368094
Light from two coherent sources of the same amplitude \(A\) and wavelength \(\lambda \) illuminates the screen. The intensity of the central maximum is \({I_{\rm{0}}}.\) If the sources were incoherent, the intensity at the same point will be
1 \(4{I_0}\)
2 \(2{I_0}\)
3 \({I_0}\)
4 \({I_0}/2\)
Explanation:
When the intensity of either of the two identical coherent sources is \(I\), the intensity at central maximum \( = 4I = {I_{0.}}\) When the two sources are non-coherent, the resultant intensity \( = 2I = {I_0}{\rm{/}}2.\)
KCET - 2007
PHXII10:WAVE OPTICS
368095
If the intensities of the two interfering beams in Young’s double-slit experiment are \({I_1}\) and \({I_2}\) then the contrast between the maximum and minimum intensities is good when
1 \({I_1}\,{\text{ and }}\,{I_2}\) is large
2 \({I_1}\,{\text{and}}\,{I_2}\) is small
3 either \({I_1}\,{\rm{or}}\,{I_2}\) is zero
4 \({I_1} = {I_2}\)
Explanation:
Conceptual Question
PHXII10:WAVE OPTICS
368096
In a double slit experiment, \({5^{th{\rm{ }}}}\) dark fringe is formed opposite to one of the slits, the wavelength of light is
1 \(\dfrac{d^{2}}{6 D}\)
2 \(\dfrac{d^{2}}{5 D}\)
3 \(\dfrac{d^{2}}{15 D}\)
4 \(\dfrac{d^{2}}{9 D}\)
Explanation:
\({n^{th{\rm{ }}}}\) dark fringe is formed at \(y_{n}=(2 n-1) \dfrac{D \lambda}{2 d}\) \(\therefore y_{5}=\dfrac{9 D \lambda}{2 d} \quad(\because n=5)\) Also, \(y_{5}=\dfrac{d}{2}\) \(\text { So, } \dfrac{d}{2}=\dfrac{9 D \lambda}{2 d} ; \lambda=\dfrac{d^{2}}{9 D}\)
PHXII10:WAVE OPTICS
368097
Two slits are separated by a distance of \(0.5\,mm\) and illuminated with light of \(\lambda = 6000\) \( \mathop A^{~~\circ} \). If the screen is placed \(2.5\,m\) from the slits, the distance of the third bright image from the center will be
1 \(1.5\,mm\)
2 \(3\,mm\)
3 \(6\,mm\)
4 \(9\,mm\)
Explanation:
Distance of the \({n^{\text {th }}}\) bright fringe from the centre \({X_{n}=\dfrac{n \lambda D}{d}}\) \( \Rightarrow {X_3} = \frac{{3 \times 6000 \times {{10}^{ - 10}} \times 2.5}}{{0.5 \times {{10}^{ - 3}}}}\) \( = 9 \times {10^{ - 3}}\;m = 9\;mm\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII10:WAVE OPTICS
368094
Light from two coherent sources of the same amplitude \(A\) and wavelength \(\lambda \) illuminates the screen. The intensity of the central maximum is \({I_{\rm{0}}}.\) If the sources were incoherent, the intensity at the same point will be
1 \(4{I_0}\)
2 \(2{I_0}\)
3 \({I_0}\)
4 \({I_0}/2\)
Explanation:
When the intensity of either of the two identical coherent sources is \(I\), the intensity at central maximum \( = 4I = {I_{0.}}\) When the two sources are non-coherent, the resultant intensity \( = 2I = {I_0}{\rm{/}}2.\)
KCET - 2007
PHXII10:WAVE OPTICS
368095
