368010 Assertion :
If the whole apparatus of Young’s experiment is immersed in water, the fringe width will decrease.
Reason :
The wavelength of light in water is more than that of air.

368011 A screen is at a distance $D=80cm$ from a diaphragm having two narrow slits $S_1$ and $S_2$ which are $d=2mm$ apart. Slit $S_1$ is covered by a transparent sheet of thickness $t_1=2.5\mu m$ and slit $S_2$ is covered by another sheet of thickness $t_2=1.25\mu m$. (as in figure). Both sheets are made of same material having refractive index ${\mu }_s=1.40$. Water is filled in the space between diaphragm and screen. A monochromatic light beam of wavelength $\lambda =5000$$A^{\circ }$ is incident normally on the diaphragm. Assuming intensity of beam to be uniform, calculate the ratio of intensity of $C$ to maximum intensity of interference pattern obtained on the screen $({\mu }_w={\displaystyle \frac{4}{3}})$.

368013 An air gap of thickness $t$ is present infront of a slit as shown in the figure. The gap between the slits and the screen is filled with a liquid of refractive index ${\mu }_1$. The path difference between $S_{1}P$ and $S_{2}P$ is

368014 In Young's double slit experiment the two slits are illuminated by light of wavelength 5890 $A^{\circ }$ and the angular distance between any two consecutive bright fringes obtained on the screen is ${0.2}^{\circ }$. if the whole apparatus is immersed in water then the angular fringe width will be, (if the refractive index of water is $4/3$ ):

368010 Assertion :
If the whole apparatus of Young’s experiment is immersed in water, the fringe width will decrease.
Reason :
The wavelength of light in water is more than that of air.

368011 A screen is at a distance $D=80cm$ from a diaphragm having two narrow slits $S_1$ and $S_2$ which are $d=2mm$ apart. Slit $S_1$ is covered by a transparent sheet of thickness $t_1=2.5\mu m$ and slit $S_2$ is covered by another sheet of thickness $t_2=1.25\mu m$. (as in figure). Both sheets are made of same material having refractive index ${\mu }_s=1.40$. Water is filled in the space between diaphragm and screen. A monochromatic light beam of wavelength $\lambda =5000$$A^{\circ }$ is incident normally on the diaphragm. Assuming intensity of beam to be uniform, calculate the ratio of intensity of $C$ to maximum intensity of interference pattern obtained on the screen $({\mu }_w={\displaystyle \frac{4}{3}})$.

368012 A double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of $1mm$ and distance between the plane of slits and screen $1.33m$. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300$A^{\circ }$. The fringe width is:

368013 An air gap of thickness $t$ is present infront of a slit as shown in the figure. The gap between the slits and the screen is filled with a liquid of refractive index ${\mu }_1$. The path difference between $S_{1}P$ and $S_{2}P$ is

368014 In Young's double slit experiment the two slits are illuminated by light of wavelength 5890 $A^{\circ }$ and the angular distance between any two consecutive bright fringes obtained on the screen is ${0.2}^{\circ }$. if the whole apparatus is immersed in water then the angular fringe width will be, (if the refractive index of water is $4/3$ ):

368010 Assertion :
If the whole apparatus of Young’s experiment is immersed in water, the fringe width will decrease.
Reason :
The wavelength of light in water is more than that of air.

368011 A screen is at a distance $D=80cm$ from a diaphragm having two narrow slits $S_1$ and $S_2$ which are $d=2mm$ apart. Slit $S_1$ is covered by a transparent sheet of thickness $t_1=2.5\mu m$ and slit $S_2$ is covered by another sheet of thickness $t_2=1.25\mu m$. (as in figure). Both sheets are made of same material having refractive index ${\mu }_s=1.40$. Water is filled in the space between diaphragm and screen. A monochromatic light beam of wavelength $\lambda =5000$$A^{\circ }$ is incident normally on the diaphragm. Assuming intensity of beam to be uniform, calculate the ratio of intensity of $C$ to maximum intensity of interference pattern obtained on the screen $({\mu }_w={\displaystyle \frac{4}{3}})$.

