367642
Each side of a cube is measured to be \(7.203\;m\). What are the total surface area and the volume of the cube to appropriate significant figures?
1 \(373.7\;{m^2},311.3\;{m^3}\)
2 \(311.3 m^{2}, 373.7 m^{3}\)
3 \(273.4 m^{2}, 342.4 m^{3}\)
4 \(423.4\;{m^2},437.4\;{m^3}\)
Explanation:
The number of significant figures in the measured length is 4. The calculated area and the volume should therefore be rounded off to 4 significant figures. Surface area of the cube \( = 6{(7.203)^2}\)\( = 311.299254\) \( = 311.3{m^2}\) Volume of the cube \( = {(7.203)^3} = 373.714754\) \( = 373.7\,\,{m^3}\)
PHXI02:UNITS AND MEASUREMENTS
367643
The number of significant figures in the numbers \(4.8000 \times {10^4}\) and \(48000.50\) are respectively you
1 \(5\,\operatorname{and} \,6\)
2 \(5\,\operatorname{and} \,7\)
3 \(2\,\operatorname{and} \,7\)
4 \(2\,\operatorname{and} \,6\)
Explanation:
All the non-zero digits are significant. The zero (\(s\)) right side to the decimal point are significant. Hence, \(48000 \times {10^4}\) has 5 significant figures. All the non-zero digits are significant. All the zeros between two non-zero digits are significant, no matter where the decimal point is. Hence, 48000.50 has 7 significant figures.
KCET - 2009
PHXI02:UNITS AND MEASUREMENTS
367644
The value of resistance is \(10.845\;\Omega \) and the current is 3.23 \(A\). On multiplying, we get the potential difference is 35.02935 \(V\). The value of potential difference in terms of significant figures would be
1 \(35.03\,V\)
2 \(35\,V\)
3 \(35.0\,V\)
4 \(35.029\,V\)
Explanation:
The final result should be 3 significant figures.So the correct answer is (3)
367642
Each side of a cube is measured to be \(7.203\;m\). What are the total surface area and the volume of the cube to appropriate significant figures?
1 \(373.7\;{m^2},311.3\;{m^3}\)
2 \(311.3 m^{2}, 373.7 m^{3}\)
3 \(273.4 m^{2}, 342.4 m^{3}\)
4 \(423.4\;{m^2},437.4\;{m^3}\)
Explanation:
The number of significant figures in the measured length is 4. The calculated area and the volume should therefore be rounded off to 4 significant figures. Surface area of the cube \( = 6{(7.203)^2}\)\( = 311.299254\) \( = 311.3{m^2}\) Volume of the cube \( = {(7.203)^3} = 373.714754\) \( = 373.7\,\,{m^3}\)
PHXI02:UNITS AND MEASUREMENTS
367643
The number of significant figures in the numbers \(4.8000 \times {10^4}\) and \(48000.50\) are respectively you
1 \(5\,\operatorname{and} \,6\)
2 \(5\,\operatorname{and} \,7\)
3 \(2\,\operatorname{and} \,7\)
4 \(2\,\operatorname{and} \,6\)
Explanation:
All the non-zero digits are significant. The zero (\(s\)) right side to the decimal point are significant. Hence, \(48000 \times {10^4}\) has 5 significant figures. All the non-zero digits are significant. All the zeros between two non-zero digits are significant, no matter where the decimal point is. Hence, 48000.50 has 7 significant figures.
KCET - 2009
PHXI02:UNITS AND MEASUREMENTS
367644
The value of resistance is \(10.845\;\Omega \) and the current is 3.23 \(A\). On multiplying, we get the potential difference is 35.02935 \(V\). The value of potential difference in terms of significant figures would be
1 \(35.03\,V\)
2 \(35\,V\)
3 \(35.0\,V\)
4 \(35.029\,V\)
Explanation:
The final result should be 3 significant figures.So the correct answer is (3)
367642
Each side of a cube is measured to be \(7.203\;m\). What are the total surface area and the volume of the cube to appropriate significant figures?
