QBManager

PHXII10:WAVE OPTICS

367884 When an unpolarised light is incident at an angle of $60^{\circ}$ on a transparent medium from air, the reflected ray is completely polarised. The angle of refraction in the medium is

1

30^{\circ}

2

45^{\circ}

3

90^{\circ}

4

60^{\circ}

Explanation:

As the ray of light is incident at polarising angle $(i_{p})$ , so the reflected and refracted rays will be perpendicular to each other.
If ' $r$ ' is the angle of refraction, then using Brewster's law
$i_{P} + r = 90^{\circ}$
$\Rightarrow r = 90^{\circ} - i_{p}$
Here, $i_{p} = 60^{\circ}$
$\Rightarrow r = 90^{\circ} - 60^{\circ} = 30^{\circ}$

JEE - 2024

PHXII10:WAVE OPTICS

367885 The polarising angle for transparent medium is $θ$ and $v$ is the speed of light in that medium. Then the relation between $θ$ and $v$ is ( $c$ = velocity of light in air)

1

θ = \tan^{- 1} (\frac{v}{c})

2

θ = \cot^{- 1} (\frac{v}{c})

3

θ = \sin^{- 1} (\frac{v}{c})

4

θ = \cos^{- 1} (\frac{v}{c})

Explanation:

From the relation, $\tan θ = μ = \frac{c}{v}$
$\Rightarrow \cot θ = \frac{v}{c}$
$∴ θ = \cot^{- 1} \frac{v}{c}$

PHXII10:WAVE OPTICS

367886 An unpolarised light beam strikes a glass surface at Brewster's angle. Then

1 The reflected light will be partially polarised.

2 The refracted light will be completely polarised.

3 Both the reflected and refracted light will be completely polarised.

4 The reflected light will be completely polarised but the refracted light will be partially polarised.

NEET - 2024

PHXII10:WAVE OPTICS

367887 Light waves can be polarised as they are

1 Of high frequency

2 Transverse

3 Reflected

4 Longitudinal

PHXII10:WAVE OPTICS

367888 Unpolarised light is incident on a dielectric of refractive index $\sqrt{3}$ , what is the angle of incidence if the reflected beam is completely polarised?

1

30^{\circ}

2

45^{\circ}

3

60^{\circ}

4

75^{\circ}

Explanation:

$μ = \tan i$
$\Rightarrow i = \tan^{- 1} (μ) = \tan^{- 1} (\sqrt{3}) = 60^{\circ}$

PHXII10:WAVE OPTICS

367884 When an unpolarised light is incident at an angle of $60^{\circ}$ on a transparent medium from air, the reflected ray is completely polarised. The angle of refraction in the medium is

1

30^{\circ}

2

45^{\circ}

3

90^{\circ}

4

60^{\circ}

Explanation:

As the ray of light is incident at polarising angle $(i_{p})$ , so the reflected and refracted rays will be perpendicular to each other.
If ' $r$ ' is the angle of refraction, then using Brewster's law
$i_{P} + r = 90^{\circ}$
$\Rightarrow r = 90^{\circ} - i_{p}$
Here, $i_{p} = 60^{\circ}$
$\Rightarrow r = 90^{\circ} - 60^{\circ} = 30^{\circ}$

JEE - 2024

PHXII10:WAVE OPTICS

367885 The polarising angle for transparent medium is $θ$ and $v$ is the speed of light in that medium. Then the relation between $θ$ and $v$ is ( $c$ = velocity of light in air)

1

θ = \tan^{- 1} (\frac{v}{c})

2

θ = \cot^{- 1} (\frac{v}{c})

3

θ = \sin^{- 1} (\frac{v}{c})

4

θ = \cos^{- 1} (\frac{v}{c})

Explanation:

From the relation, $\tan θ = μ = \frac{c}{v}$
$\Rightarrow \cot θ = \frac{v}{c}$
$∴ θ = \cot^{- 1} \frac{v}{c}$

PHXII10:WAVE OPTICS

367886 An unpolarised light beam strikes a glass surface at Brewster's angle. Then

1 The reflected light will be partially polarised.

2 The refracted light will be completely polarised.

3 Both the reflected and refracted light will be completely polarised.

4 The reflected light will be completely polarised but the refracted light will be partially polarised.

NEET - 2024

PHXII10:WAVE OPTICS

367887 Light waves can be polarised as they are

1 Of high frequency

2 Transverse

3 Reflected

4 Longitudinal

PHXII10:WAVE OPTICS

367888 Unpolarised light is incident on a dielectric of refractive index $\sqrt{3}$ , what is the angle of incidence if the reflected beam is completely polarised?

