367571
Assertion : When we change the unit of measurement of a quantity, its numerical value changes. Reason : Smaller the unit of measurement smaller is its numerical value.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that \(Q = {n_1}{u_1} = {n_2}{u_2}\) are the two units of measurement of the quantity \(Q\) and \({n_1},{n_2}\) are their respective numerical values. From relation \(nu = {\mathop{\rm constant}\nolimits} \Rightarrow \,n \propto 1/u\) i.e., smaller the unit of measurement, greater is its numerical value. So, option (3) is correct.
PHXI02:UNITS AND MEASUREMENTS
367572
A new unit of length is chosen such that the speed of light in vacuum is unity. Then the distance between the sun and the earth in terms of the new unit, if light takes 8 min and 20 \(s\) to cover this distance?
1 500 new unit of length
2 300 new unit of length
3 600 new unit of length
4 None of these
Explanation:
The speed of light in vacuum \((3) = 1\)(new unit of length \({s^{ - 1}}\)) Time taken by light to reach the earth \(t = 8\min + 20s\) \( = \left( {8 \times 60 + 20} \right)s = 500s\) \(\therefore \) Distance between the sun and the earth \( = {\rm{Speed}}\,\,of\,\,light \times {\rm{Time}}\) \(x = c \times t\) \({\rm{ = (new}}\,{\rm{unit}}\,{\rm{of}}\,{\rm{lengt}}{{\rm{h}}^{{\rm{ - 1}}}}{\rm{) \times 500}}\,\) \(s\) \( = 500\) new unit of length
367574
Match the Column I with Column II and mark the correct choice from the given codes. Column I Column II A Gravitational field P Disintegration per second B Specific activity Q Energy per second C Power R metre per second\(^2\) D Emissive power S ampere per voltmeter
1 A - R, B - P, C - Q, D - S
2 A - P, B - R, C - S, D - Q
3 A - P, B - R, C - Q, D - S
4 A - Q, B - P, C - R, D - S
Explanation:
(A) Gravitational force experienced by unit mass is gravitational field. Thus, its unit is \(m{s^{ - 2}}\) (B) The unit of specific activity is disintegration per second. (C) \({\mathop{\rm Power}\nolimits} {\rm{ = }} \frac{{Energy}}{{Time}}\) (D) Coefficient of surface tension is the force per unit length.
367571
Assertion : When we change the unit of measurement of a quantity, its numerical value changes. Reason : Smaller the unit of measurement smaller is its numerical value.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that \(Q = {n_1}{u_1} = {n_2}{u_2}\) are the two units of measurement of the quantity \(Q\) and \({n_1},{n_2}\) are their respective numerical values. From relation \(nu = {\mathop{\rm constant}\nolimits} \Rightarrow \,n \propto 1/u\) i.e., smaller the unit of measurement, greater is its numerical value. So, option (3) is correct.
PHXI02:UNITS AND MEASUREMENTS
367572
A new unit of length is chosen such that the speed of light in vacuum is unity. Then the distance between the sun and the earth in terms of the new unit, if light takes 8 min and 20 \(s\) to cover this distance?
1 500 new unit of length
2 300 new unit of length
3 600 new unit of length
4 None of these
Explanation:
The speed of light in vacuum \((3) = 1\)(new unit of length \({s^{ - 1}}\)) Time taken by light to reach the earth \(t = 8\min + 20s\) \( = \left( {8 \times 60 + 20} \right)s = 500s\) \(\therefore \) Distance between the sun and the earth \( = {\rm{Speed}}\,\,of\,\,light \times {\rm{Time}}\) \(x = c \times t\) \({\rm{ = (new}}\,{\rm{unit}}\,{\rm{of}}\,{\rm{lengt}}{{\rm{h}}^{{\rm{ - 1}}}}{\rm{) \times 500}}\,\) \(s\) \( = 500\) new unit of length
367574
Match the Column I with Column II and mark the correct choice from the given codes. Column I Column II A Gravitational field P Disintegration per second B Specific activity Q Energy per second C Power R metre per second\(^2\) D Emissive power S ampere per voltmeter
1 A - R, B - P, C - Q, D - S
2 A - P, B - R, C - S, D - Q
3 A - P, B - R, C - Q, D - S
4 A - Q, B - P, C - R, D - S
Explanation:
(A) Gravitational force experienced by unit mass is gravitational field. Thus, its unit is \(m{s^{ - 2}}\) (B) The unit of specific activity is disintegration per second. (C) \({\mathop{\rm Power}\nolimits} {\rm{ = }} \frac{{Energy}}{{Time}}\) (D) Coefficient of surface tension is the force per unit length.