If the intensities of the two interfering beams in Young’s double-slit experiment are \({I_1}\) and \({I_2}\) then the contrast between the maximum and minimum intensities is good when
1 \({I_1}\,{\text{ and }}\,{I_2}\) is large
2 \({I_1}\,{\text{and}}\,{I_2}\) is small
3 either \({I_1}\,{\rm{or}}\,{I_2}\) is zero
4 \({I_1} = {I_2}\)
Explanation:
Conceptual Question
PHXII10:WAVE OPTICS
368096
In a double slit experiment, \({5^{th{\rm{ }}}}\) dark fringe is formed opposite to one of the slits, the wavelength of light is
1 \(\dfrac{d^{2}}{6 D}\)
2 \(\dfrac{d^{2}}{5 D}\)
3 \(\dfrac{d^{2}}{15 D}\)
4 \(\dfrac{d^{2}}{9 D}\)
Explanation:
\({n^{th{\rm{ }}}}\) dark fringe is formed at \(y_{n}=(2 n-1) \dfrac{D \lambda}{2 d}\) \(\therefore y_{5}=\dfrac{9 D \lambda}{2 d} \quad(\because n=5)\) Also, \(y_{5}=\dfrac{d}{2}\) \(\text { So, } \dfrac{d}{2}=\dfrac{9 D \lambda}{2 d} ; \lambda=\dfrac{d^{2}}{9 D}\)
PHXII10:WAVE OPTICS
368097
Two slits are separated by a distance of \(0.5\,mm\) and illuminated with light of \(\lambda = 6000\) \( \mathop A^{~~\circ} \). If the screen is placed \(2.5\,m\) from the slits, the distance of the third bright image from the center will be
1 \(1.5\,mm\)
2 \(3\,mm\)
3 \(6\,mm\)
4 \(9\,mm\)
Explanation:
Distance of the \({n^{\text {th }}}\) bright fringe from the centre \({X_{n}=\dfrac{n \lambda D}{d}}\) \( \Rightarrow {X_3} = \frac{{3 \times 6000 \times {{10}^{ - 10}} \times 2.5}}{{0.5 \times {{10}^{ - 3}}}}\) \( = 9 \times {10^{ - 3}}\;m = 9\;mm\)
368094
Light from two coherent sources of the same amplitude \(A\) and wavelength \(\lambda \) illuminates the screen. The intensity of the central maximum is \({I_{\rm{0}}}.\) If the sources were incoherent, the intensity at the same point will be
1 \(4{I_0}\)
2 \(2{I_0}\)
3 \({I_0}\)
4 \({I_0}/2\)
Explanation:
When the intensity of either of the two identical coherent sources is \(I\), the intensity at central maximum \( = 4I = {I_{0.}}\) When the two sources are non-coherent, the resultant intensity \( = 2I = {I_0}{\rm{/}}2.\)
KCET - 2007
PHXII10:WAVE OPTICS
368095
If the intensities of the two interfering beams in Young’s double-slit experiment are \({I_1}\) and \({I_2}\) then the contrast between the maximum and minimum intensities is good when
1 \({I_1}\,{\text{ and }}\,{I_2}\) is large
2 \({I_1}\,{\text{and}}\,{I_2}\) is small
3 either \({I_1}\,{\rm{or}}\,{I_2}\) is zero
4 \({I_1} = {I_2}\)
Explanation:
Conceptual Question
PHXII10:WAVE OPTICS
368096
In a double slit experiment, \({5^{th{\rm{ }}}}\) dark fringe is formed opposite to one of the slits, the wavelength of light is
1 \(\dfrac{d^{2}}{6 D}\)
2 \(\dfrac{d^{2}}{5 D}\)
3 \(\dfrac{d^{2}}{15 D}\)
4 \(\dfrac{d^{2}}{9 D}\)
Explanation:
\({n^{th{\rm{ }}}}\) dark fringe is formed at \(y_{n}=(2 n-1) \dfrac{D \lambda}{2 d}\) \(\therefore y_{5}=\dfrac{9 D \lambda}{2 d} \quad(\because n=5)\) Also, \(y_{5}=\dfrac{d}{2}\) \(\text { So, } \dfrac{d}{2}=\dfrac{9 D \lambda}{2 d} ; \lambda=\dfrac{d^{2}}{9 D}\)