1

30^{\circ}

2

45^{\circ}

3

60^{\circ}

4

75^{\circ}

Explanation:

$μ = \tan i$
$\Rightarrow i = \tan^{- 1} (μ) = \tan^{- 1} (\sqrt{3}) = 60^{\circ}$

PHXII10:WAVE OPTICS

367884 When an unpolarised light is incident at an angle of $60^{\circ}$ on a transparent medium from air, the reflected ray is completely polarised. The angle of refraction in the medium is

1

30^{\circ}

2

45^{\circ}

3

90^{\circ}

4

60^{\circ}

Explanation:

As the ray of light is incident at polarising angle $(i_{p})$ , so the reflected and refracted rays will be perpendicular to each other.
If ' $r$ ' is the angle of refraction, then using Brewster's law
$i_{P} + r = 90^{\circ}$
$\Rightarrow r = 90^{\circ} - i_{p}$
Here, $i_{p} = 60^{\circ}$
$\Rightarrow r = 90^{\circ} - 60^{\circ} = 30^{\circ}$

JEE - 2024

PHXII10:WAVE OPTICS

367885 The polarising angle for transparent medium is $θ$ and $v$ is the speed of light in that medium. Then the relation between $θ$ and $v$ is ( $c$ = velocity of light in air)

1

θ = \tan^{- 1} (\frac{v}{c})

2

θ = \cot^{- 1} (\frac{v}{c})

3

θ = \sin^{- 1} (\frac{v}{c})

4

θ = \cos^{- 1} (\frac{v}{c})

Explanation:

From the relation, $\tan θ = μ = \frac{c}{v}$
$\Rightarrow \cot θ = \frac{v}{c}$
$∴ θ = \cot^{- 1} \frac{v}{c}$

PHXII10:WAVE OPTICS

367886 An unpolarised light beam strikes a glass surface at Brewster's angle. Then

1 The reflected light will be partially polarised.

2 The refracted light will be completely polarised.

3 Both the reflected and refracted light will be completely polarised.

4 The reflected light will be completely polarised but the refracted light will be partially polarised.

NEET - 2024

PHXII10:WAVE OPTICS

367887 Light waves can be polarised as they are

1 Of high frequency

2 Transverse

3 Reflected

4 Longitudinal

PHXII10:WAVE OPTICS

367888 Unpolarised light is incident on a dielectric of refractive index $\sqrt{3}$ , what is the angle of incidence if the reflected beam is completely polarised?

1

30^{\circ}

2

45^{\circ}

3

60^{\circ}

4

75^{\circ}

Explanation:

$μ = \tan i$
$\Rightarrow i = \tan^{- 1} (μ) = \tan^{- 1} (\sqrt{3}) = 60^{\circ}$

PHXII10:WAVE OPTICS

367884 When an unpolarised light is incident at an angle of $60^{\circ}$ on a transparent medium from air, the reflected ray is completely polarised. The angle of refraction in the medium is

1

30^{\circ}

2

45^{\circ}

3

90^{\circ}

4

60^{\circ}

Explanation:

As the ray of light is incident at polarising angle $(i_{p})$ , so the reflected and refracted rays will be perpendicular to each other.
If ' $r$ ' is the angle of refraction, then using Brewster's law
$i_{P} + r = 90^{\circ}$
$\Rightarrow r = 90^{\circ} - i_{p}$
Here, $i_{p} = 60^{\circ}$
$\Rightarrow r = 90^{\circ} - 60^{\circ} = 30^{\circ}$