367571
Assertion : When we change the unit of measurement of a quantity, its numerical value changes. Reason : Smaller the unit of measurement smaller is its numerical value.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that \(Q = {n_1}{u_1} = {n_2}{u_2}\) are the two units of measurement of the quantity \(Q\) and \({n_1},{n_2}\) are their respective numerical values. From relation \(nu = {\mathop{\rm constant}\nolimits} \Rightarrow \,n \propto 1/u\) i.e., smaller the unit of measurement, greater is its numerical value. So, option (3) is correct.
PHXI02:UNITS AND MEASUREMENTS
367572
A new unit of length is chosen such that the speed of light in vacuum is unity. Then the distance between the sun and the earth in terms of the new unit, if light takes 8 min and 20 \(s\) to cover this distance?
1 500 new unit of length
2 300 new unit of length
3 600 new unit of length
4 None of these
Explanation:
The speed of light in vacuum \((3) = 1\)(new unit of length \({s^{ - 1}}\)) Time taken by light to reach the earth \(t = 8\min + 20s\) \( = \left( {8 \times 60 + 20} \right)s = 500s\) \(\therefore \) Distance between the sun and the earth \( = {\rm{Speed}}\,\,of\,\,light \times {\rm{Time}}\) \(x = c \times t\) \({\rm{ = (new}}\,{\rm{unit}}\,{\rm{of}}\,{\rm{lengt}}{{\rm{h}}^{{\rm{ - 1}}}}{\rm{) \times 500}}\,\) \(s\) \( = 500\) new unit of length
367574
Match the Column I with Column II and mark the correct choice from the given codes. Column I Column II A Gravitational field P Disintegration per second B Specific activity Q Energy per second C Power R metre per second\(^2\) D Emissive power S ampere per voltmeter
1 A - R, B - P, C - Q, D - S
2 A - P, B - R, C - S, D - Q
3 A - P, B - R, C - Q, D - S
4 A - Q, B - P, C - R, D - S
Explanation:
(A) Gravitational force experienced by unit mass is gravitational field. Thus, its unit is \(m{s^{ - 2}}\) (B) The unit of specific activity is disintegration per second. (C) \({\mathop{\rm Power}\nolimits} {\rm{ = }} \frac{{Energy}}{{Time}}\) (D) Coefficient of surface tension is the force per unit length.
367571
Assertion : When we change the unit of measurement of a quantity, its numerical value changes. Reason : Smaller the unit of measurement smaller is its numerical value.
1 Both assertion and reason are correct and reason is the correct explanation of assertion.
2 Both assertion and reason are correct but reason is not the correct explanation of assertion.
3 Assertion is correct but reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
We know that \(Q = {n_1}{u_1} = {n_2}{u_2}\) are the two units of measurement of the quantity \(Q\) and \({n_1},{n_2}\) are their respective numerical values. From relation \(nu = {\mathop{\rm constant}\nolimits} \Rightarrow \,n \propto 1/u\) i.e., smaller the unit of measurement, greater is its numerical value. So, option (3) is correct.
PHXI02:UNITS AND MEASUREMENTS
367572
A new unit of length is chosen such that the speed of light in vacuum is unity. Then the distance between the sun and the earth in terms of the new unit, if light takes 8 min and 20 \(s\) to cover this distance?
1 500 new unit of length
2 300 new unit of length
3 600 new unit of length
4 None of these
Explanation:
The speed of light in vacuum \((3) = 1\)(new unit of length \({s^{ - 1}}\)) Time taken by light to reach the earth \(t = 8\min + 20s\) \( = \left( {8 \times 60 + 20} \right)s = 500s\) \(\therefore \) Distance between the sun and the earth \( = {\rm{Speed}}\,\,of\,\,light \times {\rm{Time}}\) \(x = c \times t\) \({\rm{ = (new}}\,{\rm{unit}}\,{\rm{of}}\,{\rm{lengt}}{{\rm{h}}^{{\rm{ - 1}}}}{\rm{) \times 500}}\,\) \(s\) \( = 500\) new unit of length
367574
Match the Column I with Column II and mark the correct choice from the given codes. Column I Column II A Gravitational field P Disintegration per second B Specific activity Q Energy per second C Power R metre per second\(^2\) D Emissive power S ampere per voltmeter
1 A - R, B - P, C - Q, D - S
2 A - P, B - R, C - S, D - Q
3 A - P, B - R, C - Q, D - S
4 A - Q, B - P, C - R, D - S
Explanation:
(A) Gravitational force experienced by unit mass is gravitational field. Thus, its unit is \(m{s^{ - 2}}\) (B) The unit of specific activity is disintegration per second. (C) \({\mathop{\rm Power}\nolimits} {\rm{ = }} \frac{{Energy}}{{Time}}\) (D) Coefficient of surface tension is the force per unit length.
