371223
The internal energy of an ideal gas depends upon
1 Only its pressure
2 Only its volume
3 Only its temperature
4 Its pressure and volume
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371224
The first law of thermodynamics is based on the law of conservation of
1 Energy
2 Mass
3 Momentum
4 Pressure
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371225
When small amount of common salt is dissolved in water. In this process,
1 Entropy decreases
2 Entropy increases
3 Entropy becomes zero
4 Entropy remains constant
Explanation:
No heat is added or removed from the system.
PHXI12:THERMODYNAMICS
371226
A system is taken from state \(A\) to state \(B\) along two different paths 1 and 2 . The heat absorbed and work done by the system along these two paths are \(Q_{1}, Q_{2}\) and \(W_{1}, W_{2}\) respectively then
1 \(Q_{1}-W_{1}=Q_{2}-W_{2}\)
2 \(Q_{1}=Q_{2}\)
3 \(W_{1}=W_{2}\)
4 None
Explanation:
Internal energy change is path independent functions. \(\Delta U_{1}=\Delta U_{2}\) \(Q_{1}-W_{1}=Q_{2}-W_{2}\).
PHXI12:THERMODYNAMICS
371227
If \(150\;J\) of heat is added to a system and the work done by the system is \(110\;J\), then change in internal energy will be
1 \(260\,J\)
2 \(150\,J\)
3 \(110\,J\)
4 \(40\,J\)
Explanation:
\(\Delta Q=\Delta U+\Delta W\) \( \Rightarrow \Delta U = \Delta Q - \Delta W = 150 - 110 = 40\;J\)
371223
The internal energy of an ideal gas depends upon
1 Only its pressure
2 Only its volume
3 Only its temperature
4 Its pressure and volume
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371224
The first law of thermodynamics is based on the law of conservation of
1 Energy
2 Mass
3 Momentum
4 Pressure
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371225
When small amount of common salt is dissolved in water. In this process,
1 Entropy decreases
2 Entropy increases
3 Entropy becomes zero
4 Entropy remains constant
Explanation:
No heat is added or removed from the system.
PHXI12:THERMODYNAMICS
371226
A system is taken from state \(A\) to state \(B\) along two different paths 1 and 2 . The heat absorbed and work done by the system along these two paths are \(Q_{1}, Q_{2}\) and \(W_{1}, W_{2}\) respectively then
1 \(Q_{1}-W_{1}=Q_{2}-W_{2}\)
2 \(Q_{1}=Q_{2}\)
3 \(W_{1}=W_{2}\)
4 None
Explanation:
Internal energy change is path independent functions. \(\Delta U_{1}=\Delta U_{2}\) \(Q_{1}-W_{1}=Q_{2}-W_{2}\).
PHXI12:THERMODYNAMICS
371227
If \(150\;J\) of heat is added to a system and the work done by the system is \(110\;J\), then change in internal energy will be
1 \(260\,J\)
2 \(150\,J\)
3 \(110\,J\)
4 \(40\,J\)
Explanation:
\(\Delta Q=\Delta U+\Delta W\) \( \Rightarrow \Delta U = \Delta Q - \Delta W = 150 - 110 = 40\;J\)
371223
The internal energy of an ideal gas depends upon
1 Only its pressure
2 Only its volume
3 Only its temperature
4 Its pressure and volume
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371224
The first law of thermodynamics is based on the law of conservation of
1 Energy
2 Mass
3 Momentum
4 Pressure
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371225
When small amount of common salt is dissolved in water. In this process,
1 Entropy decreases
2 Entropy increases
3 Entropy becomes zero
4 Entropy remains constant
Explanation:
No heat is added or removed from the system.
PHXI12:THERMODYNAMICS
371226
A system is taken from state \(A\) to state \(B\) along two different paths 1 and 2 . The heat absorbed and work done by the system along these two paths are \(Q_{1}, Q_{2}\) and \(W_{1}, W_{2}\) respectively then
1 \(Q_{1}-W_{1}=Q_{2}-W_{2}\)
2 \(Q_{1}=Q_{2}\)
3 \(W_{1}=W_{2}\)
4 None
Explanation:
Internal energy change is path independent functions. \(\Delta U_{1}=\Delta U_{2}\) \(Q_{1}-W_{1}=Q_{2}-W_{2}\).