JEE - 2024

PHXII10:WAVE OPTICS

367885 The polarising angle for transparent medium is $θ$ and $v$ is the speed of light in that medium. Then the relation between $θ$ and $v$ is ( $c$ = velocity of light in air)

1

θ = \tan^{- 1} (\frac{v}{c})

2

θ = \cot^{- 1} (\frac{v}{c})

3

θ = \sin^{- 1} (\frac{v}{c})

4

θ = \cos^{- 1} (\frac{v}{c})

Explanation:

From the relation, $\tan θ = μ = \frac{c}{v}$
$\Rightarrow \cot θ = \frac{v}{c}$
$∴ θ = \cot^{- 1} \frac{v}{c}$

PHXII10:WAVE OPTICS

367886 An unpolarised light beam strikes a glass surface at Brewster's angle. Then

1 The reflected light will be partially polarised.

2 The refracted light will be completely polarised.

3 Both the reflected and refracted light will be completely polarised.

4 The reflected light will be completely polarised but the refracted light will be partially polarised.

NEET - 2024

PHXII10:WAVE OPTICS

367887 Light waves can be polarised as they are

1 Of high frequency

2 Transverse

3 Reflected

4 Longitudinal

PHXII10:WAVE OPTICS

367888 Unpolarised light is incident on a dielectric of refractive index $\sqrt{3}$ , what is the angle of incidence if the reflected beam is completely polarised?

1

30^{\circ}

2

45^{\circ}

3

60^{\circ}

4

75^{\circ}

Explanation:

$μ = \tan i$
$\Rightarrow i = \tan^{- 1} (μ) = \tan^{- 1} (\sqrt{3}) = 60^{\circ}$

PHXII10:WAVE OPTICS

367884 When an unpolarised light is incident at an angle of $60^{\circ}$ on a transparent medium from air, the reflected ray is completely polarised. The angle of refraction in the medium is

1

30^{\circ}

2

45^{\circ}

3

90^{\circ}

4

60^{\circ}

Explanation:

As the ray of light is incident at polarising angle $(i_{p})$ , so the reflected and refracted rays will be perpendicular to each other.
If ' $r$ ' is the angle of refraction, then using Brewster's law
$i_{P} + r = 90^{\circ}$
$\Rightarrow r = 90^{\circ} - i_{p}$
Here, $i_{p} = 60^{\circ}$
$\Rightarrow r = 90^{\circ} - 60^{\circ} = 30^{\circ}$

JEE - 2024

PHXII10:WAVE OPTICS

367885 The polarising angle for transparent medium is $θ$ and $v$ is the speed of light in that medium. Then the relation between $θ$ and $v$ is ( $c$ = velocity of light in air)

1

θ = \tan^{- 1} (\frac{v}{c})

2

θ = \cot^{- 1} (\frac{v}{c})

3

θ = \sin^{- 1} (\frac{v}{c})

4

θ = \cos^{- 1} (\frac{v}{c})

Explanation:

From the relation, $\tan θ = μ = \frac{c}{v}$
$\Rightarrow \cot θ = \frac{v}{c}$
$∴ θ = \cot^{- 1} \frac{v}{c}$

PHXII10:WAVE OPTICS

367886 An unpolarised light beam strikes a glass surface at Brewster's angle. Then

1 The reflected light will be partially polarised.

2 The refracted light will be completely polarised.

3 Both the reflected and refracted light will be completely polarised.

4 The reflected light will be completely polarised but the refracted light will be partially polarised.

NEET - 2024

PHXII10:WAVE OPTICS

367887 Light waves can be polarised as they are

1 Of high frequency

2 Transverse

3 Reflected

4 Longitudinal

PHXII10:WAVE OPTICS

367888 Unpolarised light is incident on a dielectric of refractive index $\sqrt{3}$ , what is the angle of incidence if the reflected beam is completely polarised?

1

30^{\circ}

2

45^{\circ}

3

60^{\circ}

4

75^{\circ}

Explanation:

$μ = \tan i$
$\Rightarrow i = \tan^{- 1} (μ) = \tan^{- 1} (\sqrt{3}) = 60^{\circ}$