368012 A double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of $1mm$ and distance between the plane of slits and screen $1.33m$. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300$A^{\circ }$. The fringe width is:

368013 An air gap of thickness $t$ is present infront of a slit as shown in the figure. The gap between the slits and the screen is filled with a liquid of refractive index ${\mu }_1$. The path difference between $S_{1}P$ and $S_{2}P$ is

368014 In Young's double slit experiment the two slits are illuminated by light of wavelength 5890 $A^{\circ }$ and the angular distance between any two consecutive bright fringes obtained on the screen is ${0.2}^{\circ }$. if the whole apparatus is immersed in water then the angular fringe width will be, (if the refractive index of water is $4/3$ ):

368010 Assertion :
If the whole apparatus of Young’s experiment is immersed in water, the fringe width will decrease.
Reason :
The wavelength of light in water is more than that of air.

368011 A screen is at a distance $D=80cm$ from a diaphragm having two narrow slits $S_1$ and $S_2$ which are $d=2mm$ apart. Slit $S_1$ is covered by a transparent sheet of thickness $t_1=2.5\mu m$ and slit $S_2$ is covered by another sheet of thickness $t_2=1.25\mu m$. (as in figure). Both sheets are made of same material having refractive index ${\mu }_s=1.40$. Water is filled in the space between diaphragm and screen. A monochromatic light beam of wavelength $\lambda =5000$$A^{\circ }$ is incident normally on the diaphragm. Assuming intensity of beam to be uniform, calculate the ratio of intensity of $C$ to maximum intensity of interference pattern obtained on the screen $({\mu }_w={\displaystyle \frac{4}{3}})$.

368012 A double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of $1mm$ and distance between the plane of slits and screen $1.33m$. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300$A^{\circ }$. The fringe width is:

368013 An air gap of thickness $t$ is present infront of a slit as shown in the figure. The gap between the slits and the screen is filled with a liquid of refractive index ${\mu }_1$. The path difference between $S_{1}P$ and $S_{2}P$ is

368014 In Young's double slit experiment the two slits are illuminated by light of wavelength 5890 $A^{\circ }$ and the angular distance between any two consecutive bright fringes obtained on the screen is ${0.2}^{\circ }$. if the whole apparatus is immersed in water then the angular fringe width will be, (if the refractive index of water is $4/3$ ):

368010 Assertion :
If the whole apparatus of Young’s experiment is immersed in water, the fringe width will decrease.
Reason :
The wavelength of light in water is more than that of air.

368011 A screen is at a distance $D=80cm$ from a diaphragm having two narrow slits $S_1$ and $S_2$ which are $d=2mm$ apart. Slit $S_1$ is covered by a transparent sheet of thickness $t_1=2.5\mu m$ and slit $S_2$ is covered by another sheet of thickness $t_2=1.25\mu m$. (as in figure). Both sheets are made of same material having refractive index ${\mu }_s=1.40$. Water is filled in the space between diaphragm and screen. A monochromatic light beam of wavelength $\lambda =5000$$A^{\circ }$ is incident normally on the diaphragm. Assuming intensity of beam to be uniform, calculate the ratio of intensity of $C$ to maximum intensity of interference pattern obtained on the screen $({\mu }_w={\displaystyle \frac{4}{3}})$.

368012 A double slit apparatus is immersed in a liquid of refractive index 1.33. It has slit separation of $1mm$ and distance between the plane of slits and screen $1.33m$. The slits are illuminated by a parallel beam of light whose wavelength in air is 6300$A^{\circ }$. The fringe width is:

368013 An air gap of thickness $t$ is present infront of a slit as shown in the figure. The gap between the slits and the screen is filled with a liquid of refractive index ${\mu }_1$. The path difference between $S_{1}P$ and $S_{2}P$ is

368014 In Young's double slit experiment the two slits are illuminated by light of wavelength 5890 $A^{\circ }$ and the angular distance between any two consecutive bright fringes obtained on the screen is ${0.2}^{\circ }$. if the whole apparatus is immersed in water then the angular fringe width will be, (if the refractive index of water is $4/3$ ):