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PHXII10:WAVE OPTICS

368028 Assertion :
Distance between position of bright and dark fringe remain same in Young's double slit experiment.
Reason :
Fringe width, $β = \frac{λ D}{d}$

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect.

Explanation:

In Young's double-slit experiment, the distance between the positions of a bright and a dark fringe, known as fringe width $β$ , remains the same. This is a fundamental characteristic of interference patterns in such experiments and provides an explanation for the assertion. Fringe width $(β)$ is given by the equation $β = λ D / d$ , where $λ$ is the wavelength of the light used, $D$ is the distance between the source and the screen, and $d$ is the distance between the two slits. The fringe width depends on these parameters, and it is the same for both bright and dark fringes.

AIIMS - 2019

PHXII10:WAVE OPTICS

368029 In Young’s double slit experiment the separation $d$ between the slits is $2 m m$ , the wavelength $λ$ of the light used is $5896 \overset{\circ}{A}$ and distance $D$ between the screen and slits is $100 c m$ . It is found that the angular width of the fringes is ${0.20}^{\circ}$ . To increase the fringe angular width to ${0.21}^{\circ}$ (with same $λ a n d D$ ) the separation between the slits needs to be changed to

1

2.1 m m

2

1.7 m m

3

1.9 m m

4

1.8 m m

Explanation:

Given that
$d = 2 m m = 2 \times 10^{- 3} m, λ = 5896 \overset{\circ}{A} = 5896 \times 10^{- 10} m$
$D = 100 c m = 100 \times 10^{- 2} m$
Angular width of a fringe is $α = \frac{λ}{d}$
$∴ \frac{α_{1}}{α_{2}} = \frac{d_{2}}{d_{1}} = \frac{20}{21}$
$d_{2} = \frac{20}{21} d_{1} = \frac{20}{21} \times 2 m m = \frac{40}{21} = 1.9 m m$

NEET - 2018

PHXII10:WAVE OPTICS

368030 Assertion :
For best contrast between maxima and minima in the interference pattern of Young's double slit experiment, the intensity of light emerging out of the two slits should be equal.
Reason :
The intensity of interference pattern is proportional to amplitude.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

fringe visibility $V = [\frac{I_{max} - I_{min}}{I_{max} + I_{min}}]$
$I \propto a^{2}, I_{max} \propto {(a_{1} + a_{2})}^{2}$
$I_{min} \propto {(a_{1} - a_{2})}^{2}$
Where $a_{1}$ and $a_{2}$ are amplitudes.
For best visibility, $a_{1} = a_{2}$
So correct option is (3).

PHXII10:WAVE OPTICS

368031 In $Y D S E$ the angular fringe width does not depend upon.

1 Wavelength

(λ)

2 Distance between slits

(d)

3 Distance between slits and screen

(D)

4 Ratio

λ / d

Explanation:

$θ = \frac{β}{D} = \frac{λ}{d}$

PHXII10:WAVE OPTICS

368032 In Young’s double slit experiment the source is white light. One slit is covered with red filter and the other with blue filter. There shall be

1 Alternate red and blue fringes

2 Alternate dark and pink fringes

3 Alternate dark and yellow fringes

4 No interference

KCET - 2016

PHXII10:WAVE OPTICS

368028 Assertion :
Distance between position of bright and dark fringe remain same in Young's double slit experiment.
Reason :
Fringe width, $β = \frac{λ D}{d}$

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect.

Explanation:

In Young's double-slit experiment, the distance between the positions of a bright and a dark fringe, known as fringe width $β$ , remains the same. This is a fundamental characteristic of interference patterns in such experiments and provides an explanation for the assertion. Fringe width $(β)$ is given by the equation $β = λ D / d$ , where $λ$ is the wavelength of the light used, $D$ is the distance between the source and the screen, and $d$ is the distance between the two slits. The fringe width depends on these parameters, and it is the same for both bright and dark fringes.

