367704
A paralled beam of light of wavelength \(6000\mathop A\limits^o \) gets diffracted by a single slit of width \(0.3\,mm\). The angular position of the first minima of diffracted light is
367705
In diffraction experiment, from a single slit, the angular width of the central maxima does not depend upon
1 Ratio of wavelength and slit width
2 Distance of the slit from the screen
3 Wavelength of light used
4 Width of the slit
Explanation:
In diffraction from a single slit, the angular width of central maxima, \(\theta = \frac{{2\lambda }}{a}\) where, \(\lambda = \)wavelength of light used and \(a\) = width of the slit Therefore, Angular width does not depend upon the distance of the slit from the screen.
PHXII10:WAVE OPTICS
367706
In a Young's double slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is
1 12
2 24
3 3
4 6
Explanation:
Given that \(d = 6.1\,a\) Where \(a\) is the width of the slit. Width of central maxima is \(2\frac{{D\lambda }}{{\rm{a}}}\) \(n \times \frac{{D\lambda }}{d} = \frac{{2D\lambda }}{{\rm{a}}}\) \(n = 6.1 \times 2 = 12\)
JEE - 2014
PHXII10:WAVE OPTICS
367707
Angular width \(\left( \theta \right)\) of the central maximum of a diffraction pattern of a single slit does not depend upon:
1 Distance between slit and source
2 Wavelength of light used
3 Width of the slit
4 Frequency of light used
Explanation:
Angular width \(\theta = \frac{{2\lambda }}{a}\) \(\lambda - \) wavelength of the light \(a - \) width of the slit
PHXII10:WAVE OPTICS
367708
The first diffraction minima due to a single slit diffraciton at \(\theta = {30^ \circ }\) for a light of wavelength \(5000\mathop A\limits^ \circ \) . The width of the slit is
367704
A paralled beam of light of wavelength \(6000\mathop A\limits^o \) gets diffracted by a single slit of width \(0.3\,mm\). The angular position of the first minima of diffracted light is
367705
In diffraction experiment, from a single slit, the angular width of the central maxima does not depend upon
1 Ratio of wavelength and slit width
2 Distance of the slit from the screen
3 Wavelength of light used
4 Width of the slit
Explanation:
In diffraction from a single slit, the angular width of central maxima, \(\theta = \frac{{2\lambda }}{a}\) where, \(\lambda = \)wavelength of light used and \(a\) = width of the slit Therefore, Angular width does not depend upon the distance of the slit from the screen.
PHXII10:WAVE OPTICS
367706
In a Young's double slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is
1 12
2 24
3 3
4 6
Explanation:
Given that \(d = 6.1\,a\) Where \(a\) is the width of the slit. Width of central maxima is \(2\frac{{D\lambda }}{{\rm{a}}}\) \(n \times \frac{{D\lambda }}{d} = \frac{{2D\lambda }}{{\rm{a}}}\) \(n = 6.1 \times 2 = 12\)
JEE - 2014
PHXII10:WAVE OPTICS
367707
Angular width \(\left( \theta \right)\) of the central maximum of a diffraction pattern of a single slit does not depend upon:
1 Distance between slit and source
2 Wavelength of light used
3 Width of the slit
4 Frequency of light used
Explanation:
Angular width \(\theta = \frac{{2\lambda }}{a}\) \(\lambda - \) wavelength of the light \(a - \) width of the slit
PHXII10:WAVE OPTICS
367708
The first diffraction minima due to a single slit diffraciton at \(\theta = {30^ \circ }\) for a light of wavelength \(5000\mathop A\limits^ \circ \) . The width of the slit is
367704
A paralled beam of light of wavelength \(6000\mathop A\limits^o \) gets diffracted by a single slit of width \(0.3\,mm\). The angular position of the first minima of diffracted light is
367705
In diffraction experiment, from a single slit, the angular width of the central maxima does not depend upon
1 Ratio of wavelength and slit width
2 Distance of the slit from the screen
3 Wavelength of light used
4 Width of the slit
Explanation:
In diffraction from a single slit, the angular width of central maxima, \(\theta = \frac{{2\lambda }}{a}\) where, \(\lambda = \)wavelength of light used and \(a\) = width of the slit Therefore, Angular width does not depend upon the distance of the slit from the screen.