PHXI12:THERMODYNAMICS
371227
If \(150\;J\) of heat is added to a system and the work done by the system is \(110\;J\), then change in internal energy will be
1 \(260\,J\)
2 \(150\,J\)
3 \(110\,J\)
4 \(40\,J\)
Explanation:
\(\Delta Q=\Delta U+\Delta W\) \( \Rightarrow \Delta U = \Delta Q - \Delta W = 150 - 110 = 40\;J\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXI12:THERMODYNAMICS
371223
The internal energy of an ideal gas depends upon
1 Only its pressure
2 Only its volume
3 Only its temperature
4 Its pressure and volume
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371224
The first law of thermodynamics is based on the law of conservation of
1 Energy
2 Mass
3 Momentum
4 Pressure
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371225
When small amount of common salt is dissolved in water. In this process,
1 Entropy decreases
2 Entropy increases
3 Entropy becomes zero
4 Entropy remains constant
Explanation:
No heat is added or removed from the system.
PHXI12:THERMODYNAMICS
371226
A system is taken from state \(A\) to state \(B\) along two different paths 1 and 2 . The heat absorbed and work done by the system along these two paths are \(Q_{1}, Q_{2}\) and \(W_{1}, W_{2}\) respectively then
1 \(Q_{1}-W_{1}=Q_{2}-W_{2}\)
2 \(Q_{1}=Q_{2}\)
3 \(W_{1}=W_{2}\)
4 None
Explanation:
Internal energy change is path independent functions. \(\Delta U_{1}=\Delta U_{2}\) \(Q_{1}-W_{1}=Q_{2}-W_{2}\).
PHXI12:THERMODYNAMICS
371227
If \(150\;J\) of heat is added to a system and the work done by the system is \(110\;J\), then change in internal energy will be
1 \(260\,J\)
2 \(150\,J\)
3 \(110\,J\)
4 \(40\,J\)
Explanation:
\(\Delta Q=\Delta U+\Delta W\) \( \Rightarrow \Delta U = \Delta Q - \Delta W = 150 - 110 = 40\;J\)
371223
The internal energy of an ideal gas depends upon
1 Only its pressure
2 Only its volume
3 Only its temperature
4 Its pressure and volume
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371224
The first law of thermodynamics is based on the law of conservation of
1 Energy
2 Mass
3 Momentum
4 Pressure
Explanation:
Conceptual Question
PHXI12:THERMODYNAMICS
371225
When small amount of common salt is dissolved in water. In this process,
1 Entropy decreases
2 Entropy increases
3 Entropy becomes zero
4 Entropy remains constant
Explanation:
No heat is added or removed from the system.
PHXI12:THERMODYNAMICS
371226
A system is taken from state \(A\) to state \(B\) along two different paths 1 and 2 . The heat absorbed and work done by the system along these two paths are \(Q_{1}, Q_{2}\) and \(W_{1}, W_{2}\) respectively then
1 \(Q_{1}-W_{1}=Q_{2}-W_{2}\)
2 \(Q_{1}=Q_{2}\)
3 \(W_{1}=W_{2}\)
4 None
Explanation:
Internal energy change is path independent functions. \(\Delta U_{1}=\Delta U_{2}\) \(Q_{1}-W_{1}=Q_{2}-W_{2}\).
PHXI12:THERMODYNAMICS
371227
If \(150\;J\) of heat is added to a system and the work done by the system is \(110\;J\), then change in internal energy will be
1 \(260\,J\)
2 \(150\,J\)
3 \(110\,J\)
4 \(40\,J\)
Explanation:
\(\Delta Q=\Delta U+\Delta W\) \( \Rightarrow \Delta U = \Delta Q - \Delta W = 150 - 110 = 40\;J\)