1 \(373.7\;{m^2},311.3\;{m^3}\)
2 \(311.3 m^{2}, 373.7 m^{3}\)
3 \(273.4 m^{2}, 342.4 m^{3}\)
4 \(423.4\;{m^2},437.4\;{m^3}\)
Explanation:
The number of significant figures in the measured length is 4. The calculated area and the volume should therefore be rounded off to 4 significant figures. Surface area of the cube \( = 6{(7.203)^2}\)\( = 311.299254\) \( = 311.3{m^2}\) Volume of the cube \( = {(7.203)^3} = 373.714754\) \( = 373.7\,\,{m^3}\)
PHXI02:UNITS AND MEASUREMENTS
367643
The number of significant figures in the numbers \(4.8000 \times {10^4}\) and \(48000.50\) are respectively you
1 \(5\,\operatorname{and} \,6\)
2 \(5\,\operatorname{and} \,7\)
3 \(2\,\operatorname{and} \,7\)
4 \(2\,\operatorname{and} \,6\)
Explanation:
All the non-zero digits are significant. The zero (\(s\)) right side to the decimal point are significant. Hence, \(48000 \times {10^4}\) has 5 significant figures. All the non-zero digits are significant. All the zeros between two non-zero digits are significant, no matter where the decimal point is. Hence, 48000.50 has 7 significant figures.
KCET - 2009
PHXI02:UNITS AND MEASUREMENTS
367644
The value of resistance is \(10.845\;\Omega \) and the current is 3.23 \(A\). On multiplying, we get the potential difference is 35.02935 \(V\). The value of potential difference in terms of significant figures would be
1 \(35.03\,V\)
2 \(35\,V\)
3 \(35.0\,V\)
4 \(35.029\,V\)
Explanation:
The final result should be 3 significant figures.So the correct answer is (3)
367642
Each side of a cube is measured to be \(7.203\;m\). What are the total surface area and the volume of the cube to appropriate significant figures?
1 \(373.7\;{m^2},311.3\;{m^3}\)
2 \(311.3 m^{2}, 373.7 m^{3}\)
3 \(273.4 m^{2}, 342.4 m^{3}\)
4 \(423.4\;{m^2},437.4\;{m^3}\)
Explanation:
The number of significant figures in the measured length is 4. The calculated area and the volume should therefore be rounded off to 4 significant figures. Surface area of the cube \( = 6{(7.203)^2}\)\( = 311.299254\) \( = 311.3{m^2}\) Volume of the cube \( = {(7.203)^3} = 373.714754\) \( = 373.7\,\,{m^3}\)
PHXI02:UNITS AND MEASUREMENTS
367643
The number of significant figures in the numbers \(4.8000 \times {10^4}\) and \(48000.50\) are respectively you
1 \(5\,\operatorname{and} \,6\)
2 \(5\,\operatorname{and} \,7\)
3 \(2\,\operatorname{and} \,7\)
4 \(2\,\operatorname{and} \,6\)
Explanation:
All the non-zero digits are significant. The zero (\(s\)) right side to the decimal point are significant. Hence, \(48000 \times {10^4}\) has 5 significant figures. All the non-zero digits are significant. All the zeros between two non-zero digits are significant, no matter where the decimal point is. Hence, 48000.50 has 7 significant figures.
KCET - 2009
PHXI02:UNITS AND MEASUREMENTS
367644
The value of resistance is \(10.845\;\Omega \) and the current is 3.23 \(A\). On multiplying, we get the potential difference is 35.02935 \(V\). The value of potential difference in terms of significant figures would be
1 \(35.03\,V\)
2 \(35\,V\)
3 \(35.0\,V\)
4 \(35.029\,V\)
Explanation:
The final result should be 3 significant figures.So the correct answer is (3)