PHXII10:WAVE OPTICS
367706
In a Young's double slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is
1 12
2 24
3 3
4 6
Explanation:
Given that \(d = 6.1\,a\) Where \(a\) is the width of the slit. Width of central maxima is \(2\frac{{D\lambda }}{{\rm{a}}}\) \(n \times \frac{{D\lambda }}{d} = \frac{{2D\lambda }}{{\rm{a}}}\) \(n = 6.1 \times 2 = 12\)
JEE - 2014
PHXII10:WAVE OPTICS
367707
Angular width \(\left( \theta \right)\) of the central maximum of a diffraction pattern of a single slit does not depend upon:
1 Distance between slit and source
2 Wavelength of light used
3 Width of the slit
4 Frequency of light used
Explanation:
Angular width \(\theta = \frac{{2\lambda }}{a}\) \(\lambda - \) wavelength of the light \(a - \) width of the slit
PHXII10:WAVE OPTICS
367708
The first diffraction minima due to a single slit diffraciton at \(\theta = {30^ \circ }\) for a light of wavelength \(5000\mathop A\limits^ \circ \) . The width of the slit is
367704
A paralled beam of light of wavelength \(6000\mathop A\limits^o \) gets diffracted by a single slit of width \(0.3\,mm\). The angular position of the first minima of diffracted light is
367705
In diffraction experiment, from a single slit, the angular width of the central maxima does not depend upon
1 Ratio of wavelength and slit width
2 Distance of the slit from the screen
3 Wavelength of light used
4 Width of the slit
Explanation:
In diffraction from a single slit, the angular width of central maxima, \(\theta = \frac{{2\lambda }}{a}\) where, \(\lambda = \)wavelength of light used and \(a\) = width of the slit Therefore, Angular width does not depend upon the distance of the slit from the screen.
PHXII10:WAVE OPTICS
367706
In a Young's double slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is
1 12
2 24
3 3
4 6
Explanation:
Given that \(d = 6.1\,a\) Where \(a\) is the width of the slit. Width of central maxima is \(2\frac{{D\lambda }}{{\rm{a}}}\) \(n \times \frac{{D\lambda }}{d} = \frac{{2D\lambda }}{{\rm{a}}}\) \(n = 6.1 \times 2 = 12\)
JEE - 2014
PHXII10:WAVE OPTICS
367707
Angular width \(\left( \theta \right)\) of the central maximum of a diffraction pattern of a single slit does not depend upon:
1 Distance between slit and source
2 Wavelength of light used
3 Width of the slit
4 Frequency of light used
Explanation:
Angular width \(\theta = \frac{{2\lambda }}{a}\) \(\lambda - \) wavelength of the light \(a - \) width of the slit
PHXII10:WAVE OPTICS
367708
The first diffraction minima due to a single slit diffraciton at \(\theta = {30^ \circ }\) for a light of wavelength \(5000\mathop A\limits^ \circ \) . The width of the slit is
367704
A paralled beam of light of wavelength \(6000\mathop A\limits^o \) gets diffracted by a single slit of width \(0.3\,mm\). The angular position of the first minima of diffracted light is
367705
In diffraction experiment, from a single slit, the angular width of the central maxima does not depend upon
1 Ratio of wavelength and slit width
2 Distance of the slit from the screen
3 Wavelength of light used
4 Width of the slit
Explanation:
In diffraction from a single slit, the angular width of central maxima, \(\theta = \frac{{2\lambda }}{a}\) where, \(\lambda = \)wavelength of light used and \(a\) = width of the slit Therefore, Angular width does not depend upon the distance of the slit from the screen.
PHXII10:WAVE OPTICS
367706
In a Young's double slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is
1 12
2 24
3 3
4 6
Explanation:
Given that \(d = 6.1\,a\) Where \(a\) is the width of the slit. Width of central maxima is \(2\frac{{D\lambda }}{{\rm{a}}}\) \(n \times \frac{{D\lambda }}{d} = \frac{{2D\lambda }}{{\rm{a}}}\) \(n = 6.1 \times 2 = 12\)
JEE - 2014
PHXII10:WAVE OPTICS
367707
Angular width \(\left( \theta \right)\) of the central maximum of a diffraction pattern of a single slit does not depend upon:
1 Distance between slit and source
2 Wavelength of light used
3 Width of the slit
4 Frequency of light used
Explanation:
Angular width \(\theta = \frac{{2\lambda }}{a}\) \(\lambda - \) wavelength of the light \(a - \) width of the slit
PHXII10:WAVE OPTICS
367708
The first diffraction minima due to a single slit diffraciton at \(\theta = {30^ \circ }\) for a light of wavelength \(5000\mathop A\limits^ \circ \) . The width of the slit is