AIIMS - 2019

PHXII10:WAVE OPTICS

368029 In Young’s double slit experiment the separation $d$ between the slits is $2 m m$ , the wavelength $λ$ of the light used is $5896 \overset{\circ}{A}$ and distance $D$ between the screen and slits is $100 c m$ . It is found that the angular width of the fringes is ${0.20}^{\circ}$ . To increase the fringe angular width to ${0.21}^{\circ}$ (with same $λ a n d D$ ) the separation between the slits needs to be changed to

1

2.1 m m

2

1.7 m m

3

1.9 m m

4

1.8 m m

Explanation:

Given that
$d = 2 m m = 2 \times 10^{- 3} m, λ = 5896 \overset{\circ}{A} = 5896 \times 10^{- 10} m$
$D = 100 c m = 100 \times 10^{- 2} m$
Angular width of a fringe is $α = \frac{λ}{d}$
$∴ \frac{α_{1}}{α_{2}} = \frac{d_{2}}{d_{1}} = \frac{20}{21}$
$d_{2} = \frac{20}{21} d_{1} = \frac{20}{21} \times 2 m m = \frac{40}{21} = 1.9 m m$

NEET - 2018

PHXII10:WAVE OPTICS

368030 Assertion :
For best contrast between maxima and minima in the interference pattern of Young's double slit experiment, the intensity of light emerging out of the two slits should be equal.
Reason :
The intensity of interference pattern is proportional to amplitude.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

fringe visibility $V = [\frac{I_{max} - I_{min}}{I_{max} + I_{min}}]$
$I \propto a^{2}, I_{max} \propto {(a_{1} + a_{2})}^{2}$
$I_{min} \propto {(a_{1} - a_{2})}^{2}$
Where $a_{1}$ and $a_{2}$ are amplitudes.
For best visibility, $a_{1} = a_{2}$
So correct option is (3).

PHXII10:WAVE OPTICS

368031 In $Y D S E$ the angular fringe width does not depend upon.

1 Wavelength

(λ)

2 Distance between slits

(d)

3 Distance between slits and screen

(D)

4 Ratio

λ / d

Explanation:

$θ = \frac{β}{D} = \frac{λ}{d}$

PHXII10:WAVE OPTICS

368032 In Young’s double slit experiment the source is white light. One slit is covered with red filter and the other with blue filter. There shall be

1 Alternate red and blue fringes

2 Alternate dark and pink fringes

3 Alternate dark and yellow fringes

4 No interference

KCET - 2016

PHXII10:WAVE OPTICS

368028 Assertion :
Distance between position of bright and dark fringe remain same in Young's double slit experiment.
Reason :
Fringe width, $β = \frac{λ D}{d}$

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect.

Explanation:

In Young's double-slit experiment, the distance between the positions of a bright and a dark fringe, known as fringe width $β$ , remains the same. This is a fundamental characteristic of interference patterns in such experiments and provides an explanation for the assertion. Fringe width $(β)$ is given by the equation $β = λ D / d$ , where $λ$ is the wavelength of the light used, $D$ is the distance between the source and the screen, and $d$ is the distance between the two slits. The fringe width depends on these parameters, and it is the same for both bright and dark fringes.

AIIMS - 2019

PHXII10:WAVE OPTICS

368029 In Young’s double slit experiment the separation $d$ between the slits is $2 m m$ , the wavelength $λ$ of the light used is $5896 \overset{\circ}{A}$ and distance $D$ between the screen and slits is $100 c m$ . It is found that the angular width of the fringes is ${0.20}^{\circ}$ . To increase the fringe angular width to ${0.21}^{\circ}$ (with same $λ a n d D$ ) the separation between the slits needs to be changed to

1

2.1 m m

2

1.7 m m

3

1.9 m m

4

1.8 m m

Explanation:

Given that
$d = 2 m m = 2 \times 10^{- 3} m, λ = 5896 \overset{\circ}{A} = 5896 \times 10^{- 10} m$
$D = 100 c m = 100 \times 10^{- 2} m$
Angular width of a fringe is $α = \frac{λ}{d}$
$∴ \frac{α_{1}}{α_{2}} = \frac{d_{2}}{d_{1}} = \frac{20}{21}$
$d_{2} = \frac{20}{21} d_{1} = \frac{20}{21} \times 2 m m = \frac{40}{21} = 1.9 m m$

