367812
The interference pattern is obtained with two coherent light sources of intensity ratio \(n\). In the interference pattern, the ratio \(\frac{{{I_{\max }} - {I_{\min }}}}{{{I_{\max }} + {I_{\min }}}}\) will be
1 \(\frac{{\sqrt n }}{{n + 1}}\)
2 \(\frac{{2\sqrt n }}{{n + 1}}\)
3 \(\frac{{\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
4 \(\frac{{2\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
367813
Assertion : The maximum intensity in interference pattern is four times the intensity due to each slit. Reason : Intensity is directly proportional to square of amplitude.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(I \propto a^{2}\), \(I_{\max } \propto(a+a)^{2} \propto\left(4 a^{2}\right)\) Intensity in double-slit interference is proportional to the square of amplitude. \(I_{\min } \propto\left(a_{1}-a_{2}\right)^{2}\) Destructive interference results in zero amplitude and minimum intensity, while constructive interference yields a fourfold increase in intensity. So correct option is (2).
PHXII10:WAVE OPTICS
367814
Two light beams of intensities in the ratio of 9 : 4 are allowed to interface. The ratio of the intensity of maxima and minima will be:
367815
Two coherent sources have intensity ratio of \(100: 1\), and are used for obtaining the phenomenon of interference. Then the ratio of maximum and minimum intensity will be-
367812
The interference pattern is obtained with two coherent light sources of intensity ratio \(n\). In the interference pattern, the ratio \(\frac{{{I_{\max }} - {I_{\min }}}}{{{I_{\max }} + {I_{\min }}}}\) will be
1 \(\frac{{\sqrt n }}{{n + 1}}\)
2 \(\frac{{2\sqrt n }}{{n + 1}}\)
3 \(\frac{{\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
4 \(\frac{{2\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
367813
Assertion : The maximum intensity in interference pattern is four times the intensity due to each slit. Reason : Intensity is directly proportional to square of amplitude.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(I \propto a^{2}\), \(I_{\max } \propto(a+a)^{2} \propto\left(4 a^{2}\right)\) Intensity in double-slit interference is proportional to the square of amplitude. \(I_{\min } \propto\left(a_{1}-a_{2}\right)^{2}\) Destructive interference results in zero amplitude and minimum intensity, while constructive interference yields a fourfold increase in intensity. So correct option is (2).
PHXII10:WAVE OPTICS
367814
Two light beams of intensities in the ratio of 9 : 4 are allowed to interface. The ratio of the intensity of maxima and minima will be:
367815
Two coherent sources have intensity ratio of \(100: 1\), and are used for obtaining the phenomenon of interference. Then the ratio of maximum and minimum intensity will be-
367812
The interference pattern is obtained with two coherent light sources of intensity ratio \(n\). In the interference pattern, the ratio \(\frac{{{I_{\max }} - {I_{\min }}}}{{{I_{\max }} + {I_{\min }}}}\) will be
1 \(\frac{{\sqrt n }}{{n + 1}}\)
2 \(\frac{{2\sqrt n }}{{n + 1}}\)
3 \(\frac{{\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
4 \(\frac{{2\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
367813
Assertion : The maximum intensity in interference pattern is four times the intensity due to each slit. Reason : Intensity is directly proportional to square of amplitude.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(I \propto a^{2}\), \(I_{\max } \propto(a+a)^{2} \propto\left(4 a^{2}\right)\) Intensity in double-slit interference is proportional to the square of amplitude. \(I_{\min } \propto\left(a_{1}-a_{2}\right)^{2}\) Destructive interference results in zero amplitude and minimum intensity, while constructive interference yields a fourfold increase in intensity. So correct option is (2).
PHXII10:WAVE OPTICS
367814
Two light beams of intensities in the ratio of 9 : 4 are allowed to interface. The ratio of the intensity of maxima and minima will be:
367815
Two coherent sources have intensity ratio of \(100: 1\), and are used for obtaining the phenomenon of interference. Then the ratio of maximum and minimum intensity will be-
367812
The interference pattern is obtained with two coherent light sources of intensity ratio \(n\). In the interference pattern, the ratio \(\frac{{{I_{\max }} - {I_{\min }}}}{{{I_{\max }} + {I_{\min }}}}\) will be
1 \(\frac{{\sqrt n }}{{n + 1}}\)
2 \(\frac{{2\sqrt n }}{{n + 1}}\)
3 \(\frac{{\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
4 \(\frac{{2\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
367813
Assertion : The maximum intensity in interference pattern is four times the intensity due to each slit. Reason : Intensity is directly proportional to square of amplitude.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(I \propto a^{2}\), \(I_{\max } \propto(a+a)^{2} \propto\left(4 a^{2}\right)\) Intensity in double-slit interference is proportional to the square of amplitude. \(I_{\min } \propto\left(a_{1}-a_{2}\right)^{2}\) Destructive interference results in zero amplitude and minimum intensity, while constructive interference yields a fourfold increase in intensity. So correct option is (2).
PHXII10:WAVE OPTICS
367814
Two light beams of intensities in the ratio of 9 : 4 are allowed to interface. The ratio of the intensity of maxima and minima will be:
367815
Two coherent sources have intensity ratio of \(100: 1\), and are used for obtaining the phenomenon of interference. Then the ratio of maximum and minimum intensity will be-
367812
The interference pattern is obtained with two coherent light sources of intensity ratio \(n\). In the interference pattern, the ratio \(\frac{{{I_{\max }} - {I_{\min }}}}{{{I_{\max }} + {I_{\min }}}}\) will be
1 \(\frac{{\sqrt n }}{{n + 1}}\)
2 \(\frac{{2\sqrt n }}{{n + 1}}\)
3 \(\frac{{\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
4 \(\frac{{2\sqrt n }}{{{{\left( {n + 1} \right)}^2}}}\)
367813
Assertion : The maximum intensity in interference pattern is four times the intensity due to each slit. Reason : Intensity is directly proportional to square of amplitude.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
\(I \propto a^{2}\), \(I_{\max } \propto(a+a)^{2} \propto\left(4 a^{2}\right)\) Intensity in double-slit interference is proportional to the square of amplitude. \(I_{\min } \propto\left(a_{1}-a_{2}\right)^{2}\) Destructive interference results in zero amplitude and minimum intensity, while constructive interference yields a fourfold increase in intensity. So correct option is (2).
PHXII10:WAVE OPTICS
367814
Two light beams of intensities in the ratio of 9 : 4 are allowed to interface. The ratio of the intensity of maxima and minima will be:
367815
Two coherent sources have intensity ratio of \(100: 1\), and are used for obtaining the phenomenon of interference. Then the ratio of maximum and minimum intensity will be-
