Explanation:
We have,
\({B_y} = 2 \times {10^{ - 7}}\sin \left( {0.5 \times {{10}^3}x + 1.5 \times {{10}^{11}}t} \right)\)
Comparing with the standard equation
\({B_y} = {B_0}\sin (kx + \omega t)\), we get
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,k = 0.5 \times {10^3}\)
\( \Rightarrow \,\,\,\,\,\,\,\,\lambda = \frac{{2\pi }}{k}\)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{2\pi }}{{0.5 \times {{10}^3}}}\,\)
\({\mkern 1mu} \,\,\,\,\,\,\,\,\,\, = 0.01256\;m\)
The wavelength range of microwaves is
\({10^{ - 3}}\) to \(0.1\;m.\) The wavelength of this
wave lies between \({10^{ - 3}}\) to \(0.1\;m\), so the
equation represents a microwave.