NEET - 2018

PHXII10:WAVE OPTICS

368030 Assertion :
For best contrast between maxima and minima in the interference pattern of Young's double slit experiment, the intensity of light emerging out of the two slits should be equal.
Reason :
The intensity of interference pattern is proportional to amplitude.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

fringe visibility $V = [\frac{I_{max} - I_{min}}{I_{max} + I_{min}}]$
$I \propto a^{2}, I_{max} \propto {(a_{1} + a_{2})}^{2}$
$I_{min} \propto {(a_{1} - a_{2})}^{2}$
Where $a_{1}$ and $a_{2}$ are amplitudes.
For best visibility, $a_{1} = a_{2}$
So correct option is (3).

PHXII10:WAVE OPTICS

368031 In $Y D S E$ the angular fringe width does not depend upon.

1 Wavelength

(λ)

2 Distance between slits

(d)

3 Distance between slits and screen

(D)

4 Ratio

λ / d

Explanation:

$θ = \frac{β}{D} = \frac{λ}{d}$

PHXII10:WAVE OPTICS

368032 In Young’s double slit experiment the source is white light. One slit is covered with red filter and the other with blue filter. There shall be

1 Alternate red and blue fringes

2 Alternate dark and pink fringes

3 Alternate dark and yellow fringes

4 No interference

KCET - 2016

PHXII10:WAVE OPTICS

368028 Assertion :
Distance between position of bright and dark fringe remain same in Young's double slit experiment.
Reason :
Fringe width, $β = \frac{λ D}{d}$

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect.

Explanation:

In Young's double-slit experiment, the distance between the positions of a bright and a dark fringe, known as fringe width $β$ , remains the same. This is a fundamental characteristic of interference patterns in such experiments and provides an explanation for the assertion. Fringe width $(β)$ is given by the equation $β = λ D / d$ , where $λ$ is the wavelength of the light used, $D$ is the distance between the source and the screen, and $d$ is the distance between the two slits. The fringe width depends on these parameters, and it is the same for both bright and dark fringes.

AIIMS - 2019

PHXII10:WAVE OPTICS

368029 In Young’s double slit experiment the separation $d$ between the slits is $2 m m$ , the wavelength $λ$ of the light used is $5896 \overset{\circ}{A}$ and distance $D$ between the screen and slits is $100 c m$ . It is found that the angular width of the fringes is ${0.20}^{\circ}$ . To increase the fringe angular width to ${0.21}^{\circ}$ (with same $λ a n d D$ ) the separation between the slits needs to be changed to

1

2.1 m m

2

1.7 m m

3

1.9 m m

4

1.8 m m

Explanation:

Given that
$d = 2 m m = 2 \times 10^{- 3} m, λ = 5896 \overset{\circ}{A} = 5896 \times 10^{- 10} m$
$D = 100 c m = 100 \times 10^{- 2} m$
Angular width of a fringe is $α = \frac{λ}{d}$
$∴ \frac{α_{1}}{α_{2}} = \frac{d_{2}}{d_{1}} = \frac{20}{21}$
$d_{2} = \frac{20}{21} d_{1} = \frac{20}{21} \times 2 m m = \frac{40}{21} = 1.9 m m$

NEET - 2018

PHXII10:WAVE OPTICS

368030 Assertion :
For best contrast between maxima and minima in the interference pattern of Young's double slit experiment, the intensity of light emerging out of the two slits should be equal.
Reason :
The intensity of interference pattern is proportional to amplitude.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

fringe visibility $V = [\frac{I_{max} - I_{min}}{I_{max} + I_{min}}]$
$I \propto a^{2}, I_{max} \propto {(a_{1} + a_{2})}^{2}$
$I_{min} \propto {(a_{1} - a_{2})}^{2}$
Where $a_{1}$ and $a_{2}$ are amplitudes.
For best visibility, $a_{1} = a_{2}$
So correct option is (3).