PHXII10:WAVE OPTICS
368097
Two slits are separated by a distance of \(0.5\,mm\) and illuminated with light of \(\lambda = 6000\) \( \mathop A^{~~\circ} \). If the screen is placed \(2.5\,m\) from the slits, the distance of the third bright image from the center will be
1 \(1.5\,mm\)
2 \(3\,mm\)
3 \(6\,mm\)
4 \(9\,mm\)
Explanation:
Distance of the \({n^{\text {th }}}\) bright fringe from the centre \({X_{n}=\dfrac{n \lambda D}{d}}\) \( \Rightarrow {X_3} = \frac{{3 \times 6000 \times {{10}^{ - 10}} \times 2.5}}{{0.5 \times {{10}^{ - 3}}}}\) \( = 9 \times {10^{ - 3}}\;m = 9\;mm\)
368094
Light from two coherent sources of the same amplitude \(A\) and wavelength \(\lambda \) illuminates the screen. The intensity of the central maximum is \({I_{\rm{0}}}.\) If the sources were incoherent, the intensity at the same point will be
1 \(4{I_0}\)
2 \(2{I_0}\)
3 \({I_0}\)
4 \({I_0}/2\)
Explanation:
When the intensity of either of the two identical coherent sources is \(I\), the intensity at central maximum \( = 4I = {I_{0.}}\) When the two sources are non-coherent, the resultant intensity \( = 2I = {I_0}{\rm{/}}2.\)
KCET - 2007
PHXII10:WAVE OPTICS
368095
If the intensities of the two interfering beams in Young’s double-slit experiment are \({I_1}\) and \({I_2}\) then the contrast between the maximum and minimum intensities is good when
1 \({I_1}\,{\text{ and }}\,{I_2}\) is large
2 \({I_1}\,{\text{and}}\,{I_2}\) is small
3 either \({I_1}\,{\rm{or}}\,{I_2}\) is zero
4 \({I_1} = {I_2}\)
Explanation:
Conceptual Question
PHXII10:WAVE OPTICS
368096
In a double slit experiment, \({5^{th{\rm{ }}}}\) dark fringe is formed opposite to one of the slits, the wavelength of light is
1 \(\dfrac{d^{2}}{6 D}\)
2 \(\dfrac{d^{2}}{5 D}\)
3 \(\dfrac{d^{2}}{15 D}\)
4 \(\dfrac{d^{2}}{9 D}\)
Explanation:
\({n^{th{\rm{ }}}}\) dark fringe is formed at \(y_{n}=(2 n-1) \dfrac{D \lambda}{2 d}\) \(\therefore y_{5}=\dfrac{9 D \lambda}{2 d} \quad(\because n=5)\) Also, \(y_{5}=\dfrac{d}{2}\) \(\text { So, } \dfrac{d}{2}=\dfrac{9 D \lambda}{2 d} ; \lambda=\dfrac{d^{2}}{9 D}\)
PHXII10:WAVE OPTICS
368097
Two slits are separated by a distance of \(0.5\,mm\) and illuminated with light of \(\lambda = 6000\) \( \mathop A^{~~\circ} \). If the screen is placed \(2.5\,m\) from the slits, the distance of the third bright image from the center will be
1 \(1.5\,mm\)
2 \(3\,mm\)
3 \(6\,mm\)
4 \(9\,mm\)
Explanation:
Distance of the \({n^{\text {th }}}\) bright fringe from the centre \({X_{n}=\dfrac{n \lambda D}{d}}\) \( \Rightarrow {X_3} = \frac{{3 \times 6000 \times {{10}^{ - 10}} \times 2.5}}{{0.5 \times {{10}^{ - 3}}}}\) \( = 9 \times {10^{ - 3}}\;m = 9\;mm\)