 2}{2}\) \(W = 10 \times {10^5}\;J\)
PHXI12:THERMODYNAMICS
371299
An ideal gas undergoes four different processes from the same initial state as shown in the figure below. Those processes are adiabatic, isothermal, isobaric and isochoric. The curve which represents the adiabatic process among \(1,2,3\) and 4 is
1 2
2 3
3 4
4 1
Explanation:
1 : Isochoric \((\because \mathrm{V}=\) constant \()\) 2: Adiabatic \(\left(\because\right.\) non linear \(P V^{r}=\) constant \()\) 3: Isothermal \((\because P \propto \frac{1}{V}\,\,{\text{with}}\,\,T = \) constant ) 4: Isobaric (\(\because P = \) constant )
NEET - 2022
PHXI12:THERMODYNAMICS
371300
On a \(T - P\) diagram, two moles of ideal gas perform process \(AB\) and \(CD\). If the work done by the gas in the process \(AB\) is two times the work done in the process \(CD\) then what is the value of \(T_{1} / T_{2}\) ?
1 1
2 \(1 / 2\)
3 4
4 2
Explanation:
Let slope of line \(AC\) is \(m_{1} \&\) that of line \(DB\) is \(m_{2}\), then slope \((m)=\dfrac{T \text { coordinate }}{P \text { coordinate }}\) \(\Rightarrow P\)-coordinate \(=\dfrac{T-\text { coordinate }}{m}\) \(P_{A}=\dfrac{T_{1}}{m_{1}}, P_{B}=\dfrac{T_{1}}{m_{2}}, P_{C}=\dfrac{T_{2}}{m_{1}} \& P_{D}=\dfrac{T_{2}}{m_{2}}\)
Given that \({W_{AB}} = 2{W_{CD}}\) \(nR{T_1}\ln \frac{{{P_A}}}{{{P_B}}} = 2nR{T_2}\ln \frac{{{P_C}}}{{{P_D}}}\) \(nR{T_1}\ln \frac{{{m_2}}}{{{m_1}}} = 2nR{T_2}\ln \frac{{{m_2}}}{{{m_1}}}\frac{{{T_1}}}{{{T_2}}} = 2\)
371297
One mole of a monoatomic ideal gas follows a process \({A B}\), as shown. The specific heat of the process is \({\dfrac{13 R}{6}}\). The value of \({n}\) on \({P}\)-axis is
371298
A gas at pressure \(6 \times {10^5}N{m^{ - 2}}\) and volume \(1\;{m^3}\) and its pressure falls to \(4 \times {10^5}N{m^{ - 2}}\) when its volume is \(3\;{m^3}\). Given that the indicator diagram is a straight line, work done by the system is
1 \(6 \times {10^5}\;J\)
2 \(3 \times {10^5}\;J\)
3 \(4 \times {10^5}\;J\)
4 \(10 \times {10^5}\;J\)
Explanation:
Work done by the system \(=\) area of rectangle \(BCDE + \) area of \(\Delta ABC\) \(=4 \times 10^{5} \times 2+\dfrac{2 \times 10^{5} \times 2}{2}\) \(W = 10 \times {10^5}\;J\)
PHXI12:THERMODYNAMICS
371299
An ideal gas undergoes four different processes from the same initial state as shown in the figure below. Those processes are adiabatic, isothermal, isobaric and isochoric. The curve which represents the adiabatic process among \(1,2,3\) and 4 is
1 2
2 3
3 4
4 1
Explanation:
1 : Isochoric \((\because \mathrm{V}=\) constant \()\) 2: Adiabatic \(\left(\because\right.\) non linear \(P V^{r}=\) constant \()\) 3: Isothermal \((\because P \propto \frac{1}{V}\,\,{\text{with}}\,\,T = \) constant ) 4: Isobaric (\(\because P = \) constant )
NEET - 2022
PHXI12:THERMODYNAMICS
371300
On a \(T - P\) diagram, two moles of ideal gas perform process \(AB\) and \(CD\). If the work done by the gas in the process \(AB\) is two times the work done in the process \(CD\) then what is the value of \(T_{1} / T_{2}\) ?
1 1
2 \(1 / 2\)
3 4
4 2
Explanation:
Let slope of line \(AC\) is \(m_{1} \&\) that of line \(DB\) is \(m_{2}\), then slope \((m)=\dfrac{T \text { coordinate }}{P \text { coordinate }}\) \(\Rightarrow P\)-coordinate \(=\dfrac{T-\text { coordinate }}{m}\) \(P_{A}=\dfrac{T_{1}}{m_{1}}, P_{B}=\dfrac{T_{1}}{m_{2}}, P_{C}=\dfrac{T_{2}}{m_{1}} \& P_{D}=\dfrac{T_{2}}{m_{2}}\)
Given that \({W_{AB}} = 2{W_{CD}}\) \(nR{T_1}\ln \frac{{{P_A}}}{{{P_B}}} = 2nR{T_2}\ln \frac{{{P_C}}}{{{P_D}}}\) \(nR{T_1}\ln \frac{{{m_2}}}{{{m_1}}} = 2nR{T_2}\ln \frac{{{m_2}}}{{{m_1}}}\frac{{{T_1}}}{{{T_2}}} = 2\)
371297
One mole of a monoatomic ideal gas follows a process \({A B}\), as shown. The specific heat of the process is \({\dfrac{13 R}{6}}\). The value of \({n}\) on \({P}\)-axis is
371298
A gas at pressure \(6 \times {10^5}N{m^{ - 2}}\) and volume \(1\;{m^3}\) and its pressure falls to \(4 \times {10^5}N{m^{ - 2}}\) when its volume is \(3\;{m^3}\). Given that the indicator diagram is a straight line, work done by the system is
1 \(6 \times {10^5}\;J\)
2 \(3 \times {10^5}\;J\)
3 \(4 \times {10^5}\;J\)
4 \(10 \times {10^5}\;J\)
Explanation:
Work done by the system \(=\) area of rectangle \(BCDE + \) area of \(\Delta ABC\) \(=4 \times 10^{5} \times 2+\dfrac{2 \times 10^{5} \times 2}{2}\) \(W = 10 \times {10^5}\;J\)
PHXI12:THERMODYNAMICS
371299
An ideal gas undergoes four different processes from the same initial state as shown in the figure below. Those processes are adiabatic, isothermal, isobaric and isochoric. The curve which represents the adiabatic process among \(1,2,3\) and 4 is
1 2
2 3
3 4
4 1
Explanation:
1 : Isochoric \((\because \mathrm{V}=\) constant \()\) 2: Adiabatic \(\left(\because\right.\) non linear \(P V^{r}=\) constant \()\) 3: Isothermal \((\because P \propto \frac{1}{V}\,\,{\text{with}}\,\,T = \) constant ) 4: Isobaric (\(\because P = \) constant )
NEET - 2022
PHXI12:THERMODYNAMICS
371300
On a \(T - P\) diagram, two moles of ideal gas perform process \(AB\) and \(CD\). If the work done by the gas in the process \(AB\) is two times the work done in the process \(CD\) then what is the value of \(T_{1} / T_{2}\) ?