PHXII10:WAVE OPTICS

368031 In $Y D S E$ the angular fringe width does not depend upon.

1 Wavelength

(λ)

2 Distance between slits

(d)

3 Distance between slits and screen

(D)

4 Ratio

λ / d

Explanation:

$θ = \frac{β}{D} = \frac{λ}{d}$

PHXII10:WAVE OPTICS

368032 In Young’s double slit experiment the source is white light. One slit is covered with red filter and the other with blue filter. There shall be

1 Alternate red and blue fringes

2 Alternate dark and pink fringes

3 Alternate dark and yellow fringes

4 No interference

KCET - 2016

PHXII10:WAVE OPTICS

368028 Assertion :
Distance between position of bright and dark fringe remain same in Young's double slit experiment.
Reason :
Fringe width, $β = \frac{λ D}{d}$

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Both Assertion and Reason are incorrect.

Explanation:

In Young's double-slit experiment, the distance between the positions of a bright and a dark fringe, known as fringe width $β$ , remains the same. This is a fundamental characteristic of interference patterns in such experiments and provides an explanation for the assertion. Fringe width $(β)$ is given by the equation $β = λ D / d$ , where $λ$ is the wavelength of the light used, $D$ is the distance between the source and the screen, and $d$ is the distance between the two slits. The fringe width depends on these parameters, and it is the same for both bright and dark fringes.

AIIMS - 2019

PHXII10:WAVE OPTICS

368029 In Young’s double slit experiment the separation $d$ between the slits is $2 m m$ , the wavelength $λ$ of the light used is $5896 \overset{\circ}{A}$ and distance $D$ between the screen and slits is $100 c m$ . It is found that the angular width of the fringes is ${0.20}^{\circ}$ . To increase the fringe angular width to ${0.21}^{\circ}$ (with same $λ a n d D$ ) the separation between the slits needs to be changed to

1

2.1 m m

2

1.7 m m

3

1.9 m m

4

1.8 m m

Explanation:

Given that
$d = 2 m m = 2 \times 10^{- 3} m, λ = 5896 \overset{\circ}{A} = 5896 \times 10^{- 10} m$
$D = 100 c m = 100 \times 10^{- 2} m$
Angular width of a fringe is $α = \frac{λ}{d}$
$∴ \frac{α_{1}}{α_{2}} = \frac{d_{2}}{d_{1}} = \frac{20}{21}$
$d_{2} = \frac{20}{21} d_{1} = \frac{20}{21} \times 2 m m = \frac{40}{21} = 1.9 m m$

NEET - 2018

PHXII10:WAVE OPTICS

368030 Assertion :
For best contrast between maxima and minima in the interference pattern of Young's double slit experiment, the intensity of light emerging out of the two slits should be equal.
Reason :
The intensity of interference pattern is proportional to amplitude.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

fringe visibility $V = [\frac{I_{max} - I_{min}}{I_{max} + I_{min}}]$
$I \propto a^{2}, I_{max} \propto {(a_{1} + a_{2})}^{2}$
$I_{min} \propto {(a_{1} - a_{2})}^{2}$
Where $a_{1}$ and $a_{2}$ are amplitudes.
For best visibility, $a_{1} = a_{2}$
So correct option is (3).

PHXII10:WAVE OPTICS

368031 In $Y D S E$ the angular fringe width does not depend upon.

1 Wavelength

(λ)

2 Distance between slits

(d)

3 Distance between slits and screen

(D)

4 Ratio

λ / d

Explanation:

$θ = \frac{β}{D} = \frac{λ}{d}$

PHXII10:WAVE OPTICS

368032 In Young’s double slit experiment the source is white light. One slit is covered with red filter and the other with blue filter. There shall be

1 Alternate red and blue fringes

2 Alternate dark and pink fringes

3 Alternate dark and yellow fringes

4 No interference

KCET - 2016