367464 A physical quantity \(P\) is described by the relation \(P=a^{1 / 2} b^{2} c^{3} d^{-4}\). If the relative errors in the measurement of \(a, b, c\) and \(d\) respectively, are \(2 \%, 1 \%, 3 \%\) and \(5 \%\), then the relative error in \(P\) will be

367465 The mean absolute error in the time period of second’s pendulum is 0.05 \(s\). To express maximum estimate of error, the time period should be written as

367466 A cylindrical wire has a mass \((0.3 \pm 0.003)g\), radius \((0.5 \pm 0.005)mm\) and length \((6 \pm 0.06)cm\). The maximum percentage error in the measurement of its density is

367467 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is 20.0 \(cm\) known to 4 \(mm\) accuracy and time Period  of the pendulum is found to be 1 \(s\) using a wrist watch of accuracy \(0.005\). The accuracy in the determination of \(g\) is:

367468 The percentage of error in the measurement of mass and speed are 2% and 3% respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed?

367464 A physical quantity \(P\) is described by the relation \(P=a^{1 / 2} b^{2} c^{3} d^{-4}\). If the relative errors in the measurement of \(a, b, c\) and \(d\) respectively, are \(2 \%, 1 \%, 3 \%\) and \(5 \%\), then the relative error in \(P\) will be

367465 The mean absolute error in the time period of second’s pendulum is 0.05 \(s\). To express maximum estimate of error, the time period should be written as

367466 A cylindrical wire has a mass \((0.3 \pm 0.003)g\), radius \((0.5 \pm 0.005)mm\) and length \((6 \pm 0.06)cm\). The maximum percentage error in the measurement of its density is

367467 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is 20.0 \(cm\) known to 4 \(mm\) accuracy and time Period  of the pendulum is found to be 1 \(s\) using a wrist watch of accuracy \(0.005\). The accuracy in the determination of \(g\) is:

367468 The percentage of error in the measurement of mass and speed are 2% and 3% respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed?

367464 A physical quantity \(P\) is described by the relation \(P=a^{1 / 2} b^{2} c^{3} d^{-4}\). If the relative errors in the measurement of \(a, b, c\) and \(d\) respectively, are \(2 \%, 1 \%, 3 \%\) and \(5 \%\), then the relative error in \(P\) will be

367465 The mean absolute error in the time period of second’s pendulum is 0.05 \(s\). To express maximum estimate of error, the time period should be written as

367466 A cylindrical wire has a mass \((0.3 \pm 0.003)g\), radius \((0.5 \pm 0.005)mm\) and length \((6 \pm 0.06)cm\). The maximum percentage error in the measurement of its density is

367467 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is 20.0 \(cm\) known to 4 \(mm\) accuracy and time Period  of the pendulum is found to be 1 \(s\) using a wrist watch of accuracy \(0.005\). The accuracy in the determination of \(g\) is:

367468 The percentage of error in the measurement of mass and speed are 2% and 3% respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed?

367464 A physical quantity \(P\) is described by the relation \(P=a^{1 / 2} b^{2} c^{3} d^{-4}\). If the relative errors in the measurement of \(a, b, c\) and \(d\) respectively, are \(2 \%, 1 \%, 3 \%\) and \(5 \%\), then the relative error in \(P\) will be

367465 The mean absolute error in the time period of second’s pendulum is 0.05 \(s\). To express maximum estimate of error, the time period should be written as

367466 A cylindrical wire has a mass \((0.3 \pm 0.003)g\), radius \((0.5 \pm 0.005)mm\) and length \((6 \pm 0.06)cm\). The maximum percentage error in the measurement of its density is

367467 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is 20.0 \(cm\) known to 4 \(mm\) accuracy and time Period  of the pendulum is found to be 1 \(s\) using a wrist watch of accuracy \(0.005\). The accuracy in the determination of \(g\) is:

367468 The percentage of error in the measurement of mass and speed are 2% and 3% respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed?

367464 A physical quantity \(P\) is described by the relation \(P=a^{1 / 2} b^{2} c^{3} d^{-4}\). If the relative errors in the measurement of \(a, b, c\) and \(d\) respectively, are \(2 \%, 1 \%, 3 \%\) and \(5 \%\), then the relative error in \(P\) will be

367465 The mean absolute error in the time period of second’s pendulum is 0.05 \(s\). To express maximum estimate of error, the time period should be written as

367466 A cylindrical wire has a mass \((0.3 \pm 0.003)g\), radius \((0.5 \pm 0.005)mm\) and length \((6 \pm 0.06)cm\). The maximum percentage error in the measurement of its density is

367467 The period of oscillation of a simple pendulum is \(T = 2\pi \sqrt {\frac{L}{g}} .\) Measured value of \(L\) is 20.0 \(cm\) known to 4 \(mm\) accuracy and time Period  of the pendulum is found to be 1 \(s\) using a wrist watch of accuracy \(0.005\). The accuracy in the determination of \(g\) is:

367468 The percentage of error in the measurement of mass and speed are 2% and 3% respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed?