367268 If the time period \(t\) of the oscillation of a drop of liquid of density \(d,\) radius \(r,\) vibrating under surface tension \(s\) is given by the formula \(t=\sqrt{r^{2 b} s^{c} d^{a / 2}}\). It is observed that the time period is directly proportional \(\sqrt{\dfrac{d}{s}}\). The value of \(b\) should therefore be

367269 If \({d}\) is the depth to which a bullet of kinetic energy \({K}\) can penetrate into a human body of modulus of elasticity \({E}\), then using the method of dimension establish a relation between \({d, K}\) and \({E}\). If \({E=c d^{x} E^{y}}\), where \({c}\) is a dimensionless constant. Modulus of elasticity \({=\dfrac{\text { Force }}{\text { Area }} \times \dfrac{l}{\Delta l}}\) (where \({l}\) is length and \({\Delta l}\) is change in length). Find the value of \({x+y}\) is

367270 The frequency \((v)\) of an oscillating liquid drop may depend upon radius \((r)\) of the drop, density \((\rho)\) of liquid and the surface tension (s) of the liquid as : \(v = {r^a}\,{\rho ^b}\,{s^c}\) the values of \(a, b\), and \(c\) respectively are

367271 The relation between frequency of vibration \({f}\) and mass \({m}\) of a body suspended from a spring of spring constant \({k}\) is given by \({f={cm}^{x} k^{y}}\), where \({c}\) is a dimensionless constant. The value of \({x+y}\) is

367268 If the time period \(t\) of the oscillation of a drop of liquid of density \(d,\) radius \(r,\) vibrating under surface tension \(s\) is given by the formula \(t=\sqrt{r^{2 b} s^{c} d^{a / 2}}\). It is observed that the time period is directly proportional \(\sqrt{\dfrac{d}{s}}\). The value of \(b\) should therefore be

367269 If \({d}\) is the depth to which a bullet of kinetic energy \({K}\) can penetrate into a human body of modulus of elasticity \({E}\), then using the method of dimension establish a relation between \({d, K}\) and \({E}\). If \({E=c d^{x} E^{y}}\), where \({c}\) is a dimensionless constant. Modulus of elasticity \({=\dfrac{\text { Force }}{\text { Area }} \times \dfrac{l}{\Delta l}}\) (where \({l}\) is length and \({\Delta l}\) is change in length). Find the value of \({x+y}\) is

367270 The frequency \((v)\) of an oscillating liquid drop may depend upon radius \((r)\) of the drop, density \((\rho)\) of liquid and the surface tension (s) of the liquid as : \(v = {r^a}\,{\rho ^b}\,{s^c}\) the values of \(a, b\), and \(c\) respectively are

367271 The relation between frequency of vibration \({f}\) and mass \({m}\) of a body suspended from a spring of spring constant \({k}\) is given by \({f={cm}^{x} k^{y}}\), where \({c}\) is a dimensionless constant. The value of \({x+y}\) is

367268 If the time period \(t\) of the oscillation of a drop of liquid of density \(d,\) radius \(r,\) vibrating under surface tension \(s\) is given by the formula \(t=\sqrt{r^{2 b} s^{c} d^{a / 2}}\). It is observed that the time period is directly proportional \(\sqrt{\dfrac{d}{s}}\). The value of \(b\) should therefore be

367269 If \({d}\) is the depth to which a bullet of kinetic energy \({K}\) can penetrate into a human body of modulus of elasticity \({E}\), then using the method of dimension establish a relation between \({d, K}\) and \({E}\). If \({E=c d^{x} E^{y}}\), where \({c}\) is a dimensionless constant. Modulus of elasticity \({=\dfrac{\text { Force }}{\text { Area }} \times \dfrac{l}{\Delta l}}\) (where \({l}\) is length and \({\Delta l}\) is change in length). Find the value of \({x+y}\) is

367270 The frequency \((v)\) of an oscillating liquid drop may depend upon radius \((r)\) of the drop, density \((\rho)\) of liquid and the surface tension (s) of the liquid as : \(v = {r^a}\,{\rho ^b}\,{s^c}\) the values of \(a, b\), and \(c\) respectively are

367271 The relation between frequency of vibration \({f}\) and mass \({m}\) of a body suspended from a spring of spring constant \({k}\) is given by \({f={cm}^{x} k^{y}}\), where \({c}\) is a dimensionless constant. The value of \({x+y}\) is

367268 If the time period \(t\) of the oscillation of a drop of liquid of density \(d,\) radius \(r,\) vibrating under surface tension \(s\) is given by the formula \(t=\sqrt{r^{2 b} s^{c} d^{a / 2}}\). It is observed that the time period is directly proportional \(\sqrt{\dfrac{d}{s}}\). The value of \(b\) should therefore be

367269 If \({d}\) is the depth to which a bullet of kinetic energy \({K}\) can penetrate into a human body of modulus of elasticity \({E}\), then using the method of dimension establish a relation between \({d, K}\) and \({E}\). If \({E=c d^{x} E^{y}}\), where \({c}\) is a dimensionless constant. Modulus of elasticity \({=\dfrac{\text { Force }}{\text { Area }} \times \dfrac{l}{\Delta l}}\) (where \({l}\) is length and \({\Delta l}\) is change in length). Find the value of \({x+y}\) is

367270 The frequency \((v)\) of an oscillating liquid drop may depend upon radius \((r)\) of the drop, density \((\rho)\) of liquid and the surface tension (s) of the liquid as : \(v = {r^a}\,{\rho ^b}\,{s^c}\) the values of \(a, b\), and \(c\) respectively are

367271 The relation between frequency of vibration \({f}\) and mass \({m}\) of a body suspended from a spring of spring constant \({k}\) is given by \({f={cm}^{x} k^{y}}\), where \({c}\) is a dimensionless constant. The value of \({x+y}\) is