1 1
2 \(1 / 2\)
3 4
4 2
Explanation:
Let slope of line \(AC\) is \(m_{1} \&\) that of line \(DB\) is \(m_{2}\), then slope \((m)=\dfrac{T \text { coordinate }}{P \text { coordinate }}\) \(\Rightarrow P\)-coordinate \(=\dfrac{T-\text { coordinate }}{m}\) \(P_{A}=\dfrac{T_{1}}{m_{1}}, P_{B}=\dfrac{T_{1}}{m_{2}}, P_{C}=\dfrac{T_{2}}{m_{1}} \& P_{D}=\dfrac{T_{2}}{m_{2}}\)
Given that \({W_{AB}} = 2{W_{CD}}\) \(nR{T_1}\ln \frac{{{P_A}}}{{{P_B}}} = 2nR{T_2}\ln \frac{{{P_C}}}{{{P_D}}}\) \(nR{T_1}\ln \frac{{{m_2}}}{{{m_1}}} = 2nR{T_2}\ln \frac{{{m_2}}}{{{m_1}}}\frac{{{T_1}}}{{{T_2}}} = 2\)
371297
One mole of a monoatomic ideal gas follows a process \({A B}\), as shown. The specific heat of the process is \({\dfrac{13 R}{6}}\). The value of \({n}\) on \({P}\)-axis is
371298
A gas at pressure \(6 \times {10^5}N{m^{ - 2}}\) and volume \(1\;{m^3}\) and its pressure falls to \(4 \times {10^5}N{m^{ - 2}}\) when its volume is \(3\;{m^3}\). Given that the indicator diagram is a straight line, work done by the system is
1 \(6 \times {10^5}\;J\)
2 \(3 \times {10^5}\;J\)
3 \(4 \times {10^5}\;J\)
4 \(10 \times {10^5}\;J\)
Explanation:
Work done by the system \(=\) area of rectangle \(BCDE + \) area of \(\Delta ABC\) \(=4 \times 10^{5} \times 2+\dfrac{2 \times 10^{5} \times 2}{2}\) \(W = 10 \times {10^5}\;J\)
PHXI12:THERMODYNAMICS
371299
An ideal gas undergoes four different processes from the same initial state as shown in the figure below. Those processes are adiabatic, isothermal, isobaric and isochoric. The curve which represents the adiabatic process among \(1,2,3\) and 4 is
1 2
2 3
3 4
4 1
Explanation:
1 : Isochoric \((\because \mathrm{V}=\) constant \()\) 2: Adiabatic \(\left(\because\right.\) non linear \(P V^{r}=\) constant \()\) 3: Isothermal \((\because P \propto \frac{1}{V}\,\,{\text{with}}\,\,T = \) constant ) 4: Isobaric (\(\because P = \) constant )
NEET - 2022
PHXI12:THERMODYNAMICS
371300
On a \(T - P\) diagram, two moles of ideal gas perform process \(AB\) and \(CD\). If the work done by the gas in the process \(AB\) is two times the work done in the process \(CD\) then what is the value of \(T_{1} / T_{2}\) ?
1 1
2 \(1 / 2\)
3 4
4 2
Explanation:
Let slope of line \(AC\) is \(m_{1} \&\) that of line \(DB\) is \(m_{2}\), then slope \((m)=\dfrac{T \text { coordinate }}{P \text { coordinate }}\) \(\Rightarrow P\)-coordinate \(=\dfrac{T-\text { coordinate }}{m}\) \(P_{A}=\dfrac{T_{1}}{m_{1}}, P_{B}=\dfrac{T_{1}}{m_{2}}, P_{C}=\dfrac{T_{2}}{m_{1}} \& P_{D}=\dfrac{T_{2}}{m_{2}}\)
Given that \({W_{AB}} = 2{W_{CD}}\) \(nR{T_1}\ln \frac{{{P_A}}}{{{P_B}}} = 2nR{T_2}\ln \frac{{{P_C}}}{{{P_D}}}\) \(nR{T_1}\ln \frac{{{m_2}}}{{{m_1}}} = 2nR{T_2}\ln \frac{{{m_2}}}{{{m_1}}}\frac{{{T_1}}}{{{T_2}}} = 2\)
